UNION operator in SPARQL updates - sparql

Question

I have two SPARQL updates.First one:
INSERT
{ GRAPH <[http://example/bookStore2]> { ?book ?p ?v } }
WHERE
{ GRAPH <[http://example/bookStore]>
{ ?book dc:date ?date .
FILTER ( ?date > "1970-01-01T00:00:00-02:00"^^xsd:dateTime )
?book ?p ?v
} }
Second:
INSERT
{ GRAPH <[http://example/bookStore2]> { ?book ?p ?v } }
WHERE
{ GRAPH <[http://example/bookStore3]>
{ ?book dc:date ?date .
FILTER ( ?date > "1980-01-01T00:00:00-02:00"^^xsd:dateTime )
?book ?p ?v
} }
Can i combine them with the UNION operator? And if yes, is it an equivalent result? Is it possible to use UNION in SPARQL updates such as in "Select"?

Answer 1

AndyS's answer is correct; you can combine them, and the description of UNION is found in section 7 Matching Alternatives of the SPARQL specification. The combined query would be:
INSERT {
GRAPH <[http://example/bookStore2]> { ?book ?p ?v }
}
WHERE{
{
GRAPH <[http://example/bookStore]> {
?book dc:date ?date .
FILTER ( ?date > "1970-01-01T00:00:00-02:00"^^xsd:dateTime )
?book ?p ?v
}
}
UNION
{
GRAPH <[http://example/bookStore3]> {
?book dc:date ?date .
FILTER ( ?date > "1980-01-01T00:00:00-02:00"^^xsd:dateTime )
?book ?p ?v
}
}
}
In this particular case where the patterns are so similar, you could also just abstract out the differing parts with VALUES:
INSERT {
GRAPH <[http://example/bookStore2]> { ?book ?p ?v }
}
WHERE{
values (?graph ?startDate) {
(<[http://example/bookStore]> "1970-01-01T00:00:00-02:00"^^xsd:dateTime)
(<[http://example/bookStore3]> "1980-01-01T00:00:00-02:00"^^xsd:dateTime)
}
GRAPH ?graph {
?book dc:date ?date .
FILTER ( ?date > ?startDate )
?book ?p ?v
}
}

Answer 2

The WHERE clause is the same as SPARQL Query - you can use UNION.