I have a query like:
SELECT
id
FROM
table1
INNER JOIN
...
WHERE
...
AND eventtype IN (2000120, 2000121, 2000122, 2000123, 2000130)
EXCEPT
SELECT
id
FROM
table1
INNER JOIN
...
WHERE
...
AND eventtype IN (2000123,2000130,2000134,2000135)
Note that the queries are both identical except the last where-clause.
I would now like to count the number of records returned by this above query.
How to?
Many thanks
use COUNT and wrap it inside a SUBQUERY
SELECT COUNT(ID)
FROM (
SELECT id
FROM table1
INNER JOIN...
WHERE...
AND eventtype IN ( 2000120, 2000121, 2000122, 2000123, 2000130 )
EXCEPT
SELECT id
FROM table1
INNER JOIN...
WHERE...
AND eventtype IN ( 2000123, 2000130, 2000134, 2000135 )
) s
you just need the first query for what you want, you don't have to include the 2000130 value if you don't need it and so the other values that you don't want to be shown in you query.
SELECT
id
FROM
table1
INNER JOIN
...
WHERE
...
AND eventtype IN (2000120, 2000121, 2000122, 2000123)
If you need to exclude some values from the some query you can use
AND eventtype NOT IN (2000130)
But not both at once. And to count just a regular use SELECT COUNT(id) or a subquery if you want.
Also you can use EXISTS with INTERSECT sub-query
SELECT COUNT(ID)
FROM table1 t1 INNER JOIN ...
WHERE ... AND eventtype IN (2000120, 2000121, 2000122, 2000123, 2000130)
AND NOT EXISTS (
SELECT 1
FROM table1 t2 INNER JOIN ...
WHERE ... AND eventtype IN (2000123, 2000130, 2000134, 2000135)
AND EXISTS (SELECT t1.ID
INTERSECT
SELECT t2.ID))
Related
I have the following sql statement:
WITH
subquery AS (
select distinct id from a_table where some_field in (1,2,)
)
select id from another_table where id in subquery;
Edit
JOIN is not an option (this is just a reduced example of a bigger query)
But that obviously does not work. The id field exists in both tables (with a different name, but values are the same: numeric ids). Basically what I want to do is filter by the result of the subquery, like a kind of intersection.
Any idea how to write that query in a correct way?
You need a subquery for the second operand of IN that SELECTs from the CTE.
... IN (SELECT id FROM subquery) ...
But I would recommend to rewrite it as a JOIN.
Are you able to join on ID and then filter on the Where clause?
select a.id
from a.table
inner join b.table on a.id = b.id
where b.column in (1,2)
Since you only want the id from another_table you can use exists
with s as (
select id
from a_table
where some_field in (1,2)
)
select id
from another_table t
where exists ( select * from s where s.id=t.id )
But the CTE is really redundant since all you are doing is
select id
from another_table t
where exists (
select * from a_table a where a.id=t.id and a.some_field in (1,2)
)
I have two tables in Access, one containing IDs (not unique) and some Name and one containing IDs (not unique) and Location. I would like to return a third table that contains only the IDs of the elements that appear more than 1 time in either Names or Location.
Table 1
ID Name
1 Max
1 Bob
2 Jack
Table 2
ID Location
1 A
2 B
Basically in this setup it should return only ID 1 because 1 appears twice in Table 1 :
ID
1
I have tried to do a JOIN on the tables and then apply a COUNT but nothing came out.
Thanks in advance!
Here is one method that I think will work in MS Access:
(select id
from table1
group by id
having count(*) > 1
) union -- note: NOT union all
(select id
from table2
group by id
having count(*) > 1
);
MS Access does not allow union/union all in the from clause. Nor does it support full outer join. Note that the union will remove duplicates.
Simple Group By and Having clause should help you
select ID
From Table1
Group by ID
having count(1)>1
union
select ID
From Table2
Group by ID
having count(1)>1
Based on your description, you do not need to join tables to find duplicate records, if your table is what you gave above, simply use:
With A
as
(
select ID,count(*) as Times From table group by ID
)
select * From A where A.Times>1
Not sure I understand what query you already tried, but this should work:
select table1.ID
from table1 inner join table2 on table1.id = table2.id
group by table1.ID
having count(*) > 1
Or if you have ID's in one table but not the other
select table1.ID
from table1 full outer join table2 on table1.id = table2.id
group by table1.ID
having count(*) > 1
I have two database for which I want to compare the amount of times a case appears.
TAB1:
ID Sequence
A2D 1
A2D 2
A2D 3
A3D 1
TAB2:
ID Sequence
A2D 1
A2D 2
A3D 1
A3D 2
Now, for this example, I am trying to get this result:
ID Table1 Table2
A2D 3 2
A3D 1 2
I have tried these code without any success:
SELECT R1.ID as ID, COUNT(R1.ID) as Table1,
COUNT(R2.ID) as Table2
FROM TAB1 AS R1, TAB2 AS R2
WHERE R1.ID = R2.ID
GROUP BY R1.ID
This one gave me wrong count values...
Also, this one simply crash:
select
(
select count(*) as Table1
from TAB1
where ID = R1.ID
),(
select count(*) as Table2
from TAB2
where ID= R1.ID
)
FROM TAB1 AS R1
As you can see though, I am trying to have my criteria dynamic. Most examples I found were including basic hard-coded criteria. But for my case, I want the query to look at my first table ID, count the amount of time it appears, do it for the 2nd table with the same ID, then move on to the next ID.
If my question lacks information or is confusing just ask me, I'll do my best to be more precise.
Thanks in advance !
