If I have result set like that :
Work_hour(hh:mm)
10:24
12:59
06:28
where Work_hour is of type varchar
How to sum those hours and minutes with the same format ?
SELECT CAST(FLOOR(TMP1.MINS/60) AS VARCHAR) + ':' + CAST((TMP1.MINS % 60) AS VARCHAR) FROM (
SELECT SUM (CAST(LEFT(time_column, 2) AS INT) * 60 + CAST(RIGHT(time_column, 2) AS INT)) as MINS FROM table1
) AS TMP1
Where time_column is the column in the table and table1 is the name of the table. Example:
create table table1 (
time_column varchar(10)
);
insert into table1 (time_column) values ('12:20'), ('10:40'), ('15:50');
Results in: 38:50
Try this one -
Query:
DECLARE #temp TABLE
(
work_hour CHAR(5)
)
INSERT INTO #temp (work_hour)
VALUES
('10:24'),
('12:59'),
('06:28')
;WITH cte AS
(
SELECT mn = SUM(DATEDIFF(MINUTE, '19000101', CAST('19000101 ' + work_hour AS DATETIME)))
FROM #temp
)
SELECT CAST(FLOOR(mn / 60) AS VARCHAR(5)) + ':' + CAST(mn % 60 AS VARCHAR(2))
FROM cte
Output:
hm
--------
29:51
Update 2:
DECLARE #temp TABLE
(
transtime_out DATETIME
, transtime_in DATETIME
)
INSERT INTO #temp (transtime_out, transtime_in)
VALUES
('2013-05-19 16:40:53.000', '2013-05-19 08:58:07.000'),
('2013-05-19 16:40:53.000', '2013-05-19 08:58:07.000')
SELECT diff = LEFT(CONVERT(VARCHAR(10), CAST(SUM(CAST(a.transtime_out - a.transtime_in AS FLOAT)) AS DATETIME), 108), 5)
FROM #temp a
Related
I need to write such query:
SELECT CAST (date_time_column AS DATE) as 'Date',
AVG(CASE WHEN FORMAT(date_time_column, 'HH:mm') = '00:00' then my_values ELSE NULL end) as '00:00',
........
AVG(CASE WHEN FORMAT(date_time_column, 'HH:mm') = '23:59' then my_values ELSE NULL end) as '23:59'
FROM table
where date_time_column > '2021-08-12'
GROUP BY CAST (date_time_column AS DATE)
What is a way to avoid writing 1440 lines in a query?
Try the below method (Change the variables to match your table and field)
/*Generate all minutes in a day in a string variable*/
Declare #timeRange varchar(max)=null
declare #startdate Datetime='2021-08-12 00:00';
; WITH cte AS
(
SELECT 1 i, #startdate AS resultDate
UNION ALL
SELECT i + 1, DATEADD(minute, i, #startdate )
FROM cte
WHERE DATEADD(minute, i, #startdate ) < DateAdd(day,1,#startdate)
)
SELECT #timeRange=Coalesce(#timeRange +',' + '['+Format(resultDate,'HH:mm')+']','['+Format(resultDate,'HH:mm')+']') FROM cte
OPTION (MAXRECURSION 2000);
/* (Change These variables to match your table & fields */
declare #filterQuery varchar(300)=' where {date_time_column}>''2021-01-01''';
declare #dateTimeColumn varchar(30)='{date_time_column}';
declare #valueColumn varchar(30)='{value_column}';
declare #myTable varchar(20)='{my_table}';
/*Generate Pivot Query */
DECLARE #query AS NVARCHAR(MAX);
set #query= '
SELECT *
FROM (SELECT Cast('+ #dateTimeColumn +' as Date) Resultdate,
FORMAT(' + #dateTimeColumn + ', ''HH:mm'') DateMinute,
' + #valueColumn + ' FROM ' + #myTable + ' ' + #filterQuery +'
) FormattedData
PIVOT( AVG('+ #valueColumn + ')
FOR DateMinute IN ('+ #timeRange +')
) AS pivotTable
';
/*Execute Generated Query*/
execute(#query)
What you want to do is to return your data in rows, not columns. That is a row for every minute rather than a column for every minute.
Try it something like this:
WITH
cteNums AS
(
Select TOP (1440) ROW_NUMBER() OVER(order by (Select Null)) - 1 as num
From sys.all_columns
Order By num
)
, cteMinutes AS
(
Select FORMAT(CAST(num/cast(1440.0 as real) as DATETIME), N'HH:mm') as Minutes
From cteNums
)
select CAST(t.date_time_column AS DATE) as 'Date',
m.Minutes,
AVG(CASE WHEN FORMAT(t.date_time_column, 'HH:mm') = m.Minute then t.my_values ELSE NULL end) as AvgValues
FROM cteMinutes m
LEFT JOIN [table] t ON m.Minutes = FORMAT(t.date_time_column, 'HH:mm')
where t.date_time_column > '2021-08-12'
GROUP BY CAST(t.date_time_column AS DATE), m.Minutes
ORDER BY CAST(t.date_time_column AS DATE), m.Minutes
;
I cannot, of course, test this as no test data or table definitions were provided.
