I would like to get the average value of each day. For example, I would like to get 4 instead of getting 3 and 5 on "20130511". How can I do that on a single query? (Not hard code)
Select Val from Table 1 where??????????
Table1 :
Date Val
----------------
20130511 | 3
20130511 | 5
20130512 | 5
20130512 | 1
20130512 | 2
20130512 | 6
20130512 | 2
20130513 | 2
You have to group the date
SELECT Date, AVG(Val) FROM TABLE GROUP BY Date
You can group by date and do it in a single pass
SELECT DATE, SUM(VALUE)/COUNT(*) AS AVERAGE
FROM TABLE
GROUP BY DATE
Related
lets say I have a table which stores itemID, Date and total_shipped over a period of time:
ItemID | Date | Total_shipped
__________________________________
1 | 1/20/2000 | 2
2 | 1/20/2000 | 3
1 | 1/21/2000 | 5
2 | 1/21/2000 | 4
1 | 1/22/2000 | 1
2 | 1/22/2000 | 7
1 | 1/23/2000 | 5
2 | 1/23/2000 | 6
Now I want to aggregate based on several periods of time. For example, I Want to know how many of each item was shipped every two days and in total. So the desired output should look something like:
ItemID | Jan20-Jan21 | Jan22-Jan23 | Jan20-Jan23
_____________________________________________
1 | 7 | 6 | 13
2 | 7 | 13 | 20
How do I do that in the most efficient way
I know I can make three different subqueries but I think there should be a better way. My real data is large and there are several different time periods to be considered i. e. in my real problem I want the shipped items for current_week, last_week, two_weeks_ago, three_weeks_ago, last_month, two_months_ago, three_months_ago so I do not think writing 7 different subqueries would be a good idea.
Here is the general idea of what I can already run but is very expensive for the database
WITH
sq1 as (
SELECT ItemID, sum(Total_shipped) sum1
FROM table
WHERE Date BETWEEN '1/20/2000' and '1/21/2000'
GROUP BY ItemID),
sq2 as (
SELECT ItemID, sum(Total_Shipped) sum2
FROM table
WHERE Date BETWEEN '1/22/2000' and '1/23/2000'
GROUP BY ItemID),
sq3 as(
SELECT ItemID, sum(Total_Shipped) sum3
FROM Table
GROUP BY ItemID)
SELECT ItemID, sq1.sum1, sq2.sum2, sq3.sum3
FROM Table
JOIN sq1 on Table.ItemID = sq1.ItemID
JOIN sq2 on Table.ItemID = sq2.ItemID
JOIN sq3 on Table.ItemID = sq3.ItemID
I dont know why you have tagged this question with multiple database.
Anyway, you can use conditional aggregation as following in oracle:
select
item_id,
sum(case when "date" between date'2000-01-20' and date'2000-01-21' then total_shipped end) as "Jan20-Jan21",
sum(case when "date" between date'2000-01-22' and date'2000-01-23' then total_shipped end) as "Jan22-Jan23",
sum(case when "date" between date'2000-01-20' and date'2000-01-23' then total_shipped end) as "Jan20-Jan23"
from my_table
group by item_id
Cheers!!
Use FILTER:
select
item_id,
sum(total_shipped) filter (where date between '2000-01-20' and '2000-01-21') as "Jan20-Jan21",
sum(total_shipped) filter (where date between '2000-01-22' and '2000-01-23') as "Jan22-Jan23",
sum(total_shipped) filter (where date between '2000-01-20' and '2000-01-23') as "Jan20-Jan23"
from my_table
group by 1
item_id | Jan20-Jan21 | Jan22-Jan23 | Jan20-Jan23
---------+-------------+-------------+-------------
1 | 7 | 6 | 13
2 | 7 | 13 | 20
(2 rows)
Db<>fiddle.
