I'm writing a script that will count a numbers of days between few separate dates. I have a data in cell like:
1-In Progress#02-ASSIGNED TO TEAM#22/01/2013 14:54:23,4-On
Hold#02-ASSIGNED TO TEAM#18/01/2013 16:02:03,1-In Progress#02-ASSIGNED
TO TEAM#18/01/2013 16:02:03
That's the info about my transaction status. I want to count the numbers of days that this transaction was in "4-On Hold". So in this example it will be between 18/01/2013 and 22/01/2013.
I wrote something like this(sorry for ma native language words in text)
Sub Aktywnywiersz()
Dim wiersz, i, licz As Integer
Dim tekstwsadowy As String
Dim koniectekstu As String
Dim pozostalytekst As String
Dim dataztekstu As Date
Dim status4jest As Boolean
Dim status4byl As Boolean
Dim datarozpoczecia4 As Date
Dim datazakonczenia4 As Date
Dim dniw4 As Long
wiersz = 2 'I start my scrypt from second row of excel
Do Until IsEmpty(Cells(wiersz, "A")) 'this should work until there is any text in a row
status4jest = False 'is status 4-On Hold is now in a Loop
status4byl = False 'is status 4-On Hold was in las loop
dniw4 = 0 ' numbers od days in 4-On Hold status
tekstwsadowy = Cells(wiersz, "H").Value2 'grabing text
tekstwsadowy = dodanieprzecinka(tekstwsadowy) 'in some examples I had to add a coma at the end of text
For i = 1 To Len(tekstwsadowy)
If Right(Left(tekstwsadowy, i), 1) = "," Then licz = licz + 1 'count the number of comas in text that separates the changes in status
Next
For j = 1 To licz
koniectekstu = funkcjaliczeniadni(tekstwsadowy) 'take last record after coma
Cells(wiersz, "k") = koniectekstu
dataztekstu = funkcjadataztekstu(koniectekstu) 'take the date from this record
Cells(wiersz, "m") = dataztekstu
status4jest = funkcjaokreslenia4(koniectekstu) 'check if there is 4-On Hold in record
Cells(wiersz, "n") = status4jest
If (status4byl = False And staus4jest = True) Then
datarozpoczecia4 = dataztekstu
status4byl = True
ElseIf (status4byl = True And staus4jest = False) Then
datazakonczenia4 = dataztekstu
status4byl = False 'if elseif funkcion to check information about 4-On Hold
dniw4 = funkcjaobliczeniadniw4(dniw4, datazakonczenia4, datarozpoczecia4) 'count days in 4-On Hold
Else
'Else not needed...
End If
tekstwsadowy = resztatekstu(tekstwsadowy, koniectekstu) 'remove last record from main text
Next
Cells(wiersz, "L") = dniw4 ' show number of days in 4-On Hold status
wiersz = wiersz + 1
Loop
End Sub
Function funkcjaliczeniadni(tekstwsadowy As String)
Dim a, dl As Integer
dl = Len(tekstwsadowy)
a = 0
On Error GoTo errhandler:
Do Until a > dl
a = Application.WorksheetFunction.Find(",", tekstwsadowy, a + 1)
Loop
funkcjaliczeniadni = tekstwsadowy
Exit Function
errhandler:
funkcjaliczeniadni = Right(tekstwsadowy, dl - a)
End Function
Function dodanieprzecinka(tekstwsadowy As String)
If Right(tekstwsadowy, 1) = "," Then
dodanieprzecinka = Left(tekstwsadowy, Len(tekstwsadowy) - 1)
Else
dodanieprzecinka = tekstwsadowy
End If
End Function
Function resztatekstu(tekstwsadowy, koniectekstu As String)
resztatekstu = Left(tekstwsadowy, Len(tekstwsadowy) - Len(koniectekstu))
End Function
Function funkcjadataztekstu(koniectekstu As String)
funkcjadataztekstu = Right(koniectekstu, 19)
funkcjadataztekstu = Left(funkcjadataztekstu, 10)
End Function
Function funkcjaobliczeniadniw4(dniw4 As Long, datazakonczenia4 As Date, datarozpoczecia4 As Date)
Dim liczbadni As Integer
liczbadni = DateDiff(d, datarozpoczecia4, datazakonczenia4)
funkcjaobliczaniadniw4 = dniw4 + liczbadni
End Function
Function funkcjaokreslenia4(koniectekstu As String)
Dim pierwszyznak As String
pierwszyznak = "4"
If pierszyznak Like Left(koniectekstu, 1) Then
funkcjaokreslenia4 = True
Else
funkcjaokreslenia4 = False
End If
End Function
And for now I get
Run-time error "13"
in
dataztekstu = funkcjadataztekstu(koniectekstu) 'take the date from this record
I would be very grateful for any help.
