Simply, where does gui_upload function uploads the files in Application Server. How can I find the location of them, or is there any tcode that I can find last uploaded files or search by name ?
Thanks.
gui_upload function does not upload file to the Application server. it just reads a file from the presentation layer into an internal table. You will then need to use some other function to write this internal table to a file on the application server.
Hope this helps.
I can confirm both previous answers.
If you'd like to upload a text/csv file for example to an application server, you can use the following code.
Using GUI_UPLOAD to actually read the provided input file to an internal table:
lv_filename = p_filebp.
CLEAR lt_data_tab.
IF NOT lv_filename IS INITIAL.
CALL FUNCTION 'GUI_UPLOAD'
EXPORTING
filename = lv_filename
TABLES
data_tab = lt_data_tab
EXCEPTIONS
file_open_error = 1
OTHERS = 17.
IF sy-subrc <> 0.
EXIT.
ENDIF.
ENDIF.
Check if there was data in the text file, and has been transferred into the internal table correctly.
If so, upload it to a file on the application server. You can provide a path yourself where you want to see this uploaded:
READ TABLE lt_data_tab INDEX 1.
IF sy-subrc <> 0.
WRITE: / 'No data in input file.'.
ELSE.
CONCATENATE '/interfaces/' sy-sysid '/CRM_ACTIVITIES/' sy-datum '_INPUT.CSV' INTO p_serinp.
OPEN DATASET p_serinp FOR OUTPUT IN TEXT MODE ENCODING DEFAULT.
IF sy-subrc NE 0.
EXIT.
ENDIF.
LOOP AT lt_data_tab.
TRANSFER lt_data_tab TO p_serinp.
CLEAR lt_data_tab.
ENDLOOP.
CLOSE DATASET p_serinp.
IF sy-subrc = 0.
CLEAR gd_error_text.
CONCATENATE 'Download to file: ' p_serinp ' is finished.'
INTO gd_error_text SEPARATED BY space.
WRITE: / gd_error_text.
ENDIF.
ENDIF.
Keep in mind that, using the OPEN DATASET statement, you can write files anywhere on your network. That if at least you got the required authorizations.
Transaction AL11 can be used to explore the existing folders and files on your SAP system.
I don't have an ABAP stack on hand but I believe what you're looking for is the command OPEN DATASET, or something along those lines. This handles reading and writing files on the application server. The files that are processed via OPEN DATASET can be found with transaction AL11.
Related
I need to archive the txt file using Pentaho PDI by giving it a dynamic timestamp and append the variable to the output filename. I used get system info which automatically assigns variable as well as value. So my job was Start__ get system info___zip file. In the zip file component, I tried called the variable while giving the output filename along with ${Variable} but the output filename is not coming properly. It should be off filename__timestamp__variable. Can someone please help me with this?
What I want to do is the following...
I want to divide the input file into registers, convert each record into a
file and leave all the files in a directory.
My .csv file has the following structure:
ERP,J,JACKSON,8388 SOUTH CALIFORNIA ST.,TUCSON,AZ,85708,267-3352,,ALLENTON,MI,48002,810,710-0470,369-98-6555,462-11-4610,1953-05-00,F,
ERP,FRANK,DIETSCH,5064 E METAIRIE AVE.,BRANDSVILLA,MO,65687,252-5592,1176 E THAYER ST.,COLUMBIA,MO,65215,557,291-9571,217-38-5525,129-10-0407,1/13/35,M,
As you can see it doesn't have Header row.
Here is my flow.
My problem is that when the Split Proccessor divides my csv into flows with 400 lines, it isn't save in my output directory.
It's first time using NIFI, sorry.
Make sure your RecordReader controller service is configured correctly(delimiter..etc) to read the incoming flowfile.
Records per split value as 1
You need to use UpdateAttribute processor before PutFile processor to change the filename to unique value (like UUID) unless if you are configured PutFile processor Conflict Resolution strategy as Ignore
The reason behind changing filename is SplitRecord processor is going to have same filename for all the splitted flowfiles.
Flow:
I tried your case and flow worked as expected, Use this template for your reference and upload to your NiFi instance, Make changes as per your requirements.
I experienced an error in SAP ABAP which says DATASET_CANT_CLOSE with error number 32 (Broken Pipe). Question is: what procedure triggered this kind of error?
As far as I know, this error was triggered by:
CLOSE DATASET dset
But I can't reproduce the error since I don't know what procedure does trigger this kind of error.
This is the code I use:
method GENERATE_TXT_FILE.
DATA :
lwa_data TYPE t_line,
lv_param TYPE sxpgcolist-parameters.
"Upload File to Server
*Open Dataset
OPEN DATASET im_file_name FILTER 'dos2ux'
FOR OUTPUT IN TEXT MODE ENCODING DEFAULT.
