I'm using access, and I'm trying to write a query which will remove duplicates of one column. Here is my query so far:
SELECT
Drawings.DrawingID,
Players.NumOfGuessedAPainting,
Players.NumOfGuessedBPainting,
Players.NumOfGuessedCPainting,
Words.Word
FROM Words INNER JOIN
(Players INNER JOIN
(Drawings INNER JOIN
PlayersAndWords
ON Drawings.DrawingID = PlayersAndWords.DrawingID)
ON Players.PlayerID = PlayersAndWords.DrawingPlayerID)
ON Words.WordID = PlayersAndWords.WordID
WHERE ((Words.Word)='" + w + "')
ORDER BY (Players.NumOfGuessedAPainting
+Players.NumOfGuessedBPainting * 2
+Players.NumOfGuessedCPainting *3 ) DESC
The column Drawings.DrawingID might be duplicated, and I want the query to return only one row of each Drawings.DrawingID. "distinct" won't work here. I've read that group by might help but I couldn't figure how..
Could you help me?
Thanks in advance.
Just put these lined before ORDER BY line
GROUP BY
Drawings.DrawingID,
Players.NumOfGuessedAPainting,
Players.NumOfGuessedBPainting,
Players.NumOfGuessedCPainting,
Words.Word
Edited.
Related
I am having a problem with my SQL query using the count function.
When I don't have an inner join, it counts 55 rows. When I add the inner join into my query, it adds a lot to it. It suddenly became 102 rows.
Here is my SQL Query:
SELECT COUNT([fmsStage].[dbo].[File].[FILENUMBER])
FROM [fmsStage].[dbo].[File]
INNER JOIN [fmsStage].[dbo].[Container]
ON [fmsStage].[dbo].[File].[FILENUMBER] = [fmsStage].[dbo].[Container].[FILENUMBER]
WHERE [fmsStage].[dbo].[File].[RELATIONCODE] = 'SHIP02'
AND [fmsStage].[dbo].[Container].DELIVERYDATE BETWEEN '2016-10-06' AND '2016-10-08'
GROUP BY [fmsStage].[dbo].[File].[FILENUMBER]
Also, I have to do TOP 1 at the SELECT statement because it returns 51 rows with random numbers inside of them. (They are probably not random, but I can't figure out what they are.)
What do I have to do to make it just count the rows from [fmsStage].[dbo].[file].[FILENUMBER]?
First, your query would be much clearer like this:
SELECT COUNT(f.[FILENUMBER])
FROM [fmsStage].[dbo].[File] f INNER JOIN
[fmsStage].[dbo].[Container] c
ON v.[FILENUMBER] = c.[FILENUMBER]
WHERE f.[RELATIONCODE] = 'SHIP02' AND
c.DELIVERYDATE BETWEEN '2016-10-06' AND '2016-10-08';
No GROUP BY is necessary. Otherwise you'll just one row per file number, which doesn't seem as useful as the overall count.
Note: You might want COUNT(DISTINCT f.[FILENUMBER]). Your question doesn't provide enough information to make a judgement.
Just remove GROUP BY Clause
SELECT COUNT([fmsStage].[dbo].[File].[FILENUMBER])
FROM [fmsStage].[dbo].[File]
INNER JOIN [fmsStage].[dbo].[Container]
ON [fmsStage].[dbo].[File].[FILENUMBER] = [fmsStage].[dbo].[Container].[FILENUMBER]
WHERE [fmsStage].[dbo].[File].[RELATIONCODE] = 'SHIP02'
AND [fmsStage].[dbo].[Container].DELIVERYDATE BETWEEN '2016-10-06' AND '2016-10-08'
Hi I have a redshift table of articles that has a field on it that can contain many accounts. So there is a one to many relationship between articles to accounts.
However I want to create a new view where it lists the partner id's in one column and in another column a count of how many times the partner id appears in the articles table.
I've attempted to do this using regex and created a new redshift view, but am getting weird results where it doesn't always build properly. So one day it will say a partner appears 15 times, then the next 17, then the next 15, when the partner id count hasn't actually changed.
Any help would be greatly appreciated.
SELECT partner_id,
COUNT(DISTINCT id)
FROM (SELECT id,
partner_ids,
SPLIT_PART(partner_ids,',',i) partner_id
FROM positron_articles a
LEFT JOIN util.seq_0_to_500 s
ON s.i < regexp_count (partner_ids,',') + 2
OR s.i = 1
WHERE i > 0
AND regexp_count (partner_ids,',') = 0
ORDER BY id)
GROUP BY 1;
Let's start with some of the more obvious things and see if we can start to glean other information.
Next GROUP BY 1 on your outer query needs to be GROUP BY partner_id.
Next you don't need an order by in your INNER query and the database engine will probably do a better job optimizing performance without it so remove ORDER BY id.
If you want your final results to be ordered then add an ORDER BY partner_id or similar clause after your group by of your OUTER query.
It looks like there are also problems with how you are splitting a partnerid from partnerids but I am not positive about that because I need to understand your view and the data it provides to know how that affects your record count for partnerid.
Next your LEFT JOIN statement on the util.seq_0_to_500 I am pretty sure you can drop off the s.i = 1 as the first condition will satisfy that as well because 2 is greater than 1. However your left join really acts more like an inner join because you then exclude any non matches from positron_articles that don't have a s.i > 0.
