I use SQL developer and i made a connection to my database with the system user, after I created a user and made a another connection with that user with all needed privileges.
But when I try to proceed following I get the SQL Error
ORA-00942 table or view does not exist.:
INSERT INTO customer (c_id,name,surname) VALUES ('1','Micheal','Jackson')
Because this post is the top one found on stackoverflow when searching for "ORA-00942: table or view does not exist insert", I want to mention another possible cause of this error (at least in Oracle 12c): a table uses a sequence to set a default value and the user executing the insert query does not have select privilege on the sequence. This was my problem and it took me an unnecessarily long time to figure it out.
To reproduce the problem, execute the following SQL as user1:
create sequence seq_customer_id;
create table customer (
c_id number(10) default seq_customer_id.nextval primary key,
name varchar(100) not null,
surname varchar(100) not null
);
grant select, insert, update, delete on customer to user2;
Then, execute this insert statement as user2:
insert into user1.customer (name,surname) values ('michael','jackson');
The result will be "ORA-00942: table or view does not exist" even though user2 does have insert and select privileges on user1.customer table and is correctly prefixing the table with the schema owner name. To avoid the problem, you must grant select privilege on the sequence:
grant select on seq_customer_id to user2;
Either the user doesn't have privileges needed to see the table, the table doesn't exist or you are running the query in the wrong schema
Does the table exist?
select owner,
object_name
from dba_objects
where object_name = any ('CUSTOMER','customer');
What privileges did you grant?
grant select, insert on customer to user;
Are you running the query against the owner from the first query?
Case sensitive Tables (table names created with double-quotes) can throw this same error as well. See this answer for more information.
Simply wrap the table in double quotes:
INSERT INTO "customer" (c_id,name,surname) VALUES ('1','Micheal','Jackson')
You cannot directly access the table with the name 'customer'. Either it should be 'user1.customer' or create a synonym 'customer' for user2 pointing to 'user1.customer'. hope this helps..
Here is an answer: http://www.dba-oracle.com/concepts/synonyms.htm
An Oracle synonym basically allows you to create a pointer to an object that exists somewhere else. You need Oracle synonyms because when you are logged into Oracle, it looks for all objects you are querying in your schema (account). If they are not there, it will give you an error telling you that they do not exist.
I am using Oracle Database and i had same problem. Eventually i found ORACLE DB is converting all the metadata (table/sp/view/trigger) in upper case.
And i was trying how i wrote table name (myTempTable) in sql whereas it expect how it store table name in databsae (MYTEMPTABLE). Also same applicable on column name.
It is quite common problem with developer whoever used sql and now jumped into ORACLE DB.
in my case when i used asp.net core app i had a mistake in my sql query. If your database contains many schemas, you have to write schema_name before table_name, like:
Select * from SCHEMA_NAME.TABLE_NAME...
i hope it will helpful.
Related
I have created a new view named CONS_INTERRUPTED_DATA for the main user hfdora and the view has been created successfully. But when I am trying to create the same view for another user (cis) of the same database after giving all the privileges to the user (cis) I am getting the below error,
*oms_consumer
ERROR at line 13:
ORA-00942: table or view does not exist
Both the user hfdora and cis are the part of same database and this oms_consumer table is present at the database
I have granted the following privileges for the user cis before creating the view
grant select on energization_info to cis;
grant select on trigger_info to cis;
grant select on oms_source to cis;
grant select on oms_consumer to cis;
grant connect,resource,dba to cis;
My sql query to create the view,
>CREATE OR REPLACE VIEW CONS_INTERRUPTED_DATA AS
SELECT
trigger_info_A.b1 AS FDR_RMU_OFF_B1, trigger_info_A.b2 AS FDR_RMU_OFF_B2,
trigger_info_A.B3TEXT AS FDR_RMU_OFF_B3TEXT, trigger_info_A.elem AS FDR_RMU_OFF_ELEM,
trigger_info_B.b1 AS FDR_RMU_RESTORE_B1, trigger_info_B.b2 AS FDR_RMU_RESTORE_B2,
trigger_info_B.B3TEXT AS FDR_RMU_RESTORE_B3TEXT,
trigger_info_B.elem AS FDR_RMU_RESTORE_ELEM,
oms_consumer.consumer_code, energization_info.b1 AS AFFECTED_B1,
energization_info.b2 AS AFFECTED_B2, energization_info.b3text AS AFFECTED_B3TEXT,
to_char(energization_info.deenergized_date, 'DD-MM-YYYY Hh24:MI:SS') AS DEENERGIZED_DATE,
to_char(energization_info.energized_date, 'DD-MM-YYYY Hh24:MI:SS') AS ENERGIZED_DATE,
trigger_info_A.comments AS KEY
FROM
energization_info,
trigger_info trigger_info_A,
trigger_info trigger_info_B,
oms_consumer
WHERE
(energization_info.trigger_number = trigger_info_A.trigger_number)
AND (energization_info.ENERGIZED_TRIGGER_NUMBER = trigger_info_B.trigger_number)
AND (energization_info.b1 = oms_consumer.B1NAME
AND energization_info.b2 = oms_consumer.B2NAME
AND energization_info.b3 = oms_consumer.B3NAME)
WITH READ ONLY;
The first step in diagnosing a problem when creating a view is to try the select part on its own. In this case you would still get the ORA-00942 error, but the problem is now just a query and access issue and not to do with the view specifically.
