I'm trying to compute the area of a polygon. I don't think the results I'm getting are correct. When I drag the points of the polygon, the area doesn't change. From what the API says, getPath() "Retrieves the first path.", while getPaths() "Retrieves the paths for this polygon"
when I use:
google.maps.event.addListener(drawingManager, 'polygoncomplete', function (polygon) {
var coordinates = (polygon.getPaths().getArray());
console.log(coordinates);
area=google.maps.geometry.spherical.computeArea(coordinates);
console.log('Polygon Area is: ' + area);
});
I get a numerical result that I don't think is correct (sometimes, it doesn't change when I move the handles around. However, if I use:
var coordinates = (polygon.getPaths().getArray());
console.log(coordinates);
area=google.maps.geometry.spherical.computeArea(coordinates);
console.log('Polygon Area is: ' + area);
it complains that "coords: [object Object]
localhost/:182
NEW Polygon Area is: 0"
How do I use getPaths() correctly??
Related
I am working on a macro for ImageJ. The goal is to take colour scans with several seeds on them and crop around the seeds to get several equally sized images with one seed on each.
This is the basic idea for the macro: prompt to select folder with scans (info about the seed is in the name of the image) > threshold to select seeds > crop around each seed on the original image > save all of the cropped images in a folder (name of the cropped images still containing the information of the name of the original image)
When I run the code below, I get an error for line 31: run("HSB stack");
The error informs me about supported conversions and shows that in order to run this command I need to start with an RGB image. However, according to Fiji > Image > Type, my images are RGBs. A coding error in that part also seems unlikely since it was written with the recording function in ImageJ.
Error message
According to what I found for the error, this seems to concern a recurring bug in the software, specific to the commands run("HSB stack") and run("RGB stack") in macros.
We have tried running this on ImageJ 2.3.0/1.53s as well as 1.53q on MacOS and Windows and always got the same problem.
If it is not a software problem, where is the error? Or if it is, do you have any suggestions for workarounds or a different program that could perform the same job?
The images I am working with are colour scans, 600dpi, white background with between 1 and 90 seeds on each scan. They are large tiff images (107.4 MB) but look like this:
Example scan image
I am not sure if it is helpful, but the code is below. There are probably still errors in the latter part that I could not yet get to because I can't get past the problem in line 31.
// Directory
dir=getDirectory("Choose a data folder");
list = getFileList(dir);
processed_dir_name = dir + "Cropped" + File.separator;
print(processed_dir_name);
File.makeDirectory(processed_dir_name);
// Batch
for (i=0; j<list.length; i++) {
print(i + ":" + dir+list[i]};
// Open images
run("Bio-Formats Importer", "open=" + dir+list[i] + "color_mode=Default view =Hyperstack");
// Crop edge, set general cropping parameters, scale
makeRectangle(108, 60, 4908, 6888);
run("Crop");
main = getTitle():
default_crop_width = 350;
default_crop_height = 350;
run("Set Scale...", "distance=600 known=25.4 unit=mm global");
//Thresholding
run("Color Threshold...");
//Color Thresholder 2.3.0/1.53q
// Autogenerated macro, single images only!
min=newArray(3);
max=newArray(3);
filter=newArray(3);
a=getTitle();
run("HSB stack");
run("Convert Stack to images");
selectWindow("Hue");
rename("0");
selectWindow("Saturation");
rename("1");
selectWindow("Brightness");
rename("2");
min[0]=0;
max[0]=255;
filter[0]="pass";
min[1]=0;
max[1]=255;
filter[1]="pass";
min[2]=0;
max[2]=193;
filter[2]="pass";
for (i=0;j<3;i++){
selectWindow(""+i);
The problem lies in the fact that your image is a hyperstack, and the color thresholding doesn't know how to work with that.
There are a few options you could try: Open the image as an 8-bit RGB, e.g. via open(dir+list[i]); or split the channels of the hyperstack and threshold each separately. Based on your sample image, I assume the first option makes more sense.
The following is an edited version of your code that works for the sample that you've provided:
// Directory
dir=getDirectory("Choose a data folder");
list = getFileList(dir);
processed_dir_name = dir + "Cropped" + File.separator;
print(processed_dir_name);
File.makeDirectory(processed_dir_name);
// Batch
for (i=0; i<list.length; i++)
{
if (!File.isDirectory(dir+list[i])) // Ignore directories such as processed_dir_name
{
print(i + ":" + dir+list[i]);
// Open images
open(dir+list[i]);
// Crop edge, set general cropping parameters, scale
makeRectangle(108, 60, 4908, 6888);
run("Crop");
main = getTitle();
default_crop_width = 350;
default_crop_height = 350;
run("Set Scale...", "distance=600 known=25.4 unit=mm global");
//Thresholding
//run("Color Threshold...");
//Color Thresholder 2.3.0/1.53q
// Autogenerated macro, single images only!
min=newArray(3);
max=newArray(3);
filter=newArray(3);
a=getTitle();
run("HSB Stack");
run("Convert Stack to Images");
selectWindow("Hue");
rename("0");
selectWindow("Saturation");
rename("1");
selectWindow("Brightness");
rename("2");
min[0]=0;
max[0]=255;
filter[0]="pass";
min[1]=0;
max[1]=255;
filter[1]="pass";
min[2]=0;
max[2]=193;
filter[2]="pass";
for (j=0;j<3;j++){
selectWindow(""+j);
}
}
}
I'm struggling with Cannonjs physics lib, I got a sphere body with a changing quaternion, I just want that body to move forward according to its quaternion. I found many topics related to that but none of the suggested codes is working.
