Hi I need help on a sql query. The result must match values for a single column across the rows. Here is an example. I need to find out store(s) that must have all of these items for sale: Books, Stationery, and Toys.
Store Items
----- --------
AA PERFUMES
AA TOYS
BB STATIONERY
BB BOOKS
BB TOYS
In the example above, "BB" is the only store that matches all of our criteria and hence the result expected from the query.
I tried query with AND operator (select store from storeitem where items = 'books' and items ='toys' and items='stationery';) and it did not work as it expects all values in the same row and with in operator (select store from storeitem where items in ('books','stationery','toys');) , this doesn't follow must match all values criteria.
Need your help on this.
You could skip using subqueries alltogether and use a HAVING DISTINCT clause to return the stores you need.
SELECT store, COUNT(*)
FROM your_table
WHERE items in ('STATIONAIRY', 'BOOKS', 'TOYS')
GROUP BY
store
HAVING COUNT(DISTINCT items) = 3
;
Example
WITH your_table as (
SELECT 'AA' as Store, 'PERFUMES' as Items FROM dual UNION ALL
SELECT 'AA', 'TOYS' FROM dual UNION ALL
SELECT 'BB', 'STATIONAIRY' FROM dual UNION ALL
SELECT 'BB', 'BOOKS' FROM dual UNION ALL
SELECT 'BB', 'TOYS' FROM dual
)
SELECT store, COUNT(*)
FROM your_table
WHERE items in ('STATIONAIRY', 'BOOKS', 'TOYS')
GROUP BY
store
HAVING COUNT(DISTINCT items) = 3
;
select store
from (
select distinct store, items
from your_table
where items in ('books','stationery','toys')
)
group by store
having count(0) = 3
This is the general approach that should work (not tested on Oracle specifically):
select store from (
select store,
max(case when items = 'stationery' then 1 else 0 end) as has_stationery,
max(case when items = 'books' then 1 else 0 end) as has_books,
max(case when items = 'toys' then 1 else 0 end) as has_toys
from your_table
group by store
) as stores_by_item
where has_stationery = 1 and has_books = 1 and has_toys = 1
If I correctly understand your question, you needed that query:
Select store from storeitem where store in (select store from storeitem where items = 'books') AND store in (select store from storeitem where items ='toys') AND store in (select store from storeitem where items='stationairy')
Related
ID | Type | Code
1 Purchase A1
1 Return B1
1 Exchange C1
2 Purchase D1
2 Return NULL
2 Exchange F1
3 Purchase G1
3 Return H1
3 Exchange I1
4 Purchase J1
4 Exchange K1
Above is sample data. What I want to return is:
ID | Type | Code
1 Purchase A1
1 Return B1
1 Exchange C1
3 Purchase G1
3 Return H1
3 Exchange I1
So if a field is null in code or the values of Purchase, Return and Exchange are not all present for that ID, ignore that ID completely. However there is one last step. I want this data to then be pivoted this way:
ID | Purchase | Return | Exchange
1 A1 B1 C1
3 G1 H1 I1
I asked this yesterday without the pivot portion which you can see here:
SQL query to return data only if ALL necessary columns are present and not NULL
However I forgot to note the last part. I tried to play around with excel but had no luck. I tried to make a temp table but the data is too large to do that so I was wondering if this could all be done in 1 sql statement?
I personally used this query with success:
select t.*
from t
where 3 = (select count(distinct t2.type)
from t t2
where t2.id = t.id and
t2.type in ('Purchase', 'Exchange', 'Return') and
t2.Code is not null
);
So how can we adjust that to include the pivot part. Is that possible?
Quite easily. Just use conditional aggregation:
select t.id,
max(case when type = 'Purchase' then code end) as Purchase,
max(case when type = 'Exchange' then code end) as Exchange,
max(case when type = 'Return' then code end) as Return
from t
where 3 = (select count(distinct t2.type)
from t t2
where t2.id = t.id and
t2.type in ('Purchase', 'Exchange', 'Return') and
t2.Code is not null
)
group by t.id;
This is actually simpler to express (in my opinion) using having without the subquery:
select t.id,
max(case when type = 'Purchase' then code end) as Purchase,
max(case when type = 'Exchange' then code end) as Exchange,
max(case when type = 'Return' then code end) as Return
from t
group by t.id
having max(case when type = 'Purchase' then code end) is not null and
max(case when type = 'Exchange' then code end) is not null and
max(case when type = 'Return' then code end) is not null;
Many databases would allow:
having Purchase is not null and Exchange is not null and Return is not null
But Oracle doesn't allow the use of table aliases in the having clause.
