I am attempting to create a method which analyzes a string of text to see if it contains a numeric value. For instance, given the following string:
What is 2 * 2?
I need to determine the following information:
The string contains a numeric value: True
What is the numeric value that it contains: 2 (anyone of them should make the function return true and I should put the position of each of the 2's in the string in a variable such as position 0 for the first 2)
Here is the code I have so far:
Public Function InQuestion(question As String) As Boolean
' Possible substring operations using the position of the number in the string?
End Function
Here's an example console application:
Module Module1
Sub Main()
Dim results As List(Of NumericValue) = GetNumericValues("What is 2 * 2?")
For Each i As NumericValue In results
Console.WriteLine("{0}: {1}", i.Position, i.Value)
Next
Console.ReadKey()
End Sub
Public Class NumericValue
Public Sub New(value As Decimal, position As Integer)
Me.Value = value
Me.Position = position
End Sub
Public Property Value As Decimal
Public Property Position As Integer
End Class
Public Function GetNumericValues(data As String) As List(Of NumericValue)
Dim values As New List(Of NumericValue)()
Dim wordDelimiters() As Char = New Char() {" "c, "*"c, "?"c}
Dim position As Integer = 0
For Each word As String In data.Split(wordDelimiters, StringSplitOptions.None)
Dim value As Decimal
If Decimal.TryParse(word, value) Then
values.Add(New NumericValue(value, position))
End If
position += word.Length + 1
Next
Return values
End Function
End Module
As you can see, it passes the string `"What is 2 * 2?" and it outputs the positions and values of each numeric value:
8: 2
12: 2
Related
I'm using vb.net. I am doing some checking and scrubbing of my data when i get it from the database. I'm using an overload but it doesn't seem to be working for decimal numbers. Decimal numbers get treated as integers.
Public Class CheckData
Public Shared Function Check(row As DataRow, columnName As String, pDefaultValue As Decimal) As Decimal
Dim x As Object = ReplaceDBNullAndColumnExists(row, columnName)
Dim y As Decimal = CDec(Dempsey.fnIsNull.IsNull(x, pDefaultValue))
Return y
End Function
Public Shared Function Check(row As DataRow, columnName As String, pDefaultValue As DateTime) As DateTime
Dim x As Object = ReplaceDBNullAndColumnExists(row, columnName)
Dim y As DateTime = Dempsey.fnIsNull.IsNull(x, pDefaultValue)
Return y
End Function
Public Shared Function Check(row As DataRow, columnName As String, pDefaultValue As Integer) As Integer
Dim x As Object = ReplaceDBNullAndColumnExists(row, columnName)
Dim y As Integer = Dempsey.fnIsNull.IsNull(x, pDefaultValue)
Return y
End Function
Public Shared Function Check(row As DataRow, columnName As String, pDefaultValue As String) As String
Dim x As Object = ReplaceDBNullAndColumnExists(row, columnName)
Dim y As String = Dempsey.fnIsNull.IsNull(x, pDefaultValue)
Return y
End Function
Public Shared Function Check(row As DataRow, columnName As String, pDefaultValue As Boolean) As Boolean
Dim x As Object = ReplaceDBNullAndColumnExists(row, columnName)
Dim y As Boolean = Dempsey.fnIsNull.IsNull(x, pDefaultValue)
Return y
End Function
So if i pass in some data and the type is a string, integer, boolean or datetime it goes to the propert function. if i pass in a decimal it goes to integer. If i set a breakpoint on the public shared function check that is a integer function and do a
row.Table.Columns(columnName).DataType.Name
I get back - "Decimal" (doing this in the immediate window)
So my question is what have i done wrong that it doesn't take it to the decimal overload and return a decimal value. By the way, the actual data value is 37.50.
Thanks
shannon
I use this to populate list.
