I have 2 tables
Table A:
+------------+----------+
| Entry From | Entry To |
+------------+----------+
| 100 | 103 |
| 104 | 105 |
| 106 | 109 |
+------------+----------+
Table B:
+-------+-------+
| Entry | Value |
+-------+-------+
| 100 | 10 |
| 101 | 3 |
| 102 | 7 |
| 103 | 2 |
| 104 | 9 |
| 105 | 17 |
| 106 | 3 |
| 107 | 3 |
| 108 | 6 |
| 109 | 5 |
+-------+-------+
Desired result:
+------------+----------+-------------+
| Entry From | Entry To | Total Value |
+------------+----------+-------------+
| 100 | 103 | 22 |
| 104 | 105 | 26 |
| 106 | 109 | 17 |
+------------+----------+-------------+
Any solutions/advice is welcome.
Thanks to any help in advance!
Please try:
Select
a.EntryFrom, a.EntryTo, sum(Value) TotalValue
From TableA a INNER JOIN TableB b ON b.Entry between a.EntryFrom and a.EntryTo
Group by a.EntryFrom, a.EntryTo
What you're looking for is a subquery maybe.
SELECT
A.Entry_From, A.Entry_To,
(SELECT SUM(B.Value) FROM B
WHERE B.Entry BETWEEN A.Entry_From AND A.Entry_To) AS Total_Value
FROM A
It also depends on what version of SQL so YMMV :)
Here is a working fiddle: http://www.sqlfiddle.com/#!2/afbac/2 using this query:
select a.idxFrom, a.idxTo, sum(b.value) as total
from a inner join b on b.idx >= a.idxFrom and b.idx <= a.idxTo
group by a.idxFrom, a.idxTo
Related
Given the following SQL tables: https://imgur.com/a/NI8VrC7. For each specific ID_t I need to return the MAX() and MIN() value of Cena_c(total price) column of a given ID_t.
| ID_t | Nazwa |
| ---- | ----- |
| 1 | T1 |
| 2 | T2 |
| 3 | T3 |
| 4 | T4 |
| 5 | T5 |
| 6 | T6 |
| 7 | T7 |
| ID | ID_t | Ilosc | Cena_j | Cena_c | ID_p |
| ---- | ---- | ----- | ------ | ------ | ---- |
| 100 | 1 | 1 | 10 | 10 | 1 |
| 101 | 2 | 3 | 20 | 60 | 2 |
| 102 | 4 | 5 | 10 | 50 | 7 |
| 103 | 2 | 2 | 20 | 40 | 5 |
| 104 | 5 | 1 | 30 | 30 | 5 |
| 105 | 7 | 6 | 80 | 480 | 1 |
| 106 | 6 | 7 | 15 | 105 | 2 |
| 107 | 6 | 5 | 15 | 75 | 1 |
| 108 | 3 | 3 | 25 | 75 | 7 |
| 109 | 7 | 1 | 80 | 80 | 5 |
| 110 | 4 | 1 | 10 | 10 | 2 |
| 111 | 2 | 9 | 20 | 180 | 2 |
Based on provided tables the correct result should look like this:
| ID_t | Cena_c_max | Cena_c_min |
| ----- | ---------- | ---------- |
| T1 | 10 | 10 |
| T2 | 180 | 60 |
| T3 | 75 | 75 |
| T4 | 50 | 10 |
| T5 | 30 | 30 |
| T6 | 105 | 75 |
| T7 | 480 | 80 |
Is this even possible?
I haven't found anything yet that I could use to implement my solution.
SELECT concat('T',ID_t), max(Cena_c) as Cena_c_max, min(Cena_c) as Cena_c_min
FROM table
GROUP BY ID_t
Better is to solve it with joins of tables, because it will be avoided in the future if the prefix T is changed to another letter.
Hardcoding should be avoided.