Here I am using a UNION ALL as a subquery
SELECT ID, SUM(T1) AS Table1, SUM(T2) AS Table2
FROM
(SELECT ID, COUNT(ID) AS T1, 0 AS T2 FROM TAB1 GROUP BY ID
UNION ALL
SELECT ID, 0 AS T1, COUNT(ID) AS T2 FROM TAB2 GROUP BY ID)
GROUP BY ID
HAVING SUM(T1)>0 AND SUM(T2)>0
I used a different approach, but unfortunately I have to use two queries, i still don't know if they can be combined together. The first one is just for making sums of both tables, and combining the results:
SELECT "Tab1" AS [Table], Tab1.ID, Count(*) AS Total
FROM Tab1
GROUP BY "Tab1", Tab1.ID
UNION SELECT "Tab2" AS [Table], Tab2.ID, Count(*) AS Total
FROM Tab2
GROUP BY "Tab2", Tab2.ID
and, since Access supports Pivot queries, you can use this:
TRANSFORM Sum(qrySums.[Total]) AS Total
SELECT qrySums.[ID]
FROM qrySums
GROUP BY qrySums.[ID]
PIVOT qrySums.[Table];
Not sure if I understand your question, but you could try something like this:
SELECT DISTINCT t.ID,
(SELECT COUNT(ID) FROM R1 WHERE ID = t.ID) AS table1,
(SELECT COUNT(ID) FROM R2 WHERE ID = t.ID) AS table2
FROM table1 t
To get the desired results, I broke it down into two sub-queries (R1SQ and R2SQ) and a main UNION query - R1R2 that uses inner, left and right joins to include all row entries including those rows that do not appear in both tables:
R1SQ
SELECT R1.Builder, Count(R1.Builder) AS Table1
FROM R1
GROUP BY R1.Builder;
R2SQ
SELECT R2.Builder_E, Count(R2.Builder_E) AS Table2
FROM R2
GROUP BY R2.Builder_E;
R1R2
SELECT R1SQ.Builder, R1SQ.Table1, R2SQ.Table2
FROM R1SQ INNER JOIN R2SQ ON R1SQ.Builder = R2SQ.Builder_E
UNION
SELECT R1SQ.Builder, R1SQ.Table1, 0 AS Table2
FROM R1SQ LEFT JOIN R2SQ ON R1SQ.Builder = R2SQ.Builder_E
WHERE (((R2SQ.Builder_E) Is Null))
UNION
SELECT R2SQ.Builder_E, 0 AS Table1, R2SQ.Table2
FROM R1SQ RIGHT JOIN R2SQ ON R1SQ.Builder = R2SQ.Builder_E
WHERE (((R1SQ.Builder) Is Null))
ORDER BY R1SQ.Builder;
How to get the result of select statement grouped by a column to perform join statement on it ?
You should enclose the select statement that contains the GROUP BY instead of one of the joined table, something like this:
SELECT t1.Id, ....
FROM Table1 t1
INNER JOIN
(
SELECT Id, COUNT(*)
FROM Table2
GROUP BY Id
) t2 ON t1.Id = t2.Table1Id
This might help you:
suppose there are two table
1.student
(stud_id pk)
(branch_id fk)
2. branch
(branch_id pk)
(branch name varchar)
(city varchar)
select * from student s,branch b where s.branch_id=b.branch_id group by b.city
Table1 has columns (id, a, b, c, group). There are several rows that have the same group, but id is always unique. I would like to SELECT group,a,b FROM Table1 WHERE the group is distinct. However, I would like the returned data to be from the row with the greatest id for that group.
Thus, if we have the rows
(id=10, a=6, b=40, c=3, group=14)
(id=5, a=21, b=45, c=31, group=230)
(id=4, a=42, b=65, c=2, group=230)
I would like to return these 2 rows:
[group=14, a=6,b=40] and
[group=230, a=21,b=45] (because id=5 > id=4)
Is there a simple SELECT statement to do this?
Try:
select grp, a, b
from table1 where id in
(select max(id) from table1 group by grp)
You can do it using a self join or an inner-select. Here's inner select:
select `group`, a, b from Table1 AS T1
where id=(select max(id) from Table1 AS T2 where T1.`group` = T2.`group`)
And self-join method:
select T1.`group`, T2.a, T2.b from
(select max(id) as id,`group` from Table1 group by `group`) T1
join Table1 as T2 on T1.id=T2.id
2 selects, your inner select gets:
SELECT MAX(id) FROM YourTable GROUP BY [GROUP]
Your outer select joins to this table.
Think about it logically, the inner select gets a sub set of the data you need.
The outer select inner joins to this subset and can get further data.
SELECT [group], a, b FROM YourTable INNER JOIN
(SELECT MAX(id) FROM YourTable GROUP BY [GROUP]) t
ON t.id = YourTable.id
SELECT mi.*
FROM (
SELECT DISTINCT grouper
FROM mytable
) md
JOIN mytable mi
ON mi.id =
(
SELECT id
FROM mytable mo
WHERE mo.grouper = md.grouper
ORDER BY
id DESC
LIMIT 1
)
If your table is MyISAM or id is not a PRIMARY KEY, then make sure you have a composite index on (grouper, id).
If your table is InnoDB and id is a PRIMARY KEY, then a simple index on grouper will suffice (id, being a PRIMARY KEY, will be implictly included).
This will use an INDEX FOR GROUP-BY to build the list of distinct groupers, and for each grouper it will use the index access to find the maximal id.
Don't know how to do it in mysql. But the following code will work for MsSQL...
SELECT Y.* FROM
(
SELECT DISTINCT [group], MAX(id) ID
FROM Table1
GROUP BY [group]
) X
INNER JOIN Table1 Y ON X.ID=Table1.ID