PDO fetchColumn() and fetchObject() which is better and proper usage - pdo

It's been bugging me, I have a query which returns a single row and I need to get their corresponding column value.
//Retrieve Ticket Information to Database
$r = db_query("SELECT title, description, terms_cond, image, social_status, sched_stat FROM giveaway_table WHERE ticket_id = :ticket_id",
array(
':ticket_id' => $ticket_id
));
There are two ways that I can get data which is, by using fetchColumn() and fetchObject()
fetchObject()
$object = $r->fetchObject();
$ticket_info[] = $object->title;
$ticket_info[] = $object->description;
$ticket_info[] = $object->terms_cond;
$ticket_info[] = $object->image;
$ticket_info[] = $object->social_status;
$ticket_info[] = $object->sched_stat;
fetchColumn()
$title = $r->fetchColumn() //Returns title column value
$description = $r->fetchColumn(1) //Returns description column value
Was wondering, which one is better, or are there any pros and cons about this stuff?
if possible, can you guys also suggest the best way (if there's any) on how to retrieve all columns that's been selected in a query and store it into an array with less line of code.

There are two ways that I can get data which is, by using fetchColumn() and fetchObject()
really? what about fetch()?
There is a PDO tag wiki where you can find everything you need

I don't know pros and cons of using it. In my project I often used fetching as array rather than object. It was more comfortable. But if you make ORM projects then maybe it would be better to use fetchObject and make it your object not a std_class. You could make a contructor that has one parametr which is stdClass and make your object from this class
Answering your other question you can fetch all columns using fetchAll();
Follow this link to learn more about this function http://www.php.net/manual/en/pdostatement.fetchall.php
More about abstract database layer you can find here -> http://www.doctrine-project.org/

Related

CodeIgniter4 Model returning data results

I am starting to dabble in CI4's rc... trying to get a head of the game. I noticed that the Model is completely rewritten.
Going through their documentation, I need some guidance on how to initiate the equivalent DB query builder in CI4.
I was able to leverage return $this->findAll(), etc...
however, need to be able to be able to query w/ complex joins and also be able to return single records etc...
When trying something like
return $this->orderBy('import_date', 'desc')
->findColumn('import_date')
->first();
but getting error:
Call to a member function first() on array
Any help or guidance is appreciated.
Suppose you have a model instantiated as
$userModel = new \App\Models\UserModel;
Now you can use it to get a query builder like.
$builder = $userModel->builder();
Use this builder to query anything for e.g.
$user = $builder->first();
Coming to your error.
return $this->orderBy('import_date', 'desc')
->findColumn('import_date');
findColumn always returns an array or null. So you can't use it as object. Instead you should do following.
return $this->orderBy('import_date', 'desc')->first();

Returning one cell from Codeigniter Query

I want to query a table and only need one cell returned. Right now the only way I can think to do it is:
$query = $this->db->query('SELECT id FROM crops WHERE name = "wheat"');
if ($query->num_rows() > 0) {
$row = $query->row();
$crop_id = $row->id;
}
What I want is, since I'm select 'id' anyway, for that to be the result. IE: $query = 'cropId'.
Any ideas? Is this even possible?
Of course it's possible. Just use AND in your query:
$query = $this->db->query('SELECT id FROM crops WHERE name = "wheat" AND id = {$cropId}');
Or you could use the raw power of the provided Active Record class:
$this->db->select('id');
$this->db->from('crops');
$this->db->where('name','wheat');
$this->db->where('id',$cropId);
$query = $this->db->get();
If you just want the cropId from the whole column:
foreach ($query->result()->id as $cropId)
{
echo $cropId;
}
Try this out, I'm not sure if it will work:
$cropId = $query->first_row()->id;
Note that you want to swap your quotes around: use " for your PHP strings, and ' for your SQL strings. First of all, it would not be compatible with PostgreSQL and other database systems that check such things.
Otherwise, as Christopher told you, you can test the crop identifier in your query. Only if you define a string between '...' in PHP, the variables are not going to be replaced in the strings. So he showed the wrong PHP code.
"SELECT ... $somevar ..."
will work better.
Yet, there is a security issue in writing such strings: it is very dangerous because $somevar could represent some additional SQL and completely transform your SELECT in something that you do not even want to think about. Therefore, the Active Record as mentioned by Christopher is a lot safer.

