I have arrays of names and images like below
NSArray *names = [[NSArray alloc] initWithObjects:#"naveen", #"kumar",nil];
NSArray *images = [[NSArray alloc] initWithObjects:[UIImage imageNamed:#"1.jpg"], [UIImage imageNamed:#"2.jpg"], nil];
I want to create a dictionary in the following format
list:
item 0 : naveen
1.jpg
item 1: kumar
2.jpg
How can i create this one? Please?
You need to do like this :
NSMutableDictionary *nameImageDict=[NSMutableDictionary new];
for (NSInteger i=0; i<names.count; i++) {
NSArray *array=#[names[i],images[i]];
//or in older compiler 4.3 and below
//NSArray *array=[NSArray arrayWithObjects:[names objectAtIndex:i],[images objectAtIndex:i], nil];
[nameImageDict setObject:array forKey:[NSString stringWithFormat:#"item %d",i]];
}
for key item 0: it will have an array. The array contains name and image.
Like this:
NSDictionary *dictionary = [[NSDictionary alloc] initWithObjects:images andKeys:names];
Like this
NSDictionary * list = [NSDictionary dictionaryWithObjects:images forKeys:names];
Related
I have an NSArray of strings that I want to use as my sort order:
NSArray *permissionTypes = [NSArray arrayWithObjects:#"Read", #"Write", #"Admin", nil];
I then have a NSMutableArray that may or may not have all three of those permissions types, but sometimes it will only be 2, sometimes 1, but I still want it sorted based on my permissionsTypes array.
NSMutableArray *order = [NSMutableArray arrayWithArray:[permissions allKeys]];
How can I always sort my order array correctly based on my using the permissionTypes array as a key?
I would go about this by creating a struct or an object to hold the permission types.
Then you can have...
PermissionType
--------------
Name: Read
Order: 1
PermissionType
--------------
Name: Write
Order: 2
and so on.
Then you only need the actual array of these objects and you can sort by the order value.
[array sortUsingComparator:^NSComparisonResult(PermissionType *obj1, PermissionType *obj2) {
return [obj1.order compare:obj2.order];
}];
This will order the array by the order field.
NSMutableArray *sortDescriptors = [NSMutableArray array];
for (NSString *type in permissionTypes) {
NSSortDescriptor *descriptor = [[[NSSortDescriptor alloc] initWithKey:type ascending:YES] autorelease];
[sortDescriptors addObject:descriptor];
}
sortedArray = [myArray sortedArrayUsingDescriptors:sortDescriptors];
Use whichever sorting method on NSMutableArray you prefer, you will either provide a block or a selector to use for comparing two elements. In that block/selector rather than comparing the two strings passed in directly look each up in your permissionTypes array using indexOfObject: and compare the resulting index values returned.
I suggest you another approuch:
- (void)viewDidLoad
{
[super viewDidLoad];
arrayPermissions = [[NSMutableArray alloc] init];
NSDictionary *dicRead = [NSDictionary dictionaryWithObjectsAndKeys:
#"Read", #"Permission", nil];
NSDictionary *dicWrite = [NSDictionary dictionaryWithObjectsAndKeys:
#"Write", #"Permission", nil];
NSDictionary *dicAdmin = [NSDictionary dictionaryWithObjectsAndKeys:
#"Admin", #"Permission", nil];
NSLog(#"my dicRead = %#", dicRead);
NSLog(#"my dicWrite = %#", dicWrite);
NSLog(#"my dicAdmin = %#", dicAdmin);
[arrayPermissions addObject:dicRead];
[arrayPermissions addObject:dicWrite];
[arrayPermissions addObject:dicAdmin];
NSLog(#"arrayPermissions is: %#", arrayPermissions);
// create a temporary Dict again
NSDictionary *temp =[[NSDictionary alloc]
initWithObjectsAndKeys: arrayPermissions, #"Permission", nil];
// declare one dictionary in header class for global use and called "filteredDict"
self.filteredDict = temp;
self.sortedKeys =[[self.filteredDict allKeys]
sortedArrayUsingSelector:#selector(compare:)];
NSLog(#"sortedKeys is: %i", sortedKeys.count);
NSLog(#"sortedKeys is: %#", sortedKeys);
}
hope help
i have a NSArray created with a Dictionary:
aMapData = [[NSMutableArray alloc] initWithCapacity:sizeof(jsonResponse)];
for (NSMutableDictionary *dict in jsonResponse) {
NSDictionary *row = [NSDictionary dictionaryWithObjectsAndKeys:[dict objectForKey:#"pID"], #"pID", [dict objectForKey:#"Address"], #"Address", nil];
[aMapData addObject:row];
}
It has about 100 rows.
