I am using Oracle 11 G and have the following set of data:
12.0
4.2
Version.1
7.9
abc.72
I want to return all string characters before the period. What sort of query would I run in order to achieve this? Any help would be greatly appreciated, thanks!
You can try a combination of instr and substr.
Something like this:
select substr(field, 1, instr(field, '.') - 1)
from your_table;
Assuming field always contains a . character on it.
You can also deal with strings without a . by using case, if or any other similar valid conditional function on Oracle's SQL language implementation.
Of course, you can always put this on a function to make it look nicer on your query.
Related
Suppose there is a value 842545/003. I need to take the part after '/'.
84454/02. I want a query to take the only 02 from here
You can try below substr() and instr() function
select substr('84454/02',instr('84454/02','/')+1,
length('84454/02')-instr('84454/02','/')) as val
from dual
You can use a regex (with the usual warnings about regex performance - the simple string functions like instr and substr are faster if you are processing millions of rows).
regexp_replace(yourcolumn, '^.*/')
This removes everything up to and including the / character (or the final one if there is more than one).
If your are using SQL, you can use this.
SELECT SUBSTRING('84454/02',PATINDEX('%/%', '84454/02')+1,LEN('84454/02'));
'84454/02'= Column name
Hi all I am trying to write sql for selecting string between two special characters.
example: in the table, field value like 7185878969-129981041-000000 . how can I select only middle portion 129981041 without hard coding. What will be the best way to go about this?.Please provide sample code. Thanks
Impala has split_part():
select split_part(col, '-', 2)
Try this for MySQL:
SELECT REVERSE(SUBSTRING_INDEX(REVERSE(SUBSTRING_INDEX(Column,'-',2)),'-',1))
FROM table_name;
Result:
129981041
I require a select query that adds a space to the data based on the placement of the capital letters i.e. 'HelpMe' using this query would be displayed as 'Help Me' . Note i cannot use a stored function to do this the it must be done in the query itself. The Data is of variable length and query must be in SQL. Any Help will be appreciated.
Thanks
You need to use user defined function for this until MS give us support for regular expressions. Solution would be something like:
SELECT col1, dbo.RegExReplace(col1, '([A-Z])',' \1') FROM Table
Aldo this would produce leading space that you can remove with TRIM.
Replace regular expresion function:
http://connect.microsoft.com/SQLServer/feedback/details/378520
About dbo.RegexReplace you can read at:
TSQL Replace all non a-z/A-Z characters with an empty string
Assume if you are using Oracle RDBMS, you use the following,
REGEX_REPLACE
SELECT REGEXP_REPLACE('ILikeToWatchCSIMiami',
'([A-Z.])', ' \1')
AS RX_REPLACE
FROM dual
;
Managed to get this output: * SQLFIDDLE
But as you see it doesn't treat well on words such as CSI though.
jkdfhdjfhjh&name=ijkjkjkjkjkjk&id=kdjkjkjkjkjkjjjd&class=kdfjjfjdhfjhf
The above string has some characters starting with & and ending with =
for example we have &name= and I just need this from the above string.
similarly I need &id=, &class=
I need the output under a single column.
Final Extract
----------------------
&id=, &class=, &name=
can anyone help me out in writing a query for this.
You could try this :
select regexp_replace('jkdfhdjfhjh&name=ijkjkjkjkjkjk&id=kdjkjkjkjkjkjjjd&class=kdfjjfjdhfjhf', '\\w*?(&.*?=)\\w+((?=&)|$)', '\\1, ', 'g');
result:
regexp_replace
-------------------------
&name=, &id=, &class=,
Then it's up to you to remove the last ,.
The regexp_replace function is available in version 8.1 and after.
If you want the values along with each variable, I would implement this by splitting on "&" into an array and then taking a slice of the desired elements:
SELECT (string_to_array('jkdfhdjfhjh&name=ijkjkjkjkjkjk&id=kdjkjkjkjkjkjjjd&class=kdfjjfjdhfjhf','&'))[2:4];
Output in PostgreSQL 8.4 (array type):
{name=ijkjkjkjkjkjk,id=kdjkjkjkjkjkjjjd,class=kdfjjfjdhfjhf}
The example string is very wide so here's the general form to show the array slicing more clearly:
SELECT ((string_to_array(input_field,'&'))[2:4];
NOTE: You must have the extra parentheses around the string_to_array() call in order for the array slicing to work--you'll get an error otherwise.
In my DB, I store various version numbers, like the following :
OBJNAME
Fix_6.0.0a.1
Fix_6.0.0a.2
I would like to sort them not according to last version element (the number behind the last . character. How do I write such SQL statement ?
I guess it's something like:
SELECT SUBSTR(INSTR(OBJNAME, ".", -1)) as LAST_VERSION, OBJNAME
FROM MY_TABLE
ORDER BY LAST_VERSION
But what is the exact syntax?
The correct version is
select TO_NUMBER(SUBSTR(OBJNAME,INSTR(OBJNAME,'.',-1)+1,LENGTH(OBJNAME))) as LAST_VERSION, OBJNAME from MY_TABLE order by LAST_VERSION
i dont know which sql-software you are using, but you should have a look at substr and instr parameters. in you case you are passing 3 parameters to instr and 1 parameter in substr. but substr normally requires more. insert some blanks to get an overview of your statement, especially for the substr.... as LAST_VERSION. then you will see. wrong param count.