Check if an existing value is in a database

I was wondering how I would go about checking to see if a table contains a value in a certain column.
I need to check if the column 'e-mail' contains an e-mail someone is trying to register with, and if something exists, do nothing, however, if nothing exists, insert the data into the database.
All I need to do is check if the e-mail column contains the value the user is registering with.
I'm using the RedBeanPHP ORM, I can do this without using it but I need to use that for program guidelines.
I've tried finding them but if they don't exist it returns an error within the redbean PHP file. Here's the error:Fatal error: Call to a member function find() on a non-object in /home/aeterna/www/user/rb.php on line 2433
Here's the code that I'm using when trying this:
function searchDatabase($email) {
return R::findOne('users', 'email LIKE "' . $email . '"');
}
My approach on the function would be
function searchDatabase($email) {
$data = array('email' => $email);
$user = R::findOne('users', 'email LIKE :email, $data);
if (!empty($user)) {
// do stuff here
} // end if
} // end function
It's a bit more clean and in your function
Seems like you are not connected to a database.
Have you done R::setup() before R::find()?
RedBeanPHP raises this error if it can't find the R::$redbean instance, the facade static functions just route calls to the $redbean object (to hide all object oriented fuzzyness for people who dont like that sort of thing).
However you need to bootstrap the facade using R::setup(). Normally you can start using RB with just two lines:
require('rb.php'); //cant make this any simpler :(
R::setup(); //this could be done in rb.php but people would not like that ;)
//and then go...
R::find( ... );
I recommend to check whether the $redbean object is available or whether for some reason the code flow has skipped the R::setup() boostrap method.
Edited to account for your updated question:
According to the error message, the error is happening inside the function find() in rb.php on line 2433. I'm guessing that rb.php is the RedBean package.
Make sure you've included rb.php in your script and set up your database, according to the instructions in the RedBean Manual.
As a starting point, look at what it's trying to do on line 2433 in rb.php. It appears to be calling a method on an invalid object. Figure out where that object is being created and why it's invalid. Maybe the find function was supplied with bad parameters.
Feel free to update your question by pasting the entirety of the find() function in rb.php and please indicate which line is 2433. If the function is too lengthy, you can paste it on a site like pastebin.com and link to it from here.
Your error sounds like you haven't done R::setup() yet.
My approach to performing the check you want would be something like this:
$count = count(R::find('users', 'email LIKE :email', array(':email' => $email)));
if($count === 0)
{
$user = R::dispense('users');
$user->name = $name;
$user->email = $email;
$user->dob = $dob;
R::store($user);
}
I don't know if it is this basic or not, but with SQL (using PHP for variables), a query could look like
$lookup = 'customerID';
$result = mysql_fetch_array(mysql_query("SELECT columnName IN tableName WHERE id='".$lookup."' LIMIT 1"));
$exists = is_null($result['columnName'])?false:true;
If you're just trying to find a single value in a database, you should always limit your result to 1, that way, if it is found in the first record, your query will stop.
Hope this helps

Does CDbcommand method queryAll() in yii return indexed entries only?

I am trying to retrieve data from a simple mySql table tbl_u_type which has just two columns, 'tid' and 'type'.
I want to use a direct SQL query instead of the Model logic. I used:
$command = Yii::app()->db->createCommand();
$userArray = $command->select('type')->from('tbl_u_type')->queryAll();
return $userArray;
But in the dropdown list it automatically shows an index number along with the required entry. Is there any way I can avoid the index number?
To make an array of data usable in a dropdown, use the CHtml::listData() method. If I understand the question right, this should get you going. Something like this:
$command = Yii::app()->db->createCommand();
$userArray = $command->select('tid, type')->from('tbl_u_type')->queryAll();
echo CHtml::dropdownlist('my_dropdown','',CHtml::listData($userArray,'tid','type'));
You can also do this with the Model if you have one set up for the tbl_u_type table:
$users = UType::model()->findall();
echo CHtml::dropdownlist('my_dropdown','',CHtml::listData($users ,'tid','type'));
I hope that gets you on the right track. I didn't test my code here, as usual, so watch out for that. ;) Good luck!

drupal bootstrap script: how to get list of all nodes of type x?