You are getting that error because of Type Mismatch. dataztekstu is declared as a date and most probably the expression which is being returned by the function funkcjadataztekstu is not a date. You will have to step through it to find what value you are getting in return.
Here is a simple example to replicate that problem
This will give you that error
Option Explicit
Sub Sample()
Dim dt As String
Dim D As Date
dt = "Blah Blah"
D = getdate(dt)
Debug.Print D
End Sub
Function getdate(dd As String)
getdate = dd
End Function
This won't
Option Explicit
Sub Sample()
Dim dt As String
Dim D As Date
dt = "12/12/2014"
D = getdate(dt)
Debug.Print D
End Sub
Function getdate(dd As String)
getdate = dd
End Function
If you change your function to this
Function funkcjadataztekstu(koniectekstu As String)
Dim temp As String
temp = Right(koniectekstu, 19)
temp = Left(temp, 10)
MsgBox temp '<~~ This will tell you if you are getting a valid date in return
funkcjadataztekstu = temp
End Function
Then you can see what that function is returning.
I tried running your code, but it is a little difficult to understand just what it is that you want to do. Part of it is the code in your language, but the code is also hard to read beacuse of the lack of indentation etc. :)
Also, I do not understand how the data in the worksheet looks. I did get it running by guessing, though, and when I did I got the same error you are describing on the second run of the For loop - that was because the koniectekstu string was empty. Not sure if this is your problem, so my solution is a very general.
In order to solve this type of problem:
Use Option Explicit at the top of your code module. This will make you have to declare all variables used in the module, and you will remove many of the problems you have before you run the code. Eg you are declaring a variable status4jest but using a different variable called staus4jest and Excel will not complain unless you use Option Explicit.
Declare return types for your functions.
Format your code so it will be easier to read. Use space before and after statements. Comment everything! You have done some, but make sure a beginner can understand. I will edit you code as an example of indentation.
Debug! Step through your code using F8 and make sure all variables contain what you think they do. You will most likely solve your problem by debugging the code this way.
Ask for help here on specific problems you run into or how to solve specific problems, do not send all the code and ask why it is not working. If you break down your problems into parts and ask separately, you will learn VBA yourself a lot faster.
A specific tip regarding your code: look up the Split function. It can take a string and make an array based on a delimiter - Example: Split(tekstwsadowy, ",") will give you an array of strings, with the text between the commas.
Did I mention Option Explicit? ;)
Anyway, I hope this helps, even if I did not solve the exact error you are getting.
Related
I wrote the following function to check if the prerequisites for my Excel row are satisified.
Public Function PREREQUISITESOK(prerequisites As Range) As String
Dim cw As Worksheet
Dim prerequisite_cell As Range
Dim prerequisite_cell_txt As String
Dim training_id_cell As Range
Dim no_groups_cell_to_compare As Range
Dim no_groups_cell_to_check As Range
Dim training_id_cell_txt As String
Dim training_id_cell_row_n As Integer
Dim n As Integer
Application.Volatile
PREREQUISITESOK = "OK"
Set cw = Sheets("4c.Trainings OSS")
Set training_id = cw.Range("$B$11:$B$34")
Set no_groups_cell_to_compare = cw.Range("J" & CStr(prerequisites.Row))
For Each prerequisite_cell In prerequisites.Cells
prerequisite_cell_txt = prerequisite_cell.Text
If prerequisite_cell_txt = "" Then
Exit For
Else
For Each training_id_cell In training_id.Cells
training_id_cell_txt = training_id_cell.Text
If training_id_cell_txt = prerequisite_cell_txt Then
training_id_cell_row_n = training_id_cell.Row
Set no_groups_cell_to_check = cw.Cells(training_id_cell_row_n, no_groups_cell_to_compare.Column)
If no_groups_cell_to_check.Value < no_groups_cell_to_compare.Value Then
PREREQUISITESOK = "NOT OK"
Exit Function 'It is enough for us that one prerequisite is not satisfied so we can exit the function
Else
PREREQUISITESOK = "OK"
End If
Exit For 'Training IDs are unique so if we find the right Training ID then we may exit the loop
End If
Next training_id_cell
End If
Next prerequisite_cell
End Function
Note that the prerequisites range is inline formatted.
