This SQL:
select Name,
(select COUNT(1) from tbl_projects where statusId = tbl_sections.StatusId) as N
from tbl_sections
left join tbl_section_names on tbl_section_names.Id = NameId
Generates the follows data:
Name N
Completed 133
Cancelled 100
Unassigned 1
Sales 49
Development 10
Development 4
Development 1
I'm trying to modify it so it returns the data as follows:
Name N
Completed 133
Cancelled 100
Unassigned 1
Sales 49
Development 15
(ie, sum up the rows where the name is the same)
Can anyone suggest some clues on how to make this work ? I'm guessing I need a SUM and a GROUP BY, but it never even runs the query as all I get are errors.
Try this query. It sums N grouped by Name.
SELECT Name, SUM(N)
FROM (
SELECT Name,
(SELECT COUNT(1)
FROM tbl_projects
WHERE statusId = tbl_sections.StatusId
) AS N
FROM tbl_sections
LEFT JOIN tbl_section_names ON tbl_section_names.Id = NameId
) a
GROUP BY a.Name
Try this
select Name, count(p.statusid) N
from tbl_sections
left join tbl_section_names on tbl_section_names.Id = NameId
left outer join tbl_projects p on tbl_sections.StatusId = p.statusId
group by Name
Select Name, Sum(N) from
(select Name,
(select COUNT(1) from tbl_projects where statusId = tbl_sections.StatusId) as N
from tbl_sections
left join tbl_section_names on tbl_section_names.Id = NameId)
group by Name
This query is giving you count per status, which means Development has sections with three different status's, and the query would reflect this and make more sense if you added the status as a column:
select Name, tbl_sections.StatusId,
(select COUNT(1) from tbl_projects where statusId = tbl_sections.StatusId) as N
from tbl_sections
left join tbl_section_names on tbl_section_names.Id = NameId
I don't know the structure of your database, but I if you want a count of the number of sections per name, might be like this. This basically will look at the result of the join, and then summarize it by telling you the number of times each unique name occurs:
select Name, count(*)
from tbl_sections
left join tbl_section_names on tbl_section_names.Id = NameId
Group By Name
Try and give this a go.
select Name,
SUM(select COUNT(1) from tbl_projects where statusId = tbl_sections.StatusId) as N
from tbl_sections
left join tbl_section_names on tbl_section_names.Id = NameId
group by Name
Related
I have 4 tables in my db: incoming letters, outgoing letters, local letters and employee. In "letters" tables, there is a register_employee that have register this letter.
Every employee has his/her unique id (for example "3de9a23e-b927-4a27-a66a-c1f30b8c1464").
Tables look like this:
employee:
id first_name last_name age
incoming:
id register_employee summary letter adress date_sent
"Outgoing" and "local" tables look same as "incoming" table.
I need to count how many letters have been registered by each employee and which type.
Example results:
employee incoming outgoing local
Bob Marley 45 33 5
John Travolta 31 10 9
George Bush 98 15 38
I tried to use full joins and nested Select statments, but results that I have got are probably wrong cause I am getting millions of count for each employee (I don't have so many letters in db).
You can use OUTER JOIN and GROUP BY as follows:
-- Updated
You can use multiple sub-query:
select e.id, e.firstname,
(select count(*) from incoming i where i.register_employee = e.id) as incoming_letter,
(select count(*) from outgoing o where o.register_employee = e.id) as outgoing_letter,
(select count(*) from local l where l.register_employee = e.id) as local_letter
from employee e
We count the number of letters under different categories & left join them to the master employee table
select employee.first_name , t1.incoming, t2.outgoing, t3.local from (
select * from employee
left join
(select register_employee, count(*) as incoming from incoming_letters group by register_employee) t1 on employee.id = t1.register_employee
left join
(select register_employee, count(*) as outgoing from outgoing_letters group by register_employee) t2 on employee.id = t2.register_employee
left join
(select register_employee, count(*) as local from local group by register_employee) t3 on employee.id = t3.register_employee ) v
SELECT incom.id,incom.name,incom.incoming,out.outgoings,loc.local
FROM (SELECT
employees.id as id,
employees.short_name as name,
COUNT(incomings.register_employee) as incoming
FROM employees
LEFT JOIN incomings ON incomings.register_employee = employees.id)
GROUP BY employees.id, employees.short_name) as incom
LEFT JOIN (SELECT
employees.id as id,
COUNT(outgoings.register_employee) as outgoings
FROM employees
LEFT JOIN outgoings ON outgoings.register_employee = employees.id
GROUP BY employees.id) as out
ON incom.id=out.id
LEFT JOIN (SELECT
employees.id as id,
COUNT(local.register_employee) as local
FROM employees
LEFT JOIN outgoings ON local.register_employee = employees.id
GROUP BY employees.id) as loc
ON incom.id=loc.id;
I have a problem which I cannot resolve no matter what without using code, instead of SQL SCRIPT.
