First time caller, long time listener :) Love this site. I'm new to Objective-C but have a blast learning. I'm sorry for such a simple question but I can't figure this out. :(
I have two NSStrings in the format:
itemdate: [March 1, 2013] lastloaddate: [January 1, 1980]
I want to find out which string (date) is most recent. To do this I'm trying to convert the NSString to NSDate and then do a compare but i'm not having any luck. Here is my code. Any and all help would be greatly appreciated!
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"yyyy-MM-dd"];
NSDate *titemdate = [df dateFromString: itemdate];
NSDateFormatter *df1 = [[NSDateFormatter alloc] init];
[df1 setDateFormat:#"yyyy-MM-dd"];
NSDate *tlasttimerundate = [df1 dateFromString: lastdate];
if ([tlasttimerundate compare:titemdate] == NSOrderedDescending)
{
NSLog(#"itemdate is newer than lastdate");
}
Use [df setDateFormat:#"MMMM d,YYYY"]; instead of [df setDateFormat:#"yyyy-MM-dd"];
The MMMM format will get the full date month where as the MM format will just the months number. For example MM is 5 and MMMMM is May.
To achieve the date compare:
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"MMMM d,YYYY"];
df.locale = [[NSLocale alloc] initWithLocaleIdentifier:#"EN"];
NSDate *titemdate = [df dateFromString: itemdate];
NSDate *tlasttimerundate = [df dateFromString: lastdate];
if ([tlasttimerundate compare:titemdate] == NSOrderedDescending)
{
NSLog(#"itemdate is newer than lastdate");
}
You can find more about the date formats here: http://unicode.org/reports/tr35/tr35-10.html#Date_Format_Patterns
Related
I know that it sounds incessantly familiar, but most of the suggested solutions on SO have not worked for me for some strange reason.
I have a date string returned from an SQLite query as an NSString in this format:
2019-06-10 13:45:33
However, when any of the suggested date formatter solutions are applied, with or without timezone localisation, I keep getting such a result:
Mon Jun 10 13:45:33 2019
This is one of the routines I've tried, among many others:
NSString * dateString = #"2019-06-10 13:45:33";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"yyyy-MM-dd HH:mm:ss"];
//[dateFormatter setDateFormat:#"YYYY-MM-dd HH:mm:ss"];
//[dateFormatter setDateFormat:#"yyyy-MM-dd HH:mm:ss ZZZ"];
NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [dateFormatter dateFromString:dateString];
// dateFromString > Mon Jun 10 13:45:33 2019
Could I be doing something wrong or is there some missing step in the conversion?
TIA.
I could guess that you wanted another output format, if it is the case then you could try code like this:
NSString * dateString = #"2019-06-10 13:45:33";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"yyyy-MM-dd HH:mm:ss"];
//[dateFormatter setDateFormat:#"YYYY-MM-dd HH:mm:ss"];
//[dateFormatter setDateFormat:#"yyyy-MM-dd HH:mm:ss ZZZ"];
NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [dateFormatter dateFromString:dateString];
NSDateFormatter *printDateFormatter = [[NSDateFormatter alloc] init];
printDateFormatter.dateStyle = NSDateIntervalFormatterMediumStyle;
printDateFormatter.timeStyle = NSDateIntervalFormatterMediumStyle;
NSLog(#"%#", [printDateFormatter stringFromDate:dateFromString]);
The result will be:
10 Jun 2019 at 13:45:33
Use a different formatter to format the string from the date. For example:
NSDateFormatter * formatter=[[NSDateFormatter]alloc]init];
formatter.dateStyle = NSDateFormatterMediumStyle;
formatter.timeStyle = NSDateFormatterNoStyle;
NSString * formattedDateString = [formatter stringFromDate:date];
setDateFormat is for inputting date strings and getting NSDates.
dateStyle and timeStyle is for formatting dateStrings from NSDates.
I'm trying to get the current date with the following format: dd/MM/yyyy.
