I have a single table, first 3 entries are like so:
name | jobnum | startdate | enddate
name1 | 1 | 15/2/1990 | 11/3/1990
name2 | 2 | 12/2/1991 | 13/2/1991
name1 | 3 | 15/1/1997 | 11/2/1998
I need to group them so
it'll show
name | #jobs | # of times job ends before 30 days
I know how to show the first 2 columns. But the last one confuses me.
SELECT Table1.name, Count(Table1.start) AS #jobs
FROM Table1
GROUP BY Table1.name
Thanks.
Try the below, it is untested, I believe you can just subtract dates in Access, though if not use the same theory but the datediff function....
SELECT Table1.name, Count(Table1.start) AS #jobs,
sum(IIF(Table1.enddate - Table1.Startdate < 30,1,0)) As LessThan30Days
FROM Table1
GROUP BY Table1.name
Related
Table:
id | value
---+-----------
1 | Monday
2 | Tuesday
3 | Tuesday
4 | Wednesday
I need it to display like:
value | count | id1 | id2
----------+-------+-----+-----
Monday | 1 | 1 |
Tuesday | 2 | 2 | 3
Wednesday | 1 | 4 |
But using the Group By function will not work for obvious reasons ("id" is not contained in either the aggregate function or the GROUP BY clause).
However, I still need this done and I have exhausted my knowledge of juggling the variables into temp tables. Need this on SSMS, Any help is appreciated, thank you.
You just want string aggregation. Here is a typical method:
select value, count(*), string_agg(id, ',') as ids
from t
group by value;
If you want the values in two columns, you can use MIN() and MAX():
select value, count(*),
min(id) as id1, coalesce(max(id), min(id)) as id2
from t
group by value;
I want to find the minimum value of a column in a certain date range of a table.
so lets say I have a table like the following,
Date | Value
---------------
01-26 | 2
01-26 | 1
01-27 | 2
01-27 | 4
01-28 | 3
01-28 | 5
How can I apply the MIN() function to the subgroup of the Value column so that the result might be
Date | MIN(Value)
---------------
01-26 | 1
01-27 | 2
01-28 | 3
I thought about GROUP BY .. or such but couldn't figure out how to get the results into a table.
Using UNION and JOIN isn't quite scalable because the query could be using a date range of a month
Group by should work:
Select date, min( value )
From table1
Group by date
Maybe too simple, but seems like this would work
Select Min(col1), datecol from yourtable group by datecol;
HTH
I'm taking the max value and min value of a table composed of Date, Time, and Load. For example:
Date | Time | Temp
-------------------------------------
1/1/2014 | 09:00:00 AM | 100
-------------------------------------
1/1/2014 | 09:01:00 AM | 110
-------------------------------------
1/1/2014 | 09:02:00 AM | 120
-------------------------------------
1/1/2014 | 09:03:00 AM | 111
-------------------------------------
....................And so on
I've tried to just use the functions Min(), Max() but these values output the same data as the original table. See SQL code:
SELECT Table1.Date, Table1.Time, Min(Table1.Temp) AS MinLoad
FROM Table1
GROUP BY Table1.Date, Table1.Time;
I tried using DMin() and DMax() functions but instead of getting a value I got a null of the values. I tried the syntax
DMin("[Temp]", "[Table1]", [Time] Between #09:00# And #15:00#)
I'm fairly new to Access so any help would be appreciated.
Thanks!
Figured it out:
SELECT Date.DateLog, Min(Table1.Data) AS MinOfData
FROM [Date] INNER JOIN Table1 ON Date.DateLog = Table1.Date
GROUP BY Date.DateLog;
I have an app that has the built in initial Select option and only allows me to enter from the Where section. I have rows with duplicate values. I'm trying to get the list of just one record for each distinct value but am unsure how to get the statement to work. I've found one that almost does the trick but it doesn't give me any rows that had a dup. I assume due to the = so just need a way to get one for each that matches my where criteria. Examples below.
