I am using SPARQL for querying the DBpedia database. My first query was the following:
select ?s1 ( bif:search_excerpt ( bif:vector ( 'TENDULKAR', 'SACHIN' ) , ?o1 ) ) where
{
{
{
select ?s1, ( ?sc * 3e-1 ) as ?sc, ?o1, ( sql:rnk_scale ( <LONG::IRI_RANK> ( ?s1 ) ) ) as ? rank, ?g where
{
quad map virtrdf:DefaultQuadMap
{
graph ?g
{
?s1 ?s1textp ?o1 .
?o1 bif:contains ' ( TENDULKAR AND SACHIN ) ' option ( score ?sc ) .
}
}
}
order by desc ( ?sc * 3e-1 + sql:rnk_scale ( <LONG::IRI_RANK> ( ?s1 ) ) ) limit 20 offset 0
}
}
}
Now even if I apply the DISTINCT keyword to the query it gives the same result as before.
I want distinct results from this query.
Related
so I am trying to display top 10 richest tennis players. I want to make a query that lists tennis players according to their name ,net worth ,and nationality.
SELECT DISTINCT ?item ?itemLabel ?networths ?nationality WHERE {
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE]". }
{
SELECT DISTINCT ?item (COUNT(?statement2) AS ?networths) (COUNT(?statement1) AS ?nationality) WHERE {
?item p:P106 ?statement0.
?statement0 (ps:P106/(wdt:P279*)) wd:Q10833314.
?item p:P27 ?statement1.
?statement1 (ps:P27/(wdt:P279*)) _:anyValueP27.
?item p:P2218 ?statement2.
?statement2 (psv:P2218/wikibase:quantityAmount) ?numericQuantity.
}
GROUP BY ?item ORDER BY DESC (?networths)
}
}
ORDER BY DESC (?networths)
The following query searches all triplets where where the subject, object and relation are are elements of the set defined with ?sub, ?obj and ?rel.
select *
{
?sub ?rel ?obj
values (?sub) { ( wd:Q263 )( wd:Q328 )( wd:Q373 )( wd:Q14827288 ) }
values (?obj) { ( wd:Q263 )( wd:Q328 )( wd:Q373 )( wd:Q14827288 ) }
values (?rel) { ( wdt:P31 )( wdt:P361 )( wdt:P279 )( wdt:P527 ) }
}
Because values (?sub) ... and values (?obj) ... is redundant, I am wondering if there is a way to reformulate the query to use a list or subquery sp that it returns the same result, yet without having to repeat the list of wd:... identifiers.
Using SPARQL, how can I find entities linked to an entity by x degrees of separation, for example 4 or 5 degrees? For example, with test data like this, how do I find which of my relatives connects to which one? The aim is to form a graph from the triples. (Using only “raised” as predicates in this example, but any connection should be considered.)
<http://www.example.com/great-grandma> <:raised1> <http://www.example.com/grandma> .
<http://www.example.com/grandma> <:raised2> <http://www.example.com/ma> .
<http://www.example.com/ma> <:raised3> <http://www.example.com/me> .
<http://www.example.com/ma> <:raised4> <http://www.example.com/sis> .
<http://www.example.com/me> <:raised5> <http://www.example.com/kid> .
<http://www.example.com/spouse> <:raised6> <http://www.example.com/kid> .
So from the above, the wanted first-degree relationships would be:
<http://www.example.com/ma> <:raised3> <http://www.example.com/me> .
<http://www.example.com/me> <:raised5> <http://www.example.com/kid> .
With the whole s-p-o triple as the result.
I can get to two degrees relatively easily:
SELECT *
WHERE
{ { SELECT DISTINCT ?s ?p ?o
WHERE
{ ?s ?p1 <http://www.example.com/me> .
?s ?p ?o
}
}
UNION
{ SELECT DISTINCT ?s ?p ?o
WHERE
{ <http://www.example.com/me> ?p1 ?o .
?s ?p ?o
}
}
UNION
{ SELECT DISTINCT ?s ?p ?o
WHERE
{ ?o ?p1 <http://www.example.com/me> .
?s ?p ?o
}
}
UNION
{ SELECT DISTINCT ?s ?p ?o
WHERE
{ <http://www.example.com/me> ?p1 ?s .
?s ?p ?o
}
}
}
This finds my grandmother and sister, for example. But this does not seem practical with more degrees of separation, as the number of sub-queries would double with each new degree. Is there a better way to do this? It would need to work with larger amounts of data too, so can't just run a new query on every linked entity.
EDIT: Highlighting that different predicates should be expected, I clarified and changed the example a bit.
Property paths are your friend.
SELECT DISTINCT ?rel {
{
SELECT ?rel {
:me (:raised|^:raised) ?rel
}
}
UNION {
SELECT ?rel {
:me (:raised|^:raised)/(:raised|^:raised) ?rel
}
}
UNION {
SELECT ?rel {
:me (:raised|^:raised)/(:raised|^:raised)/(:raised|^:raised) ?rel
}
}
}
and so on...
i want to avoid using substring to eliminate by example #en in my
ontology:abstract or ontology:label, it work with sparql explorer but when i use http query in jena it dont give any result... i tried this query in android project with jena library (androjena)
SELECT ?type (STR(?l) AS ?label) {
?type a owl:Class;
rdfs:label ?l .