The way I would format it, is like this:
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"dd/MM/yyyy"];
And I would get the current date like this: [NSDate date]. How can I mix the 2 together, and get the current date with that format?
If you want to get current day like format this: dd/MM/yyyy.
You can use this code:
NSDate *datecenter = [NSDate date];
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"d, MMMM, YYYY"];
NSString *dateString = [dateFormat stringFromDate:datecenter];
lbldaymonthyear.text = dateString;
This is probably the most succinct way, you can use different NSDateFormatterStyles to change the way the date is displayed later
NSString *date = [NSDateFormatter localizedStringFromDate:[NSDate date]
dateStyle:NSDateFormatterShortStyle
timeStyle:NSDateFormatterNoStyle];
NSDateFormatterShortStyle
Specifies a short style, typically numeric only, such as “11/23/37” or “3:30 PM”.
Equal to kCFDateFormatterShortStyle.
More styles here: https://developer.apple.com/library/mac/documentation/Cocoa/Reference/Foundation/Classes/NSDateFormatter_Class/#//apple_ref/c/tdef/NSDateFormatterStyle
You can use this code:
NSDate *datecenter = [NSDate date];
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"dd, MMMM, YYYY"];
NSString *dateString = [dateFormat stringFromDate:datecenter];
yourlabel.text = dateString;
I want to format 06-06-2013 1:51 PM as Jun 06,2013.
I have tried all possible different formatting styles using NSDateFormatter but failed.
Try this
First You need to convert this string back to NSDate then again convert the NSdate to string using formatter.
NSDateFormatter *dateFormatForDB = [[NSDateFormatter alloc] init];
[dateFormatForDB setDateFormat:#"dd-MM-yyyy HH:mm a"]; //Note capital H is 4 24-hour time format
NSDate *aDate = [[[NSDate alloc] initWithTimeInterval:0 sinceDate:[dateFormatForDB dateFromString:aDateString]] autorelease];
if(aDate){
[formatter setDateFormat:#"MMM dd,yyyy"];
NSString *date = [formatter stringFromDate:aDate];
[dateFormatForDB release];
}
Try to use this format
[df setDateFormat:#"MMM dd,yyyy];
By looking at your format, i think this is what you are looking for...
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"dd-MM-yyyy hh:mm a"];
NSDate *newDate = [df dateFromString:dateString];
NSDateFormatter *df2 = [[NSDateFormatter alloc] init];
[df2 setDateFormat:#"MMM dd,yyyy"];
NSString *formattedDate = [df2 stringFromDate:newDate];
This will give you the date as string in the required format. If you want time in 24hr format, replace 'hh' with 'HH'.
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Convert NSDate to NSString
convert string to nsdate
Currently I have this code. It's for adding events to the calendar.
[...]
event.startDate = [[NSDate date] dateByAddingTimeInterval:86400];
event.endDate = [[NSDate date] dateByAddingTimeInterval:90000];
What I need is the code to add to a spesific start date and end date, and that's where NSString comes in handy. But I've had no luck converting it so far.
Refer this code :
NSString to NSDate
NSString *dateString = #"01-02-2010";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
// this is imporant - we set our input date format to match our input string
// if format doesn't match you'll get nil from your string, so be careful
[dateFormatter setDateFormat:#"dd-MM-yyyy"];
NSDate *dateFromString = [[NSDate alloc] init];
// voila!
dateFromString = [dateFormatter dateFromString:dateString];
[dateFormatter release];
NSDate convert to NSString:
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"dd-MM-yyyy"];
NSString *strDate = [dateFormatter stringFromDate:[NSDate date]];
NSLog(#"%#", strDate);
[dateFormatter release];
Hope it helps you
convert NSDate to NSString as
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateStyle:NSDateFormatterMediumStyle];
NSString *string = [dateFormatter stringFromDate:date];
[dateFormatter release];
That's an example if you need the format like “Nov 23, 1937”:
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
formatter.dateStyle= NSDateFormatterMediumStyle;
NSString* string= [formatter stringFromDate: date];
Check out the reference for other styles. If you need another style that hasn't a constant, you can use the date format, in this case it's:
formatter.dateFormat= #"MMM dd, yyyy"; // same as medium style
But the preferred way is to use the style, use the format only if there isn't a propert style.
