I need to check if any work time period is between datetime and calculate hours between for work hours sum grater than 8 hours.
Sample data:
1. Work time: 07:00 - 17:00 and datetime for checking 06:00-22:00
Answer: 2 hour
2. Work time: 13:00 - 23:00 and datetime for checking 06:00-22:00
Answer: 1 hour (only 1 hour is grater 8 hours and between 06:00-22:00 )
3. Work time: 19:00 - 05:00 and datetime for checking 22:00-06:00
Answer: 2 hour (only 2 hour is grater 8 hours and between 22:00-06:00 )
Any ideas?
Try this: T-SQL DateDiff - partition by "full hours ago", rather than "times minutes turned 00 since"
Basically, DATEDIFF(HOUR, endTime, startTime). Then, subtract your result from 8 to get the difference (if they were "under" time, the difference will be negative).
Related
I want a query that shows a time difference in months or days in Impala
How can I do this?
start 2017-11-29 19:45:00 - end 2018-11-29 21:30:00
I know that month_between and datediff shows the month of datediff but how do I make it so it also takes the year into count when counting the days / months?
For the above example, I want to to display either
month_between - 12.2 months - equivalent to the month calculation of the timestamp - might be a little off cause I did it by hand / 30 days
days_between - 366 days
not sure if you tried DATEDIFF or not , but it already gives you the dates difference in days :
select datediff(endddaate, startdate)
from tablename
I am trying to query this data set of hourly price date. The dataset defined daily prices at 12am - 12am UTC time, I am trying to define the days at 4pm - 4pm UTC time. Therefore I need to get the high and the low prices for each day between ex: '2021-12-15 16:00:00' and '2021-12-16 15:00:00' as that would be the open and close of the trading day.
I have this right now:
SELECT convert(date,dateadd(S, TimeStamp/1000, '1970-01-01')) as 'date'
,symbol
,Max([high]) as 'Max'
,Min([low]) as 'Min'
FROM [Crypto].[tblMessariPriceHistory]
WHERE symbol = 'DOGE'
and dateadd(S, TimeStamp/1000, '1970-01-01') between '2021-12-15 16:00:00' and '2021-12-16 15:00:00'
Group By convert(date,dateadd(S, TimeStamp/1000, '1970-01-01')),symbol
But it results like this:
date
symbol
Max
Min
2021-12-15
DOGE
0.175059052503167
0.170510833636204
2021-12-16
DOGE
0.180266282681554
0.177596458601872
I could just group by Symbol but I want to be able to do this over multiple days, and that wouldn't work.
Any ideas on how to define a select date range as a group or table over multiple days?
If you think about it, subtracting 16 h off every time would slide the time back to some time within the "starting day"
Monday 16:00 becomes midnight Monday
Monday 23:59 becomes 7:59 Monday
Tuesday 00:00 becomes 8:00 Monday
Tuesday 15:59 becomes 23:59 Monday
Tuesday 16:00 becomes midnight Tuesday
Anyway, once you've slid your time backwards 16h, you can just chop the time part off by dividing the unix time stamp by the number of milliseconds in a day and all the trades between Monday 16:00 and Tuesday 15:59:59.999 will go down as "Monday". If it were a DateTime we could cast it to a Date to achieve the same thing. It's handy to find ways of treating datetimes as decimal numbers where the integral is the date and the fractional is the time because chopping it to an int discards the time and allows daily aggregating. If you wanted hourly aggregating, adjusting the number so it represents the number of hours and fractions of an hour (divide by 3600000, the number of milliseconds in an hour) helps to the same end
--take off 16h then truncate to number of days since epoch
SELECT
(timestamp-57600000)/86400000 as timestamp,
symbol,
min(low) as minlow,
max(high) as maxhigh
FROM trades
GROUP BY (timestamp-57600000)/86400000 as timestamp, symbol
I am working on Snowflake, need to substract 2 hours from specifc date:
date time: 2021-06-10 14:07:04.848 -0400
'2021-06-10 14:07:04.848 -0400' - 2 hours
expected result: 2021-06-10 12:07:04.848 -0400 (now it's twelve o'clock).
Datediff didn't work:
DATEDIFF(hour,2,TO_DATE(substr(p.insertedon,1,10)))
There is any simple way to do this? just a subtraction of 2 hours to date time
Regards
Using INTERVAL:
SELECT p.insertedon - INTERVAL '2 HOURS'
FROM ...
I need to subtract two dates (including hours and minutes), but I only need to consider working hours. That is, I need to omit lunch time (from 13 to 14 hrs), weekends and hours after 18 hrs and before 9 hrs of the following day, in a working day (from Mo to Fr). Any thoughts?
I don't mind if it's an Excel formula or a vba code.
I have this formula, but it doesn't omit lunch time:
9*(NETWORKDAYS(initial_time;ending_time)-1)-24*((MOD(initial_time;1)-MOD(ending_time;1)))
Here's a possible solution. It assumes an 8 hour work days for all but the start and end date. Also that start date/time is 9:00 or after and end date/time is 18:00 or earlier and that both are on a weekday.
=(NETWORKDAYS(A2,B2)-2)*8+IF(MOD(A2,1)>0.58333,(TIME(18,0,0)-MOD(A2,1))*24,(TIME(18,0,0)-MOD(A2,1))*24-1)+IF(MOD(B2,1)>0.58333,(MOD(B2,1)-TIME(9,0,0))*24-1,(MOD(B2,1)-TIME(9,0,0))*24)
.58333 equates to 14:00. The formula:
multiplies networkdays * 8
+ hours from start date/time until 18:00 subtracting 1 hour if start time is before 14:00
+ hours from 9:00 until end date/time subtracting 1 hour if end time is after 14:00
Of course this doesn't take any holidays into account.
I need a simple SQL to accomplish the below:
Problem:
When a petrol bunk runs out of fuel, the admin makes note of the DateTime (RunOutDate) when it ran out of fuel and notes also the DateTime (ResupplyDate) when the fuel supply was back on.
I need to create a report on how many days the bunk ran out of fuel.
eg.
1/1/1 10:10 to 1/1/1 10:50 should be counted as 1
1/1/1 10:10 to 2/1/1 07:20 should be counted as 2
1/1/1 23:55 to 2/1/1 00:10 should be counted as 2
I can not bank using hours using DateDiff as 24 hours could have spanned across 2 days.
TIA
DATEDIFF(d, RunOutDate, ResupplyDate) + 1
Remember that DATEDIFF always counts the number of BOUNDARIES that you cross. For days (first argument d), it counts the number of times the clock passed midnight. So to count the number of days covered you just add 1.
DATEDIFF using day, then add 1.
DATEDIFF uses the midnight to count days so you'll get 0, 1, 1 for each example above. Then add 1.
DATEDIFF(day, '16 Dec 2008 10:10', '16 Dec 2008 10:50') + 1