Public Function populate(mDs As DataSet) As List(Of SR_SalaryRange_Current)
Dim rows As DataRowCollection
Dim drow As DataRow
Dim oSR_SalaryRange_Current As SR_SalaryRange_Current
Dim oSR_SalaryRange_Currents As List(Of SR_SalaryRange_Current) = New List(Of SR_SalaryRange_Current)
Dim dt As New DataTable
Try
dt = mDs.Tables("SR_SalaryRange_Currents")
rows = dt.Rows
For Each drow In rows
oSR_SalaryRange_Current = New SR_SalaryRange_Current
With oSR_SalaryRange_Current
.tblSR_SalaryRange_CurrentID = SitePlumbing.CheckData.Check(drow, "intTblSR_SalaryRange_CurrentID", 0)
.EffectiveDate = SitePlumbing.CheckData.Check(drow, "dtmEffectiveDate", CDate("1/1/1900"))
.WorkWeekHours = SitePlumbing.CheckData.Check(drow, "decWorkWeekHours", 0)
End With
oSR_SalaryRange_Currents.Add(oSR_SalaryRange_Current)
Next
Catch ex As Exception
ErrorMsg = "Populate Error:" & ex.InnerException.ToString
Return oSR_SalaryRange_Currents
End Try
Return oSR_SalaryRange_Currents
End Function
from there it goes into the checkdata that i mentioned before. In the code above it correctly goes to an integer and a datetime when hitting the overload, just isn't doing it for the decimal.
A decimal is implicitly covertable into an integer so the compiler is confused if you have OPTION STRICT set to off. You have two options:
1) Set OPTION STRICT to ON. Then the compiler will not convert implicitly.
2) Pass in a decimal literal like this: 10D (i.e. there is a D on the end telling the compiler it is a decimal).
For example:
'Sub Routine 1
public sub Test(ByVal d as decimal)
end sub
'Sub Routine 2
public sub Test(ByVal i as integer)
end sub
//Client
dim d1 as decimal={Number}D 'where {number} is replaced with a number
dim d2 as decimal={Number} 'where {number} is replaced with a number
Test(d1) 'this will always go to Sub Routine 1 regardless of whether OPTION strict is ON or OFF
Test(d2) 'this will go to Sub Routine 1 if option strict is ON. If it is OFF, then it may go to Sub Routine 2 depending on the size of the number.
I was given a way to work with this by Viorel on another forum. He suggested I do
Check(drow, "decWorkWeekHours", 0#)
and that did indeed work. When i asked what it does, this was his response.
With ‘#’, the constant ‘0#’ becomes a decimal one. Then VB.NET chooses the definition of Check that takes a Decimal parameter, since it is more suitable comparing with other candidates.
You can also write ‘0d’ [https://learn.microsoft.com/en-us/dotnet/visual-basic/programming-guide/language-features/data-types/type-characters].
hope that will help someone else down the road.
Thanks
shannon
I am trying to make a program that checks a stock file for all products and returns with the right information from an entered GTIN code (you will ((hopefully)) understand from looking at my code)
Public Class Form1
Dim FILE_NAME As String = "H:\Visual Studio 2013\Projects\Control Task 2 Barcode Orders\Control Task 2 Barcode Orders\bin\Debug\receipt_orders.txt"
Dim GTIN As String
Dim LineContaining As String
Dim quantity As Integer
Dim description As String
Dim singleamount As String
Dim singleprice As Double
Dim totalprices As Double
Private Sub btnEnterGTIN_Click(sender As Object, e As EventArgs) Handles btnEnterGTIN.Click
GTIN = getValidGTIN()
Call itemfinder(GTIN)
End Sub
Function getValidGTIN()
Dim GTIN, ValidGTINAmountCharacters As String
Dim GTINOK As Boolean
'Declaring variables.
GTINOK = False
Do
GTIN = InputBox("Enter the full GTIN Number (it should be 8 digits long)")
'Prompts the user to enter the GTIN.
ValidGTINAmountCharacters = Len(GTIN)
'Makes it so that the amount of characters of the GTIN is stored in the variable ValidGTINAmountCharacters.
If ValidGTINAmountCharacters = 8 Then GTINOK = True
'Makes it so the program will only accept an input if it was 8 characters long.
If Not IsNumeric(GTIN) Then GTINOK = False
'Makes it so that if any other character typed in apart from a number is not valid.
If Not GTINOK Then MsgBox("The GTIN Number isn't valid. It should be a 8 digit number. (Should not contain letters or symbols).")
'Makes it so that if the GTIN is not valid according to the above, a message appears saying it is invalid.
