I am sorry for this but my previous question was not properly framed, so creating another post.
My question is similar to following question:
http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:14582643282111
I need to write inner query which will give me a list of dates between two date ranges to outer query.
My inner query returns following 2 rows:
SELECT request.REQ_DATE, request.DUE_DATE FROM myTable where id = 100
REQ_DATE DUE_DATE
3/19/2013 3/21/2013
3/8/2013 3/8/2013
So I need inner query which will return following dates to outer query:
3/19/2013
3/20/2013
3/21/2013
3/8/2013
The answer in above post has start date and end date hard coded and in my case, it is coming from other table. So I am trying to write query like this which does not work:
Select * from outerTable where my_date in
(
select to_date(r.REQ_DATE) + rownum -1 from all_objects,
(
SELECT REQ_DATE, DUE_DATE
FROM myTable where id = 100
) r
where rownum <= to_date(r.DUE_DATE,'dd-mon-yyyy')-to_date(r.REQ_DATE,'dd-mon-yyyy')+1;
)
with
T_from_to as (
select
trunc(REQ_DATE) as d_from,
trunc(DUE_DATE) as d_to
FROM myTable
where id = 100
),
T_seq as (
select level-1 as delta
from dual
connect by level-1 <= (select max(d_to-d_from) from T_from_to)
)
select distinct d_from + delta
from T_from_to, T_seq
where d_from + delta <= d_to
order by 1
Related
I have following table structure: http://sqlfiddle.com/#!4/952e7/1
Now I am looking for a solution for the following problem:
Given an input data-time set (see below). And the SQL statement should return all of business IDs with a given business name, where every single date-times of the input set are either present in the ORDERS table or an additional function's statement is true (these both conditions are separately to be checked for each input date-time).
An example how the input date-time dataset looks like:
WITH DATES_TO_CHECK(DATETIME) AS(SELECT DATE '2021-01-03' FROM DUAL UNION ALL SELECT DATE '2020-04-08' FROM DUAL UNION ALL SELECT DATE '2020-05-07' FROM DUAL)
To be simple, the "additional function" should be a simple random number (if greather than 0.5 than true otherwise false, so the check is dbms_random.value > 0.5).
For one given date time it would look like:
SELECT BN.NAME, BD.ID
FROM BUSINESS_DATA BD, BUSINESS_NAME BN
WHERE BD.NAME_ID=BN.ID AND
BN.NAME='B1' AND
(TO_DATE('2021-01-03', 'YYYY-MM-DD') IN (SELECT OD.ORDERDATE FROM ORDERS OD WHERE OD.BUSINESS_ID=BD.ID)
OR dbms_random.value > 0.5)
ORDER BY BD.ID
Please help me, how this solution can be applied to the input date-time rowset above AND the specified name.
I don't any difference with the question you just deleted
This is the list of businesses named B1 and for which the number of order dates that match date input dates is equal to the number of input dates or dbms_random.value > 0.5
see SQL Fiddle
WITH DATES_TO_CHECK(DATETIME) AS(
SELECT DATE '2021-01-03' FROM DUAL
UNION ALL SELECT DATE '2020-04-08' fROM DUAL
UNION ALL SELECT DATE '2020-05-07' fROM DUAL
),
businesses_that_match as (
select
od.BUSINESS_ID, count(distinct OD.ORDERDATE)
from DATES_TO_CHECK dtc
left join ORDERS od on OD.ORDERDATE = dtc.datetime
group by od.BUSINESS_ID
having count(distinct OD.ORDERDATE) = (select count(distinct DATETIME) from DATES_TO_CHECK)
)
SELECT
BN.NAME, BD.ID
FROM BUSINESS_DATA BD
inner join BUSINESS_NAME BN on BD.NAME_ID=BN.ID
left join businesses_that_match btm on btm.BUSINESS_ID = bd.id
where bn.name = 'B1'
AND (btm.BUSINESS_ID is not null
OR dbms_random.value > 0.5
)
table A
no date count
1 20160401 1
1 20160403 4
2 20160407 3
result
no date count
1 20160401 1
1 20160402 0
1 20160403 4
1 20160404 0
.
