id address retailer
1 A 11
2 A 11
3 A 11
4 A 12
5 A 13
6 B 12
7 B 12
8 B 13
My output should be
id address retailer
1 A 11
4 A 12
5 A 13
6 B 12
8 B 13
i.e my query should return id's which have same address but not same retailer.
How toget this?
Try to use group by clause as below:
select min(id), address, retailer
from tab
group by address, retailer
Assuming you're joining on columns with no duplicates, which is by far the most common case:
An inner join of A and B gives the result of A intersect B, i.e. the inner part of a venn diagram intersection.
An outer join of A and B gives the results of A union B, i.e. the outer parts of a venn diagram union.
Examples:
Suppose you have two Tables, with a single column each, and data as follows:
A B
- -
1 3
2 4
3 5
4 6
Note that (1,2) are unique to A, (3,4) are common, and (5,6) are unique to B.
Inner join:
An inner join using either of the equivalent queries gives the intersection of the two tables, i.e. the two rows they have in common.
select *
from a
INNER JOIN b on a.a = b.b;
select a.*,b.*
from a,b
where a.a = b.b;
a | b
--+--
3 | 3
4 | 4
Left outer join:
A left outer join will give all rows in A, plus any common rows in B.
select *
from a
LEFT OUTER JOIN b on a.a = b.b;
select a.*,b.*
from a,b
where a.a = b.b(+);
a | b
--+-----
1 | null
2 | null
3 | 3
4 | 4
Full outer join:
A full outer join will give you the union of A and B, i.e. All the rows in A and all the rows in B. If something in A doesn't have a corresponding datum in B, then the B portion is null, and vice versa.
select *
from a
FULL OUTER JOIN b on a.a = b.b;
a | b
-----+-----
1 | null
2 | null
3 | 3
4 | 4
null | 6
null | 5
select min(id) as id,address, retailer
from table1
group by address, retailer
order by id
The query you need is:
SELECT min(id), address, retailer
FROM table1 AS t1
group by address, retailer
order by address
Here's the source
Use This: It's working:
SELECT * FROM `sampletable` GROUP BY address, retailer
Related
I have two tables total_sales_store :
store. total_sales
23 198750953.849999
29 77141561.3099999
9 77789512.9899997
15 89133935.9200002
3 57586980.0699998
32 166819624.16
26 143416610.79
12 144287538.149999
35 131520910.08
6 223756634.64
43 90565869.4100002
21 108118179.92
27 253856294.88
38 55159990.42
7 81598450.1399996
and storesdata:
store. type
1 A
2 A
3 B
4 A
5 B
6 A
7 B
8 A
9 B
10 B
11 A
I want to full join the two table so that I have this desired table:
store. Type. totalsales
1 A 123124
2 B 141221
3 C 134141
4 A. 234234
5 B 2323
6 C 123214
...
So I used the following query:
SELECT A.Store,a.total_sales
FROM totalsales_store A
FULL JOIN
(
SELECT [Type], Store
FROM storesdata
) B
ON A.Store = B.Store
ORDER BY total_sales DESC
But what I got is this:
[enter image description here][3]
which neglects the Type column. What can I do to make this work? Thank you!
With a FULL JOIN you will get all results from both tables, even when they don't match each other, so you should account for the NULL store values across tables. Otherwise simply include the Type column in the select.
I didn't see a need for a sub-query.
SELECT
ISNULL(A.Store, B.Store) Store,
B.Type,
a.total_sales
FROM
totalsales_store A
FULL JOIN storesdata B ON
A.Store = B.Store
ORDER BY
a.total_sales DESC
I suspect you can get away with
SELECT
A.Store,
B.Type,
a.total_sales
FROM
totalsales_store A
JOIN storesdata B ON
A.Store = B.Store
ORDER BY
a.total_sales DESC
i have following SQL table A in my database:
index, group, foo
1 A 2
2 A 2
3 A 0
4 A 1
5 B 2
6 B 1
7 C 1
There are few more groups and I need to write a query based on this filter table B. For each group in table A it's index should be equal or greater than index_egt from table B for the same group.
