I have a table with the following structure
sys_id(identity) | id | group_id | fld_id | val
-----------------------------------------------
I have a query
SELECT id,group_id,fld_id,val,COUNT(*)
FROM [DB_ALERT].[dbo].[DATATABLE]
GROUP BY id,group_id,fld_id,val
HAVING COUNT(*)>1
The resul set is like this
ID | group_id | fld_id | val| count(*)
__________________________________________
1000001| 1 | 1 | 23 | 2
1000003| 1 | 1 | 24 | 5
1000008| 1 | 1 | 14 | 4
Now in the result set I want to take only top 1 sys_id for each record and delete the others with same ID,Group,Fld and val (remove its dublicates). I know how to do this with cursors, but is there any way to do such operation in a single query?
Please try:
;with c as
(
select *, row_number() over(partition by ID, Group, Fld, val order by ID, Group, Fld, val) as n
from YouTable
)
delete from c
where n > 1
Related
The query is supposed to query the item table and:
filter out active=0 items
select id and groupId where there's at least one more item with that groupId
Example:
| id | groupId | active |
| --- | ------- | ------ |
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 2 | 0 |
| 4 | 3 | 1 |
| 5 | 3 | 1 |
| 6 | 4 | 1 |
Desired Output:
| id | groupId |
| --- | ------- |
| 4 | 3 |
| 5 | 3 |
Explanation
groupID 1: invalid because has only 1 member
groupID 2: invalid because has two members, but one is inactive
groupID 3: valid
groupID 4: invalid because has only 1 member
What I tried
SELECT id, groupId
FROM items
WHERE id IN (
SELECT id
FROM items
WHERE active=1
GROUP BY groupId
HAVING COUNT(*) > 1
);
But I get the id must appear in the GROUP BY clause or be used in an aggregate function error.
I understand I can mess around with the sql_mode to get rid of that error, but I would rather avoid that.
Go for window functions:
select i.*
from (select i.*, count(*) over (partition by groupid) as cnt
from items i
where active = 1
) i
where cnt > 1
Window functions is the way to go.
But if you want to fix your query then this should do it:
select a.id, a.groupId from items a
where active = 1 and groupid in(
select groupId from item
where active = 1
group by groupId
having count(distinct id) > 1
)
because we are counting which groupid has more than 1 id for the same groupid
I have a table which looks like this:
id | name| fk_something
----------------
0 | 25 | 3
1 | 25 | 2
2 | 23 | 1
and I want to add another column with a number which increments everytime row name occurs, e.g.:
id | name| fk_something| n
--------------------------
0 | 25 | 3 | 1
1 | 25 | 2 | 2
2 | 23 | 1 | 1
I'm not really sure how to achieve this. Using count() I will only get the total number of occurances of name but I want to increment n so that I have a distinct value for each row.
You want row_number() :
select t.*, row_number() over (partition by name order by id) as n
from table t;
You may try using COUNT as an analytic function:
SELECT
id,
name,
fk_something,
COUNT(*) OVER (PARTITION BY name ORDER BY id) n
FROM yourTable
ORDER BY
id;
Demo
I have a table "MARK_TABLE" as below.
How can I delete the rows with same "STUDENT", "COURSE" and "SCORE" values?
| ID | STUDENT | COURSE | SCORE |
|----|---------|--------|-------|
| 1 | 1 | 1 | 60 |
| 3 | 1 | 2 | 81 |
| 4 | 1 | 3 | 81 |
| 9 | 2 | 1 | 80 |
| 10 | 1 | 1 | 60 |
| 11 | 2 | 1 | 80 |
Now I already filtered the data I want to KEEP, but without the "ID"...