.
.
2 20160405 0
2 20160406 0
2 20160407 3
.
.
.
I'm using Oracle and I want to write a query that returns rows for every date within a range based on table A.
Is there some function in Oracle that can help me?
you can use the SEQUENCES.
First create a sequence
Create Sequence seq_name start with 20160401 max n;
where n is the max value till u want to display.
Then use the sql
select seq_name.next,case when seq_name.next = date then count else 0 end from tableA;
Note:- Its better not to use date,count as the column names.
Try this:
with
A as (
select 1 no, to_date('20160401', 'yyyymmdd') dat, 1 cnt from dual union all
select 1 no, to_date('20160403', 'yyyymmdd') dat, 4 cnt from dual union all
select 2 no, to_date('20160407', 'yyyymmdd') dat, 3 cnt from dual),
B as (select min(dat) mindat, max(dat) maxdat from A t),
C as (select level + mindat - 1 dat from B connect by level + mindat - 1 <= maxdat),
D as (select distinct no from A),
E as (select * from D,C)
select E.no, E.dat, nvl(cnt, 0) cnt
from E
full outer join A on A.no = E.no and A.dat = E.dat
order by 1, 2, 3
This isn't an oracle specific answer, you'll need to translate it to oracle yourself.
Create an intervals table, containing all integers from 0 to 999. Something like this:
CREATE TABLE intervals (days int);
INSERT INTO intervals (days) VALUES (0), (1);
DECLARE #rc int;
SELECT #rc = 2;
WHILE (SELECT Count(*) FROM intervals) < 1000 BEGIN
INSERT INTO intervals (days) SELECT days + #rc FROM intervals WHERE days + #rc < 1000;
SELECT #rc = #rc * 2
END;
Then all the dates in the range can be identified by adding intervals.days to the first date you've got, where the first date + intervals.days is <= the end date, and the resultant date is new. Do this by cross joining intervals to your own table. Something like (it would be in SQL, but again you'll need to translate):
SELECT DateAdd(a.date, d, i.days)
FROM (select min(date) from table_A) a, intervals I
WHERE DateAdd(a.date, d, i.days) < (select max(date) from table_A)
AND NOT EXISTS (select 1 from table_A aa where aa.date = DateAdd(a.date, d, i.days))
Hope this gives you a starting point
Hello i have a problem with a simple query. I need to see the max date of some articles in two direfent sites.
This is my actual query:
SELECT a.aa_codart, MAX(t.tr_fechafac), t.tr_tipo
FROM ARTALM a, traspaso t
WHERE t.tr_codart = a.aa_codart
and t.tr_tipomov > 1
and a.aa_codalm = '1'
and (t.tr_tipo >= 1 and t.tr_tipo <=2)
group by a.aa_codart, t.tr_tipo;
And the result:
01..FRB10X80 30/11/07 2
01..FRB10X80 08/03/01 1
01.32122RS 05/02/16 1
01.32122RS 02/07/10 2
01.33052Z 21/09/15 1
01.60042Z 24/02/16 2
I want, for example in the two first rows, see only one row, like this:
01..FRB10X80 30/11/07 2
01.32122RS 05/02/16 1
01.33052Z 21/09/15 1
01.60042Z 24/02/16 2
Taking the max date
Thanks
This calls for an analytical query. This query shows how the ROW_NUMBER() function will assign the value 1 to the row with the article's most recent date. Give it a try first to help understand the final query, coming up next:
SELECT
a.aa_codart,
t.tr_fechafac,
t.tr_tipo,
ROW_NUMBER() OVER (PARTITION BY a.aa_codart ORDER BY t.tr_fechafac DESC) as rnk
FROM artalm a
INNER JOIN trapaso t ON a.aa_codart = t.tr_codart
WHERE t.tr_tipomov > 1
AND a.aa_codalm = '1'
AND t.tr_tipo BETWEEN 1 AND 2
You can't apply the WHERE clause to the rnk column because the column is calculated after the WHERE clause. You can get around this using a nested query:
SELECT * FROM (
SELECT
a.aa_codart,
t.tr_fechafac,
t.tr_tipo,
ROW_NUMBER() OVER (PARTITION BY a.aa_codart ORDER BY t.tr_fechafac DESC) as rnk
FROM artalm a
INNER JOIN trapaso t ON a.aa_codart = t.tr_codart
WHERE t.tr_tipomov > 1
AND a.aa_codalm = '1'
AND t.tr_tipo BETWEEN 1 AND 2
) WHERE rnk = 1;
I apologize in advance for any column names I may have retyped badly. The Oracle syntax should be fine; the column names maybe not so much :)
I think you may want to look at row_number() (then just pick the ones where it is one) something like this.