If the group is not listed in table B, the group won't be filtered.
index_egt, group
3 A
5 B
Expected result:
index, group, foo
3 A 0
4 A 1
5 B 2
6 B 1
7 C 1
Try this, the A.index>=B.index_egt will handle cases where the group is listed in TableB and the B.index_egt IS NULL will handle cases where the group is not listed:
SELECT
A.index,
A.group,
A.foo
FROM TableA AS A
LEFT JOIN TableB AS B ON A.group=B.group
WHERE A.index>=B.index_egt
OR B.index_egt IS NULL
select
a.*
from
A a
left join
B b ON b.group = a.group
where
a.index >= b.index_egt OR b.index_egt IS NULL
I always like this trick with coalesce
SELECT a.*
FROM a_table_with_no_name a
LEFT JOIN b_table_with_no_name b ON b.group = a.group
WHERE a.index >= COALESCE(b.index_egt,a.index)
I am struggeling with a left join on a Raima database. I'd like to add an additional join condition, but in this case the join behaves like an inner join, thus I am losing some of the expected results.
Example:
TABLE_A
ID
-------
1
2
3
4
.
TABLE_B
A_ID | B
--------
1 | 1
2 | 1
2 | 2
3 | 2
Query
select * from TABLE_A left join TABLE_B
on TABLE_A.ID = TABLE_B.A_ID
and TABLE_B.B = 1
I am expecting the following result:
1 1 1
2 2 1
3 null null
4 null null
E.g. on an Oracle 11g I get the expected result, but on the Raima it shows me only the first two results. What is the problem here and how to fix it?
You need this
select * from A left join
(select * from B where B=1) bd
on A.ID = bd.A_ID
The query you gave will not give you expected result in oracle also. This will.
PS: Please use different names for table and column
I have 2 tables like below:
Table 1
---------
1
2
3
Table 2
--------
A
B
C
How do i join to get an output like below:
Output
---------
1 A
1 B
1 C
2 A
2 B
2 C
3 A
3 B
3 C
Use Cross join:
SELECT *
FROM Table1
CROSS JOIN Table2
You can change the order by replacing * with table fields.
Read more about Cross Join.
OR you could do this:
SELECT Table1.*,Table2.*
FROM Table2,Table1
Result:
ID NAME
1 A
1 B
1 C
2 A
2 B
2 C
3 A
3 B
3 C
You want to do a CROSS JOIN and that will give you the Cartesian product of all the rows.
See http://en.m.wikipedia.org/wiki/Join_(SQL)
select * from table 1,table 2 .
For o/p like A 1
A 2
A 3
B 1
B 2
B 3
C 1
C 2
C 3
just
I would like to know what's the logic for multiple joins (for example below)
SELECT * FROM B returns 100 rows
SELECT B.* FROM B LEFT JOIN C ON B.ID = C.ID returns 120 rows
As I know using left join will returns any matching data from the left table which is B if data are found for both table. But how come when using left join, it returns more data than table B itself?
What am I do wrong or misunderstood here? Any guidance are very appreciated. Thanks in advance.
Let be table B:
id
----
1
2
3
Let be table C
id name
------------
1 John
2 Mary
2 Anne
3 Stef
Any id from b is matched with ids from c, then id=2 will be matched twice. So a left join on id will return 4 rows even if base table B has 3 rows.
Now look at a more evil example:
Table B
id
----
1
2
2
3
4
table C
id name
------------
1 John
2 Mary
2 Anne
3 Stef
Every id from b is matched with ids from c, then first id=2 will be matched twice and second id=2 will be matched twice so the result of
select b.id, c.name
from b left join c on (b.id = c.id)
will be
id name
------------
1 John
2 Mary
2 Mary
2 Anne
2 Anne
3 Stef
4 (null)
The id=4 is not matched but appears in the result because is a left join.
Look at the following example :
B = {1,2}
C = {(1,a),(1,b),(1,c),(1,d),(1,e)}
The result of B left join C will be :
1 | a
1 | b
1 | c
1 | d
1 | e
2 | null
The number of rows in the result is definitely larger than rows in B (2).
In general the number of rows in result of B left join C is bounded by B.size + C.size and not only by B.size as you think...
As per your query it do the join to B Table with C and B table is Left Table so it will display all the records of Left table in our case it is B and related from other Table in our Case it is C.