Group By Multiple Columns, SUM at the first Group By Column - sql

I am writing a query that groups over two columns. this means, it will put Col1 and Col2 in the same group.
How can I do a SUM of records based on Group Col1 ?
I have this so far: http://sqlfiddle.com/#!3/eada2/1
Thank you

I was able to solve it as follows:
WITH cteActivityIds (activityId, allDocuByActivity)
AS
(SELECT activityId, COUNT(*) AS allDocuByActivity FROM #ER GROUP BY activityId)
SELECT
E.activityId AS [Actiivty ID],
docuType AS [Docu Type],
COUNT(docuType),
CONVERT(DECIMAL(16,2), (COUNT(docuType) * 100.00 / t.allDocuByActivity)) [Total DocuType in Activity],
SUM(CASE WHEN [sent] != '1-1-1900' THEN 1 END) AS [Sent],
SUM(CASE WHEN [approved] != '1-1-1900' THEN 1 END) AS [Approved]
FROM
#ER AS E
INNER JOIN cteActivityIds AS t
ON E.activityId = t.activityId
GROUP BY
E.activityId, docuType, t.allDocuByActivity
Thanks

Here is a solution that, in my opinion, looks a little cleaner - it does not require a join and uses 'partition by' to calculate the individual counts:
WITH activityCounts as (
select
activityId,
docuType,
count(activityId) OVER(PARTITION BY activityId) as activityIdCount,
count(docuType) OVER(PARTITION BY activityId, docuType) as docuTypeCount,
SUM(CASE WHEN [sent] != '1-1-1900' THEN 1 END) OVER(PARTITION BY activityId, docuType) AS [Sent],
SUM(CASE WHEN [approved] != '1-1-1900' THEN 1 END) OVER(PARTITION BY activityId, docuType) AS [Approved]
from ER
)
SELECT
activityId,
docuType,
docuTypeCount,
CONVERT(DECIMAL(16,2), (COUNT(docuTypeCount) * 100.00 / activityIdCount)) as [Total DocuType in Activity],
[Sent],
[Approved]
FROM activityCounts
GROUP BY
activityId,
docuType,
activityIdCount,
docuTypeCount,
[Sent],
[Approved]
Here is a link to sqlfiddle

You just need to put an aggregate function on t.allDocuByActivity
MIN(t.allDocuByActivity) AS [Total DocuType in Activity],
However, since your label is DocuType. Don't you need DISTINCT?

