Let say I have the following table (The ID is self incremental)
ID Name Serial Status
0 Pie A Fail
1 Pie A Fail
2 Pie A Pass
3 Pie B Fail
4 Pie B Pass
5 Pie C Pass
6 Pie C Fail
How can I get all the rows where the last row of each Group By (Name, Serial) is Pass?
This is the result I should get from the query. The serial C is removed since the last entry of the group by (Name, Serial) is 'Fail'
ID Name Serial Status
0 Pie A Fail
1 Pie A Fail
2 Pie A Pass
3 Pie B Fail
4 Pie B Pass
Thanks!
I would try something like this (assuming SQL Server):
DECLARE #myTable AS TABLE(
ID INT,
Name VARCHAR(10),
Serial VARCHAR(1),
[Status] VARCHAR(10))
INSERT INTO #myTable VALUES(0, 'Pie', 'A', 'Fail')
INSERT INTO #myTable VALUES(1, 'Pie', 'A', 'Fail')
INSERT INTO #myTable VALUES(2, 'Pie', 'A', 'Pass')
INSERT INTO #myTable VALUES(3, 'Pie', 'B', 'Fail')
INSERT INTO #myTable VALUES(4, 'Pie', 'B', 'Pass')
INSERT INTO #myTable VALUES(5, 'Pie', 'C', 'Pass')
INSERT INTO #myTable VALUES(6, 'Pie', 'C', 'Fail')
SELECT *
FROM #myTable
WHERE Serial NOT IN
(
--Get all Serial that end with a 'Fail'
SELECT T1.Serial
FROM #myTable T1
JOIN (
--Get Max ID for a serial
SELECT MAX(ID) as [ID] FROM #myTable GROUP BY Serial
) T2 ON T1.[ID] = T2.[ID]
WHERE T1.[Status] = 'Fail'
)
ORDER BY [ID]
or if you prefer NOT EXISTS (which is usually faster than NOT IN):
SELECT *
FROM #myTable T
WHERE NOT EXISTS
(
SELECT
T1.Serial
FROM #myTable T1
JOIN (
--Get Max ID for a serial
SELECT MAX(ID) as [ID] FROM #myTable GROUP BY Serial
) T2 ON T1.[ID] = T2.[ID]
WHERE
T1.[Status] = 'Fail'
AND T1.[Serial] = T.[Serial]
)
ORDER BY [ID]
We can use CTE to improve readability by implementing as a series of sequential steps:
Get max ids
Get serials for max ids that have status 'Fail'
Remove those rows that match the serials
It would look like this:
with maxIds as ( --Get max Ids
SELECT MAX(ID) as [ID] FROM myTable GROUP BY Serial
),
serials as ( -- Get serials for max ids that have status 'Fail'
SELECT T1.Serial FROM myTable T1 JOIN maxIds ON T1.[ID] = maxIds.[ID] WHERE [Status] = 'Fail'
)
select * from myTable where serial not in (select * from serials) -- Remove serials that match
Related
I have a scenario wherein I need to find the ID which only has start and END in it. Below is the table for reference.
Declare #T Table ( ID int, Name varchar(100))
Insert into #T values (1,'Start')
Insert into #T values (1,'END')
Insert into #T values (1,'Stuart')
Insert into #T values (1,'robin')
Insert into #T values (2,'Start')
Insert into #T values (2,'END')
Insert into #T values (3,'Start')
Insert into #T values (4,'END')
I want the Output as:
ID Name
2 Start
2 END
I want those ID which only has start and end in it.
What I tried so far:
SELECT * FROM #T t
WHERE EXISTS (SELECT * FROM #T WHERE id = t.id AND name = 'start')
AND EXISTS (SELECT * FROM #T WHERE id = t.id AND name = 'END')
But my query is giving ID 1 as well.
Can someone please help me rectify the problem.
I presume your issue is that record 1 has a 'Stuart' in it too?
As such, you can do a similar check in the WHERE e.g.,
SELECT * FROM #T t
WHERE EXISTS (SELECT * FROM #T WHERE id = t.id AND name = 'start')
AND EXISTS (SELECT * FROM #T WHERE id = t.id AND name = 'END')
AND NOT EXISTS (SELECT * FROM #T WHERE id = t.id AND name NOT IN ('start','END'))
Note that you may want to consider
What happens if you have two 'start' rows or two 'end' rows (e.g., start-start-end)? Can you even have two 'start' rows (e.g., start-start)?
