I want to write a query that will count how many times a certain value appears on each row - on the full table I have more columns and I need to count how many times "9" (for example) appears in all the columns,
In this case the answer would be 3:
PlayerName Nation Kills Deaths SoloKills PartyKills
666 1 9 0 9 9
select PlayerName
, sum(case when Nation = 9 then 1 else 0 end +
case when Kills = 9 then 1 else 0 end +
case when Deaths = 9 then 1 else 0 end +
...
) as SumOfNines
from YourTable
group by
PlayerName
Related
So I have a table that looks like the following:
car owner
non car owner
have dog
num ppl
1
0
1
60
0
1
1
80
1
0
0
90
1
0
0
98
I am trying to add another column to find the ratios. For example, the total number of car owners is 110. If I want to find the ratio of people who own car and have dog, then I have to divide 60/110 for the first row. Also, the total number of non car owners is 98. Therefore, if I want to find that ration, I need to divide 80 by 98 for the second row and so on.
So far, I have tried the following code:
with a as (
select
id,
case when car_owner = 1 then 1 else 0 end car_owner,
case when non_car_owner = 1 then 1 else 0 end as non_car_owner = 1
from `xyz_table`
),
b as (select
car_owner,
non_car_owner,
case when have_dog = 1 then 1 else 0 end have_dog,
count(distinct id) num_ppl
from `xyz_table`
join a using (id)
group by 1,2,3
order by 4 desc
)
select *, num_ppl/(select (case when dog_owner = 1 then 110 else 0 end) as ratio
from a)
from b
Unfortunately , it throws the following error:
Scalar subquery produced more than one element
Any help would be appreciated.
PS. I am running this code on google bigquery.
If I want to find the ratio of people who own car and have dog,
You can use avg():
select avg(car_owner * have_dog)
from t;
I want to count the number of total people who will attend to an event and this number is calculated by the person who invites and how many people will be invited.
So I have this info,
refInqCredLink RegisterDate Name Phone Email Horario Insc1 Insc2 Insc3
496 2019-08-29 15:38:13.183 Abilio 91 abilio#hotmail.com 3 albano jorge
497 2019-08-30 14:12:46.873 Duarte 25 duarte#sapo.pt 3 antonio
499 2019-08-30 14:48:29.067 AGOSTINHO 92 agostinho#gmail.com 1 Jorge Antonio Manuel Fernando
In this case "John" will attend the event and will invite "albano" and "jorge". So the total number of people in this line is 3.
I need to check if Insc1, Insc2 and Insc3 column have value and if so (<>'') count as 1 person. I need to create a view based in this table with this sum.
If I try this code,
Select
SUM(case when not Name is null then 1 else 0 end
+
case when not Insc1 is null then 1 else 0 end
+
case when not Insc2 is null then 1 else 0 end
+
case when not Insc3 is null then 1 else 0 end)
from LACTINFO_InquiryCredential_Link_Seminario
this returns 12 instead of 8.
I have 3 Names + 5 Invitees = 8
Try the following
Select
SUM(case when Insc1 is null or Insc1 = '' then 0 else 1 end
+
case when Insc2 is null or Insc2 = '' then 0 else 1 end
+
case when Insc3 is null or Insc3 = '' then 0 else 1 end)
+
count(*)
from tab
To get the total, you can use count():
select count(*) + -- everyone is counted once
count(insc1) + count(insc2) + count(insc3) -- additional invitees
from t;
First, note that this is a poor data model. You should have a separate table with one row per person invited.
Second, the same person could be invited multiple times. This formulation does not take that into account. Using just first names makes it hard to deduplicate the data.
I have a single row of data as follows:
dyn1 dyn2 dyn3 chg
1 0 1 768
Now i want to write a case condition like
Case when dyn1 = 1 then 7 When dyn2=1 then 7 When dyn3=1 then 7 End
Now for this above records it is not checking the dyn3 value as it is getting dyn1 value as true.
How to handle this code?
I'll suppose that you need to return those values in a select statement, maybe this could be helpful to you.
SELECT CASE WHEN dyn1 = 1 THEN 7 END,
CASE WHEN dyn2 = 1 THEN 7 END,
CASE WHEN dyn3 = 1 THEN 7 END
FROM (SELECT 1 AS dyn1, 1 AS dyn2, 1 AS dyn3 FROM dual);
Or, maybe you want it in an only column
SELECT CASE WHEN dyn1 = 1 THEN 7 END ||
CASE WHEN dyn2 = 1 THEN 7 END ||
CASE WHEN dyn3 = 1 THEN 7 END
from (select 1 as dyn1, 1 as dyn2, 1 as dyn3 from dual);
I have a table to update with other table data. For this I created a trigger. Inside trigger, I must check how many active occurrences of each id. If this number of occurrences is same number than a variable value then return 1 (true) otherwise 0 (false).