I have a table that has the following schema:
ID | FirstName | Surname | TransmissionID | CaptureDateTime
1 | Billy | Goat | ABCDEF | 2018-09-20 13:45:01.098
2 | Jonny | Cash | ABCDEF | 2018-09-20 13:45.01.108
3 | Sally | Sue | ABCDEF | 2018-09-20 13:45:01.298
4 | Jermaine | Cole | PQRSTU | 2018-09-20 13:45:01.398
5 | Mike | Smith | PQRSTU | 2018-09-20 13:45:01.498
There are well over 70,000 records and they store logs of transmissions to a web-service. What I'd like to know is how would I go about writing a script that would select the distinct TransmissionID values and also show the timespan between the earliest CaptureDateTime record and the latest record? Essentially I'd like to see what the rate of records the web-service is reading & writing.
Is it even possible to do so in a single SELECT statement or should I just create a stored procedure or report in code? I don't know where to start aside from SELECT DISTINCT TransmissionID for this sort of query.
Here's what I have so far (I'm stuck on the time calculation)
SELECT DISTINCT [TransmissionID],
COUNT(*) as 'Number of records'
FROM [log_table]
GROUP BY [TransmissionID]
HAVING COUNT(*) > 1
Not sure how to get the difference between the first and last record with the same TransmissionID I would like to get a result set like:
TransmissionID | TimeToCompletion | Number of records |
ABCDEF | 2.001 | 5000 |
Simply GROUP BY and use MIN / MAX function to find min/max date in each group and subtract them:
SELECT
TransmissionID,
COUNT(*),
DATEDIFF(second, MIN(CaptureDateTime), MAX(CaptureDateTime))
FROM yourdata
GROUP BY TransmissionID
HAVING COUNT(*) > 1
Use min and max to calculate timespan
SELECT [TransmissionID],
COUNT(*) as 'Number of records',datediff(s,min(CaptureDateTime),max(CaptureDateTime)) as timespan
FROM [log_table]
GROUP BY [TransmissionID]
HAVING COUNT(*) > 1
A method that returns the average time for all transmissionids, even those with only 1 record:
SELECT TransmissionID,
COUNT(*),
DATEDIFF(second, MIN(CaptureDateTime), MAX(CaptureDateTime)) * 1.0 / NULLIF(COUNT(*) - 1, 0)
FROM yourdata
GROUP BY TransmissionID;
Note that you may not actually want the maximum of the capture date for a given transmissionId. You might want the overall maximum in the table -- so you can consider the final period after the most recent record.
If so, this looks like:
SELECT TransmissionID,
COUNT(*),
DATEDIFF(second,
MIN(CaptureDateTime),
MAX(MAX(CaptureDateTime)) OVER ()
) * 1.0 / COUNT(*)
FROM yourdata
GROUP BY TransmissionID;
I want to find the minimum value of a column in a certain date range of a table.
so lets say I have a table like the following,
Date | Value
---------------
01-26 | 2
01-26 | 1
01-27 | 2
01-27 | 4
01-28 | 3
01-28 | 5
How can I apply the MIN() function to the subgroup of the Value column so that the result might be
Date | MIN(Value)
---------------
01-26 | 1
01-27 | 2
01-28 | 3
I thought about GROUP BY .. or such but couldn't figure out how to get the results into a table.
Using UNION and JOIN isn't quite scalable because the query could be using a date range of a month
Group by should work:
Select date, min( value )
From table1
Group by date
Maybe too simple, but seems like this would work
Select Min(col1), datecol from yourtable group by datecol;
HTH
Suppose I have a statistical table like this:
date | stats
-------------
10/1 | 2
10/1 | 3
10/1 | 2
10/2 | 1
10/3 | 3
10/3 | 2
10/4 | 1
10/4 | 1
What I want is three columns:
Date
sum(stats) of Date
sum(stats) of last three days before Date
I know I can use window function to handle the 2nd column, but I cannot handle 2nd and 3rd at the same time.
What should I do to archive this?
Thanks!