CLEAR lwa_data.
LOOP AT it_data INTO lwa_data.
CATCH SYSTEM-EXCEPTIONS file_access_errors = 4
OTHERS = 8.
TRANSFER lwa_data-lines TO im_file_name.
ENDCATCH.
IF sy-subrc <> 0.
CLEAR lwa_data.
EXIT.
ENDIF.
CLEAR lwa_data.
ENDLOOP.
*Close Dataset
CLOSE DATASET im_file_name.
As I have investigated through the background job log, it seems that the current server which run the background job haven't got mapped yet to the text file folder. Solution is to re-map the server to text file folder.
You are using the FILTER extension to OPEN DATASET - which can be a HUGE security issue as well as raise loads of portability issues unless you know what you're doing, but that's not what the question is about. From the documentation:
When the statement OPEN DATASET is executed, a process is started in
the operating system for the specified statement. When the file is
opened for reading, a channel (pipe) is linked with STDOUT of the
process, from which the data is read during file reading. The file
itself is linked with STDIN of the process. When the file is opened
for writing, a channel (pipe) is linked to STDIN of the process, to
which data is passed when writing. The output of the process is
diverted to this file.
In your case, the filter command probably decided to bail out - see this answer among many. Why is hard to investigate - you may have to go through various system logs to find out. If the problem really is some unmapped network folder, you could try switching to UNC paths.
I have a file in my D: drive of my computer and I want to copy this file to an SAP application server so that I am able to see my file with transaction AL11.
I know that I can create a file with AL11 but I want do this in ABAP.
Of course in my search I find this code but I cannot solve my problem with it.
data: unixcom like rlgrap-filename.
data: begin of tabl occurs 500,
line(400),
end of tabl.
dir =
unixcom = 'mkdir mydir'. "command to create dir
"to execute the unix command
call 'SYSTEM' id 'COMMAND' field unixcom
id 'TAB' field tabl[].
To upload the file to the application server, there are three steps to be followed. To open the file use the below statement:
Step1: OPEN DATASET file name FOR INPUT IN TEXT MODE ENCODING DEFAULT.
To write into the application server use.
Step2: TRANSFER name TO file name.
Dont forget to close the file once it is transferred.
Step3: CLOSE DATASET file name.
Plese mark with correct answer, if it helps! :)
If you want to do this using ABAP you could create a small report that uses the function module GUI_UPLOAD to get the file from your local disk into an internal table and then write it to the application server with something like this:
lv_filename = '\\path\to\al11\directory\file.txt'.
OPEN DATASET lv_filename FOR OUTPUT IN TEXT MODE ENCODING UTF-8.
LOOP AT lt_contents INTO lv_line.
TRANSFER lv_line TO lv_filename.
ENDLOOP.
CLOSE DATASET lv_filename.
I used CG3Z transaction and with this transaction I was able to copy a file in the application server directory.
I ran into this problem when uploading a file with a super long name - my database field was only set to 50 characters. Since then, I have increased my database field length, but I'd like to have a way to check the length of the filename before uploading. Below is my code. The validation returns '85' as the character length. And it returns the same count for every different file I upload (none of which have a file name length of 85).
<cfscript>
missing_info = "<p>There was a slight problem with your submission. The following are required or invalid:</p><ul>";
// Check the length of the file name for our database field
if ( len(Form["ResumeFile1"]) gt 100 )
{
missing_info = missing_info & "<li>'Resume File 1' is invalid. Character length must be less than 100. Current count is " & len(Form["ResumeFile1"]) & ".</li>";
validation_error = true;
ResumeFileInvalidMarker = true;
}
</cfscript>
Anyone see anything wrong with this?
Thanks!
http://www.cfquickdocs.com/cf9/#cffile.upload
After you upload the file, the variable "clientFileName" will give you the name of the uploaded file, without a file extension.
The only way to read the filename before you upload it would be to use JavaScript to read and parse the value (file path) in the file field.
A quick clarification in the wording of your question. By the time your code executes the file upload has already happened. The file resides in a temporary directory on the ColdFusion server and the form field related to the file upload contains the temporary filename for that file. Aside from checking to see if a file has been specified, do not do anything directly with that file or you'll be circumventing some built in security.
You want to use the cffile tag with the upload action (or equivalent udf) to move the temp file into a folder of your choosing. At that point you get access to a structure containing lots of information. Usually I "upload" into a temporary directory for the application, which should be outside of the webroot for security.
At this point you'll then want to do any validation against the file, such as filename length, file type, file size, etc and delete the file if it fails any checks. If it passes all checks then you move it into it's final destination which may be inside the webroot.
In your case you'll want to check the cffile structure element clientFile which is the original filename including extension (which you'll need to check, since an extension doesn't need to be present and can be any length).