select b.nazva as "Nazva", max(a.cena.c) as "Cena_c_max", min(a.cena.c) as "Cena_c_min"
from table1 as a
left join table2 as b on (
a.id_t = b.id_t
)
group by id_t
I have the following four tables:
1) mls_user
2) mls_category
3) bonus_point
4) mls_entry
In mls_user table values are like below:
*-------------------------*
| id | store_id | name |
*-------------------------*
| 1 | 101 | sandeep |
| 2 | 101 | gagan |
| 3 | 102 | santosh |
| 4 | 103 | manu |
| 5 | 101 | jagveer |
*-------------------------*
In mls_category table values are like below:
*---------------------------------*
| cat_no | store_id | cat_value |
*---------------------------------*
| 20 | 101 | 1 |
| 21 | 101 | 4 |
| 30 | 102 | 1 |
| 31 | 102 | 2 |
| 40 | 103 | 1 |
| 41 | 103 | 1 |
*---------------------------------*
In bonus_point table values are like below:
*-----------------------------------*
| user_id | store_id | bonus_point |
| 1 | 101 | 10 |
| 4 | 101 | 5 |
*-----------------------------------*
In mls_entry table values are like below:
*-------------------------------------------------------*
| user_id | store_id | category | distance | status |
*-------------------------------------------------------*
| 1 | 101 | 20 | 10 | Approved |
| 1 | 101 | 21 | 40 | Approved |
| 1 | 101 | 20 | 10 | Approved |
| 2 | 101 | 20 | 5 | Approved |
| 3 | 102 | 30 | 10 | Approved |
| 3 | 102 | 31 | 80 | Approved |
| 4 | 101 | 20 | 15 | Approved |
*-------------------------------------------------------*
And I want below output:
*--------------------------------------------------*
| user name | Points | bonus Point | Total Point |
*--------------------------------------------------*
| Sandeep | 30 | 10 | 40 |
| Santosh | 30 | 0 | 30 |
| Manu | 15 | 5 | 20 |
| Gagan | 5 | 0 | 5 |
| Jagveer | 0 | 0 | 0 |
*--------------------------------------------------*
I tell the calculation of how the points will come for user Sandeep.
Points = ((10+10)/1 + 40/4)=30
Here 1 and 4 is cat value which comes from mls_category.
I am using below code for a particular user but when i
SELECT sum(t1.totald/c.cat_value) as total_distance
FROM mls_category c
join (
select sum(distance) totald, user_id, category
FROM mls_entry
WHERE user_id=1 AND store_id='101' AND status='approved'
group by user_id, category) t1 on c.cat_no = t1.category
I have created tables in online for checking
DEMO
Computing the points (other than the bonus points) requires a separate join between the mls_entry and mls_category tables. I would do this in a separate subquery, and then join this to the larger query.
Here is one approach:
SELECT
u.name,
COALESCE(t1.points, 0) AS points,
COALESCE(b.bonus_point, 0) AS bonus_points,
COALESCE(t1.points, 0) + COALESCE(b.bonus_point, 0) AS total_points
FROM mls_user u
LEFT JOIN
(
SELECT e.user_id, SUM(e.distance / c.cat_value) AS points
FROM mls_entry e
INNER JOIN mls_category c
ON e.store_id = c.store_id AND e.category = c.cat_no
GROUP BY e.user_id
) t1
ON u.id = t1.user_id
LEFT JOIN bonus_point b
ON u.id = b.user_id
ORDER BY
total_points DESC;
This is the output I am getting from the above query in the demo you setup:
The output does not match exactly, because you have (perhaps) a typo in Santosh's data in your question, or otherwise the expected output in your question has a typo.
Table: Project Details
+-----+------------------+------------+--------------+------------+
| GPN | EmployeePosition | Project.No | ChargedHours | PayPerHour |
+-----+------------------+------------+--------------+------------+
| 2 | B | 101 | 50 | 57 |
| 3 | C | 100 | 75 | 44 |
| 4 | D | 100 | 100 | 24.75 |
| 5 | E | 103 | 125 | 19.25 |
| 6 | F | 101 | 150 | 16 |
| 7 | C | 100 | 175 | 44 |
+-----+------------------+------------+--------------+------------+
I need to find out total pay of each Project. So first I have to find out Total pay per employee and group it by Project.No.
The table below shows the Total pay per Employee which is created using other 2 existing columns
+-----+-------------+---------+------------+----------+----------------+
| GPN | EmpPosition | Proj.No | ChargedHrs | PayPerHr | TotalPayPerEmp |
+-----+-------------+---------+------------+----------+----------------+
| 2 | B | 101 | 50 | 57 | 993.75 |
| 3 | C | 100 | 75 | 44 | 2850 |
| 4 | D | 100 | 100 | 24.75 | 3300 |
| 5 | E | 103 | 125 | 19.25 | 2406.25 |
| 6 | F | 101 | 150 | 16 | 2400 |
| 7 | C | 100 | 175 | 44 | 7700 |
+-----+-------------+---------+------------+----------+----------------+
My Query:
Select EngNumber, SUM([CharHrs])[SumOfChargedHours], Levell, CostPH,
SUM([CharHrs])*CostPH [TotalPayPerEmployee]
FROM data1.dbo.PayedPerHour
GROUP BY EngNumber, Levell, TotalPayPerEmployee, CostPH
ORDER BY EngNumber;
Update data1.dbo.PayedPerHour
SET CostPH = CASE Levell
WHEN 'Associate Director' THEN '79.75'
WHEN 'Senior Manager' THEN '57'
WHEN 'Manager' THEN '44'
WHEN 'Senior' THEN '24.75'
WHEN 'Staff 2, 3 & 4' THEN '19.25'
WHEN 'Staff 1' THEN '16'
ELSE 'NULL'
END
WHERE Levell IN('Associate Director', 'Senior Manager','Manager', 'Senior',
'Staff 2, 3 & 4', 'Staff 1');
I want to group the TotalPayPerEmp by Proj.No but i cant accomplish it.
