I have two current SQL queries that I currently use to compare GM% from previous year vs. GM% this year. This is a daily report that I run every morning. The date arithmetic is not very solid and I am trying to find an alternative. Previously I thought that the report would only be for Monday forward, and not including the current day (ie if ran on Tuesday, it would only pull Monday. If ran on Monday it would not pull anything.) Recently that has changed to where when the report is ran on Monday, they want to see Friday-Sunday. What I am considering is setting it to pull the previous 5 day, not including the current day. (Ran on Monday would pull Thur, Fri, Sat, Sun.) The problem is that it has to be a day this year vs same day last year comparison. Anyone who;s tried this knows that it is not easy to get this. Here is my current code for the date arithmetic. I am at a loss guys, I could use some help.
Where DB1.TB1.CLM1>=Current Date-364 days - (DAYOFWEEK(CURRENT DATE) - 2) DAYS
And DB1.TB1.CLM1< Current Date- 364 days
If I hear you right, on Tuesday you would pull stats for Monday. Wed, you pull stats for Mon-Tues. Friday, you pull Mon-Thurs. And for all of these, you need the equivalent day prior year.
The trick is that now on Monday, you need to pull the previous weekend, i.e. Thu-Sun.
You have not defined what to do on Sunday, so I'm leaving that case out.
Try this WHERE statement:
where
( -- do this after Monday
dayofweek(current date) > 2 and
DB1.TB1.CLM1 between ((current date - 364 days) - (dayofweek(current date) - 2) days) and (current_date - 365 days)
)
or
( -- do this on Monday
dayofweek(current date) = 2 and
DB1.TB1.CLM1 between (current date - 368 days) and (current date - 365 days)
)
Related
I am working on a MODE Case Study which can be accessed here https://mode.com/sql-tutorial/a-drop-in-user-engagement/#the-problem.
I am trying to access Table 2: Events which has a date column 'occurred_at'. I wanted to check the time frame of this case study, that is weeks and months.
I wrote a simple query
select distinct(date_trunc('week', occurred_at)) as week, date_trunc('month', occurred_at) as month
from tutorial.yammer_events
where event_type = 'engagement'
order by week;
and to my surprise, the first week of '2014-04-28' showed the month 'May' instead of 'April.
Can someone please tell me what is the reason for this?
Thank you
The PostgreSQL date_trunc rolls up the date to the first instance of the date depending upon the granularity (day, week, month, etc.)
For month this instance is the first day of month i.e. Day 1.
For week this instance is the first day of week i.e. Monday.
Suppose the date is 4th July 2021 which is Sunday, then the date_trunc will result in 1st July 2021 for month and 28th June 2021 for week which is Monday inside that week.
Suppose the date is 5th July 2021 which is Monday itself, then the date_trunc will still result in 1st July 2021 for month but result in 5th July 2021 for week since it is already Monday.
I have a weekly report that uses these date parameters:
SELECT *
FROM TABLE
WHERE DATE_FIELD BETWEEN (CURRENT DATE - 8 DAYS) AND (CURRENT DATE - 2 DAYS)
This runs on Mondays to gather the previous week's data (Sun-Sat). What I want now is to run this for the same week of the previous year.
So for example, if the code above runs on Mon 29/06/20, it returns data from Sun 21/06/20 - Sat 27/06/20, i.e. week 26 of 2020. I want it to return data from Sun 23/06/19 - Sat 29/06/19, i.e. week 26 of 2019.
The report runs automatically so I can't just plug in the exact dates each time. I also can't just offset the date parameters to -357 and -367 days, as this gets thrown off by leap years.
I've searched for solutions but they all seem to rely on the DATEADD function, which my DB2 database doesn't recognise.
Does anyone know how I can get the result I'm looking for, please? Any advice would be appreciated! :)
The easiest way to do this is to build a calendar or dates table...(google sql calendar table)
Among the columns you'd have would be
date
year
month
quarter
dayofWeek
startOfWeek
endOfWeek
week_nbr
You can use the week() or week_iso() functions when loading the table, pay attention to the differences and pick the best fit for you.
Such a calendar table makes it easy to compare current period vs prior period.
If you assume that all years have 52 weeks, you can use date arithmetic:
SELECT *
FROM TABLE
WHERE DATE_FIELD BETWEEN (CURRENT DATE - (8 + 364) DAYS) AND (CURRENT DATE - (2 + 364) DAYS)
Because you want the week to start on a Monday, this doesn't have to take leap years into account. It is subtracting exactly 52 weeks -- and leap years do no affect weeks.