I need a help to change the Month & Year column as Date in Result.
Ex :
Table Name : AA
Month Year
4 2016
5 2015
Result Should Be:
01-04-2016
01-05-2015
I need a SQL query for this? Can any one help me out?
Try like this,
DECLARE #AA TABLE (
Month INT
,Year INT
)
INSERT INTO #AA (
Month
,Year
)
VALUES (
4
,2016
)
,(
5
,2015
)
SELECT convert(DATE, convert(VARCHAR(50), year * 10000 + month * 100 + 01)) AS DATE
FROM #AA
Try this code:
select '01-'+cast([month] as nvarchar) + '-'+cast([Year] as nvarchar)
from YourTable
Assuming int data types:
DECLARE #Month int = 4, #Year int = 2016
SELECT CAST(CAST(#Year * 10000 + #Month * 100 + 01 As char(8)) as date)
Assuming char/varchar data types:
DECLARE #MonthString varchar(2) = 4, #YearString char(4) = 2016
SELECT CAST(#YearString +'-'+ RIGHT('00' + #MonthString, 2) + '-01' as date)
Results in both cases:
2016-04-01 -- (Date data type)
Add square brackets for the reserve keywords:
DECLARE #AA TABLE ([Month] INT, [Year] INT);
INSERT INTO #AA ([Month], [Year]) VALUES
(4, 2016),
(5, 2015);
SELECT '01-' + RIGHT('00' + CAST([MONTH] AS VARCHAR), 2) + '-' + CAST([Year] AS VARCHAR)
FROM #AA
Result:
01-04-2016
01-05-2015
DECLARE #Table1 TABLE
(Month int, Year int)
;
INSERT INTO #Table1
(Month, Year)
VALUES
(4, 2016),
(5, 2015)
;
select '01'+'-'+RIGHT('000'+CAST(Month AS VARCHAR(3)),2)+'-'+CAST(Year AS VARCHAR) from #Table1
Do not do varchar convertions. Use like below
declare #t table([Month] int,[Year] int)
insert into #t
select 4, 2016 union all
select 5, 2015
select dateadd(month,month-1,dateadd(year,[year]-1900,0)) from #t
You can use concat function to acieve this
SELECT CONCAT('01-',year,'-',month) as req_date from tableName
try this:
declare #y varchar(4)='2015'
declare #m varchar(2)='5'
--try_prase is available starting sql 2012
print try_parse('01-'+#m+'-'+#y as datetime using 'en-us')
print convert(datetime,'01-'+#m+'-'+#y,121)
I try to cast time in HH:MM Format it works fine but when i insert time above 23 hours i.e 24:0 it generates error
"The conversion of a varchar data type to a datetime data type resulted in an out-of-range value. "
Below is code
CREATE TABLE mytable
(
timeduration varchar(25)
)
INSERT INTO mytable VALUES ('05:30')
INSERT INTO mytable values ('24:0')
INSERT INTO mytable values ('04:33')
-- OUTPUT SHOULD BE 34:3 MINUTES
select CAST
(
(SUM (datepart(hh, convert (varchar, timeduration, 108))) +
(sum(datepart(mi, convert (varchar, timeduration, 108)))/60) ) AS VARCHAR(2)
)
+ ':' +
CAST
(
sum(datepart(mi, convert (varchar, timeduration, 108))) - 60 * (sum(datepart(mi, convert (varchar, timeduration, 108)))/60)
as VARCHAR(2))
from mytable
Your problem is '24:00', Here should be '00:00' if you want it to work.
But then you have to add case expressions to you query. I suggest you to rewrite as:
DECLARE #mytable TABLE
(
timeduration VARCHAR(25)
)
INSERT INTO #mytable
VALUES ( '05:30' )
INSERT INTO #mytable
VALUES ( '24:0' )
INSERT INTO #mytable
VALUES ( '04:33' );
WITH cte
AS ( SELECT SUM(CAST(SUBSTRING(timeduration, 1, CHARINDEX(':', timeduration) - 1) AS INT)) AS Hours ,
SUM(CAST(SUBSTRING(timeduration, CHARINDEX(':', timeduration) + 1, 5) AS INT)) AS Minutes
FROM #mytable
)
SELECT CAST(Hours + Minutes / 60 AS NVARCHAR(20)) + ':' + CAST(Minutes % 60 AS NVARCHAR(20)) AS Duration
FROM cte
Output:
Duration
34:3
I want to code a query to calculate the total birthday moth based on month . Here is the sample data . Two person's bithday are April, 1980 .
How to write this query ?
John 02/21/1980
Peter 02/22/1980
Lucy 04/21/1980
------ result -----
01/1980 0
02/1980 2
03/1980 0
04/1980 1
05/1980 0
.....