When you get ORA-00942: table or view does not exist, it's because either:
The table or view name that you typed really doesn't exist.
Check the spelling - maybe there is a typo.
Are you connected to a database where it exists? Perhaps you are on a test system that doesn't have it.
Query dba_objects to see whether the table exists in another schema. (If you don't have privileges to query dba_objects, all_objects lists everything you have permission to view, which may be some help.)
It really does exist, but it's in another schema.
In that case, there are two possible issues:
You don't have permission to query it. The table's owner needs to grant read on xyz (substitute the actual table name for xyz) to either
you
public (if you want everyone to be able to see the data, not always advisable)
a role that you have (but roles aren't used by stored PL/SQL or views, though, so it's possible that you can query a table in another schema thanks to a role that you have, but still not be able to create a view or a procedure that uses it.)
You need to specify the schema. Say you want to query the REGIONS table in HR but you are connected as SCOTT. If you just select * from regions it will look for SCOTT.REGIONS, which doesn't exist. To fix that, do one of the following:
use hr.regions explicitly in your query.
in your schema, create or replace synonym regions for hr.regions;
Now whenever you refer to regions, the database will automatically redirect to hr.regions.
in any schema with permission to create public synonyms:
create or replace public synonym regions for hr.regions;
Now everyone connecting to the database will have any references to regions redirected to hr.regions, which isn't always a good idea, but it's one option anyway.
alter session set current_schema = hr;
Now the default schema for resolving names of objects is HR and not the one you logged into. For applications that always log in as a different user than the one that owns the tables, you can create an after logon trigger so this is always set. Then they can just refer to regions etc without needing to specify any schema and without any synonyms.
My issue has been resolved. :-)
I have made the following changes,
FROM
hfdora.energization_info,
hfdora.trigger_info trigger_info_A,
hfdora.trigger_info trigger_info_B,
hfdora.oms_consumer
Now the same view is created for the user cis.
A piculiarity I noticed.
When I try
create table dbname.table_name as select
I get Error creating temporary folder on: hdfs://nameservice1/apps/hive/warehouse. Error encountered near token 'TOK_TMP_FILE'
But If I first do
use dbname;
and then
create table table_name as select
It works. Why is that?
To create table in any database user need to have write permission on current database and database in which table is being created.
I.e. while running create table dbname.table_name as select statement , you need to have write permission on current database as well.
This is known issue reported in jira HIVE-11427.
I had a schema in one oracle DB as ui_prod. I asked my DBA team guys to create exactly same schema like ui_prod but as read only and name it ui_prod_readonly. Usually I will use Oracle SQL developer to connect a DB and query directly with table name like below.
--Connect to ui_prod
select * from table
but why I requested to put owner name infront when query for readonly schema they created for me, as without putting it, I get error table not exist.
--Connect to ui_prod_readonly
select * from ui_prod.table
I have project files which hardcode the sql query with only table names and adding owner name in front will cause many changes and effort. Can anyone explain me on this? or provide me any document/link to read. Thanks
You should look into synonyms, apparently the user you are connecting to the database as is not the owner of the objects. So to view the object you have to prepend the names with the schema name (the owner of the object themselves).
http://www.techonthenet.com/oracle/synonyms.php
CREATE OR REPLACE SYNONYM ui_prod_readonly.synonym_name
FOR ui_prod.object_name
It seems to me that your dbas have not created another set of tables but just granted the existing tables to the user ui_prod_readonly.
When you log in to Oracle, the current schema is the name of the user you used to log in. So if you log in with ui_prod_readonly Oracle checks that schema for the table if you do not qualify it with the owner (=schema).
If you want to change the current schema so that you don't need to fully qualify the tables, you can do that with ALTER SESSION
alter session set current_schema = ui_prod;
Once you have done that, you don't need to fully qualify the table with the owner (=schema).
if you need a user to read the data only
its simple to create new user and grant it only select privilege
you can create user and grant select privilege using
CREATE USER [user] IDENTIFIED BY [your_password];
grant select on table to [user]
Is there a way, to select data only form the own schema, even if there is an public synonym?
something like: Select * from current_schema.Table1
more info:
I got a public synonym on table1 on schema1.
now I have a package(on schema2) that selects table1, I want to select table1 of schema2 not schema1.
My problem is, I dont what the user to change the identifier when he uses the package at his server.
edit
I see my question is not clear, what i wanted to know is is there a placeholder for my current schema?
at the moment i need to do this:
Select * from schema2.Table1
and i want is something Like this :
Select * from MySchema.Table1
or
Select * from this.Table1
or
Select * from current_schema.Table1
does something like this exists in oracle?
