I have a postgresql query like this:
with r as (
select
1 as reason_type_id,
rarreason as reason_id,
count(*) over() count_all
from
workorderlines
where
rarreason != 0
and finalinsdate >= '2012-12-01'
)
select
r.reason_id,
rt.desc,
count(r.reason_id) as num,
round((count(r.reason_id)::float / (select count(*) as total from r) * 100.0)::numeric, 2) as pct
from r
left outer join
rtreasons as rt
on
r.reason_id = rt.rtreason
and r.reason_type_id = rt.rtreasontype
group by
r.reason_id,
rt.desc
order by r.reason_id asc
This returns a table of results with 4 columns: the reason id, the description associated with that reason id, the number of entries having that reason id, and the percent of the total that number represents.
This table looks like this:
What I would like to do is only display the top 10 results based off the total number of entries having a reason id. However, whatever is leftover, I would like to compile into another row with a description called "Other". How would I do this?
with r2 as (
...everything before the select list...
dense_rank() over(order by pct) cause_rank
...the rest of your query...
)
select * from r2 where cause_rank < 11
union
select
NULL as reason_id,
'Other' as desc,
sum(r2.num) over() as num,
sum(r2.pct) over() as pct,
11 as cause_rank
from r2
where cause_rank >= 11
As said above Limit and for the skipping and getting the rest use offset... Try This Site
Not sure about Postgre but SELECT TOP 10... should do the trick if you sort correctly
However about the second part: You might use a Right Join for this. Join the TOP 10 Result with the whole table data and use only the records not appearing on the left side. If you calculate the sum of those you should get your "Sum of the rest" result.
I assume that vw_my_top_10 is the view showing you the top 10 records. vw_all_records shows all records (including the top 10).
Like this:
SELECT SUM(a_field)
FROM vw_my_top_10
RIGHT JOIN vw_all_records
ON (vw_my_top_10.Key = vw_all_records.Key)
WHERE vw_my_top_10.Key IS NULL
Related
Please find below image for make understanding my issues. I have a table as shown below picture. I need to get only highlighted (yellow) records. What is the best method to find these records?
In SQL Server 2012+, you can use the lead() and lag() functions. However, this is not available in SQL Server 2008. Here is a method using outer apply:
select t.*
from t outer apply
(select top 1 tprev.*
from t tprev
on tprev.time < t.time
order by tprev.time desc
) tprev outer apply
(select top 1 tnext.*
from t tnext
on tnext.time > t.time
order by tnext.time asc
)
where (t.cardtype = 1 and tnext.cardtype = 2) or
(t.cardtype = 2 and tprev.cardtype = 1);
With your sample data, it would also be possible to use self joins on the id column. This seems unsafe, though, because there could be gaps in that columns values.
Havent tried this, but I think it should work. First, make a view of the table in your question, with the rownumber included as one column:
CREATE VIEW v AS
SELECT
ROW_NUMBER() OVER(ORDER BY id) AS rownum,
id,
time,
card,
card_type
FROM table
Then, you can get all the rows of type 1 followed by a row of type 2 like this:
SELECT
a.id,
-- And so on...
FROM v AS a
JOIN v AS b ON b.rownum = a.rownum + 1
WHERE a.card_type = 1 AND b.card_type = 2
And all the rows of type 2 preceded by a row of type 1 like this:
SELECT
b.id,
-- And so on...
FROM v AS b
JOIN v AS a ON b.rownum = a.rownum + 1
WHERE a.card_type = 1 AND b.card_type = 2
To get them both in the same set of results, you can just use UNION ALL. Technically, you don't need the view. You could use nested selects instead, but since you will need to query the table four times it might be nice to have it as a view.
Also, if the ID is continous (it goes 1, 2, 3 without any gaps), you don't need the rownum and can just use the ID instead.
here is a code you can run in sql server
select * from Table_name where id in (1,2,6,7,195,160,164,165)
SELECT TOP 10 [FINAL_FOR_DB].[Indemnity_Paid]/[FINAL_FOR_DB].[Claim_Count] AS Indemnity_Cost,
final_for_db.Claimant_Name,
final_for_db.Account_Name,
final_for_db.Claim_ID,
final_for_db.File_Date,
final_for_db.Resolution_Date,
final_for_db.Claim_Status,
final_for_db.State_Filed, final_for_db.Expense_Amount,
final_for_db.Claim_Count,
final_for_db.Indemnity_Paid AS [Total Indemnity]
FROM final_for_db
WHERE (((final_for_db.Account_Name)="Exxon"))
ORDER BY [FINAL_FOR_DB].[Indemnity_Paid]/[FINAL_FOR_DB].[Claim_Count] DESC;
This would only give me top 10 entries for Exxon but I am wondering if there is a way to get top 10 entries for each account name from the biggest indemnity cost to the lowest. I believe there is a need for subquery. I would appreciate any help on this. Thanks
Other RDBMS's support the RANK() and ROW_NUMBER() functions. Unfortunately, Access does not (to my knowledge). This should get you close to what you want. It does not handle duplicates well (two customers with the same indemnity cost would get the same rank, possibly leaving you with the top 11 or so).