You can use aggregation and window functions:
select date, sum(stats) as day_stats,
sum(sum(stats)) over (order by date rows between 3 preceding and 1 preceding) as day_stats_3
from t
group by date
order by date;
You can use a correlated query:
SELECT s.date,sum(s.stats) as today_sum,
(SELECT sum(t.stats) FROM YourTable t
where t.date between s.date - 2 and s.date) as sum_3days
FROM YourTable s
GROUP BY s.date
I’m trying to make a query that returns the difference of days to get the average of days in a period of time. This is the situation I need to get the max date from the status 2 and the max date from the status 3 from a request and get how much time the user spend on that period of time
So far this is the query I Have right now I get the mas and min and the difference between the days but are not the max of the status 2 and the max of status 3
Query I have so far:
SELECT distinct t1.user, t1.Request,
Min(t1.Time) as MinDate,
Max(t1.Time) as MaxDate,
DATEDIFF(day, MIN(t1.Time), MAX(t1.Time))
FROM [Hst_Log] t1
where t1.Request = 146800
GROUP BY t1.Request, t1.user
ORDER BY t1.user, max(t1.Time) desc
Example table:
-------------------------------
user | Request | Status | Time
-------------------------------
User 1 | 2 | 1 | 6/1/15 3:25 PM
User 2 | 1 | 1 | 2/1/15 3:24 PM
User 2 | 3 | 1 | 2/1/15 3:24 PM
User 1 | 4 | 1 | 5/10/15 3:18 PM
User 3 | 3 | 2 | 5/4/15 2:36 PM
User 2 | 2 | 2 | 6/4/15 2:34 PM
User 3 | 2 | 3 | 6/10/15 5:51 PM
User 1 | 1 | 2 | 5/1/15 5:49 PM
User 3 | 4 | 2 | 5/16/15 2:39 PM
User 2 | 4 | 2 | 5/17/15 2:32 PM
User 2 | 3 | 2 | 4/6/15 2:22 PM
User 2 | 3 | 3 | 4/7/15 2:06 PM
-------------------------------
I will appreciate all the help
You'll need to use subqueries since the groups for the min and max times are different. One query will pull the min value where the status is 2. Another will pull the max value where the status is 3.
Something like this:
SELECT MinDt.[User], minDt.MinTime, MaxDt.MaxTime, datediff(d,minDt.MinTime, MaxDt.MaxTime) as TimeSpan
FROM
(SELECT t1.[user], t1.Request,
Min(t1.Time) as MinTime
FROM [Hst_Log] t1
where t1.Request = 146800
and t1.[status] = 2
GROUP BY t1.Request, t1.[user]) MinDt
INNER JOIN
(SELECT t1.[user], t1.Request,
Max(t1.Time) as MaxTime
FROM [Hst_Log] t1
where t1.[status] = 3
GROUP BY t1.Request, t1.[user]) MaxDt
ON MinDt.[User] = MaxDt.[User] and minDt.Request = maxDt.Request
something like this?
(mysql)
SELECT t.*,MAX(t.UFecha), x.*,y.*,Min(t.UFecha) as MinDate,
Max(t.UFecha) as MaxDate,
avg(x.Expr2+y.Expr3),//?????
DATEDIFF(MIN(t.UFecha), MAX(t.UFecha)) AS Expr1
FROM `app_upgrade_hst_log` t
left join(select count(*),Request, DATEDIFF(MIN(UFecha), MAX(UFecha)) AS Expr2 FROM `app_upgrade_hst_log` where Status=1 group by Request,Status) x on t.Request= x.Request
left join(select count(*),Request, DATEDIFF(MIN(UFecha), MAX(UFecha)) AS Expr3 FROM `app_upgrade_hst_log` where Status=2) y on t.Request= y.Request
group by t.Request,t.Status
What is the SQL-Server version? Maybe you could use your query as CTE and do a follow-up SELECT where you can use the Min and Max date as date period.
EDIT: Exampel
WITH myCTE AS
(
put your query here
)
SELECT * FROM myCTE
You can use myCTE for further joins too, pick out the needed date, use sub-select, what ever... AND: have a look on the OVER-link, could be helpfull...
Depending on the version you could also think about using OVER
https://msdn.microsoft.com/en-us/library/ms189461.aspx