Convert numbers in Chinese characters to arabic numbers - objective-c

Question

I am a newbie in programming and i start with Objective C as my first language.
I am messing around with some books and tutorials, at last programing a calculator...
Everything fine and i am getting into (programming makes really fun)
Now i am asking myself how I could translate arabic numbers to chinese numbers
(e.g. arabic 4 is in chinese 四 and 8 is 八 which means 四 + 四 = 八
The chinese number system is kind of different than arabic they have signs for 100, 1000, 10000 and ja kind of twisted, which screws up my brain ... anyway do anybody have some advice, hints, tips or solutions how i can tell the computer how to work with this numbers, or even how to calculate with them?
I think everything is possible so i wont ask "If its even possible?"

Answer 1

Considering the Chinese numerical system (Mandarin) as described by wikipedia http://en.wikipedia.org/wiki/Chinese_numerals, where for instance:
45 is interpreted as [4] [10] [5] and written 四十五
114 is interpreted as [1] [100] [1] [10] [4] and written 一百一十四
So the trick is to decompose a number as powers of 10:
x = c(k)*10^k + ... + c(1)*10 + c(0)
where k is the largest power of 10 that divides x such that the quotient is at least 1. In the 2nd example above, 114 = 1*10^2 + 1*10 + 4.
This x = c(k)*10^k + ... + c(1)*10 + c(0) becomes [c(k)][10^k]...[c(1)][10][c(0)]. In the 2nd example again, 114 = [1] [100] [1] [10] [4].
Then map each number within bracket to the corresponding sinogram:
0 = 〇
1 = 一
2 = 二
3 = 三
4 = 四
5 = 五
6 = 六
7 = 七
8 = 八
9 = 九
10 = 十
100 = 百
1000 = 千
10000 = 万
As long as you keep track of the [c(k)][10^k]...[c(1)][10][c(0)] form, it's easy to convert to an integer that the computer can handle or to the corresponding Chinese numeral. So it's this [c(k)][10^k]...[c(1)][10][c(0)] form that I'd store in an integer array of size k+2.

Answer 2

I'm not familiar with Objective-C, thus I can't help you with a solution for iOS.
Nonetheless, following is the Java code for Android...
I assumed it might help you, as well as it helped me.
double text2double(String text) {
String[] units = new String[] { "〇", "一", "二", "三", "四",
"五", "六", "七", "八", "九"};
String[] scales = new String[] { "十", "百", "千", "万",
"亿" };
HashMap<String, ScaleIncrementPair> numWord = new HashMap<String, ScaleIncrementPair>();
for (int i = 0; i < units.length; i++) {
numWord.put(units[i], new ScaleIncrementPair(1, i));
}
numWord.put("零", new ScaleIncrementPair(1, 0));
numWord.put("两", new ScaleIncrementPair(1, 2));
for (int i = 0; i < scales.length; i++) {
numWord.put(scales[i], new ScaleIncrementPair(Math.pow(10, (i + 1)), 0));
}
double current = 0;
double result = 0;
for (char character : text.toCharArray()) {
ScaleIncrementPair scaleIncrement = numWord.get(String.valueOf(character));
current = current * scaleIncrement.scale + scaleIncrement.increment;
if (scaleIncrement.scale > 10) {
result += current;
current = 0;
}
}
return result + current;
}
class ScaleIncrementPair {
public double scale;
public int increment;
public ScaleIncrementPair(double s, int i) {
scale = s;
increment = i;
}
}

Answer 3

You can make use of NSNumberFormatter.
Like below code, firstly get NSNumber from chinese characters, then combine them.
func getNumber(fromText text: String) -> NSNumber? {
let locale = Locale(identifier: "zh_Hans_CN")
let numberFormatter = NumberFormatter()
numberFormatter.locale = locale
numberFormatter.numberStyle = .spellOut
guard let number = numberFormatter.number(from: text) else { return nil }
print(number)
return number
}