Select * From
(
Select *
, (
Select count(*)
From final_for_db as tbl2
where (tbl1.Indemnity_Paid/tbl1.Claim_Count) < (tbl2.Indemnity_Paid/tbl2.Claim_Count)
and tbl1.Account_Name= tbl2.Account_Name
) + 1 as rank from final_for_db tbl1
) x where x.Rank < 10
This question already has answers here:
Select first row in each GROUP BY group?
(20 answers)
Closed 8 years ago.
I am writing a program for amateur radio. Some callsigns will appear more than once in the data but the qsodate will be different. I only want the first occurrence of a call sign after a given date.
The query
select distinct
a.callsign,
a.SKCC_Number,
a.qsodate,
b.name,
a.SPC,
a.Band
from qso a, skccdata b
where SKCC_Number like '%[CTS]%'
AND QSODate > = '2014-08-01'
and b.callsign = a.callsign
order by a.QSODate
The problem:
Because contacts occur on different dates, I get all of the contacts - I have tried adding min(a.qsodate) to get only the first but then I run into all sorts of issues regarding grouping.
This query will be in a stored procedure, so creating temp tables or cursors will not be a problem.
You can use the ROW_NUMBER() to get the first row with the first date, like this:
WITH CTE
AS
(
select
a.callsign,
a.SKCC_Number,
a.qsodate,
b.name,
a.SPC,
a.Band,
ROW_NUMBER() OVER(PARTITION BY a.callsign ORDER BY a.QSODate) AS RN
from qso a,skccdata b
where SKCC_Number like '%[CTS]%'
AND QSODate > = '2014-08-01'
and b.callsign = a.callsign
)
SELECT *
FROM CTE
WHERE RN = 1;
ROW_NUMBER() OVER(PARTITION BY a.callsign ORDER BY a.QSODate) will give you a ranking number for each group of callsign ordered by QSODate, then the WHERE RN = 1 will eliminate all the rows except the first one which has the minimum QSODate.
Have you tried starting your query with SELECT TOP 1 ...(fields) Then you will only get one row. You can use TOP x .... for x number of rows, or TOP 50 PERCENT for the top half of the rows, etc. Then you can eliminate DISTINCT in this case
EDIT: misunderstood question. How about this?
select
a.callsign,
a.SKCC_Number,
a.qsodate,
(SELECT TOP 1 b.name FROM skccdata b WHERE b.callsign = a.callsign) as NAME,
a.SPC,
a.Band
from qso a
where SKCC_Number like '%[CTS]%'
AND QSODate > = '2014-08-01'
GROUP BY a.QSODate, a.callsign, a.SKCC_Number, a.SPC, a.Band
order by a.QSODate
and add callsign to your where clause to isolate callsigns
I want to select some rows based on certain criteria, and then take one entry from that set and the 5 rows before it and after it.
Now, I can do this numerically if there is a primary key on the table, (e.g. primary keys that are numerically 5 less than the target row's key and 5 more than the target row's key).
So select the row with the primary key of 7 and the nearby rows:
select primary_key from table where primary_key > (7-5) order by primary_key limit 11;
2
3
4
5
6
-=7=-
8
9
10
11
12
But if I select only certain rows to begin with, I lose that numeric method of using primary keys (and that was assuming the keys didn't have any gaps in their order anyway), and need another way to get the closest rows before and after a certain targeted row.
The primary key output of such a select might look more random and thus less succeptable to mathematical locating (since some results would be filtered, out, e.g. with a where active=1):
select primary_key from table where primary_key > (34-5)
order by primary_key where active=1 limit 11;
30
-=34=-
80
83
100
113
125
126
127
128
129
Note how due to the gaps in the primary keys caused by the example where condition (for example becaseu there are many inactive items), I'm no longer getting the closest 5 above and 5 below, instead I'm getting the closest 1 below and the closest 9 above, instead.
There's a lot of ways to do it if you run two queries with a programming language, but here's one way to do it in one SQL query:
(SELECT * FROM table WHERE id >= 34 AND active = 1 ORDER BY id ASC LIMIT 6)
UNION
(SELECT * FROM table WHERE id < 34 AND active = 1 ORDER BY id DESC LIMIT 5)
ORDER BY id ASC
This would return the 5 rows above, the target row, and 5 rows below.