Loop Until GTINOK
Return GTIN
End Function
Private Sub itemfinder(ByVal GTIN As String)
Using reader As New IO.StreamReader("receipt_orders.txt")
While Not reader.EndOfStream
Dim line As String = reader.ReadLine()
If line.Contains(GTIN) Then
line = LineContaining
Exit While
End If
End While
End Using
description = Mid$(LineContaining, 10, 17)
singleamount = Mid$(LineContaining, 38, 4)
quantity = InputBox("Enter the amount required")
totalprices = quantity * singleamount
lstGTIN.Items.Add(GTIN)
lstName.Items.Add(description)
lstQuantity.Items.Add(quantity)
lstSinglePrice.Items.Add(singleamount)
lstTotal.Items.Add(totalprices)
Dim sum As Double
For x As Integer = 0 To lstTotal.Items.Count - 1
sum += Val(lstTotal.Items.Item(x).ToString)
Next
txtTotalPrice.Text = sum.ToString
End Sub
End Class
When I type in a quantity and the item code, i get an error code relating to the calculation of the total prices - i don't know how to fix this!
Also, the textfile i am using looks like this
12345670 L-Shaped Brackets 7.20
10101010 Television 1.80
69696969 Screws 0.20
Please try to explain how to solve this problem as simple as possible! I am not very adept with Visual Basic!
Some of the code in there, such as the use of the Call keyword, indicates a vb6/vbscript era mindset. Here is an implementation of the same functionality using the modern and cleaner VB.Net coding styles:
Public Class ProductItem
Public Property GTIN As Integer
Public Property Description As String
Public Property ItemPrice As Decimal
Protected Property SourceData As String
Public Shared Function FromLineString(ByVal lineString As String) As OrderLine
Return New ProductItem() With
{
.Description = lineString.SubString(9,17),
.ItemPrice = Decimal.Parse(lineString.SubString(37,4)),
.GTIN = Int32.Parse(lineString.SubString(0,8)), 'Guessed at this field
.SourceData = lineString
}
End Function
End Class
Public Class Form1
Const FILE_NAME As String = "H:\Visual Studio 2013\Projects\Control Task 2 Barcode Orders\Control Task 2 Barcode Orders\bin\Debug\receipt_orders.txt"
Private Sub btnEnterGTIN_Click(sender As Object, e As EventArgs) Handles btnEnterGTIN.Click
Dim item As ProductItem = itemfinder(Form1.InputValidGTIN())
If item Is Nothing Then Exit Sub ' May want to show error here
Dim QTY As Integer = Form1.InputInteger("Enter the amount required", "Input was not a valid Integer. Please try again.")
Me.SuspendLayout()
lstGTIN.Items.Add(item.GTIN)
lstName.Items.Add(item.Description)
lstQuantity.Items.Add(QTY)
lstSinglePrice.Items.Add(item.ItemPrice)
lstTotal.Items.Add(QTY * item.ItemPrice)
txtTotalPrice.Text = lstTotal.Items.Cast(Of Decimal).Sum().ToString()
Me.ResumeLayout()
End Sub
Public Shared Function InputValidGTIN() As String
Dim GTIN As String = InputBox("Enter the full GTIN Number (it should be 8 digits long)").Trim()
While Not IsValidGTIN(GTIN)
MsgBox("The GTIN Number isn't valid. It should be a 8 digit number. (Should not contain letters or symbols).")
GTIN = InputBox("Enter the full GTIN Number (it should be 8 digits long)").Trim()
End While
Return GTIN
End Function
Public Shared Function IsValidGTIN(ByVal GTIN As String) As Boolean
Static regex As New Regex("^\d{8}$")
Return regex.IsMatch(GTIN)
End Function
Public Shared Function InputInteger(ByVal PromptText As String, ByVal RePromptText As String) As Integer
Dim result As Integer
Dim input As String = InputBox(PromptText)
While Not Int32.TryParse(input, result)
input = InputBox(RePromptText)
End While
Return result
End Function
Private Function itemfinder(ByVal GTIN As String) As ProductItem
Using reader As New IO.StreamReader(FILE_NAME)
Dim line As String = reader.ReadLine()
While line IsNot Nothing
If line.Contains(GTIN) Then
Return ProductItem.FromLineString(line)
End If
line = reader.ReadLine()
End While
End Using
Return Nothing
End Function
End Class
I need to find consecutive numbers in an array and return a string which tells the range and numbers that don't form a range.
I found some of the already asked questions but none of them is in VB.Net:
Add to array consecutive numbers
If the array of numbers looks like {11,12,67,68,69,70,92,97} then returned string should be of the form 11,12, 67 through 70, 92 and 97.
This is not homework; I need this function for a word document containing statistical data.