FILTER (LANG(?l) = "en")
}
once i put this in my Jena httpquery (STR(?l) AS ?label)it dont give any result anymore. someone can help me?
here is the part of the code that i try to manage to change to avoid use of substrings :
private String entityQuery(String entity, String keyWord, String language) {
return addPrefix("rdfs: <http://www.w3.org/2000/01/rdf-schema#>") +
addPrefix("ontology: <http://dbpedia.org/ontology/>") +
addQuery("SELECT ?name ?desc ?thumb WHERE {\n"
+"?author a ontology:" + entity + ";\n"
+"rdfs:label ?name;\n"
+"ontology:abstract ?desc.\n"
+"FILTER(<bif:contains>(?desc,\"'"+keyWord+"'\") && langMatches(lang(?desc), \""+language+"\") " +
"&& langMatches( lang(?name), \""+language+"\"))\n"
+"OPTIONAL { ?author ontology:thumbnail ?thumb }.\n"
+"}ORDER BY ?name\n");
}
private LinkedList<Entity> collectEntities(ResultSet results) {
LinkedList<Entity> temp = new LinkedList<>();
/* do stuff with the results */
while (results.hasNext()) {
Entity a = new Entity();
QuerySolution row = results.next();
if (row.getResource("thumb") != null)
a.setPictureURL(row.get("thumb").toString());
a.setTitle(row.get("name").toString().substring(0, row.get("name").toString().indexOf("#")));
a.setSummary(row.get("desc").toString().substring(0, row.get("desc").toString().indexOf("#")));
temp.add(a);
}
return temp;
}
private String addPrefix(String prefix) {
return "PREFIX " + prefix + "\n";
}
private String addQuery(String query) {
return query;
}
i use substring here :
a.setTitle(row.get("name").toString().substring(0, row.get("name").toString().indexOf("#")));
a.setSummary(row.get("desc").toString().substring(0, row.get("desc").toString().indexOf("#")));
I'm trying to get information about some concepts on DBpedia. I found out how to get 1, but for more it fails. I've been told filtering should help, but the processing time is too long and i get timeouts.
The thing i can't do is VALUES ?s { dbpedia:Facebook dbpedia:Google }
So I've looked for an alternative way, but it still isn;t working. Here's where I'm now:
public static String concepts[] = { "Facebook", "Google" };
public static String getQuery(String concept) {
return "prefix dbpediaowl: <http://dbpedia.org/ontology/>"
+ " prefix dbpedia: <http://dbpedia.org/resource/>"
+ " prefix owl: <http://www.w3.org/2002/07/owl#>"
+ " prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> "
+ " PREFIX dbpprop: <http://dbpedia.org/property/>"
+ " prefix dbpedia-owl: <http://dbpedia.org/ontology/>"
+ " select ?s ?p ?o where { "
+ " values ?web { dbpedia:"
+ "Facebook"
+ " } "
+ " { ?web ?p ?o bind( ?web as ?s ) } " + " union "
+ " { ?s ?p ?web bind( ?web as ?o ) } " + " filter( ?p in ( "
+ "dbpprop:available, " + "dbpprop:company, "
+ "dbpprop:inventor, " + "dbpedia-owl:foundedBy, "
+ "dbpedia-owl:subsidiary, " + "dbpprop:foundation, "
+ "dbpprop:founder, " + "dbpprop:industry, "
+ "dbpprop:programmingLanguage, " + "dbpedia-owl:successor )) ";
}
public static void main(String[] args) {
OutputStream os;
PrintStream printStream;
try {
os = new FileOutputStream("C:/Users/alex/Desktop/data.txt");
printStream = new PrintStream(os);
printStream.println("am scris");
for (int i = 0; i < concepts.length; i++) {
printStream.println(i+ " concept");
Query query = QueryFactory.create(getQuery(concepts[i]));
QueryExecution qExe = QueryExecutionFactory.sparqlService(
"http://lod.openlinksw.com/sparql", query);
ResultSet results = qExe.execSelect();
while (results.hasNext()) {
printStream.println(results.nextSolution().toString());
}
}
printStream.close();
os.close();
} catch (Exception e) {
e.printStackTrace();
System.out.println(e.getCause());
}
}
For one concept at a time, in the SPARQL it works fine, but I need to call about 50 of them. So I need to know how i can do it programatically. Also, it would be great if you could help me select the predicates as well ( without the filtering ) because I also need to allow about 30-40 of them.
Thanks a lot! Hope you can help.
I thought we'd solved the problem with VALUES ?s { dbpedia:Facebook dbpedia:Google } in your previous question, Sparql about dbpedia:World_Wide_Web. Instead of doing values ?s { dbpedia:Facebook dbpedia:Google }, you can use filter( ?s in (dbpedia:Facebook, dbpedia:Google) }. This works just fine for subjects and properties. E.g., if you wanted to get the English abstracts and labels for Google and Facebook, you could use a query like this:
select ?s ?p ?o where {
?s ?p ?o
filter( ?s in (dbpedia:Google, dbpedia:Facebook) )
filter( ?p in (rdfs:label, dbpedia-owl:abstract) )
filter( !isLiteral(?o) || langMatches(lang(?o),"en") )
}
SPARQL results
Now, if you can get rid of that union (which you might be able to do, if you're really just looking for the values of certain properties from certain subjects), then you actually can use the values blocks in the way that you'd like to. (Really, I think the problematic behavior seen in your other question is due to a DBpedia bug; I think you should be able to use values and union together.) That is, to select non-literals, and literals with an English language tag for some specified properties, you can do:
select ?s ?p ?o where {
values ?s { dbpedia:Google dbpedia:Facebook }
values ?p { rdfs:label dbpedia-owl:abstract }
?s ?p ?o
filter( !isLiteral(?o) || langMatches(lang(?o),"en") )
}
SPARQL results