Sql - Fetch next value to replace variable value - sql

Question

Hi guys my basic sql knowledge needs some help
I want to be able to replace a variable value with a value in a table and keep running the query until the end value in the table is reached
start query
DECLARE #prime_SCHEMA VARCHAR(20)
DECLARE #next_SCHEMA VARCHAR(20)
DECLARE #TABLE_name VARCHAR(100)
DECLARE #SQL VARCHAR(500)
SET #prime_SCHEMA = 'aaa'
SET #next_SCHEMA = 'bbb'
SET #TABLE = 'table1'
SET #sql = 'select top 1 * into '+#next_SCHEMA +'.'+#TABLE_name +' from '+#prime_SCHEMA +'.'+#TABLE_name +' TRUNCATE TABLE '+#next_SCHEMA +'.'+#TABLE_name
print #sql
I now want to wrap this in a Fetch and use a table called 'table_val' to update the TABLE_name value
and loop around till all the rows have been used in the table
so effectively i could end up with multiple #sql statements
thanks

Answer 1

Try this one -
Query:
DECLARE
#prime_schema SYSNAME = 'aaa'
, #next_schema SYSNAME = 'bbb'
DECLARE #SQL NVARCHAR(MAX)
SELECT #SQL = (
SELECT CHAR(13) + '
SELECT *
INTO [' + #next_schema + '].[' + o.name + ']
FROM [' + s.name + '].[' + o.name + ']
WHERE 1 != 1'
FROM sys.objects o WITH (NOWAIT)
JOIN sys.schemas s WITH (NOWAIT) ON o.[schema_id] = s.[schema_id]
WHERE o.[type] = 'U'
AND s.name = #prime_schema
AND o.name IN ('table1', 'table2', 'table3')
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)')
PRINT #SQL
Output:
SELECT *
INTO [bbb].[table1]
FROM [aaa].[table1]
WHERE 1 != 1
SELECT *
INTO [bbb].[table2]
FROM [aaa].[table2]
WHERE 1 != 1
SELECT *
INTO [bbb].[table3]
FROM [aaa].[table3]
WHERE 1 != 1