What happens if you have a blank/NULL (e.g., start-NULL-end)?
EDIT: removed 'What happens if they're out of order (e.g., end-start)?' as a question as there is no sorting in the data at all (e.g., not even an implicit sort).
You can go for CTE to get group wise count and total count as 2.
Declare #T Table ( ID int, Name varchar(100))
Insert into #T values (1,'Start')
Insert into #T values (1,'END')
Insert into #T values (1,'Stuart')
Insert into #T values (1,'robin')
Insert into #T values (2,'Start')
Insert into #T values (2,'END')
Insert into #T values (3,'Start')
Insert into #T values (4,'END')
;WITH CTE_Total_StartEnd AS
(
select id, count(*) AS Total_Cnt
, COUNT( case when Name IN ('Start') THEN 1 END) as start_cnt
, COUNT( case when Name IN ('End') THEN 1 END) as end_cnt
from #t
group by id
having COUNT( case when Name IN ('Start') THEN 1 END) =1 and
COUNT( case when Name IN ('End') THEN 1 END) = 1 and
count(*) = 2
)
SELECT t.* from #t t
inner join CTE_Total_StartEnd as c
ON c.id = t.id
+----+-------+
| ID | Name |
+----+-------+
| 2 | Start |
| 2 | END |
+----+-------+
You can do this by using group by function also like below
WITH cte AS
(
SELECT 1 AS id , 'Start' AS name
UNION ALL
SELECT 1 AS id ,'END' AS name
UNION ALL
SELECT 1 AS id ,'Stuart' AS name
UNION ALL
SELECT 1 AS id ,'robin' AS name
UNION ALL
SELECT 2 AS id ,'Start' AS name
UNION ALL
SELECT 2 AS id ,'END' AS name
UNION ALL
SELECT 3 AS id ,'Start' AS name
UNION ALL
SELECT 4 AS id ,'END' AS name
)
SELECT T.ID,SUM(T.VAL)AS SUM
FROM
(
SELECT id,name , CASE WHEN name='Start' THEN 1
WHEN name='END' THEN 2
ELSE 3
END AS VAL
FROM cte
)T
GROUP BY T.ID
HAVING SUM(T.VAL) =3
could you please try this? Pls note i added collate command in the end of sql.
SQL Server check case-sensitivity?
SELECT * FROM #T t
WHERE EXISTS (SELECT * FROM #T WHERE id = t.id AND name = 'start' COLLATE SQL_Latin1_General_CP1_CS_AS)
AND EXISTS (SELECT * FROM #T WHERE id = t.id AND name = 'END' COLLATE SQL_Latin1_General_CP1_CS_AS)
This is my existing table
In this table, each user has their own respective data according to their Status. Each of the user will surely have Status 1.
Now, there are 3 Status to be stored for every user.
Was trying to make every user to have 3 Status, by inserting new row of user copying their Status 1 data, such that:
User Ali currently only have Status 1 and its data, so need insert a new
row Ali with Status 2 and copy along the data from Status 1, again,
insert a new row Ali with Status 3 and copy along the data from
Status 1.
User John currently only have Status 1 and 2, so need insert a new
row John with Status 3 and copy along the data from Status 1.
