I have one NSDictionary and one NSMutableArray And I want store many object from NSDictionary into NSMutableArray from one key but I dont know about it.
this is my code :
//NSArray * a = [[NSArray alloc]initWithObjects:#"1",#"2",#"3",#"4",#"7",#"9", nil];
//NSArray *b = [[NSArray alloc]initWithObjects:#"1",#"2",#"3",#"4",#"5",#"0", nil];
NSDictionary * dic = [NSDictionary dictionaryWithObjectsAndKeys:a,#"number1",b,#"number2", nil];
NSMutableArray *array = [NSMutableArray alloc].... ?
I want store object in number1 key from NSDictionary in NSMutableArray
Since it appears that you store arrays as NSDictionary elements, you can do this:
NSMutableArray *array = [[NSMutableArray alloc] initiWithArray:dic[#"number1"]];
or
NSMutableArray *array = [NSMutableArray arrayWithArray:dic[#"number1"]];
To add object into NsDictionary Array do:
NSMutableDictionary * datos = [array objectAtIndex:i];
[datos setObject:#"hola" objectForKey#"newKey"];
Related
I'm working on a project where I read in a comma delimited value file generated by a device. I have no control over the file and it can contain 10-20 named parameters with thousands of values for each parameter over a time period. I plan on associating the DataRecord with the time after. That is, each time will have a DataRecord associated with it. So, my code needs to be dynamic when it comes to generating the parsing data structures. I'm having trouble figuring a way to unwrap the arrays I have parsed from the raw data file. Here is an example.
#interface DataRecord : NSObject
#property (nonatomic, strong) NSString *name;
#property (nonatomic, strong) NSArray *values;
#end
NSArray *nameArray = [[NSArray alloc] initWithObjects:
#"Analog", #"Battery", nil];
NSArray *valueArray1 = [[NSArray alloc] initWithObjects:
[NSNumber numberWithFloat:1.0f],
[NSNumber numberWithFloat:2.0f],
nil];
NSArray *valueArray2 = [[NSArray alloc] initWithObjects:
[NSNumber numberWithFloat:1.1f],
[NSNumber numberWithFloat:2.1f],
nil];
NSArray *valueArray3 = [[NSArray alloc] initWithObjects:
[NSNumber numberWithFloat:1.2f],
[NSNumber numberWithFloat:2.2f],
nil];
NSArray *valueArray4 = [[NSArray alloc] initWithObjects:
[NSNumber numberWithFloat:1.3f],
[NSNumber numberWithFloat:2.3f],
nil];
NSArray *arrayOfArrays = [NSArray arrayWithObjects:valueArray1,
valueArray2, valueArray3, valueArray4, nil];
What I'm looking to end up with is an array of Data Records,
DataRecord(0)
name: analog
values: (1.0, 1.1, 1.2, 1.3)
DataRecord(1)
name: battery
values: (2.0, 2.1, 2.2, 2.3)
Maybe I should be using Dictionaries, struct's, I'm not sure, chasing my tail.
Thank you.
Untested:
NSMutableArray *dataRecords = [NSMutableArray new];
for (NSUInteger i = 0; i < [nameArray count]; i++)
{
DataRecord *dr = [DataRecord new];
dr.name = nameArray[i];
NSMutableArray *values = [NSMutableArray new];
for (NSArray *array in arrayOfArrays)
[values addObject:array[i]];
dr.values = values;
[dataRecords addObject:dr];
}
I have a small doubt that is I have an NSArray which contains the following 4 objects:
Genesis, 1 Kings, leviticus, 2 Kings
I want to sort this array in dictionary order like i want an expected output like this
1 Kings, 2 Kings, Genesis, leviticus
How can this be achieved?
Go to this link:
https://developer.apple.com/library/archive/documentation/Cocoa/Conceptual/Collections/Articles/Arrays.html#//apple_ref/doc/uid/20000132-SW5
This is Apple documentation and your problem is solved over there.
Check out the example.