I create a custom import and export, at the moment as an external script (via bootstrap), i plan to create a module in a more generic fashion lateron.
I am building a frontend for nagios and for our host management and nagios configuration btw. Maybe it might become useful for other environments (networkmanagement)
Now i need to know how to get list of all nodes of type x?
I want to avoid direct SQL.
A suggestion i got was to make an rss and parse it
but i acess the drupal db a dozen times to extract various nodes, so it feels strange to do a web request for one thing
So what i am looking for as newbie drupal dev is just a pointer to basic search module api for this task
TIA
florian
Why do you want to avoid using SQL?
If you want to get info about what's in your db, like all the nodes of type x, the only way to get it, is through a SQL query, unless you have the data extracted already.
A query like
db_query("SELECT title, nid FROM {node} WHERE type = 'x';");
shouldn't be the thing that ruins your performance.
Edit:
The link you provided is a from Drupal 7, so you have to be be careful reading this. The reason is that in Drupal 7 it is not only possible to use db_query which basically is wrapper for the php functions mysql_query, pg_query. It's a bit different and using it, you wont have to use db_specific code. Anyways new in Drupal 7 is something that is a bit like an ORM. I haven't read about it in detail, but the idea is that you can build a query using commands on an object. This is probably what you are after. However, Drupal 7 is not ready at all for production sites. There are still a lot of critical issues and security issues. So this wont be a possibility for quite some time.
Edit 2:
If you want to get the node title and body, this is what you should do:
$type = 'x';
$query = db_query("SELECT r.nid, r.title, r.body FROM {node} AS n
LEFT JOIN {node_revisions} AS r ON r.nid = n.nid
WHERE type = '%s';", array($type));
$nodes = array();
while ($node = db_fetch_object($query)) {
$nodes[$node->nid] = $node;
}
You can use db_fetch_array instead of db_fetch_object` if you want to extract arrays instead of objects from the db.
This is a pretty old question, but for anyone coming across this page now, in Drupal 7.x best practise is to use dynamic queries.
So if you wanted to select all the nodes of type x, you could do the following:
$articles = db_select('node')
->fields('node', array('nid', 'title'))
->condition('type', 'x', '=')
->execute()
->fetchAllKeyed();
The $articles variable should then be an array of all x type nodes, keyed by nid with the arrays corresponding value set to the node title. Hope that can help.
Views is generally how you create database queries without writing them in Drupal, but this query is so simple I'm not sure it's worth the overhead of learning views, barely 5 lines after you've bootstrapped Drupal:
$nodes = array();
$results = db_query("SELECT nid FROM {node} WHERE type = '%s'", $type);
while ($result = db_fetch_object($result)) {
$nodes[] = node_load($result->nid);
}
Gotta use SQL do to this.
http://api.drupal.org/api/function/node_get_types/6
Node counts =
$node_types = node_get_types();
$type_count = array();
foreach ($node_types as $type) {
$result = db_fetch_object(db_query('SELECT count(nid) AS node_count FROM {node} WHERE type = "%s"'), $type);
$type_count[$type] = $result['count(nid)'];
}
print_r($type_count);
Nodes and their type:
$node_types = node_get_types();
$nodes = array();
foreach ($node_types as $type) {
$result = db_query('SELECT nid, title FROM {node} WHERE type = "%s"'), $type);
while ($node = db_fetch_object($result)) {
$nodes[] = array('Type' => $type, 'Title' => $node->title);
}
}
print_r($nodes);
Something like that. I am eating lunch so I didn't test that but I have done this before so it should work. Drupal 6.
The migrate module may be of interest to you. It also supports drush so you can script things fairly easily.