I am using Oracle database and I have a table that have 1.9 billion rows of records. I want to get the rows of records ranging from 100,000,001 to 200,000,000. Can someone help me on this? Thank you in advance.
generally speaking you want a pagination query , which would be of the format:
select t.*
from (select t.*, rownum rn
from (select t.yourfields
from yourtab t
order by t.something)
where rownum <= end_rownum
) t
where rn >= offset;
or
select *
from (select t.yourfields, row_number() over (order by t.something) rn
from yourtab t)
where rn between start_rownum and end_rownum;
if you mean those ranges are rownum then here is simple the query
select * from (select e.*,rownum test from hr.employees e) where test>5 and test <50;
Related
Can anyone help me to translate Teradata SQL QUALIFY ROW_NUMBER() OVER into Presto:
SELECT *
FROM table1
QUALIFY ROW_NUMBER() OVER(ORDER BY id DESC) > 5000000
AND ROW_NUMBER() OVER(ORDER BY id DESC) <= 10000000;
Or provide some suggestions how to extract large datasets by row filtering.
As far as I understand there is no direct analog for QUALIFY clause in PrestoSQL/Trino. You can just use window function in the WHERE clause. Something like this:
SELECT *
FROM table1
WHERE ROW_NUMBER() OVER(ORDER BY id DESC) BETWEEN 5000001
AND 10000000;
I have a table with 198Mil records.
I am using this query to get the LATEST records for each ID:
with cte as (
select *, row_number() OVER (Partition by ATTOM_ID ORDER BY LastLoadDate DESC) rnum from `mother-216719.PROPERTY.ATTOM_DETAIL`
) Select * from cte where rnum = 1
Of note, there's 240 columns in this table.
This has been running over an hour, with no avail.
Is there a way to make this work?
Thanks!
Try below approach - usually it helps
#standardSQL
SELECT AS VALUE ARRAY_AGG(t ORDER BY LastLoadDate DESC LIMIT 1)[OFFSET(0)]
FROM `mother-216719.PROPERTY.ATTOM_DETAIL` t
GROUP BY ATTOM_ID
How can I get the Latest amount, I already had some queries but instead it shows two records ,Im expecting to show only the the '7370' current amount
you can use correlated subquery
select * from tablename a where lasttime in (select max(lasttime) from tablename b where a.id=b.id)
OR you can use row_number()
select * from
(
select *,row_number() over(partition by id order by lasttime desc) as rn from tablename
)A where rn=1
Just add Top 1 before your fields.
Select TOP 1 fields from table
SELECT TOP 1 currentBalance FROM DBO.tbl_billing ORDER BY [date]
My requirement is to get each client's latest order, and then get top 100 records.
I wrote one query as below to get latest orders for each client. Internal query works fine. But I don't know how to get first 100 based on the results.
SELECT * FROM (
SELECT id, client_id, ROW_NUMBER() OVER(PARTITION BY client_id ORDER BY create_time DESC) rn
FROM order
) WHERE rn=1
Any ideas? Thanks.
Assuming that create_time contains the time the order was created, and you want the 100 clients with the latest orders, you can:
add the create_time in your innermost query
order the results of your outer query by the create_time desc
add an outermost query that filters the first 100 rows using ROWNUM
Query:
SELECT * FROM (
SELECT * FROM (
SELECT
id,
client_id,
create_time,
ROW_NUMBER() OVER(PARTITION BY client_id ORDER BY create_time DESC) rn
FROM order
)
WHERE rn=1
ORDER BY create_time desc
) WHERE rownum <= 100
UPDATE for Oracle 12c
With release 12.1, Oracle introduced "real" Top-N queries. Using the new FETCH FIRST... syntax, you can also use:
SELECT * FROM (
SELECT
id,
client_id,
create_time,
ROW_NUMBER() OVER(PARTITION BY client_id ORDER BY create_time DESC) rn
FROM order
)
WHERE rn = 1
ORDER BY create_time desc
FETCH FIRST 100 ROWS ONLY)
you should use rownum in oracle to do what you seek
where rownum <= 100
see also those answers to help you
limit in oracle
select top in oracle
select top in oracle 2
As Moneer Kamal said, you can do that simply:
SELECT id, client_id FROM order
WHERE rownum <= 100
ORDER BY create_time DESC;
Notice that the ordering is done after getting the 100 row. This might be useful for who does not want ordering.
