I'm trying to understand if the above question is possible. I've been conceptually thinking about it, and basically what I'm looking to do is:
Specify keywords that may appear in a title. Lets use the two terms "Portfolio" and "Mike"
I'm hoping to generate a query that will allow for me to search for when Portfolio is contained within a title, or Mike. These two titles need not to be together.
For instance, if I have a title dubbed: "Portfolio A" and another title "Mike's favorite" I'd like both of these titles to be returned.
The issue I've encountered with using a LIKE statement is the following:
WHERE 1=1
and rpt_title LIKE ''%'+#report_title+'%'''
If I were to input: 'Portfolio,Mike' it would search for the occurrence of just that within a title.
EDIT: I should have been a bit more clear. I believe it's necessary for me to input my variable as 'Portfolio, Mike' in order for it to find the multiple values. Is this possible?
I'm assuming you could maybe use a charindex with a substring and a replace?
Yep, multiple Like statements with OR will work just fine -- just make sure you use the correct parentheses:
SELECT ...
FROM ...
WHERE 1=1
and (rpt_title LIKE '%Portfolio%'
or rpt_title LIKE '%Mike%')
However, I might suggest you look into using a full-text search.
http://msdn.microsoft.com/en-us/library/ms142571.aspx
I can propose a solution where you could specify any number of masks, without using multiple LIKE -
DECLARE #temp TABLE (st VARCHAR(100))
INSERT INTO #temp (st)
VALUES ('Portfolio photo'),('- Mike'),('blank'),('else'),('est')
DECLARE #delims VARCHAR(30)
SELECT #delims = '|Portfolio|Mike|' -- %Portfolio% OR %Mike% OR etc.
SELECT t.st
FROM #temp t
CROSS JOIN (
SELECT substr =
SUBSTRING(
#delims,
number + 1,
CHARINDEX('|', #delims, number + 1) - number - 1)
FROM [master].dbo.spt_values n
WHERE [type] = N'P'
AND number <= LEN(#delims) - 1
AND SUBSTRING(#delims, number, 1) = '|'
) s
WHERE t.st LIKE '%' + s.substr + '%'
Related
In my database I am selecting from a field containing Dillon Brookfield. I tried searching for brookfield with the following statement thinking LIKE would select the data, but it didn't work.
SELECT *
FROM [Reports]
WHERE ([VisitorName] LIKE '%' + #VisitorName + '%'
OR [PlateNumber] = #PlateNumber)
I record people who have been banned from a property along with their plate (if known), but if their name is not put in exactly it doesn't return the value. What would be the best way to return similar results?
This is more like a comment, but there is code inside and the comment only allows one #.
What data type is your #PlateNumber? Is it CHAR or VARCHAR? it can make a difference. Like these tests.
DECLARE #char NCHAR(20) = 'space';
SELECT '%'+#char+ '%',IIF('space' Like '%'+#char+ '%', 1,0);
DECLARE #varchar NVARCHAR(20) = 'space';
SELECT '%'+#varchar+ '%',IIF('space' Like '%'+#varchar+ '%', 1,0);
The first SELECT will give you
'%space %',0. -- there will be 15 blank character between space and %
The second SELECT will give you
'%space%', 1.
Create fulltext index. Search names/addresses and other similar fields with fulltext search - it'll be faster and you can find all names - Dillon Brookfield vs Brookfield Dillon.
SQL SERVER 2005
SQL Sorting :
Datatype varchar
Should sort by
1.aaaa
5.xx
11.bbbbbb
12
15.
how can i get this sorting order
Wrong
1.aaaa
11.bbbbbb
12
15.
5.xx
On Oracle, this would work.
SELECT
*
FROM
table
ORDER BY
to_number(regexp_substr(COLUMN,'^[0-9]+')),
regexp_substr(column,'\..*');
You could do this by calculating a column based on what's on the left hand side of the period('.').
However this method will be very difficult to make robust enough to use in a production system, unless you can make a lot of assertions about the content of the strings.
Also handling strings without periods could cause some grief
with r as (
select '1.aaaa' as string
union select '5.xx'
union select '11.bbbbbb'
union select '12'
union select '15.' )
select *
from r
order by
CONVERT(int, left(r.string, case when ( CHARINDEX('.', r.string)-1 < 1)
then LEN(r.string)
else CHARINDEX('.', r.string)-1 end )),
r.string
If all the entries have this form, you could split them into two parts and sort be these, for example like this:
ORDER BY
CONVERT(INT, SUBSTRING(fieldname, 1, CHARINDEX('.', fieldname))),
SUBSTRING(fieldname, CHARINDEX('.', fieldname) + 1, LEN(fieldname))
This should do a numeric sort on the part before the . and an alphanumeric sort for the part after the ., but may need some tuning, as I haven't actually tried it.