This gets more complicated if you have to deal with 52 or 53 week years.
A little bit complicated, but it should work. You may run it as is or test your own date.
SELECT
YEAR_1ST_WEEK_END + WEEKS_TO_ADD * 7 - 6 AS WEEK_START
, YEAR_1ST_WEEK_END + WEEKS_TO_ADD * 7 AS WEEK_END
FROM
(
SELECT
DATE((YEAR(D) - 1)||'-01-01')
+ (7 - DAYOFWEEK(DATE((YEAR(D) - 1)||'-01-01'))) AS YEAR_1ST_WEEK_END
, WEEK(D) - 2 AS WEEKS_TO_ADD
FROM (VALUES DATE('2020-06-29')) T(D)
);
The intermediate column YEAR_1ST_WEEK_END value is the 1-st Sat (end of week) of previous year for given date.
WEEKS_TO_ADD is a number of weeks to add to the YEAR_1ST_WEEK_END date.
Please help me with an Informx SQL query to be run every Friday.
Period: 1st of the Month to the Thursday before the Friday that it is being run on. I can't just choose date ranges as it will be an auto report so the dates needs to update automatically. Is there a way to do this?
You've got two issues: the start of the month and the date of last Thursday. The simplest expression to identify the 1st day of the current month is:
MDY(MONTH(TODAY), 1, YEAR(TODAY))
The way to identify the most recent Thursday is via a CASE statement on WEEKDAY(TODAY). Something like:
CASE
WHEN WEEKDAY(TODAY) < 5 -- (Sunday (0) - Thursday (4))
THEN TODAY - WEEKDAY(TODAY) - 3 -- Calc last Sunday, back 3 days
ELSE TODAY - WEEKDAY(TODAY) + 4 -- Calc last Sunday, forward 4 days
END
Note, you will still run into issues where the 1st of current month is later than the most recent Thursday. But hopefully the examples above will point you in the right direction.
Of course, if you know this report is only ever going to be run on Fridays, then calculating the most recent Thursday is just TODAY -1.
I have a date in sql which will always fall on a Monday and I'm subtracting 13 weeks to get a weekly report. I am trying to get the same 13 week report but for last year's figures as well.
At the moment, I'm using the following:
calendar_date >= TRUNC(sysdate) - 91
which is working fine.
I need the same for last year.
However, when I split this into calendar weeks, there will also be a partially complete week as it will include 1 or 2 days from the previous week. I need only whole weeks.
e.g. the dates that will be returned for last year will be 14-Feb-2015 to 16-May-2015. I need it to start on the Monday and be 16-Feb-2015. This will change each week as I am only interested in complete weeks...
I would do this:
Get the date by substracting 91 days as you're already doing.
Get the number of the day of the week with TO_CHAR(DATE,'d')
Add the number of days until the next monday to the date.
Something like this:
SELECT TO_DATE(TO_DATE('16/05/2015','DD/MM/YYYY'),'DD/MM/YYYY')-91 + MOD(7 - TO_NUMBER(TO_CHAR(TO_DATE(TO_DATE('16/05/2015','DD/MM/YYYY'),'DD/MM/RRRR')-91,'d'))+1,7) d
FROM dual
next_day - returns date of first weekday named by char.
with dates as (select to_date('16/05/2015','DD/MM/YYYY') d from dual)
select
trunc(next_day( trunc(d-91) - interval '1' second,'MONDAY'))
from dates;
I want to get next monday from calculated date. In situation when calculated date is monday i have to move back to previous week ( -1 second).
I need some help in writing an SQL in SQL Server where I need to count number of rows group by weeks. There is a tricky description of week which is following
- For any date before 08/13/2015 the week is of 7 days (i.e. from Thu through Wed)
- For date 08/13/2015 the week is consider a 9 day week (i.e. from Thursday through Friday so its between 08/13/2015 through 08/21/2015)
- For date 08/22/2015 the week is back to 7 days (i.e. Sat through Friday)
Now having said all the above the result I want to see in my report is the following way . NOTE: WE column in the below attached image is the last day of the week for the range.
Sample Result Image
Just write a case statement for the 3 different options. You can find the start day with something like this:
DATEADD(week, DATEDIFF(day, 3,getdate()) / 7, 3) -- Thursdays
DATEADD(week, DATEDIFF(day, 5,getdate()) / 7, 5) -- Saturdays
The numbers 3 and 5 come from the fact that day 0 (=1.1.1900) is Monday.
If you use this a lot, it might be a good idea to write a inline table valued function to return the dates you need.