continue same pattern with other user
Expected result:
I would use CROSS JOIN and NOT EXISTS
with data as
(
select name,
column1,
column2
from your_table
where status = 1
), cross_join_data as
(
select d1.name, t.status, d1.column1, d1.column2
from data d1
cross join
(
select 1 status
union
select 2 status
union
select 3 status
) t
where not exists (
select 1
from your_table d2
where d2.name = d1.name and
d2.status = t.status
)
)
select *
from your_table
union all
select *
from cross_join_data
dbfiddle demo
This should work
with cte as (
select
[Name], coalesce(max(iif([Status]=1, [Column1], null)), max(iif([Status]=2, [Column1], null)), max(iif([Status]=3, [Column1], null))) col1
, coalesce(max(iif([Status]=1, [Column2], null)), max(iif([Status]=2, [Column2], null)), max(iif([Status]=3, [Column2], null))) col2
from
MyTable
group by [Name]
)
--insert into MyTable
select
cte.[Name], nums.n, cte.col1, cte.col2
from
cte
cross join (values (1),(2),(3)) nums(n)
left join MyTable on cte.[Name]=MyTable.[Name] and n=MyTable.[Status]
where
MyTable.[Status] is null
This works if data is not nullable
declare #table table (name varchar(10), status int, data int);
insert into #table values
('a', 1, 2)
, ('a', 2, 5)
, ('a', 3, 7)
, ('b', 1, 5)
, ('b', 2, 6)
, ('c', 1, 3)
select stats.status as statusStats
, tn.name as nameTN
, t.status as statusData, t.name, t.data
, ISNULL(t.data, t1.data) as 'fillInData'
from (values (1),(2),(3)) as stats(status)
cross join (select distinct name from #table) tn
left join #table t
on t.status = stats.status
and t.name = tn.name
join #table t1
on t1.name = tn.name
and t1.status = 1
order by tn.name, stats.status
Here is what I would do:
CREATE TABLE #existingtable (Name VARCHAR(50), Status INT, Column1 VARCHAR (10), Column2 VARCHAR(10));
INSERT INTO #existingtable (Name,Status,Column1,Column2) Values('Ali',1,'100','90');
INSERT INTO #existingtable (Name,Status,Column1,Column2) Values('John',1,'20','200');
INSERT INTO #existingtable (Name,Status,Column1,Column2) Values('John',2,'80','90');
INSERT INTO #existingtable (Name,Status,Column1,Column2) Values('Ming',1,'54','345');
INSERT INTO #existingtable (Name,Status,Column1,Column2) Values('Mei',1,'421','123');
INSERT INTO #existingtable (Name,Status,Column1,Column2) Values('Mei',3,'24','344');
SELECT * FROM #existingtable;
WITH CTE (Name,Column1,Column2)
AS
(
SELECT DISTINCT NAME,COLUMN1,COLUMN2
FROM #existingtable
)
, CTE2 (NAME,Status,Column1,Column2)
AS
(
SELECT NAME,1 AS STATUS,COLUMN1,COLUMN2
FROM CTE
UNION
SELECT NAME,2 AS STATUS,COLUMN1,COLUMN2
FROM CTE
UNION
SELECT NAME,3 AS STATUS,COLUMN1,COLUMN2
FROM CTE
)
INSERT INTO #existingtable (Name,Status,Column1,Column2)
SELECT C.Name,C.Status,C.Column1,C.Column2
FROM CTE2 AS C
LEFT JOIN #existingtable AS E
ON C.NAME = E.Name
AND C.Status = E.Status
WHERE E.Status IS NULL
SELECT * FROM #existingtable
ORDER BY Name, status
This has 2 edits. Initial edit added a where clause to the CTE
Second edit added the values added by the OP
Table1
Id bigint primary key identity(1,1)
Status nvarchar(20)
Insert dummy data
Insert into Table1 values ('Open') --1
Insert into Table1 values ('Open') --2
Insert into Table1 values ('Grabbed') --3
Insert into Table1 values ('Closed') --4
Insert into Table1 values ('Closed') --5
Insert into Table1 values ('Open') --6
How would I construct a single select statement which orders the data where records with 'Grabbed' status is first, followed by 'Closed', followed by 'Open' in SQL Server
Output:
Id Status
3 Grabbed
4 Closed
5 Closed
1 Open
2 Open
6 Open
I think you need something like this:
select *
from yourTable
order by case when Status = 'Grabbed' then 1
when Status = 'Closed' then 2
when Status = 'Open' then 3
else 4 end
, Id;
[SQL Fiddle Demo]
Another way is to using CTE like this:
;with cte as (
select 'Grabbed' [Status], 1 [order]
union all select 'Closed', 2
union all select 'Open', 3
)
select t.*
from yourTable t
left join cte
on t.[Status] = cte.[Status]
order by cte.[order], Id;
[SQL Fiddle Demo]
This could be done much better with a properly normalized design:
Do not store your Status as a textual content. Just imagine a typo (a row with Grabed)...