I want to get the pID column, is the only option the iteration and:
[aMapData objectAtIndex:0]
?
Thank you in advance!
I found it, is not necessary an array:
NSArray *idPath = [aMapData valueForKey:#"pID"];
Yes. Otherwise you have to store each column in a separate array.
pID = [[NSMutableArray alloc] init];
address = [[NSMutableArray alloc] init];
for (NSMutableDictionary *dict in jsonResponse) {
[pID addObject:[dict objectForKey:#"pID"]];
[address addObject:[dict objectForKey:#"address"]];
}
I have a NSMutableArray and it has the users high scores saved into it. I want to arrange the items numerically (the numbers are stored in NSStrings.)Example:4,2,7,8To2,4,7,8What is the simplest way to do this if the data is stored in NSStrings?
This code will do it:
//creating mutable array
NSMutableArray *myArray = [NSMutableArray arrayWithObjects:#"4", #"2", #"7", #"8", nil];
//sorting
[myArray sortUsingComparator:^NSComparisonResult(NSString *str1, NSString *str2) {
return [str1 compare:str2 options:(NSNumericSearch)];
}];
//logging
NSLog(#"%#", myArray);
It uses blocks, make sure your target OS supports that (It's 4.0 for iOS and 10.6 for OSX).
This code works. I tried it:
NSMutableArray *unsortedHighScores = [[NSMutableArray alloc] initWithObjects:#"4", #"2", #"7", #"8", nil];
NSMutableArray *intermediaryArray = [[NSMutableArray alloc] init];
for(NSString *score in unsortedHighScores){
NSNumber *scoreInt = [NSNumber numberWithInteger:[score integerValue]];
[intermediaryArray addObject:scoreInt];
}
NSArray *sortedHighScores = [intermediaryArray sortedArrayUsingSelector:#selector(compare:)];
NSLog(#"%#", sortedHighScores);
The output is this:
2
4
7
8
If you have any questions about the code, just ask in the comments. Hope this helps!
The NSMutableArray method sortUsingSelector: should do it:
[scoreArray sortUsingSelector:#selector(localizedCaseInsensitiveCompare:)]
should do it.
If the array is of nsdictionaries conaining numeric value for key number
isKeyAscending = isKeyAscending ? NO : YES;
[yourArray sortUsingComparator:^NSComparisonResult(NSDictionary *obj1, NSDictionary *obj2) {
NSString *str1 = [obj1 objectForKey:#"number"];
NSString *str2 = [obj2 objectForKey:#"number"];
if(isKeyAscending) { //ascending order
return [str1 compare:str2 options:(NSNumericSearch)];
} else { //descending order
return [str2 compare:str1 options:(NSNumericSearch)];
}
}];
//yourArray is now sorted
The answer from Darshit Shah make it smootly
NSSortDescriptor *descriptor = [[NSSortDescriptor alloc]initWithKey:#"rank" ascending:YES selector:#selector(localizedStandardCompare:)];
I want to select and retrieve all the contents from an NSDictionary. I have a structure like this
- (void)viewDidLoad {
[super viewDidLoad];
listaOggetti = [[NSMutableArray alloc] init];
NSArray *arrayOne = [NSArray arrayWithObjects: #"First",#"Second",#"Third", nil];
NSArray *sortedOne = [arrayOne sortedArrayUsingSelector:#selector(localizedCaseInsensitiveCompare:)];
NSDictionary *dictOne = [NSDictionary dictionaryWithObject:sortedOne forKey:#"Elementi"];
NSArray *arrayTWo = [NSArray arrayWithObjects:#"First1",#"Second1" ..., nil];
NSArray *sortedTwo = [arrayTwo sortedArrayUsingSelector:#selector(localizedCaseInsensitiveCompare:)];
NSDictionary *dictTwo = [NSDictionary dictionaryWithObject:sortedTWo forKey:#"Elementi"];
NSArray *arrayThree = [NSArray arrayWithObjects:#"First2",#"Second2" ... , nil];
NSArray *sortedThree = [arrayThree sortedArrayUsingSelector:#selector(localizedCaseInsensitiveCompare:)];
NSDictionary *dictThree = [NSDictionary dictionaryWithObject:sortedThree forKey:#"Elementi"];
[listaOggetti addObject:dictOne];
[listaOggetti addObject:dictTwo];
[listaOggetti addObject:dictThree];
}
And I want to retrieve all the objects for the key #"Elementi" (should be around 45) in order to add them in another array, like:
NSDictionary *dict = [listaOggetti objectAtIndex:indexPath.section];
NSArray *array = [dict objectForKey:#"Elementi"];
cellValue = [array objectAtIndex:indexPath.row] ;
(With this, dict is only 9 objects filled in my project).
