I am using a live data API that is returning the next arriving trains. I plan on giving the user the next 5 trains arriving. If there are less than 5 trains arriving, how you handle that? I am having trouble thinking of a way, I was thinking a way with if statements but don't know how I would set them up.
time1Depart = dataReturnedFromLiveAPI{1,1}.orig_departure_time;
time2Depart = dataReturnedFromLiveAPI{1,2}.orig_departure_time;
time3Depart = dataReturnedFromLiveAPI{1,3}.orig_departure_time;
time4Depart = dataReturnedFromLiveAPI{1,4}.orig_departure_time;
time5Depart = dataReturnedFromLiveAPI{1,5}.orig_departure_time;
time1Arrival = dataReturnedFromLiveAPI{1,1}.orig_arrival_time;
time2Arrival = dataReturnedFromLiveAPI{1,2}.orig_arrival_time;
time3Arrival = dataReturnedFromLiveAPI{1,3}.orig_arrival_time;
time4Arrival = dataReturnedFromLiveAPI{1,4}.orig_arrival_time;
time5Arrival = dataReturnedFromLiveAPI{1,5}.orig_arrival_time;
The code right now uses a matrix that goes from 1:numoftrains but I am using just the first five.
It's a bad practice to assign individual value to a separate variable. Better if you pass all related values to a vector or cell array depending on class of orig_departure_time and orig_arrival_time.
It looks like dataReturnedFromLiveAPI is a cell array of structures. Then you can do:
timeDepart = cellfun(#(x), x.orig_departure_time, ...
dataReturnedFromLiveAPI(1,1:min(5,size(dataReturnedFromLiveAPI,2))), ...
'UniformOutput',0 );
timeArrival = cellfun(#(x), x.orig_arrival_time, ...
dataReturnedFromLiveAPI(1,1:min(5,size(dataReturnedFromLiveAPI,2))), ...
'UniformOutput',0 );
Then you how to access the values one by one as
time1Depart = timeDepart{1};
If orig_departure_time and orig_arrival_time are numeric scalars, you can use ...'UniformOutput',1.... You will get output as a vector and can get single values with timeDepart(1).
Related
I've made a small program that is supposed to read data in a range input it into an object oriented program, and then return the full data set. the issue is that when I run the file it only return data on the third procedure
I tried printing other procedure sets but idk how to do that, i'm thinking this will only work if i replace the procedures from generic to specific. as in instead of Procedure name for all of them procedures 1, 2, and 3
for i in range (3):
procedure_name = ('Physical Exam')
date_of = ("Nov 6th 2022")
doctor = ('Dr. Irvine')
charge = ('$ 250.00')
procedure_name = ('X-ray')
date_of = ("Nov 6th 2022")
doctor = ('Dr. Jamison')
charge = ('$ 500.00')
procedure_name = ('Blood test')
date_of = ("Nov 6th 2022")
doctor = ('Dr. Smith')
charge = ('$ 200.00')
procedure = HW6_RODRIGUEZ_1.Procedure(procedure_name,date_of,doctor,charge)
print(f'Procedure {i+1}')
print(procedure)
print(i, end=" ")
if name == 'main':
main()
So, I think you may have misunderstood some things when it comes to variables, OOP and looping.
When you define a variable, that variable is set to the last value it is assigned. So if you have the following code:
a = 1
a = 2
a = 3
The final value of the variable 'a' will be 3, as that is the last value it is assigned.
As for loops, whatever you have written in a for loop will be repeated for a specified number of times. This means if you want to write a loop that prints "hello" 5 times, you'd write the following:
for i in range(5):
print("hello")
What your loop is essentially doing is overwriting the same 3 variables 3 times over, this won't be assigning new values to an object.
When it comes to creating an object that you assign variable to, you need to first write the code for your class. Your class can have attributes like the variables you've stated. It could look something like this:
class procedure:
def __init__(self, procedure_name, date_of, doctor, charge):
self.procedure_name = procedure_name
self.date_of = date_of
self.doctor = doctor
self.charge = charge
Now, to set up a procedure object, you just assign a variable to procedure with the desired variables as parameters, like so:
new = procedure('X-ray','Nov 6th 2022','Dr. Jamison','$ 500.00')
And to access a variable, you just need to write procedureName.attribute. For example, using the object I just set up:
print(new.doctor)
Would output 'Dr. Jamison'.
If you want to store a bunch of them, I would recommend storing them in a list or a dictionary, depending on how you want to look them up.
I hope this helps! If you are new to programming, I would recommend some simpler programs such as a program that prints the nursery rhyme 10 green bottles using loops, or maybe making a quiz.
Best of luck.
