I have two tables tables, each with primary keys for different people and the contact dates in each category.I am trying to find the most recent contact date for each person, regardless of what table its in. For example:
CustomerService columns: CustomerKey, DateContacted
CustomerOutreach columns: CustomerKey, DateContacted
And I'm just trying to find the very latest date for each person.
Use something like this.
You need to combine the two tables. You can do this by a union. There will be duplicates, but you just group by the customerKey and then find the Max DateContacted
SELECT * INTO #TEMP FROM (
SELECT
CustomerKey
, DateContacted
FROM CustomerService CS
UNION
SELECT
CustomerKey
, DateContacted
FROM CustomerOutreach CS
)
SELECT
CustomerKey
, MAX(DateContacted)
FROM #TEMP
GROUP BY
CustomerKey
Join your tables on primary keys and make a conditional projection.
Select cs.CustomerKey,
CASE WHEN cs.DateContacted <= co.DateContacted
THEN co.DateContacted
ELSE cs.DateContacted END
from CustomerService cs inner join CustomerOutreach co
on cs.CustomerKey = co.CustomerKey
I would do something like this.
Select b.customerKey, b.dateContacted
from (
select a.customerKey, a.DateContacted, Row_Number() over (Partition by customerKey order by DateContacted desc) as RN
from (
Select c.customerKey,
case when (s.DateContacted > o.dateContacted) then s.dateContacted else o.datecontacted end as DateContacted
from Customer c
left outer join customerService s on c.customerKey = s.customerKey
left outer join customerOutreach o on c.customerKey = s.customerKey
where s.customerKey is not null or o.customerKey is not null
)a
)b
where b.RN = 1
This solution should take care of preventing the case of having duplicates if both tables have the same max DateContacted.
http://sqlfiddle.com/#!3/ca968/1
Related
I am writing a Redshift query which require use of multiple case statements.
Pretext:
Customers can associated with more than one organizations like, sweet or salt etc.
Ask :
We have to check that customers associated with 'SWEETS' organization are picked first, if no affiliation with 'SWEETS' is available , than we have to take id of that organization where flag = 1.
I have to use a case statement in redshift to derive the result.
There are three different tables, customer table, organization table and 3 table that determines how customers are associated with organization.
![enter image description here][1]
Code that I have tried is below , but after executing this , I am still getting the two organization ids, instead of one id which should be of sweet org.
SELECT customer_id
, organization_id
FROM customer_details AS customer
LEFT JOIN organization AS org
ON customer.customer_id
AND organization_id = CASE WHEN organization_id IN (SELECT organization_id
FROM organization_type
WHERE organization_type = 'SWEET')
THEN organization_id
ELSE org.organization_id END
You can use window functions:
select customer_id, organization_id
from (select c.customer_id, o.organization_id,
row_number() over (partition by o.customer_id order by o.organization_type = 'SWEET' desc) as seqnum
from customer_details c left join
organization o
on c.customer_id = o.organization_id
) co
where seqnum = 1;
I have a table with a list of Client No's, ID etc & there are many Clients with different ID's. I need to pull out the MAX ID No. for each Client, e.g.
ClientNo: 1500 has 3 ID's - the maximum in the ID field is the one I need!
UPDATE: This works:
SELECT MP.ClientID, MP.SequenceID
FROM TABLENAME MP
INNER JOIN (
SELECT ClientID, MAX(SequenceID) SequenceID
FROM TABLENAME
GROUP BY ClientID
) b on MP.ClientID = b.ClientID AND MP.SequenceID = b.SequenceID
BUT....
I need to link the table to many others to pull in other data, where do I insert the left joins to these tables please?
I am assuming you have multiple same client (numbers) with different IDs and for each client (number) you have to get the maximum ID. You may do the following:
select client_number, max(ID) from client group by client_number;
Depending on your need tweak this query.
You may want to do this:
SELECT MP.ClientID, b.DesiredValue
FROM TABLENAME MP
INNER JOIN (
SELECT ClientID, DesiredValue, ROW_NUMBER () OVER (PARTITION BY ClientID order by SequenceID desc) As RecentRN
FROM TABLENAME
) b
on MP.ClientID = b.ClientID AND b.RecentRN = 1
or
SELECT MP.ClientID, b.DesiredValue
FROM TABLENAME MP
INNER JOIN (
SELECT ClientID, DesiredValue,ROW_NUMBER () OVER (PARTITION BY ClientID order by SequenceID desc) As RecentRN
FROM TABLENAME
) b
on MP.ClientID = b.ClientID
Where b.RecentRN = 1
I have 2 tables, Members and Enrollments. Both tables can be joined using primary key Member ID.
I need to write a query which returns all the members in the Members table which don't have a corresponding row in the Enrollments table and vice versa.
This is what I have so far:
IF OBJECT_ID('tempdb..#memberswithoutenrollments') IS NOT NULL
DROP TABLE #memberswithoutenrollments
SELECT m.*
INTO #memberswithoutenrollments
FROM ABC_Members m
LEFT OUTER JOIN ABC_MemEnrollment e ON m.MemberID = MemberID
FULL JOIN is a simple method for comparing lists between two tables:
SELECT COALESCE(e.MemberID, m.MemberID),
(CASE WHEN e.MemberID IS NULL THEN 'No Enrollments' ELSE 'No Member' END)
FROM ABC_Members m FULL JOIN
ABC_MemEnrollment e
ON m.MemberID = e.MemberID
WHERE e.MemberID IS NULL OR m.MemberID IS NULL;
But if you have proper foreign key relationships, then you should never have enrollments without members.