Another way (and faster) might be to create computed columns that contain the part before the . and after the . and sort by them.
A third way (if you can't create computed columns) could be to create a view over the table that has two additional columns with the respective parts of the field and then do the select on that view.
I have declare #a varchar(100) = 'abc bcd cde def'. What I need is to select from a table where a column is like 'abc' or 'bcd' or 'cde' or 'def'. I can use a split function and a while to get what I want, but somewhere I saw a smart solution using replace or something similar and I just can't remember it.
I know I can use an xml variable, and parse it that way. However, the value is part of a large procedure, and the best way for me is to use it in string form.
I know I can solve this by building a dynamic sql query, but that is not an option in the domain I'm working in.
Damn, I just can remember the solution. Its a hack, a little dirty trick that do the job.
Anyways, I ll use the code bellow (Im over SQL Server 2008), is it a good idea? I prefer it over the dirty split. Is it more performatic?
declare #w varchar(100) = 'some word'
declare #f xml
set #f = '<word>' + replace(#w, ' ', '</word><word>') + '</word>'
select
template.item.value('.', 'varchar(100)') as word
from #f.nodes('/word') template(item)
Use a function to split the individual items into a table, one record per item. Then you simply join to that table.
insert into #FilterTable (filters)
select Items from dbo.Split(#YourFilterString)
select *
from YourTable yt
join #FilterTable f on f.filters = yt.YourColumn
Of course my example is using equality. It gets more complicated if you truly intend to use "like" with wildcards.
In tsql you can use a pattern col like '[abcd]'
http://msdn.microsoft.com/en-us/library/ms179859.aspx
For matching multiple words (not letter) and without dynamic SQL, you'll have to get the values into a temp table. For a split function try this page http://www.sommarskog.se/arrays-in-sql-2005.html#iterative and look at the List of Strings function iter_charlist_to_table.
Or maybe you are thinking of this little trick Parameterize an SQL IN clause from the SO CEO.
for 4 sections max
WHERE
PARSENAME(REPLACE(#a, ' ', '.'), 1) = 'xxx'
OR
PARSENAME(REPLACE(#a, ' ', '.'), 2) = 'xxx'
OR
PARSENAME(REPLACE(#a, ' ', '.'), 3) = 'xxx'
OR
PARSENAME(REPLACE(#a, ' ', '.'), 4) = 'xxx'
I am trying to create a query using a db on OpenOffice where a string is entered in the query, and all permutations of the string are searched in the database and the matches are displayed. My database has fields for a word and its definition, so if I am looking for GOOD I will get its definition as well as the definition for DOG.
You'll need a third column as well. In this column you'll have the word - but with the letters sorted in alphabetical order. For example, you'll have the word APPLE and in the next column the word AELPP.
You would sort the word your looking for - and run a some SQL code like
WHERE sorted_words = 'my_sorted_word'
for the word apple, you would get something like this:
unsorted sorted
AELPP APPLE
AELPP PEPLA
AELPP APPEL
Now, you also wanted - correct me if I'm wrong, but you want all the words that can be made with **any combination ** of the letters, meaning APPLE also returns words like LEAP and PEA.
To do this, you would have to use some programming language - you would have to write a function that preformed the above recursively, for example - for the word AELLP you have
ELLP
ALLP
AELP
and so forth.. (each time subtracting one letter in every combination, and then two letters in every combination possible ect..)
Basically, you can't easily do permutations in single SQL statement. You can easily do them in another language though, for example here's how to do it in C#: http://msdn.microsoft.com/en-us/magazine/cc163513.aspx
Ok, corrected version that I think handles all situations. This will work in MS SQL Server, so you may need to adjust it for your RDBMS as far as using the local table and the REPLICATE function. It assumes a passed parameter called #search_string. Also, since it's using VARCHAR instead of NVARCHAR, if you're using extended characters be sure to change that.
One last point that I'm just thinking of now... it will allow duplication of letters. For example, "GOOD" would find "DODO" even though there is only one "D" in "GOOD". It will NOT find words of greater length than your original word though. In other words, while it would find "DODO", it wouldn't find "DODODO". Maybe this will give you a starting point to work from though depending on your exact requirements.
DECLARE #search_table TABLE (search_string VARCHAR(4000))
DECLARE #i INT
SET #i = 1
WHILE (#i <= LEN(#search_string))
BEGIN
INSERT INTO #search_table (search_string)
VALUES (REPLICATE('[' + #search_string + ']', #i)
SET #i = #i + 1
END
SELECT
word,
definition
FROM
My_Words
INNER JOIN #search_table ST ON W.word LIKE ST.search_string
The original query before my edit, just to have it here:
SELECT
word,
definition
FROM
My_Words
WHERE
word LIKE REPLICATE('[' + #search_string + ']', LEN(#search_string))
maybe this can help:
Suppose you have a auxiliary Numbers table with integer numbers.