Related

CTE function with insert statement

I have 2 queries and I need to combine them into one query with an insert statement.
This is my first query that already has an insert statement:
with q as (
select s.department
,s.months
,s.years
,count(case when s.sum_lost_time >='10:00:00' then NAME end) as RTOTALLOSTTIME
,count(case when s.sum_ot >='20' then NAME end) as ROT
from (select MONTH(STATUSIN) as [months]
,YEAR(STATUSIN) as [years]
,NIP
,NAME
,DEPARTMENT
,convert(varchar,dateadd(second,sum(datediff(second,'00:00:00',cast(TOTALLT as time))),0),108) as sum_lost_time
,SUM(CAST(OT AS FLOAT)) as sum_ot
from SUMMARYDATA b
group by MONTH(STATUSIN)
,YEAR(STATUSIN)
,NIP
,NAME
,DEPARTMENT
)s
group by s.department
,s.months
,s.years
)
INSERT INTO REPORTDATA(DEPARTMENT,MONTHS,YEARS,RTOTALLOSTTIME,ROT)
SELECT DEPARTMENT,MONTHS,YEARS,RTOTALLOSTTIME,ROT
FROM q
This is the result from first query in table REPORTDATA:
And this is my second query.
WITH cte AS
(
SELECT DISTINCT [NAME], DEPARTMENT, MONTH(STATUSIN) [MONTH], YEAR(STATUSIN) [YEAR],
SUM(CASE WHEN LATECOME = '00:00:00' THEN 0 ELSE 1 END) OVER(PARTITION BY [NAME], DEPARTMENT, MONTH(STATUSIN), YEAR(STATUSIN)) Total
,SUM(CASE WHEN EARLYLEAVE = '00:00:00' THEN 0 ELSE 1 END) OVER(PARTITION BY [NAME], DEPARTMENT, MONTH(STATUSIN), YEAR(STATUSIN)) TotalEarlyLeave
FROM SUMMARYDATA
)
SELECT SUM(CASE WHEN TOTAL > 2 THEN 1 ELSE 0 END) LATECOME,
SUM(CASE WHEN TotalEarlyLeave > 1 THEN 1 ELSE 0 END) EARLYLEAVE
FROM cte
GROUP BY DEPARTMENT, [MONTH], [YEAR]
And this is the result from second query:
I want to place it into my first query but I don't know how to combine it into one in insert statement. Can anyone solve my problems?
This is the sample to my first query: Count summary records per month with conditional SQL
and this is the sample to second query: Count records per month with condition in SQL Server
It's easy if you concatenate your queries as multiple CTEs, and finally JOIN them.
Like this :
;
with cte1 as (
select s.department
,s.months
,s.years
,count(case when s.sum_lost_time >='10:00:00' then NAME end) as RTOTALLOSTTIME
,count(case when s.sum_ot >='20' then NAME end) as ROT
from (select MONTH(STATUSIN) as [months]
,YEAR(STATUSIN) as [years]
,NIP
,NAME
,DEPARTMENT
,convert(varchar,dateadd(second,sum(datediff(second,'00:00:00',cast(TOTALLT as time))),0),108) as sum_lost_time
,SUM(CAST(OT AS FLOAT)) as sum_ot
from SUMMARYDATA b
group by MONTH(STATUSIN)
,YEAR(STATUSIN)
,NIP
,NAME
,DEPARTMENT
)s
group by s.department
,s.months
,s.years
),
cte2 as (
SELECT DISTINCT [NAME], DEPARTMENT, MONTH(STATUSIN) [MONTH], YEAR(STATUSIN) [YEAR],
SUM(CASE WHEN LATECOME = '00:00:00' THEN 0 ELSE 1 END) OVER(PARTITION BY [NAME], DEPARTMENT, MONTH(STATUSIN), YEAR(STATUSIN)) Total
,SUM(CASE WHEN EARLYLEAVE = '00:00:00' THEN 0 ELSE 1 END) OVER(PARTITION BY [NAME], DEPARTMENT, MONTH(STATUSIN), YEAR(STATUSIN)) TotalEarlyLeave
FROM SUMMARYDATA
),
cte3 as (
SELECT DEPARTMENT, [MONTH], [YEAR], SUM(CASE WHEN TOTAL > 2 THEN 1 ELSE 0 END) LATECOME,
SUM(CASE WHEN TotalEarlyLeave > 1 THEN 1 ELSE 0 END) EARLYLEAVE
FROM cte2
GROUP BY DEPARTMENT, [MONTH], [YEAR]
)
INSERT INTO REPORTDATA (DEPARTMENT, MONTHS, YEARS, RTOTALLOSTTIME, ROT, RLATECOME, REARLYLEAVE)
SELECT cte1.DEPARTMENT, cte1.MONTHS, cte1.YEARS, cte1.RTOTALLOSTTIME, cte1.ROT,
cte3.LATECOME, cte3.EARLYLEAVE
FROM cte1
LEFT JOIN cte3 ON cte3.DEPARTMENT = cte1.DEPARTMENT and cte3.[MONTH] = cte1.[MONTH] and cte3.[YEAR] = cte1.[YEAR]

expected result is not getting

I have a data like this:
And I want this - I am trying with PIVOT but not getting the expected results:
Query is
SELECT AttendeeID,[Quantity1],[PROD1],[Quantity2],[PROD2],[Quantity3],[PROD3] FROM
(SELECT * ,
row_number() over(partition by AttendeeID order by AttendeeID)rn
from #ProductTestingwithPosition2) TT
PIVOT
(MAX(product) for ProductPosition in ([PROD1],[PROD2],[PROD3])) AS Tab2
PIVOT
(sum(Quantity) for QuantityPosition in ([Quantity1],[Quantity2],[Quantity3])) AS Tab3
I am getting this output:
Just use conditional aggregation:
SELECT AttendeeID,
MAX(CASE WHEN ProductPosition = 'PROD1' THEN product END) as prod1,
MAX(CASE WHEN QuantityPosition = 'QUANTITY1' THEN quantity END) as quantity1,
MAX(CASE WHEN ProductPosition = 'PROD2' THEN product END) as prod2,
MAX(CASE WHEN QuantityPosition = 'QUANTITY2' THEN quantity END) as quantity2,
MAX(CASE WHEN ProductPosition = 'PROD3' THEN product END) as prod3,
MAX(CASE WHEN QuantityPosition = 'QUANTITY3' THEN quantity END) as quantity3
FROM (SELECT ptp.* ,
row_number() over (partition by AttendeeID, ProductPosition order by AttendeeID) as seqnum
FROM #ProductTestingwithPosition2 ptp
) ptp
GROUP BY AttendeeID, seqnum;
PIVOT -- in addition to being non-standard -- is very finicky. Conditional aggregation is much more powerful and less prone to errors.

