Basically i have the following query and i am trying to distinguish only the unique ranks from this:
WITH numbered_rows
as (
SELECT Claim,
reserve,
time,
RANK() OVER (PARTITION BY ClaimNumber ORDER BY time asc) as 'Rank'
FROM (
SELECT cc.Claim,
MAX(csd.time) as time,
csd.reserve
FROM ClaimData csd WITH (NOLOCK)
JOIN Core cc WITH (NOLOCK)
on cc.ClaimID = csd.ClaimID
GROUP BY cc.Claim, csd.Reserve
) as t
)
select *
from numbered_rows cur, numbered_rows prev
where cur.Claim= prev.Claim
and cur.Rank = prev.Rank -1
The results set I get is the following:
Claim reserve Time Rank Claim reserve Time Rank
--------------------------------------------------------------------
11 0 12/10/2012 1 11 15000 5/30/2013 2
34 2000 1/21/2013 1 34 750 1/31/2013 2
34 750 1/31/2013 2 34 0 3/31/2013 3
07 800000 5/9/2013 1 07 0 5/10/2013 2
But what I only want to see the following: (have the Claim 34 Rank 2 removed because its not the highest
Claim reserve Time Rank Claim reserve Time Rank
--------------------------------------------------------------------
11 0 12/10/2012 1 11 15000 5/30/2013 2
34 750 1/31/2013 2 34 0 3/31/2013 3
07 800000 5/9/2013 1 07 0 5/10/2013 2
I think you can do this by just reversing your logic, i.e. order by time DESC, switching cur and prev in your final select and changing -1 to +1 in your final select, then just limiting prev.rank to 1, therefore ensuring that the you only include the latest 2 results for each claim:
WITH numbered_rows AS
( SELECT Claim,
reserve,
time,
[Rank] = RANK() OVER (PARTITION BY ClaimNumber ORDER BY time DESC)
FROM ( SELECT cc.Claim,
[Time] = MAX(csd.time),
csd.reserve
FROM ClaimData AS csd WITH (NOLOCK)
INNER JOIN JOIN Core AS cc WITH (NOLOCK)
ON cc.ClaimID = csd.ClaimID
GROUP BY cc.Claim, csd.Reserve
) t
)
SELECT *
FROM numbered_rows AS prev
INNER JOIN numbered_rows AS cur
ON cur.Claim= prev.Claim
AND cur.Rank = prev.Rank + 1
WHERE prev.Rank = 1;
Related
I would like to allocate rows from one table to another using a sort on TopLvlOrd field. The inputs are the [Orders] table and the [Defects] table. I would like to create an SQL that produces [Output]. Even after a bunch of online research I'm not sure how to do this. I'd prefer not to do a cursor, but will go there if necessary. Any ideas? Using SQL Server 2012.
Rules:
(1) Allocate by TopLvlOrd asc,
(2) Allocate one TopLvlOrd row per PegQty
[Orders]
TopLvlOrd IntOrd PegQty
========= ====== ======
67 25 3
120 25 1
111 25 1
16 25 1
127 25 1
127 65 1
127 85 1
[Defects]
DefectID IntOrd TotQty
======== ====== ======
1 25 10
2 25 10
3 25 10
4 25 10
5 25 10
6 25 10
7 25 10
8 25 10
9 25 10
10 25 10
11 65 1
12 85 2
13 85 2
[Output]
DefectID IntOrd TotQty TopLvlOrd
======== ====== ====== =========
1 25 10 16
2 25 10 67
3 25 10 67
4 25 10 67
5 25 10 111
6 25 10 120
7 25 10 127
8 25 10 NULL
9 25 10 NULL
10 25 10 NULL
11 65 1 127
12 85 2 127
13 85 2 NULL
This answers the original version of the question.
I think you want to join on an implicit sequence number, which you can add using row_number():
select d.*, o.*
from (select d.*,
row_number() over (partition by intord order by defectid) as seqnum
from defects d
) d left join
(select o.*,
row_number() over (partition by IntOrd order by TopLvlOrd) as seqnum
from orders o
) o
on d.intord = o.intord and d.seqnum = o.seqnum
Please another time make another question. Please check this query:
SELECT DefectID, IntOrd,
TotQty, TopLvlOrd, PegQty
FROM
(
SELECT B. DefectID, COALESCE (A.IntOrd, B. IntOrd) IntOrd,
B.TotQty, A. TopLvlOrd, A.PegQty FROM
(
SELECT TopLvlOrd ,IntOrd, ROW_NUMBER () OVER (PARTITION By IntOrd ORDER by
TopLvlOrd) Num, PegQty FROM Orders
) A
FULL JOIN
(
SELECT DefectID , IntOrd ,TotQty, ROW_NUMBER () OVER (PARTITION By IntOrd ORDER by
TotQty) Num FROM Orders
) B
ON A. IntOrd=B.IntOrd AND A.Num=B.Num
)C
JOIN
master.dbo.spt_values Tab
ON Tab.type='P' AND Tab.number<C.PegQty
SELECT B. DefectID, COALESCE (A.IntOrd, B. IntOrd) IntOrd,
B.TotQty, A. TopLvlOrd FROM
(
SELECT TopLvlOrd ,IntOrd , ROW_NUMBER () OVER (PARTITION By IntOrd ORDER by TopLvlOrd) Num FROM Orders
) A
FULL JOIN
(
SELECT DefectID , IntOrd ,TotQty, ROW_NUMBER () OVER (PARTITION By IntOrd ORDER by TotQty) Num FROM Orders
) B
ON A. IntOrd=B.IntOrd AND A. Num=B.Num
I would need to determine how long amounts have been less than 200.