//First create the array of dictionaries
NSString *last = #"lastName";
NSString *first = #"firstName";
NSMutableArray *array = [NSMutableArray array];
NSArray *sortedArray;
NSDictionary *dict;
dict = [NSDictionary dictionaryWithObjectsAndKeys:
#"Jo", first, #"Smith", last, nil];
[array addObject:dict];
dict = [NSDictionary dictionaryWithObjectsAndKeys:
#"Joe", first, #"Smith", last, nil];
[array addObject:dict];
dict = [NSDictionary dictionaryWithObjectsAndKeys:
#"Joe", first, #"Smythe", last, nil];
[array addObject:dict];
dict = [NSDictionary dictionaryWithObjectsAndKeys:
#"Joanne", first, #"Smith", last, nil];
[array addObject:dict];
dict = [NSDictionary dictionaryWithObjectsAndKeys:
#"Robert", first, #"Jones", last, nil];
[array addObject:dict];
//Next we sort the contents of the array by last name then first name
// The results are likely to be shown to a user
// Note the use of the localizedCaseInsensitiveCompare: selector
NSSortDescriptor *lastDescriptor =[[NSSortDescriptor alloc] initWithKey:last
ascending:YES
selector:#selector(localizedCaseInsensitiveCompare:)];
NSSortDescriptor *firstDescriptor =
[[NSSortDescriptor alloc] initWithKey:first
ascending:YES
selector:#selector(localizedCaseInsensitiveCompare:)];
NSArray *descriptors = [NSArray arrayWithObjects:lastDescriptor, firstDescriptor, nil];
sortedArray = [array sortedArrayUsingDescriptors:descriptors];
This code is an example from Apple documentation.
You can sort an array of NSString alphabetically like this:
NSArray *sortedArray = [myArray sortedArrayUsingSelector:#selector(caseInsensitiveCompare:)];
What is the difference between of Parsing in the following code segments.
which codes segments is faster in Parsing?
NSArray *arr = [[NSArray alloc] initWithObjects:#"Apple",#"Macbook", nil];
NSMutableArray *data = (NSMutableArray *)arr;
(and)
NSArray *arr = [[NSArray alloc] initWithObjects:#"Apple",#"Macbook", nil];
NSMutableArray *data = [NSMutableArray arrayWithArray:arr];
You have the same mistake in both snippets, you allocate memory for the object, and then assign something else to data, which makes you lose the previous (and have memory leak), e.g. this:
NSMutableArray *data = [[NSMutableArray alloc] init];
data = [NSMutableArray arrayWithArray:arr];
should be
NSMutableArray *data = [NSMutableArray arrayWithArray:arr];
Now for the question itself:
The first case is a bad idea, you cast the NSArray, but you canot modify it, as you didn't really changed its type, only assigned it to NSMutaleArray pointer.
The second case will create a new NSMutableArray which is mutable, with the contents of the NSArray, and this is cool, you may alter this array now.
It looks like what you want is either:
NSArray *arr = [[NSArray alloc] initWithObjects:#"Apple",#"Macbook", nil];
NSMutableArray *data = [arr mutableCopy];
or:
NSMutableArray *data = [[NSMutableArray alloc] initWithObjects:#"Apple",#"Macbook", nil];
I have a variable declared as NSDictionary. How can I copy it to an extern const NSArray variable? For example:
NSMutableDictionary *selectedItem = [self.dataArray objectAtIndex:indexPath.row];
[selectedItem setObject:[NSNumber numberWithBool:targetCustomCell.checked]
forKey:#"checked"];
allKeys returns an NSArray containing all the keys. allValues returns an NSArray containing all the values.
NSArray *keys = [myDict allKeys];
NSArray *values = [myDict allValues];
Can each index of array hold the NSDictionary?
Thank You.
Yes, the value of an NSArray can resolve to an object identifier for an NSDictionary. However, the array doesn't "hold" the NSDictionary, nor can the index of an NSArray be an NSDictionary. An index from an Array is always an integer value.
An NSArray can hold any type of object, so yes, putting an NSDictionary in an NSArray works just fine.
You sure can, here is an example:
NSDictionary *dict1 = [[NSDictionary alloc] initWithObjectsAndKeys:
#"value1", #"key1", #"value2", #"key2", nil];
NSDictionary *dict2 = [[NSDictionary alloc] initWithObjectsAndKeys:
#"Billy", #"Goat", #"Rover", #"Dog", nil];
NSArray *arrayWithDictionaries = [[NSArray alloc] initWithObjects:
dict1, dict2, nil];
[dict1 release];
[dict2 release];