I have table with about 100000 records.I need update same fields like this.
For example this is my table
id name
1 sss
2 bbb
3 ccc
4 avg
5 bbb
6 bbb
7 sss
8 mmm
9 avg
After executing script I need get
id name
1 sss
2 bbb
3 ccc
4 avg
5 bbb-5
6 bbb-6
7 sss-7
8 mmm
9 avg-9
How can I do that?
By using CTE
WITH greaterRecord
AS
(
SELECT id,
name,
ROW_NUMBER() OVER(PARTITION BY name ORDER BY id) RN
FROM TableName
)
UPDATE greaterRecord
SET name = name + '-' + CAST(id AS VARCHAR(10))
WHERE RN > 1
SQLFiddle Demo
This is the common query that works on most RDBMS
UPDATE a
SET a.Name = a.Name + '-' + CAST(ID AS VARCHAR(10))
FROM tableName a
LEFT JOIN
(
SELECT MIN(ID) min_ID, name
FROM tableName
GROUP BY name
) b ON a.name = b.name AND
a.ID = b.Min_ID
WHERE b.Name IS NULL
SQLFiddle Demo
OUTPUT after the update statement has been executed
╔════╦═══════╗
║ ID ║ NAME ║
╠════╬═══════╣
║ 1 ║ sss ║
║ 2 ║ bbb ║
║ 3 ║ ccc ║
║ 4 ║ avg ║
║ 5 ║ bbb-5 ║
║ 6 ║ bbb-6 ║
║ 7 ║ sss-7 ║
║ 8 ║ mmm ║
║ 9 ║ avg-9 ║
╚════╩═══════╝
This should do:
;WITH CTE AS
(
SELECT id,
name,
RN = ROW_NUMBER() OVER(PARTITION BY name ORDER BY id)
FROM YourTable
)
UPDATE CTE
SET name = name + '-' + CAST(id AS VARCHAR(8))
WHERE RN > 1
Related
I have a table like below :
Id Price1 Price2
3 30 20
3 40 20
3 50 20
I want to write a query to get a below result :
Desired Ouput :
RowNo Id Price
1 3 20
2 3 30
3 3 40
4 3 50
Please help!!
Use Cross apply to unpivot the data and generate row number
SELECT Row_number()OVER(ORDER BY price) AS Rowno,*
FROM (SELECT DISTINCT Id,
Price
FROM (VALUES (3,30,20),
(3,40,20),
(3,50,20) ) tc ( Id, Price1, Price2)
CROSS apply (VALUES (Price1),
(Price2)) Cs (Price)) A
Result :
╔═══════╦════╦═══════╗
║ Rowno ║ Id ║ Price ║
╠═══════╬════╬═══════╣
║ 1 ║ 3 ║ 20 ║
║ 2 ║ 3 ║ 30 ║
║ 3 ║ 3 ║ 40 ║
║ 4 ║ 3 ║ 50 ║
╚═══════╩════╩═══════╝
You can use union to combine the rows (so duplicates are removed). And then row_number() to calculate rownum:
select row_number() over (order by price) as rownum, id, price
from ((select id, price1 as price from t) union
(select id, price2 from t
) t
order by price;
How sort this
a 1 15
a 2 3
a 3 34
b 1 55
b 2 44
b 3 8
to (by third column sum):
b 1 55
b 2 44
b 3 8
a 1 15
a 2 3
a 3 34
since (55+44+8) > (15+3+34)
If you are using SQL Server/Oracle/Postgresql you could use windowed SUM:
SELECT *
FROM tab
ORDER BY SUM(col3) OVER(PARTITION BY col) DESC, col2
LiveDemo
Output:
╔═════╦══════╦══════╗
║ col ║ col2 ║ col3 ║
╠═════╬══════╬══════╣
║ b ║ 1 ║ 55 ║
║ b ║ 2 ║ 44 ║
║ b ║ 3 ║ 8 ║
║ a ║ 1 ║ 15 ║
║ a ║ 2 ║ 3 ║
║ a ║ 3 ║ 34 ║
╚═════╩══════╩══════╝
You can do this using ANSI standard window functions. I prefer to use a subquery although this is not strictly necessary:
select col1, col2, col3
from (select t.*, sum(col3) over (partition by col1) as sumcol3
from t
) t
order by sumcol3 desc, col3 desc;
...and an example how to do it without windowing functions, in for example MySQL (but also in just about any other standard SQL version)
SELECT m.col1, m.col2, m.col3
FROM myTable m
JOIN (
SELECT col1, SUM(col3) groupsum FROM myTable GROUP BY col1
) z ON m.col1 = z.col1
ORDER BY z.groupsum DESC, col2;
Basically, calculate the group sum in a subquery and join/order the results by the group's sum descending.
An SQLfiddle to test with.
As we all know general sorting is using order by. The sort I want to perform is different. I want the smallest length value in middle of table n the largest ones in top and bottom of it. One half should be descending and another half should be ascending. Can you guys help. It was an interview question.