I get the variable
DECLARE #num_gerencias numeric(2, 0)
SELECT #num_gerencias = (SELECT COUNT(id_gerencia) FROM FR_GERENCIES)
select #num_gerencias
This works ok... returns 5
Then, I make a count of occurrences of the l_activo variable in other table (variable is a bit):
SELECT id_operacio, SUM(CASE WHEN l_activo = 1 THEN 1 ELSE 0 END)
FROM FR_GERENCIES_OPERACIONS o
GROUP BY o.id_operacio
This query also works nice, returns:
2958 5
2959 0
2960 5
2961 3
2962 5
2963 5
2964 2
2965 4
2966 5
2967 5
All perfect... now i must get same list, but if sum equals to #num_gerencias, then put 1 and 0 otherwise.
Expected result table
2958 1
2959 0
2960 1
2961 0
2962 1
2963 1
2964 0
2965 0
2966 1
2967 1
I've tried with CASE
SELECT DISTINCT id_operacio, CASE WHEN
(
SELECT SUM(CASE WHEN l_activo = 1 THEN 1 ELSE 0 END)
FROM FR_GERENCIES_OPERACIONS o
GROUP BY o.id_operacio
) = #num_gerencias THEN 1 ELSE 0 END
but I'm getting error:
Mens . 512 , Level 16 , State 1, Line 6
The subquery returned more than one value , which is not correct when it goes below = , ! = , <, < = ,>, > = Or when used as an expression .
I also tried with an IF (i guess this option is totally wrong for this case... but I've tried)
SELECT DISTINCT id_operacio,
IF #num_gerencias = (SELECT SUM(CASE WHEN l_activo = 1 THEN 1 ELSE 0 END)
FROM FR_GERENCIES_OPERACIONS o
GROUP BY o.id_operacio)
1
ELSE 0
FROM FR_GERENCIES_OPERACIONS
But I have syntax errors...
Any idea how can i reach expected result table?
You were nearly there, however your grouping and selection must occur outside of your case statement:
SELECT DISTINCT
id_operacio
,CASE
WHEN SUM(CAST(l_activo AS INTEGER)) = #num_gerencias THEN 1
ELSE 0
END
FROM FR_GERENCIES_OPERACIONS o
GROUP BY o.id_operacio
I am having a table called as 'Alphabets' with columns named from 'A to G'.
Table Name: Alphabets
Column Names: A | B | C | D | E | F | G
Now, I need a SQL query to retrieve all rows from the table which satisfy at least four criteria from the following list:
A = 1
B = 2
C = 3
D = 4
E = 5
F = 6
G = 7
I am using Oracle 10g database.
SELECT * FROM Alphabets where
CASE WHEN A=1 THEN 1 ELSE 0 END +
CASE WHEN B=2 THEN 1 ELSE 0 END +
CASE WHEN C=3 THEN 1 ELSE 0 END +
CASE WHEN D=4 THEN 1 ELSE 0 END +
CASE WHEN E=5 THEN 1 ELSE 0 END +
CASE WHEN F=6 THEN 1 ELSE 0 END +
CASE WHEN G=7 THEN 1 ELSE 0 END >= 4
But something about this table and query seem suspect - It feels like it should really be a table of two columns, Letter and Value say.
One ugly solution I could think of (I'm sure there must be better solutions, but this one should work, though I'm not conviced it is optimal in any sense...)
SELECT *
FROM Alphabets
WHERE
CASE WHEN A=1 THEN 1 ELSE 0 END +
CASE WHEN B=2 THEN 1 ELSE 0 END +
CASE WHEN C=3 THEN 1 ELSE 0 END +
CASE WHEN D=4 THEN 1 ELSE 0 END +
CASE WHEN E=5 THEN 1 ELSE 0 END +
CASE WHEN F=6 THEN 1 ELSE 0 END +
CASE WHEN G=7 THEN 1 ELSE 0 END BETWEEN 4 AND 7
This has problems:
doesn't scale well - new constraint - new line in query...
performance wise it is not optimal
also just plain horribly ugly