My dataset looks like
Id user time amount max_amount
25 3618 1 0 1
25 3618 1 17040 3
25 3618 1 30 2
27 4281 1 0 1
27 4281 1 14188 3
27 4281 1 17372 4
27 4281 1 190 2
And so on
The code to generate it is the following:
Select t2.id, t2.user, t1.time, sum(t1.amount_amt as float) / (t1.eur_amt as float) as amount,
rank () over (partition by t2.user order by amount) max_amount
From table1
Inner join table2 as t2
on t1.user=t2.user
Group by 1,2,3
My expected output would be
Id user time spent
25 3618 1 2
27 4281 1 2
How could I get this result?
I think you just want filtering and aggregation:
select id, user, time, count(*)
from t
where amount < 200
group by id, user, time;
If that table is generated by the code in the question, you can just use a CTE before the above query:
with t as (
<query>
)
How to get the max value order of each customer ?
select num, max(sum(paid*quantity))
from orders join
pizza
using (order#)
group by customer#;
table
num orderN price
-------- --- -------
1 109 30
1 118 25
3 101 30
3 115 27
4 107 23
5 100 17
5 129 16
output req-
num Pnum price
-------- --- -------
1 109 30
3 101 30
4 107 23
5 100 17
You want to select the record having the highest price in each group of nums.
If your RDBMS supports window functions, that's straight forward with ROW_NUMBER() :
SELECT num, pnum, price
FROM (
SELECT t.*, ROW_NUMBER OVER(PARTITION BY num ORDER BY price DESC) rn
FROM mytable t
) x
WHERE rn = 1
Else, you can take the following approach, that uses a NOT EXISTS condition with a correlated subquery to ensure that the record being joined in the one with the highest price for the current num :
SELECT num, pnum, price
FROM mytable t
WHERE NOT EXISTS (
SELECT 1 FROM mytable t1 WHERE t1.num = t.num AND t1.price > t.price
)
I am attempting to remove transactions that have been reversed from a table. the table has Account, Date, Amount and Row. If a transaction has been reversed Account will match and Amount will be inverse of each other.
Example Table
Account Date Amount Row
12 1/1/18 45 72 -- Case 1
12 1/2/18 50 73
12 1/2/18 -50 74
12 1/3/18 52 75
15 1/1/18 51 76 -- Case 2
15 1/2/18 51 77
15 1/2/18 -51 78
15 1/2/18 51 79
18 1/2/18 50 80 -- Case 3
18 1/2/18 50 81
18 1/2/18 -50 82
18 1/2/18 -50 83
18 1/3/18 50 84
18 1/3/18 50 85
20 1/1/18 57 88 -- Case 4
20 1/2/18 57 89
20 1/4/18 -57 90
20 1/5/18 57 91
Desired Results Table
Account Date Amount Row
12 1/1/18 45 72 -- Case 1
12 1/3/18 52 75
15 1/1/18 51 76 -- Case 2
15 1/2/18 51 79
18 1/3/18 50 84 -- Case 3
18 1/3/18 50 85
20 1/1/18 57 88 -- Case 4
20 1/5/18 57 91
Removing all instances of inverse transactions does not work when there are multiple transactions when all other columns are the same. My attempt was to count all duplicate transactions, count of all inverse duplicate transactions, subtracting those to get the number of rows I needed from each transactions group. I was going to pull the first X rows but found in most cases I want the last X rows of each group, or even a mix (the first and last in Case 2).
I either need a method of removing pairs from the original table, or working from what I have so far, a method of distinguishing which transactions to pull.