I have a dataframe which has a column called hexa which has hex values like this. They are of dtype object.
hexa
0 00802259AA8D6204
1 00802259AA7F4504
2 00802259AA8D5A04
I would like to remove the first and last bits and reverse the values bitwise as follows:
hexa-rev
0 628DAA592280
1 457FAA592280
2 5A8DAA592280
Please help
I'll show you the complete solution up here and then explain its parts below:
def reverse_bits(bits):
trimmed_bits = bits[2:-2]
list_of_bits = [i+j for i, j in zip(trimmed_bits[::2], trimmed_bits[1::2])]
reversed_bits = [list_of_bits[-i] for i in range(1,len(list_of_bits)+1)]
return ''.join(reversed_bits)
df['hexa-rev'] = df['hexa'].apply(lambda x: reverse_bits(x))
There are possibly a couple ways of doing it, but this way should solve your problem. The general strategy will be defining a function and then using the apply() method to apply it to all values in the column. It should look something like this:
df['hexa-rev'] = df['hexa'].apply(lambda x: reverse_bits(x))
Now we need to define the function we're going to apply to it. Breaking it down into its parts, we strip the first and last bit by indexing. Because of how negative indexes work, this will eliminate the first and last bit, regardless of the size. Your result is a list of characters that we will join together after processing.
def reverse_bits(bits):
trimmed_bits = bits[2:-2]
The second line iterates through the list of characters, matches the first and second character of each bit together, and then concatenates them into a single string representing the bit.
def reverse_bits(bits):
trimmed_bits = bits[2:-2]
list_of_bits = [i+j for i, j in zip(trimmed_bits[::2], trimmed_bits[1::2])]
The second to last line returns the list you just made in reverse order. Lastly, the function returns a single string of bits.
def reverse_bits(bits):
trimmed_bits = bits[2:-2]
list_of_bits = [i+j for i, j in zip(trimmed_bits[::2], trimmed_bits[1::2])]
reversed_bits = [list_of_bits[-i] for i in range(1,len(list_of_bits)+1)]
return ''.join(reversed_bits)
I explained it in reverse order, but you want to define this function that you want applied to your column, and then use the apply() function to make it happen.
I'm very confused on the apply function for pandas. I have a big dataframe where one column is a column of strings. I'm then using a function to count part-of-speech occurrences. I'm just not sure the way of setting up my apply statement or my function.
def noun_count(row):
x = tagger(df['string'][row].split())
# array flattening and filtering out all but nouns, then summing them
return num
So basically I have a function similar to the above where I use a POS tagger on a column that outputs a single number (number of nouns). I may possibly rewrite it to output multiple numbers for different parts of speech, but I can't wrap my head around apply.
I'm pretty sure I don't really have either part arranged correctly. For instance, I can run noun_count[row] and get the correct value for any index but I can't figure out how to make it work with apply how I have it set up. Basically I don't know how to pass the row value to the function within the apply statement.
df['num_nouns'] = df.apply(noun_count(??),1)
Sorry this question is all over the place. So what can I do to get a simple result like
string num_nouns
0 'cat' 1
1 'two cats' 1
EDIT:
So I've managed to get something working by using list comprehension (someone posted an answer, but they've deleted it).
df['string'].apply(lambda row: noun_count(row),1)
which required an adjustment to my function:
def tagger_nouns(x):
list_of_lists = st.tag(x.split())
flat = [y for z in list_of_lists for y in z]
Parts_of_speech = [row[1] for row in flattened]
c = Counter(Parts_of_speech)
nouns = c['NN']+c['NNS']+c['NNP']+c['NNPS']
return nouns
I'm using the Stanford tagger, but I have a big problem with computation time, and I'm using the left 3 words model. I'm noticing that it's calling the .jar file again and again (java keeps opening and closing in the task manager) and maybe that's unavoidable, but it's really taking far too long to run. Any way I can speed it up?
I don't know what 'tagger' is but here's a simple example with a word count that ought to work more or less the same way:
f = lambda x: len(x.split())
df['num_words'] = df['string'].apply(f)
string num_words
0 'cat' 1
1 'two cats' 2
Basically:
I am making a game in the LÖVE Engine where you click to create blocks
Every time you click, a block gets created at your Mouse X and Mouse Y
But, I can only get one block to appear, because I have to name that block (or table) 'object1'
Is there any way to create table after table with increasing values? (like object1{}, object2{}, object3{}, etc... But within the main table, 'created_objects')
But only when clicked, which I suppose rules out the looping part (but if it doesn't please tell me)
Here's my code so far, but it doesn't compile.
function object_create(x, y, id) **--Agruments telling the function where the box should spawn and what the ID of the box is (variable 'obj_count' which increases every time a box is spawned)**
currobj = "obj" .. id **--Gives my currently created object a name**
crob.[currobj] = {} **--Is supposed to create a table for the current object, which holds all of its properties. **
crob.[currobj].body = love.physics.newBody(world, x, y, "dynamic")
crob.[currobj].shape = love.physics.newRectangleShape(30, 30)
crob.[currobj].fixture = love.physics.newFixture(crob.[currobj].body, crob.[currobj].shape, 1) **--The properties**
crob.[currobj].fixture:setRestitution(0.3)
But what should I replace [currobj] with?