Entered directly into the reply window, so there's almost certainly a bug or three:
Public Class Range
Public Shared Function PrintRanges(ByVal numbers() As Integer) As String
Dim buffer As New List(Of Range)()
Dim CurrentRange As Range = Nothing
For Each i As Integer in numbers ' you may want to add a .OrderBy() here
If CurrentRange IsNot Nothing AndAlso i - 1 = CurrentRange.EndValue Then
CurrentRange.Increase()
Else
CurrentRange = New Range(i)
buffer.Add(CurrentRange)
End If
Next i
'Got a little lazy for this line - it still does a ", " rather than " and " for the final delimiter. Simple code to fix it, just tedious.
Return String.Join(", ", buffer.Select(Function(r) r.ToString()).ToArray())
End Function
Private Sub New(ByVal InitialValue As Integer)
EndValue = IntialValue
Length = 1
End Sub
'For completeness, these two properties should be made read only outside the class, but the private constructor makes that largely moot
Public Property EndValue As Integer
Public Property Length As Integer
Public Sub Increase()
Length += 1
EndValue += 1
End Sub
Public Overrides Function ToString() As String
If Length == 1 Then Return EndValue.ToString()
If Length == 2 Then Return (EndValue -1).ToString() & "," & LastValue.ToString()
Return (EndValue - Length).ToString() & " through " & EndValue.ToString()
End Function
End Class
In VB.NET, how can I convert the following string into some kind of key/value type such as a Hashtable, Dictionary, etc?
"Name=Fred;Birthday=19-June-1906;ID=12345"
I want to extract Birthday or ID without having to split the string into an array.
EDIT: I'd prefer not to split the string into an array in case the format of the string changes later. I don't have control over the string. What if someone switches the order around or adds another element?
I’m currently unable to test this, lacking a VB compiler, but the following solution should also work, and it has the advantage of not requiring an explicit loop. It uses the Linq method ToDictionary and two nested Split operations:
Dim s = "Name=Fred;Birthday=19-June-1906;ID=12345"
Dim d = s.Split(";"c).Select(Function (kvp) kvp.Split("="c)) _
.ToDictionary( _
Function (kvp) kvp(0), _
Function (kvp) kvp(1))
First, we split on the outer delimiter (i.e. the semi-colon). From the resulting array, we select by splitting again, this time on =. The resulting array of arrays is converted to a dictionary by specifying that the first item is to become the key and the second is to become the value (the identifier kvp stands for “key-value pair”).
Since I can’t check the exact VB syntax and the above may contain subtle errors, here is the equivalent C# code (tested for correctness):
var s = "Name=Fred;Birthday=19-June-1906;ID=12345";
var d = s.Split(';').Select(kvp => kvp.Split('='))
.ToDictionary(kvp => kvp[0], kvp => kvp[1]);
Not sure why you don't want to split it. If you're sure there won't be any extra = or ; then you could just do:
Dim s As String = "Name=Fred;Birthday=19-June-1906;ID=12345"
Dim d As New Dictionary(Of String, String)
For Each temp As String In s.Split(";"c)
Dim index As Int32 = temp.IndexOf("="c)
d.Add(temp.Substring(0, index), temp.Substring(index + 1))
Next
Which might not be beautiful, but is very easy to understand.
input.Split(";"c) returns an array of key/value:
{ "Name=Fred", "Birthday=19-June-1906" , "ID=12345" }
so pair.Split("="c) returns { "Name", "Fred" } etc
If you want an alternative to doing a String.Split; there is always Regular Expressions as an alternative:
Dim map As Dictionary(Of String, String) = New Dictionary(Of String, String)
Dim match As Match = Regex.Match("Name=Fred;Birthday=19-June-1906;ID=12345", "(?<Name>[^=]*)=(?<Value>[^;]*);?")
While (match.Success)
map.Add(match.Groups("Name").Value, match.Groups("Value").Value)
match = match.NextMatch()
End While
The regular expression itself could be beefed up to better handle whitespace between key/value's and pair's but you hopefully get the idea. This should only pass through the string once to build up a string dictionary of keys and values.
Dim persSeparator as string=";"
Dim keyValSeparator as string="=";
Dim allPersons As New Dictionary(Of String, Person)
Dim str As String = "Name=Fred;Birthday=19-June-1906;ID=12345"
Dim parts As New List(Of String)(str.Split(persSeparator.ToCharArray)) 'why dont want you to split this string??