SELECT student, course, score FROM mark_table
INTERSECT
SELECT student, course, score FROM mark_table
The output:
| STUDENT | COURSE | SCORE |
|---------|--------|-------|
| 1 | 1 | 60 |
| 1 | 2 | 81 |
| 1 | 3 | 81 |
| 2 | 1 | 80 |
Use the following query to delete the desired rows:
DELETE FROM MARK_TABLE M
WHERE
EXISTS (
SELECT
1
FROM
MARK_TABLE M_IN
WHERE
M.STUDENT = M_IN.STUDENT
AND M.COURSE = M_IN.COURSE
AND M.SCORE = M_IN.SCORE
AND M.ID < M_IN.ID
)
OUTPUT
db<>fiddle demo
Cheers!!
use distinct
SELECT distinct student, course, score FROM mark_table
Assuming you don't just want to select the unique data you want to keep (you mention you've already done this), you can proceed as follows:
Create a temporary table to hold the data you want to keep
Insert the data you want to keep into the temporary table
Empty the source table
Re-Insert the data you want to keep into the source table.
select * from
(
select row_number() over (partition by student,course,score order by score)
rn,student,course,score from mark_table
) t
where rn=1
Use CTE with RowNumber
create table #MARK_TABLE (ID int, STUDENT int, COURSE int, SCORE int)
insert into #MARK_TABLE
values
(1,1,1,60),
(3,1,2,81),
(4,1,3,81),
(9,2,1,80),
(10,1,1,60),
(11,2,1,80)
;with cteDeleteID as(
Select id, row_number() over (partition by student,course,score order by score) [row_number] from #MARK_TABLE
)
delete from #MARK_TABLE where id in
(
select id from cteDeleteID where [row_number] != 1
)
select * from #MARK_TABLE
drop table #MARK_TABLE
I have a SQL Server table that has duplicate entries in one of the columns e.g.:
+----+-----------+------------+
| id | object_id | status_val |
+----+-----------+------------+
| 1 | 1 | 0 |
| 2 | 1 | 0 |
| 3 | 1 | 0 |
| 4 | 2 | 0 |
| 5 | 3 | 0 |
| 6 | 4 | 0 |
| 7 | 4 | 0 |
+----+-----------+------------+
I need the output to be like this:
+----+-----------+------------+
| id | object_id | status_val |
+----+-----------+------------+
| 4 | 2 | 0 |
| 5 | 3 | 0 |
+----+-----------+------------+
How to resolve this?
Is this what you are looking for?
SELECT * FROM <yourTable> t1
WHERE t1.object_id NOT IN
(
SELECT t2.object_id
FROM <yourTable> t2
GROUP BY t2.object_id
HAVING COUNT(object_id) > 1
)
Try this:
select min(id),
object_id,
min(status_val)
from table
group by object_id
having count(*) = 1
Use HAVING and GROUP BY
SELECT MIN(id) id, object_id, MIN(status_val) status_val
FROM yourtable
GROUP BY object_id
HAVING COUNT(object_id) = 1
Output
id object_id status_val
4 2 0
5 3 0
SQL Fiddle: http://sqlfiddle.com/#!6/7f643f/9/0
You can use group by for unique record like below :-
SELECT * from TABLENAME
group by TABLE_COLOUM_NAME
This query give you only unique value from your Table.
Give a row number for each row partitioned and ordered by the columns [object_id], [status_val]. Then from the result set select the rows which having maximum row number 1.
Query
;with cte as(
select [rn] = row_number() over(
partition by [object_id], [status_val]
order by [object_id], [status_val]
), *
from [your_table_name]
)
select min([id]) as [id], [object_id], [status_val]
from cte
group by [object_id], [status_val]
having max([rn]) = 1;
Find a demo here
SELECT COUNT(*)
FROM(
SELECT DISTINCT object_id
FROM object_table ) as row_count, status_val,id,object_id FROM object_table where row_count = 1;
I think you are looking for that
I have a table in the form of :
| ID | COURSE | PASS |
---------------------------
| 1 | 1 | 1 |
| 1 | 2 | 1 |
| 1 | 3 | 1 |
| 1 | 4 | 0 |
| 1 | 5 | 0 |
and I want row in the form:
| ID | FAILED | PASSED |
---------------------------
| 1 | 4,5 | 1,2,3 |
the only i figured is something like this:
select NVL(passed.id, failed.id), passed.test, failed.test from
(select id, listagg(course, ',') within group (order by course) test from table1 where pass = 1 group by id ) passed
full outer join
(select id, listagg(course, ',') within group (order by course) test from table1 where pass = 0 group by id ) failed
on passed.id = failed.id
is there a way to do it in a single query ?
Try
select id,
listagg(case when pass = 1 then course end, ',') within group (order by course) passed,
listagg(case when pass = 0 then course end, ',') within group (order by course) failed
from table1
group by id
Here is a sqlfiddle demo