SQL query hourly for each day - sql

Question

I have a question that seems to be quite complex. I needed to know what happens in a session that day, at a certain time.
Briefly I have a table that shows me all sessions of a given area. These sessions have a start date and a start time and an end time.
You can see in this table:
idArea | idSession | startDate | startTime | endTime
1 | 1 | 2013-01-01 | 1900-01-01 09:00:00 | 1900-01-01 12:00:00
1 | 2 | 2013-01-01 | 1900-01-01 14:00:00 | 1900-01-01 15:00:00
1 | 3 | 2013-01-04 | 1900-01-01 09:00:00 | 1900-01-01 13:00:00
1 | 4 | 2013-01-07 | 1900-01-01 10:00:00 | 1900-01-01 12:00:00
1 | 5 | 2013-01-07 | 1900-01-01 13:00:00 | 1900-01-01 18:00:00
1 | 6 | 2013-01-08 | 1900-01-01 10:00:00 | 1900-01-01 12:00:00
Then I also have a table that shows me all hours interspersed, ie every half hour (I created this table on purpose for this requirement, if someone has a better idea, I can say that I will try to adapt).
idHour | Hour
1 | 1900-01-01 00:00:00
2 | 1900-01-01 00:30:00
3 | 1900-01-01 01:00:00
............................
4 | 1900-01-01 09:00:00
5 | 1900-01-01 09:30:00
6 | 1900-01-01 10:00:00
7 | 1900-01-01 10:30:00
............................
In the end that's what I want to present was this:
startDate | startTime | SessionID
2013-01-01 | 1900-01-01 09:00:00 | 1
2013-01-01 | 1900-01-01 09:30:00 | 1
2013-01-01 | 1900-01-01 10:00:00 | 1
2013-01-01 | 1900-01-01 10:30:00 | 1
2013-01-01 | 1900-01-01 11:00:00 | 1
2013-01-01 | 1900-01-01 11:30:00 | 1
2013-01-01 | 1900-01-01 11:30:00 | 1
2013-01-01 | 1900-01-01 14:00:00 | 1
2013-01-01 | 1900-01-01 14:30:00 | 1
2013-01-01 | 1900-01-01 15:00:00 | 1
This table is only for idSession=1 what I wanted was for all sessions. If there are no sessions for one day can return NULL.
The hard this query or procedure, is that they have to show me all the days of the month when there are sessions for that area.
For this, I already used this query:
;WITH t1 AS
(
SELECT
startDate,
DATEADD(MONTH, DATEDIFF(MONTH, '1900-01-01', startDate), '1900-01-01') firstInMonth,
DATEADD(DAY, -1, DATEADD(MONTH, DATEDIFF(MONTH, '1900-01-01', startDate) + 1, '1900-01-01')) lastInMonth,
COUNT(*) cnt
FROM
#SessionsPerArea
WHERE
idArea = 1
GROUP BY
startDate
), calendar AS
(
SELECT DISTINCT
DATEADD(DAY, c.number, t1.firstInMonth) d
FROM
t1
JOIN
master..spt_values c ON type = 'P'
AND DATEADD(DAY, c.number, t1.firstInMonth) BETWEEN t1.firstInMonth AND t1.lastInMonth
)
SELECT
d date,
cnt Session
FROM
calendar c
LEFT JOIN
t1 ON t1.startDate = c.d
It is quite complex, if anyone has an easy way to do this was excellent.

Answer 1

If I understand correctly, this is simply a join between the calendar table and #SessionPerArea,w ith the right conditions:
select spa.StartDate, c.hour as StartTime, spa.idSession as SessionId
from calendar c join
#SessionsPerArea spa
on c.hour between spa.startTime and spa.EndTime
The join is matching all times between the start and end times in the data, and then returning the values.

Answer 2

I think maybe you simply need an outer join between calendar and #SessionsPerArea...so all the days in the calendar table are returned regardless of a match to the #SessionsPerArea table?