At the end, the *array should be around 45 objects filled. I tried with allValues, but didn't work.
How can I fix it?
The easiest is to do this in -viewDidLoad:
NSMutableArray *allObjects = [[NSMutableArray alloc] init];
[allObjects addObjectsFromArray:sortedOne];
[allObjects addObjectsFromArray:sortedTwo];
[allObjects addObjectsFromArray:sortedThree];
Alternately, you can get them from the dictionaries in a similar fashion:
NSMutableArray *allObjects = [[NSMutableArray alloc] init];
[allObjects addObjectsFromArray:[[listaOggetti objectAtIndex:0] objectForKey#"Elementi"];
[allObjects addObjectsFromArray:[[listaOggetti objectAtIndex:1] objectForKey#"Elementi"];
[allObjects addObjectsFromArray:[[listaOggetti objectAtIndex:2] objectForKey#"Elementi"];
What you are failing to understand is that listaOggetti is an NSMutableArray containing three objects. When you call
NSDictionary *dict = [listaOggetti objectAtIndex:indexPath.section];
the result is that dict is a single dictionary, one of the three objects in listaOggetti. Therefore when you call
NSArray *array = [dict objectForKey:#"Elementi"];
the result is that array is the object for the key #"Elementi" of that one single dictionary dict. Your code makes no attempt to combine the three DIFFERENT dictionaries or to combine the three arrays, each set as objectForKey:#"Elementi" for the three DIFFERENT dictionaries.
If you want one array that is the concatenation of all three different arrays, then use one of the snippets provided above. In both of these snippets, the result is that allObjects is an NSMutableArray containing all three arrays, in order.
I am a bit confused as to how arrays are handled in Objective-C.
If I have an array such as
NSarray *myArray = [[NSArray alloc]
initWithObjects:#"N", #"N", #"N", #"N", #"N",
nil];
how do I change the first occurrence to "Y"?
You need an NSMutableArray ..
NSMutableArray *myArray = [[NSMutableArray alloc]
initWithObjects:#"N", #"N", #"N", #"N", #"N",
nil];
and then
[myArray replaceObjectAtIndex:0 withObject:#"Y"];
You can't, because NSArray is immutable. But if you use NSMutableArray instead, then you can. See replaceObjectAtIndex:withObject::
[myArray replaceObjectAtIndex:0 withObject:#"Y"]
Write a helper method
-(NSArray *)replaceObjectAtIndex:(int)index inArray:(NSArray *)array withObject:(id)object {
NSMutableArray *mutableArray = [array mutableCopy];
mutableArray[index] = object;
return [NSArray arrayWithArray:mutableArray];
}
Now you can test this method with
NSArray *arr = #[#"a", #"b", #"c"];
arr = [self replaceObjectAtIndex:1 inArray:arr withObject:#"d"];
logObject(arr);
This outputs
arr = (
a,
d,
c
)
You can use similar method for NSDictionary
-(NSDictionary *)replaceObjectWithKey:(id)key inDictionary:(NSDictionary *)dict withObject:(id)object {
NSMutableDictionary *mutableDict = [dict mutableCopy];
mutableDict[key] = object;
return [NSDictionary dictionaryWithDictionary:mutableDict];
}
You can test it with
NSDictionary *dict = #{#"name": #"Albert", #"salary": #3500};
dict = [self replaceObjectWithKey:#"salary" inDictionary:dict withObject:#4400];
logObject(dict);
which outputs
dict = {
name = Albert;
salary = 4400;
}
You could even add this as a category and have it easily available.