I have 2 tables
Person
ID Name Type
1 A A1
2 B A2
3 C A3
4 D A4
5 E A6
PersonHomes
HOMEID Location PurchaseDate PersonID
1 CA 20160101 1
2 CT 20160202 1
3 DT 20160101 2
4 BT 20170102 3
5 CT 20160303 1
6 CA 20160101 2
PersonID is foreign key of Person Table
There are no other rowz in the tables
So, we have to show detail of EACH person WITH home
The rule to write output is
IF Person has SINGLE entry in PersonHomes then use it
IF Person has MORE than ONE entry in PersonHomes then we have to look at purchase date, IF they are different then USE the PersonHomes ROW with OLDEST date in it. AND DELETE OTHER ROWS OF HIM
IF Person has MORE than ONE entry in PersonHomes then we have to look at purchase date, and IF DATES are SAME then USE the ROW with LOWER ID AND DELETE THE OTHER ROWS of HIM
This is very easy to do in code but using SQL it is complex
What I tried was to
WITH PERSON (
SELECT * FROM Person)
SELECT * FROM PERSON
INNER JOIN PersonHomes ON Person.ID = PersonHomes.PersonID
WHERE PersonHomes.PersonID = CASE WHEN (COUNT (*) FROM PersonHomes...)
Then I think I can write SQL function ?
I am stuck, Please help!
SAMPLE OUTPUT for PERSON A
ID NAME Type HOMEID Location PurchaseDate
1 A A1 5 CT 20160303
For PERSON B
ID NAME Type HOMEID Location PurchaseDate
1 A A2 3 DT 20160101
Aiden
It is not so easy to get desired output with SQL. we should write more than one sql queries.
First I created a temp table which consists of home details:
select PersonID, count(*) as HomeCount, count(distinct PurchaseDate) as
PurchaseDateCount, min(PurchaseDate) oldestPurchaseDate, min(HOMEID) as
LowerHomeID into #PersonHomesAbstractTable from PersonHomes group by PersonID
Then for the output of your first rule:
select p.ID, p.NAME, p.Type, ph.HOMEID, ph.Location, ph.PurchaseDate from Person p
inner join #PersonHomesAbstractTable a on p.ID = a.PersonID
inner join PersonHomes ph on p.ID = ph.PersonID
where a.HomeCount = 1
For the output of your second rule:
select p.ID, p.NAME, p.Type, ph.HOMEID, ph.Location, ph.PurchaseDate
from Person p inner join #PersonHomesAbstractTable a on p.ID = a.PersonID
inner join PersonHomes ph on p.ID = ph.PersonID and
ph.PurchaseDate = a.oldestPurchaseDate
where a.HomeCount > 1 and a.PurchaseDateCount <> 1
And finally for the output of your third rule:
select p.ID, p.NAME, p.Type, ph.HOMEID, ph.Location, ph.PurchaseDate
from Person p inner join #PersonHomesAbstractTable a on p.ID = a.PersonID
inner join PersonHomes ph on p.ID = ph.PersonID and
ph.HOMEID = a.LowerHomeID
where a.HomeCount > 1 and a.PurchaseDateCount = 1
Of course there are some other ways, but now this way is come to my mind.
If you want to delete undesired rows, you can use scripts below:
delete from PersonHomes where HOMEID in
(
select ph.HOMEID from #PersonHomesAbstractTable a
inner join PersonHomes ph on a.PersonID = ph.PersonID and
ph.PurchaseDate <> a.oldestPurchaseDate
where a.HomeCount > 1 and a.PurchaseDateCount <> 1
union
select p.HOMEID from #PersonHomesAbstractTable a
inner join PersonHomes ph on a.PersonID = ph.PersonID and
ph.HOMEID <> a.LowerHomeID
where a.HomeCount > 1 and a.PurchaseDateCount = 1
)
You seem to have a prioritization query. I would solve this using row_number():
select ph.*
from (select ph.*,
row_number() over (partition by personid
order by purchasedate asc, homeid asc
) as seqnum
from personhomes ph
) ph
where seqnum = 1;
This doesn't actually change the data in the table. Although you say delete, it seems like you just want a result set with one home per person.
This is shortest approach got by Link
;WITH cte AS
(
SELECT *, RowN = ROW_NUMBER() OVER (PARTITION BY ID ORDER BY AddressMoveDate DESC) FROM Address
)
DELETE FROM cte WHERE RowN > 1
I have below 3 tables and I want to write a SQL query which will list the store present in all city: (here the result should be "Walmart")
Stores:
ID Name
1 Walmart
2 Target
3 Sears
Stores_City
ID Store_id City ID
1 1 10
2 1 20
3 2 10
4 1 30
City
ID Name
10 NewYork
20 Boston
30 Eagan
I am unable to find a query that works. Any help is appreciated!
select s.Name
from Stores s
inner join
(
select store_id, count(distinct city_id)
from stores_city
group by store_id
having count(distinct city_id) = (select count(*) from City)
) x
on x.store_id = s.id;
You can do it by grouping on store_id and checking for the count from stores table.