Code so far:
--adding row Numbers
with a as (
select
account a,
date d,
amount f,
row_number() over(order by account, date) r
from table),
--counting Duplicates
b as (
select a.a, a.f, Dups
from a join (
select a, f, count(*) Dups
from a
group by a.a, a.f
having count(*)>1
) b
on a.a=b.a and
b.f=a.f
where a.f>0
),
--counting inverse duplicates
c as (
select a.a, a.f, InvDups
from a join (
select a, f, count(*) InvDups
from a
group by a.a, a.f
having count(*)>1
) b
on a.a=b.a and
-b.f=a.f
where a.f>0
),
--combining c and d to get desired number of rows of each transaction group
d as (
select
b.a, b.f, dups, InvDups, Dups-InvDups TotalDups
from b join c
on b.a=c.a and
b.f=c.f
),
--getting the number of rows from the beginning of each transaction group
select d.a, d.d, d.f
from
(select
a, d, f, row_number() over (group by a, d, f) r2
from a) e
join d
on e.a=d.a and
TotalDups<=r2
You can try this.
SELECT T_P.* FROM
( SELECT *, ROW_NUMBER() OVER(PARTITION BY Account, Amount ORDER BY [Row] ) RN from #MyTable WHere Amount > 0 ) T_P
LEFT JOIN
( SELECT *, ROW_NUMBER() OVER(PARTITION BY Account, Amount ORDER BY [Row] ) RN from #MyTable WHere Amount < 0 ) T_N
ON T_P.Account = T_N.Account
AND T_P.Amount = ABS(T_N.Amount)
AND T_P.RN = T_N.RN
WHERE
T_N.Account IS NULL
The following handles your three cases:
with t as (
select t.*,
row_number() over (partition by account, date, amount order by row) as seqnum
from table t
)
select t.*
from t
where not exists (select 1
from t t2
where t2.account = t.account and t2.date = t.date and
t2.amount = -t.amount and t2.seqnum = t.seqnum
);
Use This
;WITH CTE
AS
(
SELECT
[Row]
FROM YourTable YT
WHERE Amount > 0
AND EXISTS
(
SELECT 1 FROM YourTable WHERE Account = YT.Account
AND [Date] = YT.[Date]
AND (Amount+YT.Amount)=0
)
UNION ALL
SELECT
[Row]
FROM YourTable YT
WHERE Amount < 0
AND EXISTS
(
SELECT 1 FROM YourTable WHERE Account = YT.Account
AND [Date] = YT.[Date]
AND (Amount+YT.Amount)>0
)
)
SELECT * FROM YourTable
WHERE EXISTS
(
SELECT 1 FROM CTE WHERE [Row] = YourTable.[Row]
)
I need a little help on a SQL query. I could not get the result that I wanted.
ID I10 H 10NS HNS CC NSCC
0 1 1 1 1 14 14
1 0 1 0 1 6 2
1 0 2 0 2 12 2
1 0 3 0 3 17 4
1 0 3 0 3 18 4
1 0 3 0 3 19 4
1 0 3 0 3 20 4
What I want to have is one from each ID with highest CC
For example,
ID I10 H 10NS HNS CC NSCC
0 1 1 1 1 14 14
1 0 3 0 3 20 4
I tried with this code:
SELECT a.ID, b.name, a.i10 as[i-10-index], a.h as[h-index], 10ns as[i-10-index based on non-self-citation], a.hns as [h-index based on non-self-citation],
max(a.[Citation Count]), (a.[Non-Self-Citation Count])
FROM tbl_lpNumerical as a
join tbl_lpAcademician as b
on a.ID= (b.ID-1)
GROUP BY a.ID, b.name, a.i10, a.h, a.10ns, a.hns,
a.[Non-Self-Citation Count]
order by a.ID desc
However, I could not get the desired results.
Thank you for your time.
You can simply get all the row where not exist another row with an higher CC
SELECT n.*
FROM tbl_lpNumerical n
WHERE NOT EXISTS ( SELECT 'b'
FROM tbl_lpNumerical n2
WHERE n2.ID = n.ID
AND n2.CC > n.CC
)
In SQL Server, you can use row_number() for this. Based on your sample data`, something like:
select sd.*
from (select sd.*, row_number() over (partition by id order by cc desc) as seqnum
from sampledata sd
) sd
where seqnum = 1;
I have no idea what your query has to do with the sample data. If it generates the data, then you can use a CTE:
with sampledata as (
<some query here>
)
select sd.*
from (select sd.*, row_number() over (partition by id order by cc desc) as seqnum
from sampledata sd
) sd
where seqnum = 1;
The following query will select a single row from each ID partition: the one with the highest CC value:
SELECT *
FROM (SELECT *,
ROW_NUMBER() OVER (PARTITION BY ID ORDER BY CC DESC) AS rn
FROM mytable) t
WHERE t.rn = 1
If there can be multiple rows having the same CC max value and you want all of them selected, then you can replace ROW_NUMBER() with RANK().