UPDATE - Based on discussion in the question comments, my previous query had a faulty assumption (which I carried over from what I thought I saw in the original query in the question); I've eliminated the bad assumption.
select id
, max(case when type='Purchase' then Code end) Purchase
, max(case when type='Return' then Code end) Return
, max(case when type='Exchange' then Code end) Exchange
from t
where code is not null
and type in ('Purchase', 'Return', 'Exchange')
group by id
having count(distinct type) = 3
I will point out again (as I did in your other thread) that analytic functions will do the job much faster - they need the base table to be read just once, and there are no explicit or implicit joins.
with
test_data ( id, type, code ) as (
select 1, 'Purchase', 'A1' from dual union all
select 1, 'Return' , 'B1' from dual union all
select 1, 'Exchange', 'C1' from dual union all
select 2, 'Purchase', 'D1' from dual union all
select 2, 'Return' , null from dual union all
select 2, 'Exchange', 'F1' from dual union all
select 3, 'Purchase', 'G1' from dual union all
select 3, 'Return' , 'H1' from dual union all
select 3, 'Exchange', 'I1' from dual union all
select 4, 'Purchase', 'J1' from dual union all
select 4, 'Exchange', 'K1' from dual
)
-- end of test data; actual solution (SQL query) begins below this line
select id, purchase, return, exchange
from ( select id, type, code
from ( select id, type, code,
count( distinct case when type in ('Purchase', 'Return', 'Exchange')
then type end
) over (partition by id) as ct_type,
count( case when code is null then 1 end
) over (partition by id) as ct_code
from test_data
)
where ct_type = 3 and ct_code = 0
)
pivot ( min(code) for type in ('Purchase' as purchase, 'Return' as return,
'Exchange' as exchange)
)
;
Output:
ID PURCHASE RETURN EXCHANGE
--- -------- -------- --------
1 A1 B1 C1
3 G1 H1 I1
2 rows selected.
HI I am unable to filter materials that belong to only specific list.
Select material
from price
where region='04'
and pricelist ='5'
and pricelist not in ('4','6','7');
I want only those materials which are unique only in pricelist 5 and not in any other pricelists. how can i get this?
You might try something like this (alternately, you could do a self-join, but I think this is just as easy, if not easier, to understand):
SELECT material
FROM price a
WHERE region = '04'
AND pricelist = '5'
AND NOT EXISTS ( SELECT 1 FROM price b
WHERE b.material = a.material
AND b.region = a.region
AND b.pricelist != a.pricelist )
What the above will do will find values of material in region '04' where the pricelist is '5' while excluding those same materials in the same region but on a different price list.
Your current query will only return results where pricelist = 5 -- the not in statement is irrelevant unless it exclude that record. It sounds like you want to return any material which matches on the 5, but doesn't have any other non-5 matches.
One option is to use exist. Here's another option using conditional aggregation with max and case which eliminates the need for multiple queries:
select material
from (
select material,
max(case when pricelist = '5' then 1 else 0 end) haspl5,
max(case when pricelist != '5' then 1 else 0 end) hasothers
from price
where region='04'
group by material
) t
where haspl5 = 1 and hasothers != 1
SQL Fiddle Demo
I am writing data to a table and allocating a "group-id" for each batch of data that is written. To illustrate, consider the following table.
GroupId Value
------- -----
1 a
1 b
1 c
2 a
2 b
3 a
3 b
3 c
3 d
In this example, there are three groups of data, each with similar but varying values.
How do I query this table to find a group that contains a given set of values? For instance, if I query for (a,b,c) the result should be group 1. Similarly, a query for (b,a) should result in group 2, and a query for (a, b, c, e) should result in the empty set.
I can write a stored procedure that performs the following steps:
select distinct GroupId from Groups -- and store locally
for each distinct GroupId: perform a set-difference (except) between the input and table values (for the group), and vice versa
return the GroupId if both set-difference operations produced empty sets
This seems a bit excessive, and I hoping to leverage some other commands in SQL to simplify. Is there a simpler way to perform a set-comparison in this context, or to select the group ID that contains the exact input values for the query?
This is a set-within-sets query. I like to solve it using group by and having:
select groupid
from GroupValues gv
group by groupid
having sum(case when value = 'a' then 1 else 0 end) > 0 and
sum(case when value = 'b' then 1 else 0 end) > 0 and
sum(case when value = 'c' then 1 else 0 end) > 0 and
sum(case when value not in ('a', 'b', 'c') then 1 else - end) = 0;
The first three conditions in the having clause check that each elements exists. The last condition checks that there are no other values. This method is quite flexible, for various exclusions and inclusion conditions on the values you are looking for.