Initial Data Set
Date | Name | ANI | CallIndex | Duration
---------------------------------------------------------
2/2/2015 | John | 5555051000 | 00000.0001 | 60
2/2/2015 | John | | 00000.0001 | 70
3/1/2015 | Jim | 5555051001 | 00000.0012 | 80
3/4/2015 | Susan | | 00000.0022 | 90
3/4/2015 | Susan | 5555051002 | 00000.0022 | 30
4/10/2015 | April | 5555051003 | 00000.0030 | 35
4/11/2015 | Leon | 5555051004 | 00000.0035 | 10
4/15/2015 | Jane | 5555051005 | 00000.0050 | 20
4/15/2015 | Jane | 5555051005 | 00000.0050 | 60
4/15/2015 | Kevin | 5555051006 | 00000.0061 | 35
What I Want the Query to Return
Date | Name | ANI | CallIndex | Duration
---------------------------------------------------------
2/2/2015 | John | 5555051000 | 00000.0001 | 60
3/1/2015 | Jim | 5555051001 | 00000.0012 | 80
3/4/2015 | Susan | 5555051002 | 00000.0022 | 30
4/10/2015 | April | 5555051003 | 00000.0030 | 35
4/11/2015 | Leon | 5555051004 | 00000.0035 | 10
4/15/2015 | Jane | 5555051005 | 00000.0050 | 20
4/15/2015 | Kevin | 5555051006 | 00000.0061 | 35
Here is what I was able to get but when i run it I don't get the rows that did have dups callindex values. duration doesn't mattern and they never match up so if it helps to query using that as a filter that would be fine. I've added mock data to assist.
use Database
SELECT * FROM table
WHERE Date between '4/15/15 00:00' and '4/15/15 23:59'
and callindex in
(SELECT callindex
FROM table
GROUP BY callinex
HAVING COUNT(callindex) = 1)
Any help would be greatly appreciated.
Ok with the assistance of everyone here i was able to get the query to work perfectly within SQL. That said apparently the app I'm trying this on has a built in character limit and the below query is too long. This is the query i have to use as far as the restrictions and i have to be able to search both ID's at the same time because some get stamped with one or the other rarely both. I'm hoping someone might be able to help me shorten it?
use Database
select * from tblCall
WHERE
flddate between '4/15/15 00:00' and '4/15/15 23:59'
and fldAgentLoginID='1234'
and fldcalldir='incoming'
and fldcalltype='external'
and EXISTS (SELECT * FROM (SELECT MAX(fldCallName) AS fldCallName, fldCallID FROM tblCall GROUP BY fldCallID) derv WHERE tblCall.fldCallName = derv.fldCallName AND tblCall.fldCallID = derv.fldCallID)
or
flddate between '4/15/15 00:00' and '4/15/15 23:59'
and '4/15/15 23:59'
and fldPhoneLoginID='56789'
and fldcalldir='incoming'
and fldcalltype='external'
and EXISTS (SELECT * FROM (SELECT MAX(fldCallName) AS fldCallName, fldCallID FROM tblCall GROUP BY fldCallID) derv WHERE tblCall.fldCallName = derv.fldCallName AND tblCall.fldCallID = derv.fldCallID)
If the constraint is that we can only add to the WHERE clause, I don't think it's possible, due to there being 2 absolutely identical rows:
4/15/2015 | Jane | 5555051005 | 00000.0050
4/15/2015 | Jane | 5555051005 | 00000.0050
Is it possible that you can add HAVING or GROUP BY to the WHERE? or possibly UNION the SELECT to another SELECT statement? That may open up some additional possibilities.
Maybe with an union:
SELECT *
FROM table
GROUP BY Date, Name, ANI, CallIndex
HAVING ( COUNT(*) > 1 )
UNION
SELECT *
FROM table
WHERE Name not in (SELECT name from table
GROUP BY Date, Name, ANI, CallIndex
HAVING ( COUNT(*) > 1 ))
From your sample, it seems like you could just exclude rows in which there was no value in the ANI column. If that is the case you could simply do:
use Database
SELECT * FROM table
WHERE Date between '4/15/15 00:00' and '4/15/15 23:59'
and ANI is not null
If this doesn't work for you, let me know and I can see what else I can do.
Edit:
You've made it sound like the CallIndex combined with the Duration is a unique value. That seems somewhat doubtful to me, but if that is the case you could do something like this:
use Database
SELECT * FROM table
WHERE Date between '4/15/15 00:00' and '4/15/15 23:59'
and cast(callindex as varchar(80))+'-'+cast(min(duration) as varchar(80)) in
(SELECT cast(callindex as varchar(80))+'-'+cast(min(duration) as varchar(80))
FROM table
GROUP BY callindex)
There are two keywords you can use to get non-duplicated data, either DISTINCT or GROUP BY. In this case, I would use a GROUP BY, but you should read up on both.