The function that I wrote is supposed to return String value so I completely do not understand why am I getting #VALUE! error.
What is interesting that if I clear formatting from the prerequisites cells that are used as arguments of the function then #VALUE! error disappears.
Do you have any idea why this happens?
I would like to convert a range of numbers (and single digits) from a number-only format to alpha-numeric format. Entire statement is in a single, excel cell and would like the converted version to be in a neighboring cell.
As an example:
Assuming 1-24=B1-B24
Assuming 25-48=C1-C24
INPUT—
screen 1-3,5,7-9,11-30,32-37,39-40,41,44-46
DESIRED OUTPUT (all acceptable)
screen B1-B3,B5,B7-B9,B11-C6,C8-C13,C15-C16,C17,C20-C22
OR
screen B1-B3,B5,B7-B9,B11-B24,C1-C6,C8-C13,C15-C16,C17,C20-C22
OR
screen B1-B3,B5,B7-B9,B11-B24
screen C1-C6,C8-C13,C15-C16,C17,C20-C22
Using excel functions is proving quite cumbersome so excel macro would be better. I've looked for examples of requested conversion but haven't found anything.
Any help is greatly appreciated.
Cheers,
Bob
Hey here is a solution that i tested out. Not sure if "screen" needs to be in the string or not. Let me know and I will tweak it if that's the case.
Its a user defined function. So drop this vba in a module and then go to a worksheet and type in "=AlphaConvert(" + the cell reference.
Assumption here is that only one cell will be referenced at a time.
Last this could easily be converted to a sub routine and probably run a bit faster than the function.
Public Function AlphaConvert(TargetCell As Range)
Dim v As Long
Dim vArr() As String
Dim i As Long
Dim iArr() As String
Dim a As String
vArr = Split(TargetCell.Value, ",")
For v = LBound(vArr) To UBound(vArr)
If InStr(vArr(v), "-") > 0 Then
iArr = Split(vArr(v), "-")
For i = LBound(iArr) To UBound(iArr)
If i = LBound(iArr) Then
a = AlphaCode(iArr(i))
Else
a = a & "-" & AlphaCode(iArr(i))
End If
Next i
vArr(v) = a
Else
vArr(v) = AlphaCode(vArr(v))
End If
If v = LBound(vArr) Then
AlphaConvert = vArr(v)
Else
AlphaConvert = AlphaConvert & "," & vArr(v)
End If
Next v
End Function
Private Function AlphaCode(Nbr As Variant)
Select Case Nbr
Case 1 To 24
AlphaCode = "B" & Nbr
Case Else
AlphaCode = "C" & Nbr - 24
End Select
End Function
What I want to do is replace all 'A' in a string with "Bb". but it will only loop with the original string not on the new string.
for example:
AAA
BbAA
BbBbA
and it stops there because the original string only has a length of 3. it reads only up to the 3rd index and not the rest.
Dim txt As String
txt = output_text.Text
Dim a As String = a_equi.Text
Dim index As Integer = txt.Length - 1
Dim output As String = ""
For i = 0 To index
If (txt(i) = TextBox1.Text) Then
output = txt.Remove(i, 1).Insert(i, a)
txt = output
TextBox2.Text += txt + Environment.NewLine
End If
Next
End Sub
I think this leaves us looking for a String.ReplaceFirst function. Since there isn't one, we can just write that function. Then the code that calls it becomes much more readable because it's quickly apparent what it's doing (from the name of the function.)
Public Function ReplaceFirst(searched As String, target As String, replacement As String) As String
'This input validation is just for completeness.
'It's not strictly necessary.
'If the searched string is "null", throw an exception.
If (searched Is Nothing) Then Throw New ArgumentNullException("searched")
'If the target string is "null", throw an exception.
If (target Is Nothing) Then Throw New ArgumentNullException("target")
'If the searched string doesn't contain the target string at all
'then just return it - were done.
Dim foundIndex As Integer = searched.IndexOf(target)
If (foundIndex = -1) Then Return searched
'Build a new string that replaces the target with the replacement.