Further more a lookup table allows you to add side data, e.g. a sort order.
CREATE TABLE StatusLookUp(StatusID INT IDENTITY PRIMARY KEY /*you should name your constraints!*/
,StatusName VARCHAR(100) NOT NULL
,SortRank INT NOT NULL)
INSERT INTO StatusLookUp VALUES
('Open',99) --ID=1
,('Closed',50)--ID=2
,('Grabbed',10)--ID=3
CREATE TABLE Table1(Id bigint primary key identity(1,1) /*you should name your constraints!*/
,StatusID INT FOREIGN KEY REFERENCES StatusLookUp(StatusID));
Insert into Table1 values (1) --1
Insert into Table1 values (1) --2
Insert into Table1 values (3) --3
Insert into Table1 values (2) --4
Insert into Table1 values (2) --5
Insert into Table1 values (1) --6
SELECT *
FROM Table1 AS t1
INNER JOIN StatusLookUp AS s ON t1.StatusID=s.StatusID
ORDER BY s.SortRank;
I find that the simplest method uses a string:
order by charindex(status, 'Grabbed,Closed,Open')
or:
order by charindex(',' + status + ',', ',Grabbed,Closed,Open,')
If you are going to put values in the query, I think the easiest way uses values():
select t1.*
from t1 left join
(values ('Grabbed', 1), ('Closed', 2), ('Open', 3)) v(status, priority)
on t1.status = v.status
order by coalesce(v.priority, 4);
Finally. This need suggests that you should have a reference table for statuses. Rather than putting the string name in other tables, put an id. The reference table can have the priority as well as other information.
Try this:
select Id,status from tablename where status='Grabbed'
union
select Id,status from tablename where status='Closed'
union
select Id,status from tablename where status='Open'
My script is as below
CREATE TABLE #t (Id int, Name varchar(10))
INSERT INTO #t VALUES (1, 'A')
INSERT INTO #t VALUES (1, 'B')
INSERT INTO #t VALUES (1, 'C')
INSERT INTO #t VALUES (1, 'D')
INSERT INTO #t VALUES (2, 'E')
SELECT COUNT(0)FROM (SELECT COUNT(0) FROM #t GROUP BY Id) a
but I am getting an error
Msg 8155, Level 16, State 2, Line 5
No column name was specified for column 1 of 'A'.
When you use a subquery, all the columns need to given names:
SELECT COUNT(0)
FROM (SELECT COUNT(0) as cnt FROM #t GROUP BY Id
) a;
However, a simpler way to write this is:
SELECT COUNT(DISTINCT id)
FROM #t;
Actually, this isn't exactly the same. Your version will count NULL values but this does not. The exact equivalent is:
SELECT COUNT(DISTINCT id) + MAX(CASE WHEN id IS NULL THEN 1 ELSE 0 END)
FROM #t;
I ran into an interesting SQL problem today and while I came up with a solution that works I doubt it's the best or most efficient answer. I defer to the experts here - help me learn something and improve my query! RDBMS is SQL Server 2008 R2, query is part of an SSRS report that will run against about 100,000 rows.
Essentially I have a list of IDs that could have multiple values associated with them, the values being Yes, No, or some other string. For ID x, if any of the values are a Yes, x should be Yes, if they are all No, it should be No, if they contain any other values but yes and no, display that value. I only want to return 1 row per ID, no duplicates.
The simplified version and test case:
DECLARE #tempTable table ( ID int, Val varchar(1) )
INSERT INTO #tempTable ( ID, Val ) VALUES ( 10, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 11, 'N')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 11, 'N')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 12, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 12, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 12, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 13, 'N')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 14, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 14, 'N')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 15, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 16, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 17, 'F')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 18, 'P')
SELECT DISTINCT t.ID, COALESCE(t2.Val, t3.Val, t4.Val)
FROM #tempTable t
LEFT JOIN
(
SELECT ID, Val
FROM #tempTable
WHERE Val = 'Y'
) t2 ON t.ID = t2.ID
LEFT JOIN
(
SELECT
ID, Val FROM #tempTable
WHERE Val = 'N'
) t3 ON t.ID = t3.ID
LEFT JOIN
(
SELECT ID, Val
FROM #tempTable
WHERE Val <> 'Y' AND Val <> 'N'
) t4 ON t.ID = t4.ID
Thanks in advance.