Is it a simple way to achieve that simple task?
So far I tried the solution given here but the using of vmult() method do not change the vector3 at all...
body.quaternion = new CANNON.Quaternion(0,1,0,0); // Whatever value you put here will not change the result of the vmult() operation below
var localVelocity = new CANNON.Vec3(0, 0, 1);
var worldVelocity = body.quaternion.vmult(localVelocity); //-> worldVelocity = (0,0,1)
body.velocity.copy(worldVelocity);
Try to set and not copy the body.velocity, this way:
let directionVector = new CANNON.Vec3(0, 0, 1);
directionVector.z -= moveDistance;
directionVector = vehicleBody.quaternion.vmult( directionVector );
vehicleBody.velocity.set( directionVector.x, directionVector.y, directionVector.z );
I found createfishnet method in arcobject, but it doesn't work.Where is my mistake?
Geoprocessor gp = new Geoprocessor();
gp.OverwriteOutput = true;
ESRI.ArcGIS.DataManagementTools.CreateFishnet fishnet = new ESRI.ArcGIS.DataManagementTools.CreateFishnet();
fishnet.template = buffer_out;
//txtOutputPath2.Text="E:\\program\\shenzhen_science_committee\\sc\\landuse_subway\\shenzhen_subway\\23_net.shp"
fishnet.out_feature_class = txtOutputPath2.Text;
IFeatureCursor cursor1=buffer_out.Search(null,true);
IFeature buffer=cursor1.NextFeature();
IPoint centerPoint =new ESRI.ArcGIS.Geometry.Point();
IArea pArea = buffer.Shape as IArea;
pArea.QueryCentroid(centerPoint);
fishnet.origin_coord = centerPoint;
double height=0;
double width=0;
fishnet.cell_height = 0.1;
fishnet.cell_width = 0.1;
fishnet.number_columns = 50;
fishnet.number_rows = 50;
IGeoProcessorResult results = (IGeoProcessorResult)gp.Execute(fishnet, null);
The result shows wrong HRESULT E_FAIL.
I have tried this in ArcObjects with Java. What I found was that the fishnet could not be generated for area within a particular polygon, as in the ArcMap application. You would have to intersect or use spatial filter on the fishnet output.
Also, try giving all the parameters, even the optional ones like set corner coordinate. If you are using data in a particular projection system, that can be set to the output by setting the template (and this takes only Envelope).
Below is the code that I have used. I wanted the fishnet label as well, so I have enabled it. Make sure you use a space between the x and y coordinate of a point, entered as a String, which is probably the issue here.
GeoProcessor gp = new GeoProcessor();
gp.setOverwriteOutput(true);
IEnvelope aoi = buffer_out.getEnvelope();
CreateFishnet createFishnet = new CreateFishnet();
createFishnet.setOutFeatureClass(tempDir+"/"+fishnetOutput+".shp");
createFishnet.setTemplate(aoi);
createFishnet.setOriginCoord(aoi.getXMin()+" "+aoi.getYMin());
createFishnet.setYAxisCoord(aoi.getXMin()+" "+aoi.getYMax());
createFishnet.setCornerCoord(aoi.getXMax()+" "+aoi.getYMax());
createFishnet.setCellHeight(30.0);
createFishnet.setCellWidth(30.0);
createFishnet.setNumberRows(0);
createFishnet.setNumberColumns(0);
createFishnet.setLabels("LABELS");
createFishnet.setGeometryType("POLYLINE");
gp.execute(createFishnet, null);
I hope you can use this example and apply it to your code.
How to show current location point on alert (Geolocation in titanium ) in titatnium.I don't find any good tutorial for that . .can you please give some example.
I find some where this
First, you will need to define why you want to use the geolocation. This message will be displayed to the user.