EDIT:
If you want to pass in a list, you can use:
with thelist as (
select 'a' as value union all
select 'b' union all
select 'c'
)
select groupid
from GroupValues gv left outer join
thelist
on gv.value = thelist.value
group by groupid
having count(distinct gv.value) = (select count(*) from thelist) and
count(distinct (case when gv.value = thelist.value then gv.value end)) = count(distinct gv.value);
Here the having clause counts the number of matching values and makes sure that this is the same size as the list.
EDIT:
query compile failed because missing the table alias. updated with right table alias.
This is kind of ugly, but it works. On larger datasets I'm not sure what performance would look like, but the nested instances of #GroupValues key off GroupID in the main table so I think as long as you have a good index on GroupID it probably wouldn't be too horrible.
If Object_ID('tempdb..#GroupValues') Is Not Null Drop Table #GroupValues
Create Table #GroupValues (GroupID Int, Val Varchar(10));
Insert #GroupValues (GroupID, Val)
Values (1,'a'),(1,'b'),(1,'c'),(2,'a'),(2,'b'),(3,'a'),(3,'b'),(3,'c'),(3,'d');
If Object_ID('tempdb..#FindValues') Is Not Null Drop Table #FindValues
Create Table #FindValues (Val Varchar(10));
Insert #FindValues (Val)
Values ('a'),('b'),('c');
Select Distinct gv.GroupID
From (Select Distinct GroupID
From #GroupValues) gv
Where Not Exists (Select 1
From #FindValues fv2
Where Not Exists (Select 1
From #GroupValues gv2
Where gv.GroupID = gv2.GroupID
And fv2.Val = gv2.Val))
And Not Exists (Select 1
From #GroupValues gv3
Where gv3.GroupID = gv.GroupID
And Not Exists (Select 1
From #FindValues fv3
Where gv3.Val = fv3.Val))
I don't quite know how I should describe the problem for title, but here's my question.
I have a table named hello with two columns named time and state.
Time | State
Here's an example of the data I have
1 DC
1 VA
1 VA
2 DC
2 MD
3 MD
3 MD
3 VA
3 DC
I would like to get all the possible time and the count of "VA" (0 if "VA" doesn't appear at the time)
The output would look like this
Time Number
1 2
2 0
3 1
I tried to do
SELECT DISTINCT time,
COUNT(state) as Number
FROM hello
WHERE state = 'VA'
GROUP BY time
but it doesn't seem to work.
This is a conditional aggregation:
select time, sum(case when state = 'VA' then 1 else 0 end) as NumVA
from hello
group by time
I want to add that you should never use distinct when you have a group by. The two are redundant. Distinct as a keyword is not even needed in the SQL language; semantically, it is just shorthand for grouping by all the columns.
SELECT TIME,
SUM(CASE WHEN State = 'VA' THEN 1 ELSE 0 END)
FROm tableName
GROUP BY Time
SQLFiddle Demo
One rule of thumb is to get your counts first and put them into a temp for use later.
See below:
Create table temp(Num int, [state] varchar(2))
Insert into temp(Num,[state])
Select 1,'DC'
UNION ALL
Select 1,'VA'
UNION ALL
Select 1,'VA'
UNION ALL
Select 2,'DC'
UNION ALL
Select 2,'MD'
UNION ALL
Select 3,'MD'
UNION All
Select 3,'MD'
UNION ALL
Select 3,'VA'
UNION ALL
Select 3,'DC'
Select t.Num [Time],t.[State]
, CASE WHEN t.[state] = 'VA' THEN Count(t.[State]) ELSE 0 END [Number]
INTO #temp2
From temp t
Group by t.Num, t.[state]
--drop table #temp2
Select
t2.[time]
,SUM(t2.[Number])
From #temp2 t2
group by t2.[time]
I have two queries:
Select count(*) as countOne where field = '1'
Select count(*) as countTwo where field = '2'
What I want to see after executing these queries in my results viewer:
countOne | countTwo
23 | 123
How can I get the results from both queries by only running one query?
SELECT COUNT(CASE WHEN field = '1' THEN 1 END) AS countOne,
COUNT(CASE WHEN field = '2' THEN 1 END) AS countTwo
FROM YourTable
WHERE field IN ( '1', '2' )
The simplest way is to run each as a subselect eg.
SELECT
(
Select count(*) where field = '1' as countOne,
Select count(*) where field = '2' as countTwo
)
BUt this is not necesarily the best way
Another wayto do it would be to Group by field and then do PIVOT to select out each group as a separate column.