Let's answer an easier problem: for each id, get the Val which is last in the alphabet. This will work if Y and N are the only values. And the query is much simpler:
SELECT t.ID, MAX(t.Val) FROM t GROUP BY t.ID;
So, reduce your case to the simple case. Use an enum (if your DB supports it) or break the value codes into another table with a collation column (in this case, you could have 1 for Y, 2 for N, and 999 for all other possible values, and you want the smallest). Then
SELECT ID, c.Val FROM
(SELECT t.ID, MIN(codes.collation) AS mx
FROM t join codes on t.Val = codes.Val GROUP BY t.ID) AS q
JOIN codes c ON mx=c.collation;
Here codes has two columns, Val and Collation.
You can also do this with a CTE type query, as long as you have the Values ordered as you want them. This approach has one join to a small lookup table and should be much, much faster than 3 self-joins.
WITH q AS (SELECT t.id, t.Val, ROW_NUMBER() AS r FROM t JOIN codes ON t.Val=codes.Val
PARTITION BY t.id ORDER BY codes.collation)
SELECT q.id, q.Val WHERE r=1;
I'd change it to this just to make it easier to read:
SELECT DISTINCT t.ID, COALESCE(t2.Val, t3.Val, t4.Val)
FROM #tempTable t
LEFT JOIN #tempTable t2 ON t.ID = t2.ID and t2.Val = 'Y'
LEFT JOIN #tempTable t3 ON t.ID = t3.ID and t3.Val = 'N'
LEFT JOIN #tempTable t4 ON t.ID = t4.ID and t4.Val <> 'Y' AND t4.Val <> 'N'
Gives the same results as your example.
I also looked at the execution plans for both and they looked exactly the same, I doubt you'd see any performance difference.
Try this:
;WITH a AS (
SELECT
ID,
SUM(CASE Val WHEN 'Y' THEN 1 ELSE 0 END) AS y,
SUM(CASE Val WHEN 'N' THEN 0 ELSE 1 END) AS n,
MIN(CASE WHEN Val IN ('Y','N') THEN NULL ELSE Val END) AS first_other
FROM #tempTable
GROUP BY ID
)
SELECT
ID,
CASE WHEN y > 0 THEN 'Y' WHEN n = 0 THEN 'N' ELSE first_other END AS Val
FROM a
If there are any 'Y' values then the sum of y will be greater than 0
If all values are 'N' then the sum of n will be zero
Get the first non 'Y' or 'N' character available if needed
In this case the result can be determined with only one pass through
the table
I'm reading your spec like this:
if any ID is Y then Y
if all IDs are N then N
else display value (other than Y or N)
eliminate rows per (1)
delete from #tempTable
where not Val='Y' and ID in (
select distinct ID
from #tempTable
where Val='Y'
)
select distinct to eliminate multiple N's per (2).
select distinct * from #tempTable
group up various "other" values to get a single row per ID.
SELECT A.Id, AllVals =
SubString(
(SELECT ', ' + B.Val
FROM C as B
WHERE A.Id = B.Id
FOR XML PATH ( '' ) ), 3, 1000)
FROM C as A
GROUP BY Id
Entire runnable query:
declare #tempTable table (ID int, Val char(1))
INSERT INTO #tempTable ( ID, Val ) VALUES ( 10, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 11, 'N')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 11, 'N')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 12, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 12, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 12, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 13, 'N')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 14, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 14, 'N')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 15, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 16, 'Y')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 17, 'F')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 18, 'P')
INSERT INTO #tempTable ( ID, Val ) VALUES ( 18, 'F')
delete from #tempTable
where not Val='Y' and ID in (
select distinct ID
from #tempTable
where Val='Y'
);
WITH C as (select distinct * from #tempTable)
SELECT A.Id, AllVals =
SubString(
(SELECT ', ' + B.Val
FROM C as B
WHERE A.Id = B.Id
FOR XML PATH ( '' ) ), 3, 1000)
FROM C as A
GROUP BY Id
OUTPUT:
Id AllVals
10 Y
11 N
12 Y
13 N
14 Y
15 Y
16 Y
17 F
18 F, P