Ti.Geolocation.purpose = "Location will be used for app X";
What is use of this line ? can we write anything here intead of this line Location will be used for app X
I am using this simple code, you can print an alert with latitude and longitude variables:
if(Ti.Network.online){
Ti.Geolocation.purpose = "Receive User Location";
Titanium.Geolocation.getCurrentPosition(function(e){
if (!e.success || e.error)
{
alert('Could not find the device location');
return;
}
var longitude = e.coords.longitude;
var latitude = e.coords.latitude;
alert("latitude: " + latitude + "longitude: " + longitude);
});
}else{
alert("Internet connection is required to use localization features");
}
Have a look at the documentation:
http://docs.appcelerator.com/titanium/latest/#!/api/Titanium.Geolocation-method-getCurrentPosition
Whether I use XTextFormatter or not, I get the same error about the LayoutRectangle having to have a height of 0 or something like this.
new PdfSharp.Drawing.Layout.XTextFormatter(_gfx).DrawString(text
, new PdfSharp.Drawing.XFont(fontName, fontSize, (PdfSharp.Drawing.XFontStyle)fontStyle)
, new PdfSharp.Drawing.XSolidBrush(PdfSharp.Drawing.XColor.FromArgb(foreColour))
, new PdfSharp.Drawing.XRect(new PdfSharp.Drawing.XPoint(xPos, yPos), new PdfSharp.Drawing.XPoint(xLimit, yLimit))
, PdfSharp.Drawing.XStringFormats.Default);
fontStyle is of type System.Drawing.FontStyle
foreColour is of type System.Drawing.Color
I have already predefined _gfx from a PdfPage with Orientation = Landscape, Size = Letter
xPos and yPos are parameters of type double, the same with xLimit and yLimit.
I get the runtime error that the
LayoutRectangle must have a height of
zero (0)...
Per definition a rectangle is meant to have a height, otherwise call it a line! I don't get it!...
I tried with the XGraphics.DrawString() method directly, and I get the same error. It seems that I can't use the LayoutRectangle but have to manage that the text fit within the desired area manually.
var textFont = new PdfSharp.Drawing.XFont(fontName, fontSize, (PdfSharp.Drawing.XFontStyle)fontStyle);
while (xPos + _gfx.MeasureString(text, textFont).Width > xLimit)
textFont = new PdfSharp.Drawing.XFont(fontName, --fontSize, (PdfSharp.Drawing.XFontStyle)fontStyle);
while (yPos + _gfx.MeasureString(text, textFont).Height > yLimit && fontSize > 0)
textFont = new PdfSharp.Drawing.XFont(fontName, --fontSize, (PdfSharp.Drawing.XFontStyle)fontStyle);
_gfx.DrawString(text
, textFont
, new PdfSharp.Drawing.XSolidBrush(PdfSharp.Drawing.XColor.FromArgb(foreColour))
, new PdfSharp.Drawing.XPoint(xPos, yPos));
Though the yPos variable value is the exact same value!
*yPos = Page.Height * .4093, either 40,93% of the page's height.*
Herewith an example of what I try to do:
"Hello World!" "Hello
World!"
And here is what I get:
"Hello World!"
"Hello World!"
And because of different printing area limits and size of the font and the different font style, I can't just write these into one simple sentence including the correct number of spaces.
Quoting error messages exactly helps others to help you.
The error message reads:
DrawString: With XLineAlignment.BaseLine the height of the layout rectangle must be 0.
The text will be aligned at a line, therefore height must be 0. Yes, that's a line.
Use a different alignment if you specify a rectangle.
The TextLayout sample shows how to format text.
The Graphics sample also shows how to layout text (single lines of text, no automatic line breaks; the technique shown in the TextLayout sample handles line breaks automatically using the XTextFormatter class).
While trying to figure out how text positioning works with PdfSharp, I noticed that the DrawString() method writes on top of the Y coordinate that we specify.
If I wish to write at (0, 100)(x, y), this points to the lower-left corner while I thought this was the top-left corner coordinates. As a result, the text string Y coordinate that I should have specified is 100 + string.Height * .6.
PdfDocument pdfDoc = new PdfDocument();
PdfPage pdfPage = new pdfPage();
pdfPage.Size = PageSize.Letter;
pdfPage.Orientation = Orientation.Landscape;
pdfDoc.Pages.Add(pdfPage);
double posX = 0;
double posY = pdfPage.Height * .4093;
string helloString = "Hello"
string worldString = "World!"
XFont helloFont = new XFont("Helvetica", 25, XFontStyle.Regular);
XFont worldFont = new XFont("Helvetica", 270, XFontStyle.Bold);
using(var pdfGfx = XGraphics.FromPdfPage(pdfPage)) { // assuming the default Point UOM
XSize helloStringSize = pdfGfx.MeasureString(helloString, helloFont);
XSize worldStringSize = pdfGfx.MeasureString(worldString, worldFont);
pdfGfx.DrawString(helloString
, helloFont
, XBrushes.Black
, posX
, posY + helloStringSize.Height * .6
, XStringFormats.Default);
pdfGfx.DrawString(worldString
, worldFont
, XBrushes.Black
, pdfPage.Width * .3978
, posY + (worldStringSize.Height + helloStringSize.Height) * .6
, XStringFormats.Default);
}
You'll perhaps wonder why I only add 60% of the string size when I want to get my string written below my Y coordinate? That is because the full height of the font includes somekind of leap on top. So, the computing result will not be what is expected. On the other hand, you don't have to care about a leap if you need one. In my particular case, I don't require leap, so I must take it off the string's height.
If you feel like my explanation needs more accurate details, please feel free to either add them as comments or keep me informed so that I may include them.
Thanks!