You can loop for every months like this:
DECLARE #month INT
DECLARE #year INT
DECLARE #result TABLE (MonthYear varchar(7),BirthdaysCount INT)
SET #month = 1
SET #year = 1980
WHILE(#month < 13)
BEGIN
INSERT INTO #result
SELECT (CAST(#month as VARCHAR) + '/' + CAST(#year as VARCHAR)),
COUNT(*)
FROM test
WHERE MONTH(birth) = #month AND YEAR(birth) = #year
SET #month = #month + 1
END
select * from #result
See the fiddle: http://sqlfiddle.com/#!3/20692/2
In MySQL you would do this:
select concat(month(dob), '/', year(dob)) monthYear, count(*) cnt from t
group by monthYear
order by year(dob), month(dob)
However, in order to get the "missing dates" you'll have to generate data, because 01/1980 is not in any table, as far as I can see. Check this answer to see how.
how about this for sql-server
create table #temp
(
name varchar(50),
DOB datetime
)
insert into #temp values ('john', '2/21/1980')
insert into #temp values ('peter', '2/22/1980')
insert into #temp values ('lucy', '4/21/1980')
select convert(varchar(2), MONTH(DOB)) + '/' + Convert(varchar(4), YEAR(DOB)) as [MM/YYYY]
, count(*) as TotalCount
from #temp
group by convert(varchar(2), MONTH(DOB)) + '/' + Convert(varchar(4), YEAR(DOB))
drop table #temp
EDIT - This will get you all records for the dates included in the dates in the table. It will use the Min/Max Date in the table to get the date range, you then use this range to get the count of the birthdays in each month:
create table #temp
(
name varchar(50),
DOB datetime
)
insert into #temp values ('john', '2/21/1980')
insert into #temp values ('peter', '2/22/1980')
insert into #temp values ('lucy', '4/21/1980')
;with cte as
(
select min(DOB) as MinDate, max(DOB) as MaxDate
from #temp
union all
SELECT dateadd(mm, 1, t.MinDate), t.MaxDate
from cte t
where dateadd(mm, 1, t.MinDate) <= t.MaxDate
)
select convert(varchar(2), MONTH(c.MinDate)) + '/' + Convert(varchar(4), YEAR(c.MinDate))
, IsNull(t.TotalCount, 0) as TotalCount
from cte c
LEFT JOIN
(
SELECT convert(varchar(2), MONTH(DOB)) + '/' + Convert(varchar(4), YEAR(DOB)) as [MM/YYYY]
, count(*) as TotalCount
FROM #temp
group by convert(varchar(2), MONTH(DOB)) + '/' + Convert(varchar(4), YEAR(DOB))
) t
on convert(varchar(2), MONTH(C.MinDate)) + '/' + Convert(varchar(4), YEAR(C.MinDate))
= t.[MM/YYYY]
drop table #temp
I have a table like this...
create table test
(
dt datetime
)
In that table the datetime are as follows,
2011/02/02 12:55:00
2011/03/05 00:40:00
2011/02/03 00:12:00
I want to calculate sum hours,mi,ss
In a single Select query not sp.
If any one know please tell me.
Thanks ...
You could sum the times as seconds, then convert to hours, minutes and seconds:
select TotalSeconds / 3600 as [Hours], (TotalSeconds % 3600) / 60 as [Minutes], (TotalSeconds % 3600) % 60 as [Seconds]
from
(
select sum(datepart(hour, dt) * 3600) + sum(datepart(minute, dt) * 60) + sum(datepart(second, dt)) as TotalSeconds
from test
) t
Assuming the sum won't be more than 999 hours:
DECLARE #t TABLE(dt DATETIME);
INSERT #t SELECT '20110202 12:55'
UNION SELECT '20110305 00:40'
UNION SELECT '20110203 00:12';
WITH s AS
(
SELECT s = SUM(DATEDIFF(SECOND,
DATEADD(DAY, 0, DATEDIFF(DAY, 0, dt)), dt))
FROM #t
)
SELECT
s,
hhmmss = RIGHT('000' + RTRIM(s/3600), 3)
+ ':' + RIGHT('00' + RTRIM((s % 3600) / 60), 2)
+ ':' + RIGHT('00' + RTRIM((s % 3600) % 60), 2)
FROM s;
However, if what you are really storing is duration, why not store the number of seconds instead of wedging your data into an inappropriate data type that requires all kinds of workarounds to process properly?
Declare #Table Table
(
DateTimeCol DateTime
)
insert into #Table values ( '2011/02/02 12:55:00')
insert into #Table values ('2011/03/05 00:40:00')
insert into #Table values ('2011/02/03 00:12:00')
;with CTE As
(
--first of all find total seconds of datecolumn
--sum all seconds
Select SUM(
(datepart(hour,DateTimeCol)*60*60)+(datepart(minute,DateTimeCol)*60)+(datepart(second,DateTimeCol))
) As TotalSecond
From #Table
)
--devides with 3600 to get the total hours and then to 60 to get total minutes
Select CONVERT(VARCHAR(10),TotalSecond/3600)+ '.' +
CONVERT(VARCHAR(20),TotalSecond%3600/60) + '.' +
CONVERT(VARCHAR(20),TotalSecond%3600%60) AS [Time] --Total of Time
From CTE