Return String.Concat(searched.Substring(0, foundIndex), replacement, _
searched.Substring(foundIndex + target.Length, searched.Length - (foundIndex + target.Length)))
End Function
Notice how when you read the code below, you don't even have to spend a moment trying to figure out what it's doing. It's readable. While the input string contains "A", replace the first "A" with "Bb".
Dim input as string = "AAA"
While input.IndexOf("A") > -1
input = input.ReplaceFirst(input,"A","Bb")
'If you need to capture individual values of "input" as it changes
'add them to a list.
End While
You could optimize or completely replace the function. What matters is that your code is readable, someone can tell what it's doing, and the ReplaceFirst function is testable.
Then, let's say you wanted another function that gave you all of the "versions" of your input string as the target string is replaced:
Public Function GetIterativeReplacements(searched As String, target As String, replacement As String) As List(of string)
Dim output As New List(Of String)
While searched.IndexOf(target) > -1
searched = ReplaceFirst(searched, target, replacement)
output.Add(searched)
End While
Return output
End Function
If you call
dim output as List(of string) = GetIterativeReplacments("AAAA","A","Bb")
It's going to return a list of strings containing
BbAAA, BbBbAA, BbBbBbA, BbBbBbBb
It's almost always good to keep methods short. If they start to get too long, just break them into smaller methods with clear names. That way you're not trying to read and follow and test one big, long function. That's difficult whether or not you're a new programmer. The trick isn't being able to create long, complex functions that we understand because we wrote them - it's creating small, simpler functions that anyone can understand.
Check your comments for a better solution, but for future reference you should use a while loop instead of a for loop if your condition will be changing and you're wanting to take that change into account.
I've made a simple example below to help you understand. If you tried the same with a for loop, you'd only get "one" "two" and "three" printed because the for loop doesn't 'see' that vals was changed
Dim vals As New List(Of String)
vals.Add("one")
vals.Add("two")
vals.Add("three")
Dim i As Integer = 0
While i < vals.Count
Console.WriteLine(vals(i))
If vals(i) = "two" Then
vals.Add("four")
vals.Add("five")
End If
i += 1
End While
If you do want to replace one by one instead of using the Replace function, you could use a while loop to look for the index of your search character/string, and then replace/insert at that index.
Sub Main()
Dim a As String = String.Empty
Dim b As String = String.Empty
Dim c As String = String.Empty
Dim d As Int32 = -1
Console.Write("Whole string: ")
a = Console.ReadLine()
Console.Write("Replace: ")
b = Console.ReadLine()
Console.Write("Replace with: ")
c = Console.ReadLine()
d = a.IndexOf(b)
While d > -1
a = a.Remove(d, b.Length)
a = a.Insert(d, c)
d = a.LastIndexOf(b)
End While
Console.WriteLine("Finished string: " & a)
Console.ReadLine()
End Sub
Output would look like this:
Whole string: This is A string for replAcing chArActers.
Replace: A
Replace with: Bb
Finished string: This is Bb string for replBbcing chBbrBbcters.
I was going to write a while loop to answer your question, but realized (with assistance from others) that you could just .replace(x,y)
Output.Text = Input.Text.Replace("A", "Bb")
'Input = N A T O
'Output = N Bb T O
Edit: There is probably a better alternative, but i quickly jotted this loop down, hope it helps.
You've said your new and don't fully understand while loops. So if you don't understand functions either or how to pass arguments to them, I'd suggest looking that up too.
This is your Event, It can be a Button click or Textbox text change.
'Cut & Paste into an Event (Change textboxes to whatever you have input/output)
Dim Input As String = textbox1.Text
Do While Input.Contains("A")
Input = ChangeString(Input, "A", "Bb")
' Do whatever you like with each return of ChangeString() here
Loop
textbox2.Text = Input
This is your Function, with 3 Arguments and a Return Value that can be called in your code
' Cut & Paste into Code somewhere (not inside another sub/Function)
Private Function ChangeString(Input As String, LookFor As Char, ReplaceWith As String)
Dim Output As String = Nothing
Dim cFlag As Boolean = False
For i As Integer = 0 To Input.Length - 1
Dim c As Char = Input(i)
If (c = LookFor) AndAlso (cFlag = False) Then
Output += ReplaceWith
cFlag = True
Else
Output += c
End If
Next
Console.WriteLine("Output: " & Output)
Return Output
End Function
I have an excel formula:
=SplitKey(GetSysCd(INDEX([ReportValue],MATCH("mtr_make_model",[FieldName],0)),INDEX([ListName],MATCH("mtr_make_model",[FieldName],0))), 0)
which is running a few subroutines in VBA, but mainly matching values and inserting those values into a cell. When it finds a value for "mtr_make_model" it runs and matches the values inside a sys codes table. The issue I am having is that it is calculating once and then it removes the formula and now has solely the value... In the event that I go to the mtr_make_model field and change the value, the formula does not recalculate. Has anyone heard of this happening? Is this due to something in the VBA code? How do I make that formula stay put and if certain values change, the formula recalculates?