This is one way:
;WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER(ORDER BY LEN(YourColumn))
FROM dbo.YourTable
)
SELECT *
FROM CTE
ORDER BY RN%2, (CASE WHEN RN%2 = 0 THEN 1 ELSE -1 END)*RN DESC
Test Data
DECLARE #Table TABLE
(ID INT, Value VARCHAR(10))
INSERT INTO #Table VALUES
(1 , 'A'),
(2 , 'AB'),
(3 , 'ABC'),
(4 , 'ABCD'),
(5 , 'ABCDE'),
(6 , 'ABCDEF'),
(7 , 'ABCDEFG'),
(8 , 'ABCDEFGI'),
(9 , 'ABCDEFGIJ'),
(10 ,'ABCDEFGIJK')
Query
;WITH CTE AS (
SELECT *
,NTILE(2) OVER (ORDER BY LEN(Value) DESC) rn
FROM #Table )
SELECT *
FROM CTE
ORDER BY CASE WHEN rn = 1 THEN LEN(Value) END DESC
,CASE WHEN rn = 2 THEN LEN(Value) END ASC
Result
╔════╦════════════╦════╗
║ ID ║ Value ║ rn ║
╠════╬════════════╬════╣
║ 10 ║ ABCDEFGIJK ║ 1 ║
║ 9 ║ ABCDEFGIJ ║ 1 ║
║ 8 ║ ABCDEFGI ║ 1 ║
║ 7 ║ ABCDEFG ║ 1 ║
║ 6 ║ ABCDEF ║ 1 ║
║ 1 ║ A ║ 2 ║
║ 2 ║ AB ║ 2 ║
║ 3 ║ ABC ║ 2 ║
║ 4 ║ ABCD ║ 2 ║
║ 5 ║ ABCDE ║ 2 ║
╚════╩════════════╩════╝
Here's a short approach that would ge t you started:
WITH cte AS
(
SELECT TOP 1000 number
FROM master..spt_values
WHERE type = 'P' and number >0
)
SELECT number, row_number() OVER(ORDER BY CASE WHEN number %2 = 1 THEN number ELSE -(number) END) pos
FROM cte
I am trying to add a Group column to a data set based on some criteria. For a simple example:
╔════╦══════╗
║ ID ║ DATA ║
╠════╬══════╣
║ 1 ║ 12 ║
║ 2 ║ 20 ║
║ 3 ║ 3 ║
║ 4 ║ 55 ║
║ 5 ║ 11 ║
╚════╩══════╝
Let's say our criteria is that the Data should be greater than 10. Then the result should be similar to:
╔════╦══════╦═══════╗
║ ID ║ DATA ║ GROUP ║
╠════╬══════╬═══════╣
║ 1 ║ 12 ║ 1 ║
║ 2 ║ 20 ║ 1 ║
║ 3 ║ 3 ║ 2 ║
║ 4 ║ 55 ║ 3 ║
║ 5 ║ 11 ║ 3 ║
╚════╩══════╩═══════╝
So, all the rows that satisfied the criteria until an exception to the criteria occurred became part of a group. The numbering of the group doesn't necessarily need to follow this pattern, I just felt like this was a logical/simple numbering to explain the solution I am looking for.
You can calculate the group identifier by finding each row where data <= 10. Then, the group identifier is simply the number of rows where that condition is true, before the given row.
select t.*,
(select count(*)
from t t2
where t2.id <= t.id and
t2.data <= 10
) as groupId
from t;
SQL Server 2012 has cumulative sum syntax. The statement would be simpler in that database:
select t.*,
sum(case when t2.data <= 10) over (order by id) as groupId
from t;
EDIT:
The above does not take into account that the values less than 10 are in their own group. The logic above is that they start a new group.
The following assigns a group id with this constraint:
select t.*,
((select 2*count(*)
from t t2
where t2.id < t.id and
t2.data <= 10
) + (case when t.id <= 10 then 1 else 0 end)
) as groupId
from t;
This can be done easily with a recursive query:
;WITH CTE
AS (SELECT *,
1 AS [GROUP]
FROM TABLEB
WHERE ID = 1
UNION ALL
SELECT T1.ID,
T1.DATA,
CASE
WHEN T1.DATA < 10 THEN T2.[GROUP] + 1
ELSE T2.[GROUP]
END [GROUP]
FROM TABLEB T1
INNER JOIN CTE T2
ON T1.ID = T2.ID + 1)
SELECT *
FROM CTE
A working example can be found on SQL Fiddle.
Good Luck!
I have one table (tblproduct) with fields: dept, product, qty.
sample data below:
dept product qty
IT A 2
IT B 1
PU C 4
SAL D 1
SER D 2
SER A 4
I want to create stored pro in sql server with the result below:
product qty remark
A 6 IT=2,SER=4
B 1 IT=1
C 4 PU=4
D 3 SAL=1,SER=2
this is my stored pro
select product,
sum(qty)
from tblproduct
group by product
order by product
Pls. any help. thanks.
SELECT
[product], SUM(qty) Total_Qty,
STUFF(
(SELECT ',' + dept + '=' + CAST(qty AS VARCHAR(10))
FROM TableName
WHERE [product] = a.[product]
FOR XML PATH (''))
, 1, 1, '') AS Remark
FROM TableName AS a
GROUP BY [product]
SQLFiddle Demo
OUTPUT
╔═════════╦═══════════╦═════════════╗
║ PRODUCT ║ TOTAL_QTY ║ REMARK ║
╠═════════╬═══════════╬═════════════╣
║ A ║ 6 ║ IT=2,SER=4 ║
║ B ║ 1 ║ IT=1 ║
║ C ║ 4 ║ PU=4 ║
║ D ║ 3 ║ SAL=1,SER=2 ║
╚═════════╩═══════════╩═════════════╝
Please try:
SELECT product, SUM(qty) Qty,
STUFF(
(SELECT ','+b.dept+'='+CAST(qty as nvarchar(10))
FROM YourTable b where b.product=a.product
FOR XML PATH(''),type).value('.','nvarchar(max)'), 1, 1, '')
from YourTable a
group by product