Here's another way to do it with analytic functions lead and lag. It would be nice if we could use analytic functions in the WHERE clause. So instead you need to use subqueries or CTE's. Here's an example that will work with the pagila sample database.
WITH base AS (
SELECT lag(customer_id, 5) OVER (ORDER BY customer_id) lag,
lead(customer_id, 5) OVER (ORDER BY customer_id) lead,
c.*
FROM customer c
WHERE c.active = 1
AND c.last_name LIKE 'B%'
)
SELECT base.* FROM base
JOIN (
-- Select the center row, coalesce so it still works if there aren't
-- 5 rows in front or behind
SELECT COALESCE(lag, 0) AS lag, COALESCE(lead, 99999) AS lead
FROM base WHERE customer_id = 280
) sub ON base.customer_id BETWEEN sub.lag AND sub.lead
The problem with sgriffinusa's solution is that you don't know which row_number your center row will end up being. He assumed it will be row 30.
For similar query I use analytic functions without CTE. Something like:
select ...,
LEAD(gm.id) OVER (ORDER BY Cit DESC) as leadId,
LEAD(gm.id, 2) OVER (ORDER BY Cit DESC) as leadId2,
LAG(gm.id) OVER (ORDER BY Cit DESC) as lagId,
LAG(gm.id, 2) OVER (ORDER BY Cit DESC) as lagId2
...
where id = 25912
or leadId = 25912 or leadId2 = 25912
or lagId = 25912 or lagId2 = 25912
such query works more faster for me than CTE with join (answer from Scott Bailey). But of course less elegant
You could do this utilizing row_number() (available as of 8.4). This may not be the correct syntax (not familiar with postgresql), but hopefully the idea will be illustrated:
SELECT *
FROM (SELECT ROW_NUMBER() OVER (ORDER BY primary_key) AS r, *
FROM table
WHERE active=1) t
WHERE 25 < r and r < 35
This will generate a first column having sequential numbers. You can use this to identify the single row and the rows above and below it.
If you wanted to do it in a 'relationally pure' way, you could write a query that sorted and numbered the rows. Like:
select (
select count(*) from employees b
where b.name < a.name
) as idx, name
from employees a
order by name
Then use that as a common table expression. Write a select which filters it down to the rows you're interested in, then join it back onto itself using a criterion that the index of the right-hand copy of the table is no more than k larger or smaller than the index of the row on the left. Project over just the rows on the right. Like:
with numbered_emps as (
select (
select count(*)
from employees b
where b.name < a.name
) as idx, name
from employees a
order by name
)
select b.*
from numbered_emps a, numbered_emps b
where a.name like '% Smith' -- this is your main selection criterion
and ((b.idx - a.idx) between -5 and 5) -- this is your adjacency fuzzy-join criterion
What could be simpler!
I'd imagine the row-number based solutions will be faster, though.
In my application I use SELECT TOP 12 * clause to select top 12 records from database and show it to user. In another case I have to show the same result one by one. So I use SELECT TOP 1 * clause,rest of the query is same. I used Sql row_number() function to select items one by on serially.
The problem is SELECT TOP 1 * doesn't return me same row as I get in SELECT TOP 12 *. Also the result set of SELECT TOP 12 * get changed each time I execute the query.
Can anybody explain me why the result is not get same in SELECT TOP 12 * and SELECT TOP 1 *.
FYI: here is my sql
select distinct top 1 * from(
select row_number() over ( ORDER BY Ratings desc ) as Row, * from(
SELECT vw.IsHide, vw.UpdateDate, vw.UserID, vw.UploadPath, vw.MediaUploadID, vw.Ratings, vw.Caption, vw.UserName, vw.BirthYear, vw.BirthDay, vw.BirthMonth, vw.Gender, vw.CityProvince, vw.Approved
FROM VW_Media as vw ,Users as u WITH(NOLOCk)
WHERE vw.IsHide='false' and
GenderNVID=5 and
vw.UserID=u.UserID and
vw.UserID not in(205092) and
vw.UploadTypeNVID=1106 and
vw.IsDeleted='false' and
vw.Approved = 1 and
u.HideProfile=0 and
u.StatusNVID=126 and
vw.UserID not in(Select BlockedToUserID from BlockList WITH(NOLOCk) where UserID=205092) a) totalres where row >0
Thanks in Advance
Sachin
When you use SELECT TOP, you must use also the ORDER BY clause to avoid different results every time.
For performance resons, the database is free to return the records in any order it likes if you don't specify any ordering.
So, you always have to specify in which order you want the records, if you want them in any specific order.
Up to some version of SQL Server (7 IIRC) the natural order of the table was preserved in the result if you didn't specify any ordering, but this feature was removed in later versions.