How to get the following output ?
Input:
t1
-----------------
col1 col2
----------------
2 a
1 c
3 b
----------------
Output:
t1
-----------------
col1 col2
----------------
1 a
2 b
3 c
----------------
You can try using row number like:
SELECT row_number() OVER (ORDER BY a.col2) as col1, col2
FROM t1 a ORDER BY a.col2
select C1.col1, C2.col2
from
(select col1, row_number() over (order by col1) rn
from t1) C1
join
(select col2, row_number() over (order by col2) rn
from t1) C2
on C1.rn=C2.rn
order by C1.rn
I think following query may help you.
SELECT * FROM t1 ORDER BY col1 ;
please check this link for more practice
http://www.sqlfiddle.com/#!3/2e3e9/1/0
Try this..
select col1,col2 from
(select col1,rownum rn from(select col1 from t1 order by col1)) a,
(select col2,rownum rn from(select col2 from t1 order by col2)) b
where a.rn=b.rn
Related
For this example tables:
Table A:
Col1 Col2
-----------
2015 A
2015 B
2015 C
Table B:
Col1 Col2
------------
2015 X
2015 Y
2015 Z
I want a query that returns:
Col1 Col2
------------
A X
B Y
C Z
I have tried something like this:
SELECT TA.COL2, TB.COL2
FROM
(SELECT * FROM TABLE_A WHERE COL1=2015) TA,
(SELECT * FROM TABLE_B WHERE COL1=2015) TB,
But I'm getting duplicated results
Col1 Col2
-----------
A X
A Y
A Z
B X
B Y
B Z
C X
C Y
C Z
A way to do it is to use the row number:
SELECT TA.COL2, TB.COL2
FROM
(SELECT TABLE_A.COL2, ROWNUM AS R1 FROM TABLE_A WHERE COL1=2015) TA,
(SELECT TABLE_B.COL2, ROWNUM AS R2 FROM TABLE_B WHERE COL1=2015) TB,
WHERE T1.R1 = T2.R2
In a SELECT statement, include DISTINCT or DISTINCTROW keyword after the SELECT clause.
For More Details:
http://www.geeksengine.com/database/basic-select/eliminate-duplicate-rows.php
Not sure why you want this but here is my method for doing it.
SELECT
TA.COL2 AS Col1,
TB.COL2 AS Col2
FROM
(SELECT COL1, COL2, ROW_NUMBER() OVER (PARTITION BY COL1 ORDER BY COL2) AS Seq FROM TABLE_A) TA
JOIN
(SELECT COL1, COL2, ROW_NUMBER() OVER (PARTITION BY COL1 ORDER BY COL2) AS Seq FROM TABLE_B) TB
ON TA.COL1 = TB.COL1
AND TA.Seq = TB.Seq
A union all/group by approach may be what you want:
SELECT MAX(COL2_a) as COL2_a, MAX(COL2_B) as COL2_B
FROM ((SELECT COL2 as COL2_A, NULL as COL2_B,
ROW_NUMBER() OVER (ORDER BY COL2) as seqnum
FROM TABLE_A
WHERE COL1 = 2015
) UNION ALL
(SELECT NULL, COL2, ROW_NUMBER() OVER (ORDER BY COL2) as seqnum
FROM TABLE_B
WHERE COL1 = 2015
) UNION ALL
) t
GROUP BY seqnum;
Alternatively, use a FULL JOIN:
SELECT a.COL2 as COL2_a, b.COL2 as COL2_B
FROM (SELECT a.*,
ROW_NUMBER() OVER (ORDER BY COL2) as seqnum
FROM TABLE_A a
WHERE COL1 = 2015
) a FULL JOIN
(SELECT b.*,
ROW_NUMBER() OVER (ORDER BY COL2) as seqnum
FROM TABLE_B b
WHERE COL1 = 2015
) b
ON a.seqnum = b.seqnum;
Both these methods returns all values, if one table has more values than the other.
I have a table with three columns (id, col2, col3, col4) where col2 is A or B and col3 and col4 are integers. My problem is, there are many columns that have the same id and a different col2 value, and I want to select ONLY the rows that have a maximum value in col3.
For instance, if we have:
id | col2 | col3 | col4
1 | A | 3 | 2
1 | B | 5 | 3
2 | A | 6 | 2
...
I want to keep only the tuple (1, B, 5, 3). How can I achieve this?
I've tried this:
SELECT id, col2, MAX(col3), col4 FROM t GROUP BY id;
but I get an error saying that this is not a valid GROUP BY statement.
You can use keep:
SELECT id,
MAX(col2) KEEP (DENSE_RANK FIRST ORDER BY col3 DESC) as col2
MAX(col3),
MAX(col4) KEEP (DENSE_RANK FIRST ORDER BY col3 DESC) as col4
FROM t
GROUP BY id;
Or:
SELECT id, col2, col3, col4
FROM (SELECT t.*,
ROW_NUMBER() OVER (PARTITION BY id ORDER BY col3 DESC) as seqnum
FROM t
) t
WHERE seqnum = 1;
This query:
select t.*
from tablename t inner join (
select id, max(col3) col3
from tablename
group by id
having count(distinct col2) > 1
) g on g.id = t.id and g.col3 = t.col3
returns for each id that has different values in col2 only 1 row: the one containing the maximum value of col3.
