Hi I have table badge which has columns facility and date (other columns are not important).
I want to select count(*) which should look like this:
DATE | FACILITY 4 COUNT | FACILITY 1 COUNT
12/12/2012 | 234 | 647
I wrote two separate queries for facility 1 and 4 but how to join it to one Query;
SELECT
date,
COUNT(*)
FROM badge
WHERE facility = 3
AND xtype = 19
AND date BETWEEN 'some_date' AND 'some_date'
GROUP BY date
another query differs only in the value of facility.
EDIT: It's informix database.
SELECT date,
SUM(case when facility = 1 then 1 else 0 end) "FACILITY 1 COUNT",
SUM(case when facility = 4 then 1 else 0 end) "FACILITY 4 COUNT"
FROM badge
WHERE (facility = 1 OR facility = 4)
AND xtype = 19
AND date BETWEEN 'some_date' AND 'some_date'
GROUP BY date
give this a try,
SELECT date,
SUM(CASE WHEN facility = 3 THEN 1 ELSE 0 END) `Facility 3 Count`,
SUM(CASE WHEN facility = 1 THEN 1 ELSE 0 END) `Facility 1 Count`
FROM badge
WHERE xtype = 19 AND
date BETWEEN 'some_date' AND 'some_date'
GROUP BY date
Related
Can you help me plase ?
I want a result like the table below with Sqlite
.
task_name
status_code
department
1
A
START
PUR
2
B
START
ENG
3
C
FINISH
ENG
4
D
NOT ACTIVE
DES
5
E
START
DES
6
F
NOT ACTIVE
ENG
.
START
FINISH
NOT ACTIVE
TOTAL
PUR
1
1
ENG
1
1
1
3
DES
1
1
2
You can use conditional aggregation such as
SELECT department,
SUM(CASE WHEN status_code = 'START' THEN 1 END) AS "START",
SUM(CASE WHEN status_code = 'FINISH' THEN 1 END) AS "FINISH",
SUM(CASE WHEN status_code = 'NOT ACTIVE' THEN 1 END) AS "NOT ACTIVE",
COUNT(*) AS total
FROM t
GROUP BY department
Demo
I have table of customers operations:
date, client_id, gender
1 1 M
1 1 M
1 2 M
1 2 M
1 3 F
2 1 M
2 1 M
2 1 M
2 2 M
2 2 M
2 3 F
2 3 F
2 4 F
2 5 M
2 5 M
etc
Desired output is:
date, amount of males, (also need amount of females)
1 2 1
2 3 2
I need to group it by date, so i did it, then my goal is to find amount of each gender in each grouped group.
so i tried to do this to count amount of males:
sum(case when gender = 'M' then 1 else NULL end) as 'M%'
but its counted clients id 1 and 2 two times each, but i need to count it distinct.
On example above i expect this to return 2 because 2 male. But it return 4 because distinct construction doesnt work.
I tried this but it doesnt work and count '1' in result:
sum(distinct case when gender = 'M' then 1 else NULL end) as 'M%'
It's easier to count from the distinct rows of the table.
Also, use SQLite's feature to treat boolean expressions as 1 for true and 0 for false so you can sum them instead of using CASE expressions:
SELECT date,
SUM(gender = 'M') [amount of males],
SUM(gender = 'F') [amount of females]
FROM (SELECT DISTINCT date, client_id, gender FROM tablename)
GROUP BY date
See the demo.
You seem to want conditional count(distinct):
select date,
count(distinct case when gender = 'M' then client_id end) as count_m,
count(distinct case when gender = 'F' then client_id end) as count_f
from t
group by date;
I've got a beginner question. My SQL table looks like:
| Date | Type | Manufacturer |
2016/04/01 A X
2016/04/01 B Y
2016/04/02 B X
2016/05/07 A Z
... ... ...
My aim is to count the quantity of "Types" by manufacturers between two dates. I would like to get a result like following:
| Manufacturer | Quantity_TypeA | Quantity_TypeB |
X 1 1
Y 0 1
Z 1 0
My query looks like:
select Manufacturer as Manufacturer,
COUNT(*) as Quantity_TypeA
From MyTable
Where [Type] = 'A' and
Date between '20150101' and '20160930',
COUNT(*) as Quantity_TypeB
From MyTable
Where [Type] = 'B' and
Date between '20150101' and '20160930'
group by Manufacturer Order by Quantity_TypeA DESC
I have also tried to use functions like CASE on the Type and it didn't work. I am missing something but what?