I want to see what is getting stored in an NSDate, so I am using NSLog, but it's showing (null), whereas if I print the string stf2, it's showing the proper value.
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"YYYY-MM-dd"];
NSDateFormatter *formatter1 = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"MMM dd, yyyy"];
NSString *stf2 = [[pact.date componentsSeparatedByString:#" "] objectAtIndex:0];
NSLog(#"date %#",stf2);
NSDate *date_ = [formatter dateFromString:stf2];
pact.date = [formatter1 stringFromDate:date_];
NSLog(#"date %#",[NSDate date_]);
There are two specific problems in the code you've presented in the question.
Format Reset
First you do,
[formatter setDateFormat:#"YYYY-MM-dd"];
and then you initialize the second formatter followed by resetting the first formatter's format,
NSDateFormatter *formatter1 = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"MMM dd, yyyy"];
To emphasize
[formatter setDateFormat:#"MMM dd, yyyy"];
This should've been formatter1 but is formatter.
Date Format
If you look at the format you've use YYYY-MM-dd, it looks fine. But apparent YYYY have a different purpose and can be different from our usual calendar year. You should use the lowercase y instead.
[formatter setDateFormat:#"yyyy-MM-dd"];
And I don't think you meant this but
NSLog(#"date %#",[NSDate date_]);
should be
NSLog(#"date %#", date_);
you need to correct the dateformatter by setting proper date formatter. first do this
[formatter setDateFormat:#"yyyy-dd-MM"];
//it should be in the way as your string is. like if your string is 2011-Jun- 27 then fromatter should be
[formatter setDateFormat:#"yyyy-MM-dd"];
set the formatter as per your string's date format. then get the date back from this line
NSDate *date_ = [formatter dateFromString:stf2];
Assuming "stf2" is your string, then perhaps your object formatter is nil.
Below functions will be helpful to you.
"getDateTimeFromString" will take date and time as argument and it will return NSDate object.\
-(NSDate *)getDateTimeFromString :(NSString *)tempDate :(NSString *)tempTime{
NSString *dateValue = [tempDate stringByAppendingFormat:#" %#",tempTime];
NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease];
[dateFormatter setDateFormat:#"yyyy-MM-dd HH:mm"];
NSDate *date = [[NSDate alloc] init];
date = [dateFormatter dateFromString:dateValue];
NSTimeZone* sourceTimeZone = [NSTimeZone timeZoneWithAbbreviation:#"GMT"];
NSTimeZone* destinationTimeZone = [NSTimeZone systemTimeZone];
NSInteger sourceGMTOffset = [sourceTimeZone secondsFromGMTForDate:date];
NSInteger destinationGMTOffset = [destinationTimeZone secondsFromGMTForDate:date];
NSTimeInterval interval = destinationGMTOffset - sourceGMTOffset;
NSDate* destinationDate = [[[NSDate alloc] initWithTimeInterval:interval sinceDate:date] autorelease];
return date;
}
"getDateStringFromDate" will take NSDate as argument and it will return NSString.
So, you can NSLog that value.
-(NSString *)getDateStringFromDate :(NSDate *)dateValue{
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"yyyy-MM-dd"];
NSDateFormatter *timeFormat = [[NSDateFormatter alloc] init];
[timeFormat setTimeStyle:NSDateFormatterShortStyle];
[timeFormat setDateFormat:#"HH:mm a"];
NSString *theDate = [dateFormat stringFromDate:dateValue];
/*NSLog(#"\n"
"theDate: |%#| \n"
"theTime: |%#| \n"
, theDate, theTime);*/
return theDate;
}
Hope you will get the answer.