Oddly then your entire join and inner query gets kind of discarded because you only want articles that have no commas in their partnerids: regexp_count (partner_ids,',') = 0
I would suggest posting the code for your util.seq_0_to_500 and if you have a partner table let use know about that as well because you can probably get your answer a lot easier with that additional table depending on how regexp_count works. I suspect regex_count(partnerids,partnerid) exampleregex_count('12345,678',1234) will return greater than 0 at which point you have no choice but to split the delimited strings into another table before counting or building a new matching function.
If regex_count only matches exact between commas and you have a partner table your query could be as easy as this:
SELECT
p.partner_id
,COUNT(a.id) AS ArticlesAppearedIn
FROM
positron_articles a
LEFT JOIN PARTNERTABLE p
ON regexp_count(a.partnerids,p.partnerid) > 0
GROUP BY
p.partner_id
I will actually correct myself as I just thought of a way to join a partner table without regexp_count. So if you have a partner table this might work for you. If not you will need to split strings. It basically tests to see if the partnerid is the entire partnerids, at the beginning, in the middle, or at the end of partnerids. If one of those is met then the records is returned.
SELECT
p.partner_id
,COUNT(a.id) AS ArticlesAppearedIn
FROM
PARTNERTABLE p
INNER JOIN positron_articles a
ON
(
CASE
WHEN a.partnerids = CAST(p.partnerid AS VARCHAR(100)) THEN 1
WHEN a.partnerids LIKE p.partnerid + ',%' THEN 1
WHEN a.partnerids LIKE '%,' + p.partnerid + ',%' THEN 1
WHEN a.partnerids LIKE '%,' + p.partnerid THEN 1
ELSE 0
END
) = 1
GROUP BY
p.partner_id
So I got this query:
Data structure:
Users
id---inlog----name----more stuff
llntoets
id---code----inlog----more stuff
oefeningen
id---speler---status----morestuff
(inlog and speler are always the same values for a user)
SELECT
// Some other stuff working
SUM(o.status) AS oefn
FROM users AS u
LEFT JOIN llntoets AS l
ON (u.inlog = l.inlog)
LEFT JOIN oefeningen AS o
ON (u.inlog = o.speler) AND o.status = 'afgewerkt'
WHERE
code = '$code'
GROUP BY l.inlog
ORDER BY klas ASC, klasnr ASC
Everything runs fine except 1 thing the oefn variable. It shows a number sometimes it shows the correct value and sometimes it shows a value that is much higher than it should be. Someone told me it could be because of the GROUP BY. Can someone help me pls?
It is supposed to count the total records from table oefeningen where status = 'afgewerkt' and where the speler is the inlog from users. Thanks, if you got other questions ask will try to explain more.
the SUM(o.status) in your query it is not supposed to count the total records of table oefeningen.
that sum is the sum of the values of all the joined rows that satisfy your criteria that can be a much higher number.
also note that applying the filter o.status = 'afgewerkt' you are performing a JOIN even if you wrote LEFT JOIN throghout the query.
I have tow tables 'matches' and 'forum' I need to get match information from the matches table which has comments in the forum table so I use the following query:
SELECT distinct forum.match_static_id, matches.*
from forum
INNER JOIN matches
ON forum.match_static_id = matches.static_id
WHERE forum.comments_yes_or_no = 1
I use distinct to avoid getting the same match twice if it has more than one comment in the forum table.
The problem is I want to get the count of each match comments with the same query is it possible? I use :
SELECT distinct forum.match_static_id, count(forum.comments), matches.*
from forum
INNER JOIN matches
ON forum.match_static_id = matches.static_i
WHERE forum.comments_yes_or_no = 1
but it give me just one record (which is wrong). What is the problem ?? does I need to use group by ? and if yes where to but it in this crowded query?
Please try this:
SELECT forum.match_static_id, count(matches.id), matches.*
from forum
INNER JOIN matches
ON forum.match_static_id = matches.static_i
WHERE forum.comments_yes_or_no = 1
GROUP BY forum.id
I know there are a lot of other SO entries that seem like this one, but I haven't found one that actually answers my question so hopefully one of you can either answer it or point me to another SO question that is related.
Basically, I have the following query that returns Venues that have any CheckIns that contain the searched Keyword ("foobar" in this example).
SELECT DISTINCT v.*
FROM "venues" v
INNER JOIN "check_ins" c ON c."venue_id" = v."id"
INNER JOIN "keywordings" ks ON ks."check_in_id" = c."id"
INNER JOIN "keywords" k ON ks."keyword_id" = k."id"
WHERE (k."name" = 'foobar')
I want to SELECT and ORDER BY the count of the matched Keyword for each given Venue. E.g. if there have been 5 CheckIns that have been created, associated with that Keyword, then there should be a returned column (called something like keyword_count) with the value 5 which is sorted.
Ideally this should be done without any queries in the SELECT clause, or preferably none at all.
I've been struggling with this for a while and my mind is just going blank (perhaps it's been too long a day) so some help would be greatly appreciated here.
Thanks in advance!
Sounds like you need something like:
SELECT v.x, v.y, count(*) AS keyword_count
FROM "venues" v
INNER JOIN "check_ins" c ON c."venue_id" = v."id"
INNER JOIN "keywordings" ks ON ks."check_in_id" = c."id"
INNER JOIN "keywords" k ON ks."keyword_id" = k."id"
WHERE (k."name" = 'foobar')
GROUP BY v.x, v.y
ORDER BY 3