In my application i have string like this 1,2,3&&4,5,6. Now i want check each and every element in single for each loop. Is it possible or not? If its possible how can i acheive this?.
Am trying using split method. But if i am using split method i want more than loop.
Like
dim sa as string=1,2,3&&4,5,6
for each x as string in sa.split("&&")
for each y as string in x.split(",")
''' Here My Process
next
next
How can over come this?. how can change to single loop?. It is possible or not?.
String.Split has an overload that accepts an array of string delimiters:
Dim input As String = "1,2,3&&4,5,6"
For Each element As String In input.Split({",", "&&"}, StringSplitOptions.None)
'do your processing on (1,2,3,4,5,6)
Next
As I understand, you want to use only one for each instead of using for each in for each.
You can first split by "&&" and then join with ",":
dim sa as string=1,2,3&&4,5,6
dim stringArray = String.Join(",", sa.split("&&")).split(",")
for each x as string in stringArray
end for
You could split using a regular expression as a delimiter:
Imports System.Text.RegularExpressions 'goes at the top of the module
For Each x As String In Regex.Split(sa, "\,|&&")
Where the regular expression means "comma or two ampersands". Note that you need to 'escape' the comma using a backslash; this is because commas do something special in regular expressions.
Don't forget to enclose your string in quotes:
dim sa as string="1,2,3&&4,5,6"
One option would be to split on the "," and the "&" via the Split method and ignore empty entries, as such:
Dim sa As String = "1,2,3&&4,5,6"
Dim split As String() = sa.Split(New Char() {",", "&"}, StringSplitOptions.RemoveEmptyEntries)
For Each value In split
Debug.WriteLine(value)
Next
Related
I'm using a very particular program that doesn't have many pre loaded functions on it. I would like to split a Date and time into individual variables. 6 variables to be exact
I get the date and time like this 5/28/2014 15:34:40 so I have 3 characters "/" " " and ":" separating the 6 variables I want, but I can only get one to work at a time. I have tried many other ways but the x.Split() is the only syntax that this program seems to like (PARCView).
Dim x as String = "5/28/2014 15:34:40"
Dim y as String() = x.Split(New Char() {":"c})
So how can I add all three at once or use consecutive steps to store each number as a unique variable?
You actually have the Char Array that you need, though it only has one delineator... just fill it with the other delineators and it will split it for you.
Dim y As String() = x.Split(New Char() {":"c, "/"c, " "c})
example:
Another option is to parse it as a datetime object which will contain all the parts as properties:
Dim teststr = "5/28/2014 15:34:40"
Dim dt = DateTime.Parse(teststr)
I am trying to split a string with multiple characters. The string might sometimes contain a - or a /. What I have achieved is the hyphen but I am not able to search for the slash. Any thoughts on how to split the string based on both characters at once ? Once I split after - I add the value after the - to the result list as a separate index and I would like to accomplish the same for '/'.
So For example the Split string has Jet-blue, the below code will add Jet in the result list with index(0) and blue with index(1). In addition to splitting with '-' I would also like to split with '/'. Any suggestions ?
Code:
Dim result As New List(Of String)()
For Each str_get As String In Split
Dim splitStr = str_get.Split("-")
For Each str_split As String In splitStr
result.Add(str_split) ' Enter into result list
' result.TrimExcess()
Next
result.Remove("")
Next
You can either use this or this overload of the Split method.
The first one takes an array of Char:
"Hello World".Split({"e"c, "o"c}) ' Notice the c!
The second one takes an array of String and StringSplitOptions:
"Hello World".Split({"el", "o"}, StringSplitOptions.None)
i have a string "<PinX F='53mm'></PinX>", I want to access the 53 within the string and do some addition to it and then add the answer back into that string. I've been thinking about this and wasn't sure whether this can be done with regular expression or not? Can anybody help me out.
thanks
Yes, you can use a regular expression. This will get the digits, parse them to a number, add one to it, and put it back in the string (that is, the result is actually a new string as strings are immutable).
string s = Regex.Replace(
input,
#"(\d+)",
m => (Int32.Parse(m.Groups[1].Value) + 1).ToString()
);
Take a look at the HTML Agility Pack.
A regular expression looks like a good fit for this particular problem:
\d+
Will match one or more digits.