This query groups all of the records by CallIndex and takes the MAX value for each of the other columns and should give you the results you want:
SELECT MAX(Date) AS Date, MAX(Name) AS Name, MAX(ANI) AS ANI, CallIndex
FROM table
GROUP BY CallIndex
EDIT
Since you can't use GROUP BY directly but you can have any SQL in the WHERE clause you can do:
SELECT *
FROM table
WHERE EXISTS
(
SELECT *
FROM
(
SELECT MAX(Date) AS Date, MAX(Name) AS Name, MAX(ANI) AS ANI, CallIndex
FROM table
GROUP BY CallIndex
) derv
WHERE table.Date = derv.Date
AND table.Name = derv.Name
AND table.ANI = derv.ANI
AND table.CallIndex = derv.CallIndex
)
This selects all rows from the table where there exists a matching row from the GROUP BY.
It won't be perfect, if any two rows match exactly, you'll still have duplicates, but that's the best you'll get with your restriction.
In your data, why not just do this?
SELECT *
FROM table
WHERE Date >= '2015-04-15' and Date < '2015-04-16'
ani is not null;
If the blank values are only a coincidence, then you have a problem just using a where clause. If the results are full duplicates (no column has a different value), then you probably cannot do what you want with just a where clause -- unless you are using SQLite, Oracle, or Postgres.
Need help with Min Function in SQL
I have a table as shown below.
+------------+-------+-------+
| Date_ | Name | Score |
+------------+-------+-------+
| 2012/07/05 | Jack | 1 |
| 2012/07/05 | Jones | 1 |
| 2012/07/06 | Jill | 2 |
| 2012/07/06 | James | 3 |
| 2012/07/07 | Hugo | 1 |
| 2012/07/07 | Jack | 1 |
| 2012/07/07 | Jim | 2 |
+------------+-------+-------+
I would like to get the output like below
+------------+------+-------+
| Date_ | Name | Score |
+------------+------+-------+
| 2012/07/05 | Jack | 1 |
| 2012/07/06 | Jill | 2 |
| 2012/07/07 | Hugo | 1 |
+------------+------+-------+
When I use the MIN() function with just the date and Score column I get the lowest score for each date, which is what I want. I don't care which row is returned if there is a tie in the score for the same date. Trouble starts when I also want name column in the output. I tried a few variation of SQL (i.e min with correlated sub query) but I have no luck getting the output as shown above. Can anyone help please:)
Query is as follows
SELECT DISTINCT
A.USername, A.Date_, A.Score
FROM TestTable AS A
INNER JOIN (SELECT Date_,MIN(Score) AS MinScore
FROM TestTable
GROUP BY Date_) AS B
ON (A.Score = B.MinScore) AND (A.Date_ = B.Date_);
Use this solution:
SELECT a.date_, MIN(name) AS name, a.score
FROM tbl a
INNER JOIN
(
SELECT date_, MIN(score) AS minscore
FROM tbl
GROUP BY date_
) b ON a.date_ = b.date_ AND a.score = b.minscore
GROUP BY a.date_, a.score
SQL-Fiddle Demo
This will get the minimum score per date in the INNER JOIN subselect, which we use to join to the main table. Once we join the subselect, we will only have dates with names having the minimum score (with ties being displayed).
Since we only want one name per date, we then group by date and score, selecting whichever name: MIN(name).
If we want to display the name column, we must use an aggregate function on name to facilitate the GROUP BY on date and score columns, or else it will not work (We could also use MAX() on that column as well).
Please learn about the GROUP BY functionality of RDBMS.
SELECT Date_,Name,MIN(Score)
FROM T
GROUP BY Name
This makes the assumption that EACH NAME and EACH date appears only once, and this will only work for MySQL.
To make it work on other RDBMSs, you need to apply another group function on the Date column, like MAX. MIN. etc
SELECT T.Name, T.Date_, MIN(T.Score) as Score FROM T
GROUP BY T.Date_
Edit: This answer is not corrected as pointed out by JNK in comments
SELECT Date_,MAX(Name),MIN(Score)
FROM T
GROUP BY Date_
Here I am using MAX(NAME), it will pick one name if two names were found with the same goal numbers.
This will find Min score for each day (no duplicates), scored by any player. The name that starts with Z will be picked first than the name that starts with A.
Edit: Fixed by removing group by name