Update:
To use order by with rownum you have to write something like this:
SELECT * from (SELECT id, client_id FROM order ORDER BY create_time DESC) WHERE rownum <= 100;
First 10 customers inserted into db (table customers):
select * from customers where customer_id <=
(select min(customer_id)+10 from customers)
Last 10 customers inserted into db (table customers):
select * from customers where customer_id >=
(select max(customer_id)-10 from customers)
Hope this helps....
To select top n rows updated recently
SELECT *
FROM (
SELECT *
FROM table
ORDER BY UpdateDateTime DESC
)
WHERE ROWNUM < 101;
Try this:
SELECT *
FROM (SELECT * FROM (
SELECT
id,
client_id,
create_time,
ROW_NUMBER() OVER(PARTITION BY client_id ORDER BY create_time DESC) rn
FROM order
)
WHERE rn=1
ORDER BY create_time desc) alias_name
WHERE rownum <= 100
ORDER BY rownum;
Or TOP:
SELECT TOP 2 * FROM Customers; //But not supported in Oracle
NOTE: I suppose that your internal query is fine. Please share your output of this.
How can I select the Nth row from a table in Oracle?
I tried
SELECT PRICE FROM AAA_PRICING WHERE ROWNUM = 2
but that didn't work. Please help!
Based on the classic answer:
http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:127412348064
select *
from ( select a.*, rownum rnum
from ( YOUR_QUERY_GOES_HERE -- including the order by ) a
where rownum <= N_ROWS )
where rnum >= N_ROWS
/
Will not works with '=' (will works <2 or >2, but not equal)
so you can
SELECT Price from (SELECT PRICE, ROWNUM AS RN FROM AAA_PRICING) WHERE RN = 2
To address the reason for this:
The RowNum is a pseudo-column supplied by Oracle. It is generated while the SELECT-clause is being processed. Since the WHERE-clause is handled before the SELECT-clause, the RowNum does not have a proper value yet.
One can argue whether or not it makes sense to have Oracle throw an exception in situation, but because RowNum still is a pseudo-column it's still valid to have it there.
Note: Don't confuse this with RowId, which is an entire different story!
IMPORTANT EDIT:
Note that what I wrote about RowNum is only true for =, >, >=, IN () and maybe others. If you check for, e.g. RowNum < 10, you only get nine records!? I don't know why that is the case!
Select * From
(
Select Row_Number() OVER (Order by empno) rno, e.*
From scott.emp e
)
Where rno in (1, 3, 11)
SELECT PRICE
FROM (
SELECT PRICE,
ROWNUM rnum
FROM AAA_PRICING
ORDER BY PRICE ASC
)
WHERE rnum = 2
If you are on Oracle 12 or above, You can use the result offset and fetch clauses:
SELECT PRICE FROM AAA_PRICING
offset 1 rows fetch next 1 rows only
SELECT * FROM
(SELECT PRICE, ROWNUM AS RN FROM AAA_PRICING )
WHERE RN = 2;
select * from (Select Price, rownum as rn from(Select * from AAA_PRICING a order by a.Price))
where rn=2;
It will give you 2nd lowest price from the Price column. If you want simply 2nd row remove Order By condition.
ROWNUM is a pseudo column which generates unique pseudo values (equals to the number of records present in the SELECT statement o/p) during the execution of SELECT clause. When this pseudo column is specified with the WHERE clause it's value becomes 1 by default. So it behaves according to the comparison operator specified with it.
SELECT * FROM (
SELECT ROWNUM RN, E.*
FROM Emp E
)
WHERE RN = 10;
select *
From (select PRICE, DENSE_RANK() over(ORDER BY PRICE desc) as RNO
From AAA_PRICING
) t where RNO=2;
select a.*, rownum rnum
from ( select * from xyz_menu order by priority desc) a
where rownum < 5 ;
select * from xyz_menu order by priority desc
creating virtual table and also defining row number in virtual table
note: for oracle
Problem solved!
To select 2nd row in Oracle..
select SEN_NO,ITEM_NO from (select * from master_machine where
sen_no ='BGCWKKL23' and rownum <=2 order by
rownum desc,timestamp asc) where rownum <=1
Thank You!