DECLARE #s VARCHAR(5);
SET #s = 'ABCDE';
WITH Subsets AS (
SELECT CAST(SUBSTRING(#s, Number, 1) AS VARCHAR(5)) AS Token,
CAST('.'+CAST(Number AS CHAR(1))+'.' AS VARCHAR(11)) AS Permutation,
CAST(1 AS INT) AS Iteration
FROM dbo.Numbers WHERE Number BETWEEN 1 AND 5
UNION ALL
SELECT CAST(Token+SUBSTRING(#s, Number, 1) AS VARCHAR(5)) AS Token,
CAST(Permutation+CAST(Number AS CHAR(1))+'.' AS VARCHAR(11)) AS
Permutation,
s.Iteration + 1 AS Iteration
FROM Subsets s JOIN dbo.Numbers n ON s.Permutation NOT LIKE
'%.'+CAST(Number AS CHAR(1))+'.%' AND s.Iteration < 5 AND Number
BETWEEN 1 AND 5
--AND s.Iteration = (SELECT MAX(Iteration) FROM Subsets)
)
SELECT * FROM Subsets
WHERE Iteration = 5
ORDER BY Permutation
Token Permutation Iteration
----- ----------- -----------
ABCDE .1.2.3.4.5. 5
ABCED .1.2.3.5.4. 5
ABDCE .1.2.4.3.5. 5
(snip)
EDBCA .5.4.2.3.1. 5
EDCAB .5.4.3.1.2. 5
EDCBA .5.4.3.2.1. 5
(120 row(s) affected)
In my database (SQL 2005) I have a field which holds a comment but in the comment I have an id and I would like to strip out just the id, and IF possible convert it to an int:
activation successful of id 1010101
The line above is the exact structure of the data in the db field.
And no I don't want to do this in the code of the application, I actually don't want to touch it, just in case you were wondering ;-)
This should do the trick:
SELECT SUBSTRING(column, PATINDEX('%[0-9]%', column), 999)
FROM table
Based on your sample data, this that there is only one occurence of an integer in the string and that it is at the end.
I don't have a means to test it at the moment, but:
select convert(int, substring(fieldName, len('activation successful of id '), len(fieldName) - len('activation successful of id '))) from tableName
Would you be open to writing a bit of code? One option, create a CLR User Defined function, then use Regex. You can find more details here. This will handle complex strings.
If your above line is always formatted as 'activation successful of id #######', with your number at the end of the field, then:
declare #myColumn varchar(100)
set #myColumn = 'activation successful of id 1010102'
SELECT
#myColumn as [OriginalColumn]
, CONVERT(int, REVERSE(LEFT(REVERSE(#myColumn), CHARINDEX(' ', REVERSE(#myColumn))))) as [DesiredColumn]
Will give you:
OriginalColumn DesiredColumn
---------------------------------------- -------------
activation successful of id 1010102 1010102
(1 row(s) affected)
select cast(right(column_name,charindex(' ',reverse(column_name))) as int)
CAST(REVERSE(LEFT(REVERSE(#Test),CHARINDEX(' ',REVERSE(#Test))-1)) AS INTEGER)
-- Test table, you will probably use some query
DECLARE #testTable TABLE(comment VARCHAR(255))
INSERT INTO #testTable(comment)
VALUES ('activation successful of id 1010101')
-- Use Charindex to find "id " then isolate the numeric part
-- Finally check to make sure the number is numeric before converting
SELECT CASE WHEN ISNUMERIC(JUSTNUMBER)=1 THEN CAST(JUSTNUMBER AS INTEGER) ELSE -1 END
FROM (
select right(comment, len(comment) - charindex('id ', comment)-2) as justnumber
from #testtable) TT
I would also add that this approach is more set based and hence more efficient for a bunch of data values. But it is super easy to do it just for one value as a variable. Instead of using the column comment you can use a variable like #chvComment.
If the comment string is EXACTLY like that you can use replace.
select replace(comment_col, 'activation successful of id ', '') as id from ....
It almost certainly won't be though - what about unsuccessful Activations?
You might end up with nested replace statements
select replace(replace(comment_col, 'activation not successful of id ', ''), 'activation successful of id ', '') as id from ....
[sorry can't tell from this edit screen if that's entirely valid sql]
That starts to get messy; you might consider creating a function and putting the replace statements in that.
If this is a one off job, it won't really matter. You could also use a regex, but that's quite slow (and in any case mean you now have 2 problems).