You can use NOT IN to your benefit here.
WITH
-- Create a list of all of the matches
in_table AS
(
SELECT
Member_ID
FROM
Enrollments
WHERE
Members.MemberID = Enrollments.Member_ID
),
result_table AS
(
SELECT
*
FROM
Members
-- Grab only the values from members that DO NOT APPEAR in in_table
WHERE
MemberID NOT IN (SELECT DISTINCT FROM in_table)
)
-- Grab all results
SELECT * FROM result_table
I've been trying to remove duplicates using HAVING count(*) > 1, group by, distinct and sub queries but can't get any of these to work..
SELECT UserID, BuildingNo
FROM Staff INNER JOIN TblBuildings ON Staff.StaffID =
TblBuildingsStaffID
GROUP BY TblStaff.User_Code, BuildingNo
What I get is..
StaffID1 | BuildingNo1
StaffID1 | BuildingNo2
StaffID2 | BuildingNo2
StaffID3 | BuildingNo1
StaffID3 | BuildingNo2
I'm trying to get it so it just displays staff with one building number (if they have two regardless of which it shows) like:
StaffID1 | BuildingNo1
StaffID2 | BuildingNo2
StaffID3 | BuildingNo1
It can't be too hard.. I've tried CTE's left joining the building to the staff table, these come up NULL for some reason when I try this
Any help would be great!
Don't group by BuildingNo, then you can use having to filter out the groups you want.
SELECT s.UserID, min(b.BuildingNo) as buildingno
FROM Staff s
JOIN TblBuildings ON s.StaffID = b.TblBuildingsStaffID
GROUP BY s.UserID
having count(distinct b.BuildingNo) = 1;
The min() aggregate is required because buildingno is not part of the group by clause. But as the having() clause only returns those with one building, it doesn't change anything.
If you want to display all staff members, and simply pick one (arbitrary) building, then simply leave out the having condition.
If you want to include staff members without a building you need a left join:
SELECT s.UserID, min(b.BuildingNo) as buildingno
FROM Staff s
LEFT JOIN TblBuildings b ON s.StaffID = t.TblBuildingsStaffID
GROUP BY t.UserID;
Use row partition keyword in your query to avoid duplicacy
WITH CTE AS( SELECT ROW_NUMBER() OVER(PARTITION BY UserID ORDER BY UserID ) AS 'Num',UserID, BuildingNo
FROM Staff INNER JOIN TblBuildings ON Staff.StaffID =
TblBuildingsStaffID
GROUP BY TblStaff.User_Code, BuildingNo)
SELECT * FROM CTE
WHERE Num =1
try this -
SELECT distinct UserID, BuildingNo
FROM Staff INNER JOIN TblBuildings ON Staff.StaffID =
TblBuildingsStaffID
Suppose we have 2 tables :
Patients (ID, name)
Patients_Treatments (PatientID, treatment_code)
I would like the query to retrieve all the patients who received at least all the treatments of patient with id='999999999'
I've tried many combinations and nothing worked, all I've got is patients who got at least one of '9999999999' treatments.
One method uses a self join and comparison in the having clause:
select pt2.patientId
from patient_treatments pt join
patient_treatments pt2
on pt.treatment_code = pt2.treatment_code and pt.patientid <> pt2.patientid
where pt.id = '999999999'
group by pt2.patientId
having count(pt2.treatment_code) = (select count(*) from patient_treatments pt where pt.id = '999999999');
Note: this version assumes that there are no duplicates in Patient_Treatments.
If you have duplicates in the data, you can use count(distinct):
having count(distinct pt2.treatment_code) = (select count(distinct pt.treatment_code) from patient_treatments pt where pt.id = '999999999');
The idea is
(1) Select treatment codes belonging to patient "999999999"
(2) Select only treatment records whose treatment code matches one of the treatment codes belonging to patient "999999999"
(3) Group these by patient_id
(4) Use a HAVING statement and COUNT (DISTINCT) to select only those Patient ID's which have the same number of different treatment codes as patient "999999999".
select pt.Patient_ID,count(distinct pt.treatment_code)
from
Patient_treatments pt
inner join
(select distinct treatment_code
from
Patient_treatments pt
where pt.Patient_ID="999999999"
)t1
on t1.treatment_code=pt.treatment_code
where pt.Patient_ID<>"999999999"
group by pt.Patient_ID
having count(distinct pt.treatment_code)=
(select count(distinct treatment_code)
from
Patient_treatments pt
where pt.Patient_ID="999999999"
);
With the following schema, only patient 1 is selected:-
Create table Patient_Treatments
(
Patient_ID varchar(10),
Treatment_code varchar(10)
);
Insert into Patient_Treatments
values
("1","abc"),
("1","def"),
("1","def"),
("1","ghi"),
("2","abc"),
("2","def"),
("2","def"),
("3","ghi"),
("999999999","abc"),
("999999999","def"),
("999999999","ghi"),
("999999999","ghi")
http://sqlfiddle.com/#!9/03a84b