The same table SQL Joins

I have two select statements, my purpose is to display the sum of billing and the sum of penalty. Can it be done using joins?
SELECT SUM([Amount]) AS 'BILLING',(SELECT SUM([Amount])
FROM Transactions
WHERE CAST([TransactionDate] AS DATE)>(SELECT TOP 1 CAST([TransactionDate] AS DATE)
FROM Transactions WHERE CustNo = 6313 AND [Particulars]='Payment' ORDER BY [Id] DESC)
AND [CustNo]=6313
AND [Particulars]='Penalty') AS 'PENALTY'
FROM Transactions
WHERE CAST([TransactionDate] AS DATE)>(SELECT TOP 1 CAST([TransactionDate] AS DATE)
FROM Transactions WHERE CustNo = 6313
AND [Particulars]='Payment' ORDER BY [Id] DESC)
AND [CustNo]=6313
AND [Particulars]='Billing'
You can use conditional aggregation:
SELECT SUM(CASE WHEN [Particulars]='Billing' THEN [Amount] ELSE 0 END) AS 'BILLING',
SUM(CASE WHEN [Particulars]='Penalty' THEN [Amount] ELSE 0 END) AS 'PENALTY',
FROM Transactions
WHERE CAST([TransactionDate] AS DATE)>(SELECT TOP 1 CAST([TransactionDate] AS DATE)
FROM Transactions WHERE CustNo = 6313
AND [Particulars]='Payment' ORDER BY [Id] DESC)
AND [CustNo]=6313
AND [Particulars]='Billing'

How to get count of a particular row

I have table that contain Id,Date and Status i.e open/close
i just want a result in sql that contain month wise open,close and total count of Id's
e.g In Jan open count 15,close count 5 and total count 20
Use RollUp() and Group By as below:
;WITH T AS
(
SELECT
Id,
DATENAME(MONTH,[Date]) AS [MonthName],
Status
FROM #tblTest
)
SELECT
[MonthName],
[Status],
StatusCount
FROM
(
SELECT
MonthName,
CASE ISNULL(Status,'') WHEN '' THEN 'Total' ELSE Status END AS Status,
Count(Status) AS StatusCount
FROM T
GROUP BY ROLLUP([MonthName],[Status])
)X
WHERE X.MonthName IS NOT NULL
ORDER BY X.[MonthName],X.[Status]
Output:
Note: If required data in single row by month then apply PIVOT
select year(date), month(date),
sum(case when status = 'open' then 1 else 0 end) as open_count,
sum(case when status = 'closed' then 1 else 0 end) as closed_count,
count(*) as total_count
from your_table
group by year(date), month(date)

Get the Highest Value in different Select SUM

I want to get the highest value in my query
Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS'Total Monday',
SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS'Total Tuesday'
FROM tbl_sched
WHERE teacherID='2014279384'
The Output would be TotalMonday ='1' and TotalTuesday ='2'
I need to get the highest value from the outputs which in this case is TotalTuesday=2
select max(daycnt) from
(Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS daycnt
from tbl_sched WHERE teacherID='2014279384'
union all
Select SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS daycnt
from tbl_sched WHERE teacherID='2014279384')
If you need the max between many columns:
Something interesting in SQLServer 2008 and above
SELECT (SELECT Max(v)
FROM (VALUES ([Total Monday]), ([Total Tuesday]), ...) AS value(v)) as [MaxDate]
From
(
Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS'Total Monday',
SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS'Total Tuesday'
..........
FROM tbl_sched
WHERE teacherID='2014279384'
)a
Another option:
SELECT Case When [Total Monday] > [Total Tuesday] then [Total Monday] else [Total Tuesday] End as maxvalue
FROM
(
Select SUM(CASE WHEN Day='Monday' THEN 1 END) AS'Total Monday',
SUM(CASE WHEN Day='Tuesday' THEN 1 END) AS'Total Tuesday'
FROM tbl_sched
WHERE teacherID='2014279384'
)a
I'd say the query below is better in terms of performance and highlights the intention better, because basically we are just GROUPing by days and COUNTing the groups, we don't need CASE's or SUM's (in which case SQL Server will have to go over all the records of the selected teacher).
SELECT TOP 1 Day, COUNT(*) AS Total
FROM tbl_sched
WHERE teacherID='2014279384'
AND Day IN ('Monday','Tuesday')
GROUP BY Day
ORDER BY Total DESC
You can just group by Day, sort by COUNT(*) DESC and get the top count:
SELECT TOP (1)
TotalCount = COUNT(*)
FROM
dbo.tbl_sched
WHERE
teacherID = '2014279384'
GROUP BY
Day
ORDER BY
TotalCount DESC
;
You can also include Day into the output to return the day that had the topmost result.
You can achieve this by using Max Function
Select MAX(SUM(CASE WHEN Day='Monday' THEN 1 END)) AS 'Total Monday',
MAX(SUM(CASE WHEN Day='Tuesday' THEN 1 END)) AS 'Total Tuesday'
FROM tbl_sched
WHERE teacherID='2014279384'