If you also want the other rows where each id does not have different values in col2, then use UNION ALL:
select t.*
from tablename t inner join (
select id, max(col3) col3
from tablename
group by id
having count(distinct col2) > 1
) g on g.id = t.id and g.col3 = t.col3
union all
select t.* from tablename t
where not exists (
select 1 from tablename
where id = t.id and col2 <> t.col2
)
select * from TableName where col3 = (select max(col3) from TableName)
I have an output of some part of my stored proedure like this:
col1 col2 col3 col4
--------------------------
2016-05-05 1 2 2
2016-05-05 1 3 32
2016-05-12 2 1 11
2016-05-12 3 1 31
Now I need to get result based on this condition
col2 = 1 and col3 = max or col3 = 1
and col2 = max
The final result should be
col1 col2 col3 col4
-------------------------
2016-05-05 1 3 32
2016-05-12 3 1 31
Not sure if thats the most efficient way , but you can use ROW_NUMBER() :
SELECT * FROM (
SELECT t.*,
ROW_NUMBER() OVER(PARTITION BY t.col1 ORDER BY t.col3 DESC) as rnk,
WHERE t.col2 = 1
UNION ALL
SELECT t.*,
ROW_NUMBER() OVER(PARTITION BY t.col1 ORDER BY t.col2 DESC) as rnk,
WHERE t.col3 = 1) tt
WHERE rnk = 1
This will give you all the records with
(col2=1 and col3=max) or (col3=1 and col2=max)
This is a bit tricky. Your data has no ambiguities, such as duplicate maximuma in col4 or "1" values in both col2 and col3.
The following is a direct translation of the logic in your question:
select t.*
from t
where t.col4 = (select max(t2.col4)
from t t2
where t2.col1 = t.col1 and (t2.col2 = 1 or t2.col3 = 1)
);
Try this. Note if there are more than 1 same max value, then you need all of those in output. And it will work for all scenarios, even when col1 is not in sync with col2 and col3.
I am first finding highest values of col2 and col3 and assigning them value as 1. Then in outer query, I am using your join condition. Demo created for Postgres DB as SQLServer wasn't available.
SQLFiddle Demo
select col1,col2,col3,col4
from
(
select t.*,
RANK() OVER(ORDER BY col3 DESC) as col3_max,
RANK() OVER(ORDER BY col2 DESC) as col2_max
from your_table t
) t1
where
(col2=1 and col3_max=1)
OR
(col3=1 and col2_max=1)
Alternative way:
SELECT * FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY col1 ORDER BY iif(col2 = 1, col3, col2) DESC) as r
FROM tbl) t
WHERE r = 1
If I have tlb1 as :
col1
1
2
3
Now I have tlb2 as:
col2 col3
4 Four
5 Five
6 SIX
No I have tlb3 as
col4 col5
sample14 sample15
sample24 sample25
sample34 sample35
What can be the query if I want result as :
col1 col2 col3 col4 col5
1 4 Four sample14 sample15
2 5 Five sample24 sample25
3 6 Six sample34 sample35
I tried with :
select ( (select * from tlb1), (select * from tlb2),(select * from tlb3)) T
But this failed.
Please help me.
with t1 as (select col1, row_number() over (order by col1) rn from tbl1 ),
t2 as (select col2,col3, row_number() over (order by col2) rn from tbl2),
t3 as ( select col4,col5, row_number() over (order by col4) rn from tbl3)
select t1.col1,t2.col2,t2.col3,t3.col4,t3.col5
from t1 full outer join t2 on t1.rn = t2.rn
t3 full outerjoin t2 on t2.rn = t3.rn
try something like this...
I have only one column in my table having all distinct values I need to group it into pairs of 3 and make 3 columns out of 3 rows please help
Source
COL1
-----
A
B
C
D
E
F
Required output 1:
COL1
------
A,B,C
D,E,F
Required output 2:
col1 col2 col3
---- ---- ----
A B C
D E F
Output 1:
select listagg(col1, ',') within group (order by col1) as col
from (
select col1,
case
when row_number() over (order by col1) <= (count(*) over ()) / 2 then 0
else 1
end as grp
from foo
)
group by grp
order by grp;
For Output 2:
select max(col1) as col1,
max(col2) as col2,
max(col3) as col3
from (
select case mod(row_number() over (order by col1),3)
when 1 then col1
else null
end as col1,
case mod(row_number() over (order by col1),3)
when 2 then col1
else null
end as col2,
case mod(row_number() over (order by col1),3)
when 0 then col1
else null
end as col3,
case
when row_number() over (order by col1) <= (count(*) over ()) / 2 then 0
else 1
end as grp
from foo
)
group by grp
order by grp;
SQLFiddle example: http://sqlfiddle.com/#!4/d699c/1
Please try below query for second solution:
select Col1, Col2, Col3 From(
select
ceil(row_number() over(order by Col1)/3) Rnum,
mod(row_number() over(order by Col1)+2, 3)+1 Row_Num,
COl1
from
YourTable
)x pivot (min(Col1) for Row_Num in ('1' as Col1, '2' as Col2, '3' as Col3));
Fiddle Demo
Another way (will work for every multiple of 3 of records)
output1
select listagg(col1, ',') within group (order by col1) col1
from
(select col1, row_number() over(order by col1) rn
from t) tt
group by rn - decode(mod (rn, 3) ,0,3,mod (rn, 3));
output2
select c2_col col1, c3_col col2, c1_col col3
from
(select rn - decode(mod (rn, 3) ,0,3,mod (rn, 3)) grp, mod(rn, 3) rnm, col1
from
(select col1, row_number() over(order by col1) rn
from t)) tt
pivot
(
max(col1) as col
for rnm in (0 as c1,1 c2,2 c3)
);
Here is a sqlfiddle demo