A straight join would work
Select distinct s.name from stores s inner join store _city SC on s.id=sc.id
Inner join city c on
Sc.city_id = c.id
Here is another way that will work:
select s.*
from stores s
where not exists (
select c.id
from city c
except
select sc.city_id
from stores_city sc
where sc.store_id = s.id
)
Try this:
SELECT
s.Name
FROM Stores s
WHERE NOT EXISTS (SELECT TOP 1
1
FROM City c
LEFT JOIN Stores_City sc
ON c.ID = sc.CityID
AND sc.Store_id = s.ID
WHERE sc.ID IS NULL)
I am trying to create some SQL that will count the number of employees within each company and return only those companies with greater than or equal to n employees.
I have the following tables (simplified):
CompanyEmployee Table
ID Name IsCompany
1 John Joe 0
2 Company Y 1
3 Company X 1
4 Sally Jeff 0
5 James Peach 0
Employment Table
ID EmployeeID CompanyID
1 1 2
2 4 3
3 5 3
My desired result for n=2:
ID Name IsCompany
3 Company X 1
I have the following SQL:
SELECT t.* FROM CompanyEmployee AS t
WHERE t.ID IN (
SELECT DISTINCT (t.ID)
FROM CompanyEmployee AS t
INNER JOIN Employment AS t0 ON t.ID = t0.CompanyID
WHERE t.IsCompany = 1
GROUP BY t0.CompanyID
HAVING COUNT(t0.EmployeeID) >= n)
But it generates the following error:
Column 'CompanyEmployee.ID' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
Any help or advice would be greatly appreciated!
Mixing companies and employees this way is a bad idea. Using a straight inner join may work as long as the id values between the two different types of rows never intersect. I guess if it's an identity column then that's not supposed to happen.
with Companies as (
select ID as CompanyID, Name
from CompanyEmployee
where IsCompany = 1
), Employees as (
select CompanyID, Name
from CompanyEmployee where
IsCompany = 0
)
select c.CompanyID, Name, 1 as IsCompany
from
Companies as c
inner join Employment as ec on ec.CompanyID = c.CompanyID
inner join Employees as e on e.EmployeeID = ce.EmployeeID
group by
c.CompanyID
having count(*) >= n
There is still a straightforward way to do it:
select *
from CompanyEmployee
where ID in (
select CompanyID
from Employment
group by CompanyID
having count(*) >= n)
)
Try this:
SELECT t1.CompanyId, t2.CompanyName, COUNT(t1.CompanyId)
FROM Employment AS t1 INNER JOIN CompanyEmployee AS t2 ON t1.CompanyId = t2.Id
GROUP BY t1.CompanyId, t2.CompanyName
HAVING COUNT(t1.CompanyId)>=n
where n is a number of employees...
I need to select only the most significant value from a table. Using Postgre SQL (last version) Follows the data sample:
Table Company
Id, Name, ExternalId, StartAt
1 Comp1 54123 21/05/2000
2 Comp2 23123 21/05/2000
Table Address
Id, Company, Address_Type, City
1 1 7 A
2 2 2 B
3 2 62 C
Table Adress_Type
Id, Name, importance_order
62 Adt1 1
7 Adt2 2
2 Adt3 2
What i need to do is to get the company and its major Address, based on the "importance_order". There is already a function that returns this result:
Create function~~~~
Select * from Company c
join Address a on c.address_id = a.id
Join AddressType at on a.adresstype_id = at.id
ORDER by at.importance_order
Limit 1
My problem now is that this function is called one time for every row in the query, and it take so much time (about 20 min.). Should it be possible to do this similar aproach by joinning tables? I need this join to get the First "most important"address, and then get the City name, but need to do this in a "faster" way. I need to reduce subquery`s number to its minimal.
Select * from table t
inner join Company c on t.company_id = c.id
left join address a on (c.company_id = c.id)
left join addresstype at on (a.adresstype_id = at.id)
where at.id = (
select max(id) from addresstype
where adresstype in (
select adresstype from adress where company_id = c.id
)
)
If it is not clear tell me that i get more into details.
Thanks.
For this you need PostgreSQL 8.4+ I suppose
SELECT T.*
FROM TABLE AS T
INNER JOIN
(
SELECT * FROM
(
SELECT C1.*, ROW_NUMBER() OVER(partition by C1.ID ORDER BY T.IMPORTANCE_ORDER) AS RN
FROM COMPANY AS C1
INNER JOIN ADDRESS AS A
ON C1.ID = A.COMPANY
INNER JOIN ADDRESS_TYPE AS T
ON T.ID = A.ADDRESS_TYPE_ID
) A
WHERE RN = 1
) AS B
ON B.ID= T.COMPANY_ID