WITH t
AS (SELECT 'A' aa_codart,
TO_DATE ('17/05/00', 'dd/mm/yy') mydt,
1 tr_tipo
FROM DUAL
UNION ALL
SELECT 'A', TO_DATE ('12/04/00', 'dd/mm/yy'), 2 FROM DUAL
UNION ALL
SELECT 'B', TO_DATE ('30/06/98', 'dd/mm/yy'), 2 FROM DUAL
UNION ALL
SELECT 'C', TO_DATE ('30/06/98 ', 'dd/mm/yy'), 2 FROM DUAL),
t2
AS (SELECT aa_codart,
mydt,
tr_tipo,
ROW_NUMBER ()
OVER (PARTITION BY aa_codart ORDER BY mydt DESC)
rn
FROM t)
SELECT *
FROM t2
WHERE rn = 1
I am having no luck attempting to get the top (x number) of rows from a joined table. I want the top 2 resources (ordered by name) which in this case should be Katie and Simon and regardless of what I've tried, I can't seem to get it right. You can see below what I've commented out - and what looks like it should work (but doesn't). I cannot use a union. Any ideas?
select distinct
RTRESOURCE.RNAME as Resource,
RTTASK.TASK as taskname, SUM(distinct SOTRAN.QTY2BILL) AS quantitytobill from SOTRAN AS SOTRAN INNER JOIN RTTASK AS RTTASK ON sotran.taskid = rttask.taskid
left outer JOIN RTRESOURCE AS RTRESOURCE ON rtresource.keyno=sotran.resid
WHERE sotran.phantom<>'y' and sotran.pgroup = 'L' and sotran.timesheet = 'y' and sotran.taskid >0 AND RTRESOURCE.KEYNO in ('193','159','200') AND ( SOTRAN.ADDDATE>='8/15/2015 12:00:00 AM' AND SOTRAN.ADDDATE<'9/3/2015 11:59:59 PM' )
//and RTRESOURCE.RNAME in ( select distinct top 2 RTRESOURCE.RNAME from RTRESOURCE order by RTRESOURCE.RNAME)
//and ( select count(*) from RTRESOURCE RTRESOURCE2 where RTRESOURCE2.RNAME = RTRESOURCE.RNAME ) <= 2
GROUP BY RTRESOURCE.rname,RTTASK.task,RTTASK.taskid,RTTASK.mdsstring ORDER BY Resource,taskname
You should provide a schema.
But lets assume your query work. You create a CTE.