Dim person As New Person
For Each part As String In parts
Dim keyValue() As String = part.Split(keyValSeparator.toCharArray())
Select Case keyValue(0).ToUpper
Case "ID"
person.ID = keyValue(1)
Case "NAME"
person.Name = keyValue(1)
Case "BIRTHDAY"
person.BirthDay= keyValue(1)
End Select
Next
If Not allPersons.ContainsKey(person.ID) Then
allPersons.Add(person.ID, person)
End If
Public Class Person
Private _name As String
Private _birthday As String
Private _id As String = String.Empty
Public Sub New()
End Sub
Public Sub New(ByVal id As String)
Me._id = id
End Sub
Public Sub New(ByVal id As String, ByVal name As String)
Me._id = id
Me._name = name
End Sub
Public Sub New(ByVal id As String, ByVal name As String, ByVal birthday As String)
Me._id = id
Me._name = name
Me._birthday = birthday
End Sub
Public Property ID() As String
Get
Return Me._id
End Get
Set(ByVal value As String)
Me._id = value
End Set
End Property
Public Property Name() As String
Get
Return Me._name
End Get
Set(ByVal value As String)
Me._name = value
End Set
End Property
Public Property BirthDay() As String
Get
Return Me._birthday
End Get
Set(ByVal value As String)
Me._birthday = value
End Set
End Property
Public Overrides Function Equals(ByVal obj As Object) As Boolean
If TypeOf obj Is Person AndAlso Not obj Is Nothing Then
Return String.Compare(Me._id, DirectCast(obj, Person).ID) = 0
Else : Return False
End If
End Function
End Class
If you were just wanting to extract the birthday and ID from the string and place as a value pair in some sort of dictionary, for simplicity I would use regular expressions and then a generic dictionary (of string, valuepair structure). Something like this:
Imports System.Text.RegularExpressions
Imports System.Collections.Generic
Sub Main()
Dim Person As New Dictionary(Of String, ValuePair)
Dim s As String = "Name=Fred;Birthday=19-June-1906;ID=12"
Dim r As Regex = New Regex("Name=(.*);Birthday=(.*);ID=(.*$)")
Dim m As Match = r.Match(s)
Person.Add(CStr(m.Groups(1).Value), _
New ValuePair(CDate(m.Groups(2).Value), CInt(m.Groups(3).Value)))
Console.WriteLine(Person("Fred").Birthday.ToString)
Console.WriteLine(Person("Fred").ID.ToString)
Console.Read()
End Sub
Friend Structure ValuePair
Private _birthday As Date
Private _ID As Int32
Public ReadOnly Property ID() As Int32
Get
Return _ID
End Get
End Property
Public ReadOnly Property Birthday() As Date
Get
Return _birthday
End Get
End Property
Sub New(ByVal Birthday As Date, ByVal ID As Int32)
_birthday = Birthday
_ID = ID
End Sub
End Structure
How do i Declare a string like this:
Dim strBuff As String * 256
in VB.NET?
Use the VBFixedString attribute. See the MSDN info here
<VBFixedString(256)>Dim strBuff As String
It depends on what you intend to use the string for. If you are using it for file input and output, you might want to use a byte array to avoid encoding problems. In vb.net, A 256-character string may be more than 256 bytes.
Dim strBuff(256) as byte
You can use encoding to transfer from bytes to a string
Dim s As String
Dim b(256) As Byte
Dim enc As New System.Text.UTF8Encoding
...
s = enc.GetString(b)
You can assign 256 single-byte characters to a string if you need to use it to receive data, but the parameter passing may be different in vb.net than vb6.
s = New String(" ", 256)
Also, you can use vbFixedString. I'm not sure exactly what this does, however, because when you assign a string of different length to a variable declared this way, it becomes the new length.
<VBFixedString(6)> Public s As String
s = "1234567890" ' len(s) is now 10
To write this VB 6 code:
Dim strBuff As String * 256
In VB.Net you can use something like:
Dim strBuff(256) As Char
Use stringbuilder
'Declaration
Dim S As New System.Text.StringBuilder(256, 256)
'Adding text
S.append("abc")
'Reading text
S.tostring
Try this:
Dim strbuf As New String("A", 80)
Creates a 80 character string filled with "AAA...."'s
Here I read a 80 character string from a binary file:
FileGet(1,strbuf)
reads 80 characters into strbuf...
You can use Microsoft.VisualBasic.Compatibility:
Imports Microsoft.VisualBasic.Compatibility
Dim strBuff As New VB6.FixedLengthString(256)
But it's marked as obsolete and specifically not supported for 64-bit processes, so write your own that replicates the functionality, which is to truncate on setting long values and padding right with spaces for short values. It also sets an "uninitialised" value, like above, to nulls.