I would have made silly mistakes in the query since I'm very new to sql so please regret them
Expected table:
+---------+--------------------+
| Proj.No | TotalPayPerProject |
+---------+--------------------+
| 100 | 14093.75 |
| 101 | 5250 |
| 103 | 4881.25 |
+---------+--------------------+
I think this could be done using some of your algorithm, except at the ProjectNo granularity:
SELECT ProjectNo
,SUM(ChargedHours*PayPerHour) [TotalPayPerProject]
FROM ProjectDetails
GROUP BY ProjectNo
This gives output:
ProjectNo TotalPayPerProject
100 13475
101 5250
103 2406.25
This is different from your expected output, for some reason.
Here's a SQL fiddle: http://sqlfiddle.com/#!6/21a33/2/0
There are 3 Tables (SorMaster, SorDetail, and InvWarehouse):
SorMaster:
+------------+
| SalesOrder |
+------------+
| 100 |
| 101 |
| 102 |
+------------+
SorDetail:
+------------+------------+---------------+
| SalesOrder | MStockCode | MBackOrderQty |
+------------+------------+---------------+
| 100 | PN-1 | 4 |
| 100 | PN-2 | 9 |
| 100 | PN-3 | 1 |
| 100 | PN-4 | 6 |
| 101 | PN-1 | 6 |
| 101 | PN-3 | 2 |
| 102 | PN-2 | 19 |
| 102 | PN-3 | 14 |
| 102 | PN-4 | 6 |
| 102 | PN-5 | 4 |
+------------+------------+---------------+
InvWarehouse:
+------------+-----------+-----------+
| MStockCode | Warehouse | QtyOnHand |
+------------+-----------+-----------+
| PN-1 | A | 1 |
| PN-2 | B | 9 |
| PN-3 | A | 0 |
| PN-4 | B | 1 |
| PN-1 | A | 0 |
| PN-3 | B | 5 |
| PN-2 | A | 9 |
| PN-3 | B | 4 |
| PN-4 | A | 6 |
| PN-5 | B | 0 |
+------------+-----------+-----------+
Desired Results:
+------------+-----------------+--------------+
| MStockCode | SumBackOrderQty | SumQtyOnHand |
+------------+-----------------+--------------+
| PN-1 | 10 | 10 |
| PN-2 | 28 | 1 |
| PN-3 | 17 | 5 |
| PN-4 | 12 | 13 |
| PN-5 | 11 | 6 |
+------------+-----------------+--------------+
I have been going around in circles with no end in sight. Seems like it should be simple but just can't wrap my head around it. The SumBackOrderQty obviously getting counted twice as the SumQtyOnHand is evaluated. To this point I have been doing the calculations in the PHP instead of the select statement but would like to clean things up a bit where possible.
Current query statement is:
SELECT SorDetail.MStockCode,
SUM(SorDetail.MBackOrderQty) AS 'SumMBackOrderQty',
SUM(InvWarehouse.QtyOnHand) AS 'SumQtyOnHand'
FROM SysproCompanyJ.dbo.SorMaster SorMaster,
SysproCompanyJ.dbo.SorDetail SorDetail LEFT OUTER JOIN SysproCompanyJ.dbo.InvWarehouse InvWarehouse
ON SorDetail.MStockCode = InvWarehouse.StockCode
WHERE SorMaster.SalesOrder = SorDetail.SalesOrder
AND SorMaster.ActiveFlag != 'N'
AND SorDetail.MBackOrderQty > '0'
AND SorDetail.MPrice > '0'
GROUP BY SorDetail.MStockCode
ORDER BY SorDetail.MStockCode ASC
Without providing the complete picture, in terms of your RDBMS, database schema, a description of the problem you're trying to solve and sample data that matches the aforementioned, the following is just an illustration of what a solution based on Barmar's comment could look like:
SELECT SD.MStockCode,
SD.SumBackOrderQty,
IW.SumQtyOnHand
FROM (SELECT MStockCode,
SUM(MBackOrderQty) AS `SumBackOrderQty`
FROM SorDetail
JOIN SorMaster ON SorDetail.SalesOrder=SorMaster.SalesOrder
WHERE SorMaster.ActiveFlag != 'N'
AND SorDetail.MBackOrderQty > 0
AND SorDetail.MPrice > 0
GROUP BY MStockCode) AS SD
LEFT JOIN (SELECT MStockCode,
SUM(QtyOnHand) AS `SumQtyOnHand`
FROM InvWarehouse
GROUP BY MStockCode) AS IW ON SD.MStockCode=IW.MStockCode
ORDER BY SD.MStockCode;
Here's one approach:
select MStockCode,
(select sum(MBackOrderQty) from sorDetail as T2
where T2.MStockCode = T1.MStockCode ) as SumBackOrderQty,
(select sum(QtyOnHand) from invWarehouse as T3
where T3.MStockCode = T1.MStockCode ) as SumQtyOnHand
from
(
select mstockcode from sorDetail
union
select mstockcode from invWarehouse
) as T1
In a fiddle here: http://sqlfiddle.com/#!9/fdaca/6
Though my SumQtyOnHand values don't match yours (as #Gordon pointed out).