WITH youQuery as (
SELECT *
FROM < you big join query>
), maxBill as (
SELECT Resource, Max(quantitytobill) as Bill
FROM yourQuery
)
SELECT top 2 *
FROM maxBill
ORDER BY Bill
IF you want top 2 alphabetical
WITH youQuery as (
SELECT *
FROM < you big join query>
), Names as (
SELECT distinct Resource
FROM yourQuery
Order by Resource
)
SELECT top 2 *
FROM Names
suppose there are records as follows:
Employee_id, work_start_date, work_end_date
1, 01-jan-2014, 07-jan-2014
1, 03-jan-2014, 12-jan-2014
1, 23-jan-2014, 25-jan-2014
2, 15-jan-2014, 25-jan-2014
2, 07-jan-2014, 15-jan-2014
2, 09-jan-2014, 12-jan-2014
The requirement is to write an SQL select statment which would summarize the work days grouped by employee_id, but exclude the overlapped periods (meaning - take them into calculation only once).
The desired output would be:
Employee_id, worked_days
1, 13
2, 18
The calculations for working days in the date range are done like this:
If work_start_date = 5 and work_end_date = 9 then worked_days = 4 (9 - 5).
I could write a pl/sql function which solves this (manually iterating over the records and doing the calculation), but I'm sure it can be done using SQL for better performance.
Can someone please point me in the right direction?
Thanks!
This is a slightly modified query from similar question:
compute sum of values associated with overlapping date ranges
SELECT "Employee_id",
SUM( "work_end_date" - "work_start_date" )
FROM(
SELECT "Employee_id",
"work_start_date" ,
lead( "work_start_date" )
over (Partition by "Employee_id"
Order by "Employee_id", "work_start_date" )
As "work_end_date"
FROM (
SELECT "Employee_id", "work_start_date"
FROM Table1
UNION
SELECT "Employee_id","work_end_date"
FROM Table1
) x
) x
WHERE EXISTS (
SELECT 1 FROM Table1 t
WHERE t."work_start_date" > x."work_end_date"
AND t."work_end_date" > x."work_start_date"
OR t."work_start_date" = x."work_start_date"
AND t."work_end_date" = x."work_end_date"
)
GROUP BY "Employee_id"
;
Demo: http://sqlfiddle.com/#!4/4fcce/2
This is a tricky problem. For instance, you can't use lag(), because the overlapping period may not be the "previous" one. Or different periods can start and or stop on the same day.
The idea is to reconstruct the periods. How to do this? Find the records where the periods start -- that is, there is no overlap with any other. Then use this as a flag and count this flag cumulatively to count overlapping groups. Then getting the working days is just aggregation from there:
with ps as (
select e.*,
(case when exists (select 1
from emps e2
where e2.employee_id = e.employee_id and
e2.work_start_date <= e.work_start_date and
e2.work_end_date >= e.work_end_date
)
then 0 else 1
) as IsPeriodStart
from emps e
)
select employee_id, sum(work_end_date - work_start_date) as Days_Worked
from (select employee_id, min(work_start_date) as work_start_date,
max(work_end_date) as work_end_date
from (select ps.*,
sum(IsPeriod_Start) over (partition by employee_id
order by work_start_date
) as grp
from ps
) ps
group by employee_id, grp
) ps
group by employee_id;
date_tbl type
create or replace package RG_TYPE is
type date_tbl is table of date;
end;
function (result as a table with the dates between 2 parameters)
create or replace function dates
(
p_from date,
p_to date
) return rg_type.date_tbl pipelined
is
l_idx date:=p_from;
begin
loop
if l_idx>nvl(p_to,p_from) then
exit;
end if;
pipe row(l_idx);
l_idx:=l_idx+1;
end loop;
return;
end;
SQL:
select employee_id,sum(c)
from
(select e.employee_id,d.column_value,count(distinct w.employee_id) as c
from (select distinct employee_id from works) e,
table(dates((select min(work_start_date) as a from works),(select max(work_end_date) as b from works))) d,
works w
where e.employee_id=w.employee_id
and d.column_value>=w.work_start_date
and d.column_value<w.work_end_date
group by e.employee_id,d.column_value) Sub
group by employee_id
order by 1,2