Solved
Found what I was looking for. Here's the code if people are wondering:
function block_create(x, y, id) --(the mouse x and y, and the variable that increases)
blocks[id] = {}
blocks[id][1] = love.physics.newBody(world, x, y, "dynamic")
blocks[id][2] = love.physics.newRectangleShape(45, 45)
blocks[id][3] = love.physics.newFixture(blocks[id][1], blocks[id][2])
blocks[id][3]:setRestitution(0.2)
blocks[id][4] = math.random(0, 255) --The Color
blocks[id][5] = math.random(0, 255)
blocks[id][6] = math.random(0, 255)
blockcount = blockcount + 1
i would probably do something like this.
local blocks = {} -- equivalent of your crob table
function create_block(x, y)
local block = funcToCreateBlock() -- whatever code to create the block
table.insert(blocks, block)
return block
end
if you wanted to get a reference to the block you just created with the function, just capture it.
-- gives you the new block, automatically adds it to the list of created blocks
local new_block = create_block(0, 10)
that sticks block objects in your block table and automatically gives each one a numeric index in the table. so if you called create_block() 3 times for 3 different mouse clicks, the blocks table would look like this:
blocks = {
[1] = blockobj1,
[2] = blockobj2,
[3] = blockobj3
}
you could get the second block obj from the blocks table by doing
local block2 = blocks[2]
or you could loop over all the blocks in the table using pairs or ipairs
for idx, block in pairs(blocks) do
-- do something with each block
end
sorry if this doesn't exactly answer your question. but from what you wrote, there didn't seem to be a real reason why you'd need to name the blocks anything specific in the crob table.
If you want those tables to be global, then you can do something like:
sNameOfTable = "NAME"
_G[sNameOfTable] = {1,2}
and then you will have a table variable NAME as depicted here (Codepad).
Otherwise, if you want it to be a child to some other table, something like this would also do:
tTbl = {}
for i = 1, 20 do
local sName = string.format( "NAME%02d", i )
tTbl[sName] = {1,2}
end
for i, v in pairs(tTbl) do
print( i, v )
end
Don't worry about the unsorted output here(Codepad). Lua tables with indexes need not be sorted to be used.
I built a simple vb.net winforms project that pings IP addresses and logs the results. It works fine on most machines I've tried it on. I log the status result of the ping (System.Net.NetworkInformation.IPStatus) by using the IPStatus.tostring method.
Normally this returns a text result such as "Success" or "TimedOut"
Yesterday, on one machine it returned "65" ...which is not one of the enum values. I have a feeling it might be a combination of values. I ran some test code:
Dim status As System.Net.NetworkInformation.IPStatus
status = Net.NetworkInformation.IPStatus.Success
MsgBox(status.ToString)
Which returns "Success"
And this:
status = Net.NetworkInformation.IPStatus.BadDestination Or Net.NetworkInformation.IPStatus.BadHeader
MsgBox(status.ToString)
Which returns "11050"
I suspect the "65" I saw was the result of some combination of enum values. Is there any way I can change the code in my second example to show the text names of both values? That is... any way I can see ALL values in this variable?
IPStatus is NOT a Flags enum, therefore it is not appropriate to combine its member values in this way. This is its definition via Reflector:
Public Enum IPStatus
' Fields
BadDestination = &H2B0A
BadHeader = &H2B22
BadOption = &H2AFF
BadRoute = &H2B04
DestinationHostUnreachable = &H2AFB
DestinationNetworkUnreachable = &H2AFA
DestinationPortUnreachable = &H2AFD
DestinationProhibited = &H2AFC
DestinationProtocolUnreachable = &H2AFC
DestinationScopeMismatch = &H2B25
DestinationUnreachable = &H2B20
HardwareError = &H2B00
IcmpError = &H2B24
NoResources = &H2AFE
PacketTooBig = &H2B01
ParameterProblem = &H2B07
SourceQuench = &H2B08
Success = 0
TimedOut = &H2B02
TimeExceeded = &H2B21
TtlExpired = &H2B05
TtlReassemblyTimeExceeded = &H2B06
Unknown = -1
UnrecognizedNextHeader = &H2B23
End Enum
How you are getting an IPStatus value of 65 - now that's the real question :)
Try using System.Enum to get the name of the value.
In your example, use:
MsgBox(System.Enum.GetName(GetType(Net.NetworkInformation.IPStatus), status))
It looks like apart from Success (0) and Unknown (-1), the defined enum values range from 11002 to 11045, so 65 is not a combination of any of the defined enum values.
If you are getting 65 back, you will not be able to resolve this to a string.
That enum is not marked with the FlagsAttribute and therefore should not be or'd together because the result could overlap. You are better off creating your own enum to contain the values you are looking for.
You should be able to loop over the enum's range using something like [1], test whether the current enum bit is represented in the value and add it to a string builder.
I find it hard to write up a working sample in VB.NET in this little text box, but I'm sure someone else will oblige.
[1] http://damieng.com/blog/2008/04/10/using-linq-to-foreach-over-an-enum-in-c