My string looks something like this:
R392P328N87R3928N32P328N123
Line end is defined by that N followed by a number.
I need to split each line into an array object. I was thinking about using simply componentsSeparatedByString: but there's a number following N and I want it to include N in the created objects.
Also notice that what comes before N is not a constant.
In other words, from that line above, I need it to create 3 array objects:
R392P328N87
R3928N32
P328N123
What's the best way to go about doing this? Should I try something that looks for 'N' and stop when it reaches another non-hex letter(I might have hexadecimal after N)?
Thanks!
Elijah
Sounds like a job for regular expressions.
NSString *string = #"R392P328N87R3928N32P328N123";
NSString *pattern = #".*?N\\d+";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:0 error:NULL];
NSMutableArray *lines = [NSMutableArray array];
[regex enumerateMatchesInString:string options:0 range:NSMakeRange(0, string.length) usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) {
[lines addObject:[string substringWithRange:result.range]];
}];
NSLog(#"%#", lines);
// => ["R392P328N87", "R3928N32", "P328N123"]
Related
I have a TextField which has values as shown below.
#"Testing<Car>Testing<Car2>Working<Car3 /Car 4> on the code"
Here I have to loop through the text field and check for the text present within Angle brackets(< >).
There can be space or any special characters within the Angle Brackets.
I tried using NSPredicate and also componentsSeparatedByString, but I was not able to get the exact text within.
Is there any way to get the exact text along with Angle Brackets. Like in the above mentioned example want only
#"<Car>,<Car2> , <Car3 /Car 4>"
Thanks for the help in Advance.
A possible solution is Regular Expression. The pattern checks for < followed by one or more non-> characters and one >.
enumerateMatchesInString extracts the substrings and append them to an array. Finally the array is flattened to a single string.
NSString *string = #"Testing<Car>Testing<Car2>Working<Car3 /Car 4> on the code";
NSRegularExpression *regex = [[NSRegularExpression alloc] initWithPattern:#"<[^>]+>" options:0 error:nil];
__block NSMutableArray<NSString *> *matches = [NSMutableArray array];
[regex enumerateMatchesInString:string options:0 range:NSMakeRange(0, string.length) usingBlock:^(NSTextCheckingResult * _Nullable result, NSMatchingFlags flags, BOOL * _Nonnull stop) {
if (result) [matches addObject:[string substringWithRange:result.range]];
}];
NSLog(#"%#", [matches componentsJoinedByString:#", "]);
We can solve it in different ways. Now I am showing one of the way. You can place textFiled.text in place of str.
NSString *str = #"This is just Added < For testing %# ___ & >";
NSRange r1 = [str rangeOfString:#"<" options: NSBackwardsSearch];
NSRange r2 = [str rangeOfString:#">" options: NSBackwardsSearch];
NSRange rSub = NSMakeRange(r1.location + r1.length, r2.location - r1.location - r1.length);
NSString *sub = [str substringWithRange:rSub];
I would like to get a substring for a NSString that contains a percentage value.
For example:
1. Get 10% off with this item.
2. 55% off when you purchase this.
function should return 10% and 55% respectively.
I am using regex in Java \\d+%
I don't know how to do the same in objective c.
I have searched it but I am a bit lost.
You should be able to use NSRegularExpression to execute the same regex that you use in java. There is a good tutorial for NSRegularExpression here.
https://www.raywenderlich.com/30288/nsregularexpression-tutorial-and-cheat-sheet
I was able to accomplish it with this code:
NSString *string = #"10% off with this item";
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"\\d+%" options:0 error:&error];
NSTextCheckingResult *result = [regex firstMatchInString:string options:0 range:NSMakeRange(0, [string length])];
NSString *substring = [string substringWithRange:result.range];
NSLog(#"%#", substring); // 10%
The key is in the TextCheckingResult. It contains the NSRange for the match in the original string so you can grab a substring of the match.
I need to get the word that comes after a certain sign, and remove it.
example :
NSString *me=#" i am going to make !somthing great" ;
I need to remove the word something, together with the ! sign, where ever it will occur in that text.
Is there some method like stringByReplacingOccurrencesOfString: to not only find the sign ,but identify the word that attached to it ?
Thanks.
You want a regular expression. In this case, you want one with the pattern #"!\w*". (An NSScanner would also work, but I think a regular expression is more concise in this case.)
