Using distinct and sum in sql server 2008 - sql

Question

I'm trying to get the SUM(Values) for each Acct, but my issue is trying to get at least one entire row for a DISTINCT Acct with the SUM(Values).
I have some sample data for example:
Acct Values Name Street
123456789 100.20 John 66 Main Street
123456789 200.80 John 22 Main Avenue
222222222 50.25 Jane 1 Blvd
333333333 25.00 Joe 55 Test Ave
333333333 50.00 Joe 8 Douglas Road
555555555 75.00 Tim 12 Clark Ave
666666666 500.00 Tim 12 Clark Street
666666666 500.00 Tim 3 Main Rd.
My query consisted of:
SELECT DISTINCT Acct, SUM(Value) AS [TOTAL]
FROM TABLE_NAME
GROUP BY Acct
The above query gets me close to what I need, but I need the entire row.
Example below of what I am looking for:
Acct Total Name Addr1
123456789 301.00 John 66 Main Street
222222222 50.25 Jane 1 Blvd
333333333 75.00 Joe 55 Test Ave
555555555 75.00 Tim 12 Clark Ave
666666666 1000.00 Tim 12 Clark Street
Thanks.

Answer 1

If it does not matter what address you return, then you can apply and aggregate to the other columns:
SELECT Acct,
SUM(Value) AS [TOTAL],
max(name) name,
max(Street) addr1
FROM TABLE_NAME
GROUP BY Acct;
See SQL Fiddle with Demo

Answer 2

You can do this using window functions such as row_number() in most databases:
select acct, total, name, addr1
from (select t.*, row_number() over (partition by acct order by acct) as seqnum,
sum(value) over (partition by acct) as Total
from table_name
) t
where seqnum = 1;

Answer 3

I would use Windowing Functions (the OVER clause) to solve this.
SELECT DISTINCT
Acct
,SUM([Values]) OVER (PARTITION BY Acct) AS 'Total'
,Name
,FIRST_VALUE(Street) OVER (PARTITION BY Acct ORDER BY Street DESC) AS 'Addr1'
FROM TABLE_NAME
;
The nice thing about Windowing Functions is that you do not add things to a grouping that you do not need in your functions (e.g. SUM), instead you can focus on describing what you are looking for.
In the SQL above, we are saying we want the SUM of Values grouped by (or PARTITION BY as it is called in the OVER clause) Acct. The FIRST_VALUE allows use to return the first value of the street address. The same did not have a DATETIME column so it is hard to say what the order should be for the first value. There is also a LAST_VALUE windowing function. Assuming you do have a DATETIME column you would want to ORDER BY that column value, if not you can just pick some value like I did with Street (MAX might also be a good option then too, but having some type of DATETIME value would be the best way to do it).
Check out this SQL Fiddle: http://sqlfiddle.com/#!6/a474c/8
Here is the BOL about SUM using the OVER clause: http://msdn.microsoft.com/en-us/library/ms187810.aspx
Here is more info on FIRST_VALUE: http://blog.sqlauthority.com/2011/11/09/sql-server-introduction-to-first-_value-and-last_value-analytic-functions-introduced-in-sql-server-2012/
Here is a blog post I've done on the Windowing Functions: http://comp-phil.blogspot.com/2013/03/higher-order-functions.html