Try this
select Manufacturer as Manufacturer,
SUM(case when [Type] = 'A' then 1 else 0 end) as Quantity_TypeA,
SUM(case when [Type] = 'B' then 1 else 0 end) as Quantity_TypeB
From MyTable
Where
Date between '20150101' and '20160930'
group by Manufacturer
Use case expressions to do conditional counting:
select Manufacturer as Manufacturer,
COUNT(case when [Type] = 'A' then 1 end) as Quantity_TypeA,
COUNT(case when [Type] = 'B' then 1 end) as Quantity_TypeB
from MyTable
where Date between '20150101' and '20160930',
group by Manufacturer
order by Quantity_TypeA DESC
count() does only count non-null values. The case expressions either return 1 or null, i.e. only A's or B's are counted.
How to write a SQL to get the Net change in capacity by using the capacity (when status is 1 or 2) and minus the total capacity (when status is 3) for each month? Thanks. Here is the table:
STATUS MONTH CAPACITY
1 01/16 5
3 01/16 2
1 02/16 11
3 02/16 20
1 03/16 8
3 03/16 12
1 04/16 4
2 04/16 10
3 04/16 18
2 05/16 14
3 05/16 37
2 06/16 4
3 06/16 8
For example, the net change in capacity for Jan. 16 is 5 minus 2 equals 3.
You need a conditional sum:
SUM(CASE WHEN STATUS IN (1,2) THEN CAPACITY ELSE 0 END) -
SUM(CASE WHEN STATUS IN (3) THEN CAPACITY ELSE 0 END)
dnoeth answer can be simplified to
SUM(CASE WHEN STATUS IN (1,2) THEN CAPACITY WHEN STATUS IN (3) THEN -CAPACITY ELSE 0 END)
Builds on 1,2 < 3
select MONTH, [Net change]=SUM(CASE STATUS/3 WHEN 0 THEN CAPACITY ELSE -CAPACITY END)
from t
group by MONTH;
no CASE statement:
select month, sum(capacity)-2*sum((status/3)*capacity) from table group by month;
Here is an example
You can join the table to itself and perform the calculation like so:
SELECT
a.status,
a.month,
a.capacity,
b.capacity AS total_capacity,
a.capacity - b.capacity AS net_capacity
FROM
table a
JOIN
table b
ON (a.month = b.month)
AND (b.status = 3)
WHERE
a.status IN (1,2);
-- If you don't want to have the status and instead aggregate in the event there are two within the same month:
SELECT
a.month,
SUM(a.capacity) AS capacity,
SUM(b.capacity) AS total_capacity,
SUM(a.capacity) - MAX(b.capacity) AS net_capacity
FROM
table a
JOIN
table b
ON (a.month = b.month)
AND (b.status = 3)
WHERE
a.status IN (1,2)
GROUP BY
a.month;
SELECT
"Status",
"Month",
SUM(Capacity) AS Capacity
FROM ( SELECT
"Status",
"Month",
CASE WHEN Status = 3 THEN -1 * Capacity ELSE Capacity END AS Capacity FROM tbl
) t
GROUP BY
"Status",
"Month"
I want to use this table to store tickets in PostgreSQL.
CREATE TABLE TICKET(
ID INTEGER NOT NULL,
TITLE TEXT,
STATUS INTEGER,
LAST_UPDATED DATE,
CREATED DATE
)
;
I use column 'status' to set different status(1, 2, 3, 4). How I can count all tickets by status and day with one SQL query?
I would like to get the final result for example like simple array of numbers:
32 31 23 42 9.11.215
31 21 13 22 10.11.215
3 3 2 43 11.11.215
You can doing it with conditional aggregation, which will unite separate rows into 1 aggregated row :
SELECT t.created,
COUNT(CASE WHEN t.status = '1' THEN 1 END) as cnt_status1,
COUNT(CASE WHEN t.status = '2' THEN 1 END) as cnt_status2,
COUNT(CASE WHEN t.status = '3' THEN 1 END) as cnt_status3,
COUNT(CASE WHEN t.status = '4' THEN 1 END) as cnt_status4
FROM ticket t
GROUP BY t.created