Thanks in advance.
Here are the two functions:
Public Function GetSysCd(ByVal name As String, sysCdTableName As String) As String
Dim r As Integer
Dim sysCdTable As Range
Dim nameList As Variant
Dim sysCd As String
On Error GoTo GetSysCd_Error
Set sysCdTable = Worksheets("sys_cd").Range(sysCdTableName)
nameList = WorksheetFunction.Index(sysCdTable, 0, 2)
r = WorksheetFunction.Match(name, nameList, 0)
sysCd = WorksheetFunction.Index(sysCdTable, r, 1)
GetOutOfHere:
On Error GoTo 0
GetSysCd = sysCd
Exit Function
GetSysCd_Error:
sysCd = ""
GoTo GetOutOfHere
End Function
Public Function SplitKey(s As String, v As Integer)
Dim aString As Variant
Dim r As Integer
If Len(s) > 2 Then
aString = Split(s, "_")
If v = 0 Or v = 1 Then
SplitKey = aString(v)
Else
SplitKey = aString(0)
End If
Else
SplitKey = ""
End If
End Function
I don't think the functions are relevant at this point, but rather just a matter of the function not recalculating when a variable in the formula changes...
The problem could be that Excel only recalculates functions when one of their arguments changes, and your GetSysCd function is referring to a range that is not in its argument list
Set sysCdTable = Worksheets("sys_cd").Range(sysCdTableName)
where sysCdTableName is just a string rather than a reference.
You can make the functions recalculate in real time by adding Application.Volatile True to the top of each function.
I have been trying to write a small piece of code to validate to confirm whether or not a date is included in an array. I have been able to scroll through the code until I reach the line If lists(i) = TodaysDate Then when the lists(i) show subscript out of range. I have searched through the Internet and I'm unable to resolve this issue.
My Macro reads as follows:
Sub size_an_array()
Dim i As Integer
Dim Range_of_Dates As Integer
Dim TodaysDate As Variant, finish As String
TodaysDate = Range("Sheet11!c2")
ThisWorkbook.Worksheets("Sheet11").Activate
lists = Range("Processed_Dates")
Range_of_Dates = UBound(lists, 1) - LBound(lists, 1) + 1
For c = 1 To UBound(lists, 1) ' First array dimension is rows.
For R = 1 To UBound(lists, 2) ' Second array dimension is columns.
Debug.Print lists(c, R)
Next R
Next c
x = Range_of_Dates 'UBound(lists, 1)
ReDim lists(x, 1)
i = 1
Do Until i = x
If lists(i) = TodaysDate Then
Exit Do
End If
Loop
MsgBox "The date has not been found"
End Sub
I'm relatively new to VBA and I have been trying to use named ranges to pull in the array but I'm completely at my wits end in trying to solve this piece.
Any help would be greatly appreciated.
You have ReDimmed the array lists from a one dimensioned array to a two dimensioned array and you are then trying to reference an element using only one dimension in the suspect line (below), which is causing your error.
If lists(i) = TodaysDate Then
For reference, Run-time error 9: Subscript out of range means you are referencing a non-existent array element.
I think this is what you are trying?
Sub size_an_array()
Dim i As Integer
Dim TodaysDate As Variant, lists
Dim bFound As Boolean
'~~> Change SomeWorksheet to the relevant sheet
TodaysDate = Sheets("SomeWorksheet").Range("c2")
lists = Sheets("Sheet11").Range("Processed_Dates")
i = 1
Do Until i = UBound(lists)
If lists(i, 1) = TodaysDate Then
bFound = True
Exit Do
End If
i = i + 1
Loop
If bFound = True Then
MsgBox "The date has been found"
Else
MsgBox "The date has not been found"
End If
End Sub
If I understand you correctly then it is much easier to use .Find. If you are interested then have a look at this link.