Sample code from LinqPad (which I can't get to allow Imports Microsoft.VisualBasic.Compatibility I think because it is marked obsolete, but I have no proof of that):
Imports Microsoft.VisualBasic.Compatibility
Dim U As New VB6.FixedLengthString(5)
Dim S As New VB6.FixedLengthString(5, "Test")
Dim L As New VB6.FixedLengthString(5, "Testing")
Dim p0 As Func(Of String, String) = Function(st) """" & st.Replace(ChrW(0), "\0") & """"
p0(U.Value).Dump()
p0(S.Value).Dump()
p0(L.Value).Dump()
U.Value = "Test"
p0(U.Value).Dump()
U.Value = "Testing"
p0(U.Value).Dump()
which has this output:
"\0\0\0\0\0"
"Test "
"Testi"
"Test "
"Testi"
This object can be defined as a structure with one constructor and two properties.
Public Structure FixedLengthString
Dim mValue As String
Dim mSize As Short
Public Sub New(Size As Integer)
mSize = Size
mValue = New String(" ", mSize)
End Sub
Public Property Value As String
Get
Value = mValue
End Get
Set(value As String)
If value.Length < mSize Then
mValue = value & New String(" ", mSize - value.Length)
Else
mValue = value.Substring(0, mSize)
End If
End Set
End Property
End Structure
https://jdiazo.wordpress.com/2012/01/12/getting-rid-of-vb6-compatibility-references/
Have you tried
Dim strBuff as String
Also see Working with Strings in .NET using VB.NET
This tutorial explains how to
represent strings in .NET using VB.NET
and how to work with them with the
help of .NET class library classes.
Dim a as string
a = ...
If a.length > theLength then
a = Mid(a, 1, theLength)
End If
This hasn't been fully tested, but here's a class to solve this problem:
''' <summary>
''' Represents a <see cref="String" /> with a minimum
''' and maximum length.
''' </summary>
Public Class BoundedString
Private mstrValue As String
''' <summary>
''' The contents of this <see cref="BoundedString" />
''' </summary>
Public Property Value() As String
Get
Return mstrValue
End Get
Set(value As String)
If value.Length < MinLength Then
Throw New ArgumentException(String.Format("Provided string {0} of length {1} contains less " &
"characters than the minimum allowed length {2}.",
value, value.Length, MinLength))
End If
If value.Length > MaxLength Then
Throw New ArgumentException(String.Format("Provided string {0} of length {1} contains more " &
"characters than the maximum allowed length {2}.",
value, value.Length, MaxLength))
End If
If Not AllowNull AndAlso value Is Nothing Then
Throw New ArgumentNullException(String.Format("Provided string {0} is null, and null values " &
"are not allowed.", value))
End If
mstrValue = value
End Set
End Property
Private mintMinLength As Integer
''' <summary>
''' The minimum number of characters in this <see cref="BoundedString" />.
''' </summary>
Public Property MinLength() As Integer
Get
Return mintMinLength
End Get
Private Set(value As Integer)
mintMinLength = value
End Set
End Property
Private mintMaxLength As Integer
''' <summary>
''' The maximum number of characters in this <see cref="BoundedString" />.
''' </summary>
Public Property MaxLength As Integer
Get
Return mintMaxLength
End Get
Private Set(value As Integer)
mintMaxLength = value
End Set
End Property
Private mblnAllowNull As Boolean
''' <summary>
''' Whether or not this <see cref="BoundedString" /> can represent a null value.
''' </summary>
Public Property AllowNull As Boolean
Get
Return mblnAllowNull
End Get
Private Set(value As Boolean)
mblnAllowNull = value
End Set
End Property
Public Sub New(ByVal strValue As String,
ByVal intMaxLength As Integer)
MinLength = 0
MaxLength = intMaxLength
AllowNull = False
Value = strValue
End Sub
Public Sub New(ByVal strValue As String,
ByVal intMinLength As Integer,
ByVal intMaxLength As Integer)
MinLength = intMinLength
MaxLength = intMaxLength
AllowNull = False
Value = strValue
End Sub
Public Sub New(ByVal strValue As String,
ByVal intMinLength As Integer,
ByVal intMaxLength As Integer,
ByVal blnAllowNull As Boolean)
MinLength = intMinLength
MaxLength = intMaxLength
AllowNull = blnAllowNull
Value = strValue
End Sub
End Class