If you have reasons not to use regular expressions (or if you are not familiar with them) you can use following
NSString *me=#" i am going to make !somthing great" ;
NSRange r1 = [me rangeOfString:#"!"];
if (r1.location != NSNotFound) {
NSRange r2 = [me rangeOfCharacterFromSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]
options:0
range:NSMakeRange(r1.location, me.length - r1.location)];
if (r2.location != NSNotFound) {
me = [me stringByReplacingCharactersInRange:NSMakeRange(r1.location, r2.location - r1.location) withString:#""];
}
}
Here's code:
NSMutableString *mutableMe = [me mutableCopy];
NSError *error;
NSRegularExpression *regex = [[NSRegularExpression alloc] initWithPattern:#"!\\w*" options:0 error:&error];
[regex replaceMatchesInString:mutableMe options:0 range:NSMakeRange(0, [mutableMe length]) withTemplate:#""];
If you want to find it first than use
[regex enumerateMatchesInString:mutableMe options:0 range:NSMakeRange(0, [mutableMe length]) usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) {
NSRange rangeOfString = [result rangeAtIndex:0];
[mutableMe replaceCharactersInRange:rangeOfString withString:#""];
}];
Try following syntax this can help you
NSString *replacedString=[NSString stringByReplacingOccurancesOfString:#"!something" withString:#" "];
I want to split NSString into array with fixed-length parts. How can i do this?
I searched about it, but i only find componentSeparatedByString method, but nothing more. It's also can be done manually, but is there a faster way to do this ?
Depends what you mean by "faster" - if it is processor performance you refer to, I'd guess that it is hard to beat substringWithRange:, but for robust, easy coding of a problem like this, regular expressions can actually come in quite handy.
Here's one that can be used to divide a string into 10-char chunks, allowing the last chunk to be of less than 10 chars:
NSString *pattern = #".{1,10}";
Unfortunately, the Cocoa implementation of the regex machinery is less elegant, but simple enough to use:
NSString *string = #"I want to split NSString into array with fixed-length parts. How can i do this?";
NSError *error = NULL;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern: pattern options: 0 error: &error];
NSArray *matches = [regex matchesInString:string options:0 range:NSMakeRange(0, [string length])];
NSMutableArray *result = [NSMutableArray array];
for (NSTextCheckingResult *match in matches) {
[result addObject: [string substringWithRange: match.range]];
}
Break the string into a sequence of NSRanges and then try using NSString's substringWithRange: method.
You can split a string in different ways.
One way is to split by spaces(or any character):
NSString *string = #"Hello World Obj C is Awesome";
NSArray *words = [string componentsSeparatedByString:#" "];
You can also split at exact points in a string:
NSString *word = [string substringWithRange:NSMakeRange(startPoint, FIXED_LENGTH)];
Simply put it in a loop for a fixed length and save to Mutable Array:
NSMutableArray *words = [NSMutableArray array];
for (int i = 0; i < [string length]; i++) {
NSString *word = [string substringWithRange:NSMakeRange(i, FIXED_LENGTH)]; //you may want to make #define
[array addObject:word];
}
Hope this helps.
I'm pretty green at regex with Objective-C. I'm having some difficulty with it.
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"\\b([1-9]+)\\b" options:NSRegularExpressionCaseInsensitive error:®Error];
if (regError) {
NSLog(#"%#",regError.localizedDescription);
}
__block NSString *foundModel = nil;
[regex enumerateMatchesInString:self.model options:kNilOptions range:NSMakeRange(0, [self.model length]) usingBlock:^(NSTextCheckingResult *match, NSMatchingFlags flags, BOOL *stop) {
foundModel = [self.model substringWithRange:[match rangeAtIndex:0]];
*stop = YES;
}];
All I'm looking to do is take a string like
150A
And get
150
First the problems with the regex:
You are using word boundaries (\b) which means you are only
looking for a number that is by itself (e.g. 15 but not 150A).
Your number range does not include 0 so it would not capture 150. It needs to be [0-9]+ and better yet use \d+.
So to fix this, if you want to capture any number all you need is \d+. If you want to capture anything that starts with a number then only put the word boundary at the beginning \b\d+.
Now to get the first occurrence you can use -[regex rangeOfFirstMatchInString:options:range:]
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"\\b\\d+" options:NSRegularExpressionCaseInsensitive error:®Error];
if (regError) {
NSLog(#"%#",regError.localizedDescription);
}
NSString *model = #"150A";
NSString *foundModel = nil;
NSRange range = [regex rangeOfFirstMatchInString:model options:kNilOptions range:NSMakeRange(0, [model length])];
if(range.location != NSNotFound)
{
foundModel = [model substringWithRange:range];
}
NSLog(#"Model: %#", foundModel);
What about .*?(\d+).*? ?
Demo:
That would backreference the number and you would be able to use it wherever you want.