The scoping rules are quite clear. When the databse parses a query it looks for objects matching the identifiers in your statement in the following order of precedence:
objects of that name in your schema
private synonyms of that name (in your schema)
public synonys of that name
But if you want to be clear certainly you can prefix your table references with the specific schema name. That is helpful in communicating your intent to others looking at your code.
Furthermore, if you have a table TABLE1 in your schema and there is a public synonym called TABLE1 pointing at a table in another schema which you want to query instead you must prefix your reference with that other schema.
"what i wanted to know is is there a placeholder for my current
schema"
No, because it's not necessary. The default is always your current schema. That is, this statement ...
SQL> select * from t23;
... will always select from T23 in your current schema, if it has a table (or a private synonym) with that name.
Note that it is possible to change the value of your current schema, with the ALTER SESSION command:
SQL> alter session set current_schema=scott;
Now if you executed the previous select it would return results from SCOTT.T23 providing the SCOTT schema had such a table, and taht you had privileges on it. You can find out more about Oracle schemas in a blog piece I wrote a while back.
I was trying to understand what problem you were having, and I noticed that your scenario is one user executing a package owned by another user. Now, by default a package owned by SCHEMA2 will run against objects owned by SCHEMA2 and use the privileges on other objects granted to SCHEMA2.
But PL/SQL offers us the ability to change that: the AUTHID clause determines whether the package runs with the definer's privileges (that is the package owner) or invoker's privileges (the current user. So if SCHEMA2 defined their package with AUTHID CURRENT_USER when SCHEMA1 runs it the instance of TABLE2 will be the one in scope of SCHEMA1, which would be the one owned by SCHEMA1 or the one indicated by a public synonym.
Find out more.
I am using insert statement and trying to insert data into the database table. I am using stored procedures.
But I am getting this error while doing so.
Message: ORA-00942: table or view does
not exist ORA-06512
I checked if the tables/stored procedures are present or not and everything is in place. Also there is no typo in table names or in sp. If I run the part of SP from query editor it works fine but when I execute the entire SP it throws an error.
I tried the steps provided by Stephen but since I have logged in with the same user/owner when I run Grant command it gives me an error saying 'Cannot Grant/revoke on own'.
One more addition to this. I have a stored procedure SP1 in which I am using a select statement as
Select a from table_name where condition;
When I execute this seperately, it returns me some results. But when I execute sp it gives an error at the same line where it is written.
Can anyone help me out to resolve this issue. I am using SQL +.
Thanks in advance
Vijay
Justin's answer is correct but let me expand a bit.
Everyone who said that the table doesn't exist didn't read your whole post. Since you are able to:
If I run the part of SP from query editor it works fine
Obviously the table is there.
Obviously you have some access to it. Otherwise this wouldn't work when it clearly does.
but when I execute the entire SP it throws an error.
This is because Oracle distinguishes between permissions granted directly and those granted via a role.
Say I do this:
Create Table TABLE_A
Create Role READ_ONLY
Grant Select on TABLE_A to READ_ONLY
Grant READ_ONLY to VIJAY
In a SQL Window/prompt you could query that table without issue. So now you need to create a view
Create VIJAY.VIEW_A as SELECT * FROM TABLE_A
You'll get the error that TABLE_A does exist. Because a view is compiled, like a procedure it runs without any roles. Since it runs without the READ_ONLY role, it's blind to the fact that TABLE_A exists. Now what I need to do is
Grant Select on TABLE_A to VIJAY.
Now that you have a direct permission, you can compile a view or procedure/package that uses that table.
Does the table exist in the schema where the stored procedure exists? If not, the simplest explanation is that the owner of your procedure has been granted access to the table via a role not via a direct grant. A definer's rights stored procedure needs to have direct access to the objects it accesses. A quick way to test this is to disable roles for the session, i.e.
SQL> set role none;
SQL> <<execute your query>>
If that generates the error, the problem is the lack of a direct grant.
In Oracle you can choose if the stored procedure is executed with the rights of the invoker or the definer: http://download.oracle.com/docs/cd/E11882_01/appdev.112/e17126/subprograms.htm#i18574
Check if the AUTHID property of the stored procedure is correct and if the resulting user has appropriate permissions.
Well, put very simply, the table that you are trying to insert data into does not exist in the database you are connected to. You need to check both those things (i.e. what are you connected to, and is the table there and accessible for the user context you are using).
As Joe Stefanelli said .. there are a lot of possibilities for the error being shown here.
Check whether:
You are connecting to the correct Oracle Instance.
You have permissions to query or perform processing on table that you are referencing in your query.
There is a difference between ordinary select statements and procedures. Procedures in oracle do not respect the roles assigned to a user; rather the permission needs to be explicitly granted to the user. For more information read the following linkORA-00942