Int32.Parse(Regex.Match("<PinX F='53mm'></PinX>", #"\d+").Value)
Will return 53.
In this single case yes. "'(.*?)' then access the first group, but if this is part of a larger xml regular expressions should not be used. You should utilize the xml parser build into .net find the attribute with xsd and get the value.
Alternatively, here's a small routine...
' Set testing string
Dim s As String = "<PinX F='53mm'></PinX>"
' find first occurence of CHAR ( ' )
Dim a As Integer = s.IndexOf("'")
' find last occurence of CHAR ( ' )
Dim b As Integer = s.LastIndexOf("'")
' get substring "53mm" from string
Dim substring As String = s.Substring(a, b - a)
' get integer values from substring
Dim length As Integer = substring.Length
Dim c As Char = Nothing
Dim result As String = Nothing
For i = 1 To length - 1
c = substring.Chars(i)
If IsNumeric(c) Then
result = result & c
End If
Next
Console.WriteLine(Int32.Parse(result))
Console.ReadLine()
I got this url for example "http://www.yellowpages.com/manhattan-beach-ca/mip/marriott-manhattan-beach-4933923?lid=185795402"
I want to get the last digit numbers and the rest could be anything.
I need a format like this "http://www.yellowpages.com/anything.... lid=randomdigitnumbers" or as long as i get those numbers.
My knowledge is very poor in this regex thing so please guys help me.
the following did not work
Dim r As New System.Text.RegularExpressions.Regex("http://www.yellowpages.com/.*lid=d*", RegexOptions.IgnoreCase)
Dim m As Match = r.Match(txt)
If (m.Success) Then
Dim int1 = m.Groups(1)
MsgBox("(" + int1.ToString() + ")" + "")
End If
thank you in advance
Using Regular Expressions for this is a bit of overkill, IMO.
You could accomplish the same thing using string functions:
Dim url As String = "http://www.yellowpages.com/manhattan-beach-ca/mip/marriott-manhattan-beach-4933923?lid=185795402"
Dim queryString As String = url.SubString(url.IndexOf("?"), url.Length - url.IndexOF("?"))
Dim nameValuePairs As String() = queryString.Split("=")
Dim lid As String = nameValuePairs(1)
This is off the top of my head, so you may need to tweak it a bit. The basic concept is to the portion of the URL after the ? (the query string), and then split it on the = sign, taking the second element of the resulting array (the value).
Also, if the query string has more than one name value pair, they'll be separated by &, so you'll need to split on the ampersand (&) first, then the equal signs.
Just find lid= and get everything after that:
Dim url As String = "http://www.yellowpages.com/manhattan-beach-ca/mip/marriott-manhattan-beach-4933923?lid=185795402"
Dim lidIndex As Integer = url.IndexOf("lid=") + "lid=".Length
Dim lid As Integer = url.Substring(lidIndex)
I need to split one variable into 3 variables. For example I have a variable called Data and it contains AAA00000001. I need to have them be split between the "AAA", "0000000", and "1". I looked at the Split() function but didn't get a clear example for this situation. The reason I need to do this is because I want to store these 3 variables into fields for a MySQL database.
Are the three subvariables always of the same length?
If so, you can use Substrings:
Dim substring1 As String = Data.Substring(0, 3)
Dim substring2 As String = Data.Substring(3, 7)
Dim substring3 As String = Data.Substring(10, 1)
Assuming the string is ALWAYS the EXACT same length and need to be split at the SAME place, you can use Substring().
dim s as String = "AAA00000001"
dim s1 as String = s.Substring(0, 3)
dim s2 as String = s.Substring(3, 7)
dim s3 as String = s.Substring(10)
If they're not always the same length, you're probably going to need to use Regular Expressions.
Split will break your string apart based on a character, or group of. It's not appropriate here, that is unless you're always splitting on 0000000, which I doubt you are.
If you know that the first 3 characters will always be your first group, second 7 your next, and last character, your final group, you could do something like this.
This uses the Substring function, e.g.
Dim yourString as String = "AAA00000001"
Dim c1 As String = yourString.Substring(0, 3)
Dim c2 As String = yourString.Substring(3, 7)
Dim c3 As String = yourString.Substring(10, 1)