I have 3 tables shown below in MS Access 2010:
Table: devices
id | device_id | Company | Version | Revision |
-----------------------------------------------
1 | dev_a | Almaras | 1.5.1 | 0.2A |
2 | dev_b | Enigma | 1.5.1 | 0.2A |
3 | dev_c | Almaras | 1.5.1 | 0.2C |
*Field: device_id is Primary Key Unique String
*Field ID is just an auto-number column
Table: activities
id | act_id | act_date | act_type | act_note |
------------------------------------------------
1 | dev_a | 07/22/2013 | usb_axc | ok |
2 | dev_a | 07/23/2013 | usb_axe | ok | (LAST ROW for dev_a)
3 | dev_c | 07/22/2013 | usb_axc | ok | (LAST ROW for dev_c)
4 | dev_b | 07/21/2013 | usb_axc | ok | (LAST ROW for dev_b)
*Field: act_id contains device_id; NOT UNIQUE
*Field ID is just an auto-number column
Table: matrix
id | mat_id | tc | ts | bat | cycles |
-----------------------------------------
1 | dev_a | 2811 | 10 | 99 | 200 |
2 | dev_a | 2911 | 10 | 97 | 400 |
3 | dev_a | 3007 | 10 | 94 | 600 |
4 | dev_a | 3210 | 10 | 92 | 800 | (LAST ROW for dev_d)
5 | dev_b | 1100 | 5 | 98 | 100 |
6 | dev_b | 1300 | 8 | 93 | 200 |
7 | dev_b | 1411 | 11 | 90 | 300 | (LAST ROW for dev_b)
8 | dev_c | 4000 | 27 | 77 | 478 | (LAST ROW for dev_c)
*Field: mat_id contains device_id; NOT UNIQUE
*Field ID is just an auto-number column
Is there any way to query tables to get results as shown below (each device from devices and only last row added [see example output table] from each of the other two tables):
Query Results:
device_id | Company | act_date | act_type | bat | cycles |
------------------------------------------------------------
device_a | Almaras | 07/23/2013 | usb_axe | 92 | 800 |
device_b | Enigma | 07/21/2013 | usb_axc | 90 | 300 |
device_c | Almaras | 07/22/2013 | usb_axc | 77 | 478 |
Any ideas? Thank you in advance for reading and helping me out :)
I think is what you want,
SELECT a.device_id, a.Company,
b.act_date, b.act_type,
c.bat, c.cycles
FROM ((((devices AS a
INNER JOIN activities AS b
ON a.device_id = b.act_id)
INNER JOIN matrix AS c
ON a.device_id = c.mat_id)
INNER JOIN
(
SELECT act_id, MAX(act_date) AS max_date
FROM activities
GROUP BY act_id
) AS d ON b.act_id = d.act_id AND b.act_date = d.max_date)
INNER JOIN
(
SELECT mat_id, MAX(tc) AS max_tc
FROM matrix
GROUP BY mat_id
) AS e ON c.mat_id = e.mat_id AND c.tc = e.max_tc)
The subqueries: d and e separately gets the latest row for every act_id.
Try
SELECT devices.device_id, devices.Company, activities.act_data, activities.act_type, matrix.bat, matrix.cycles
FROM devices
LEFT JOIN activities
ON devices.device_id = activities.act_id
LEFT JOIN matrix
ON devices.device_id = matrix.mat_id;
What do you consider the "last" row in Matrix?
You need to do something like
WHERE act_date in (SELECT max(a.act_date) from activities a where a.mat_id=d.device_id GROUP BY a.mat_id)
and something similar for the join to matrix.