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In SQL how can I remove (from displaying on my report no deleting from database) the first 3 characters (CN=) and everything after the comma that is followed by "OU" so that I am left with the name and last name in the same column? for example:
CN=Tom Chess,OU=records,DC=1234564786_data for testing, 1234567
CN=Jack Bauer,OU=records,DC=1234564786_data for testing, 1234567
CN=John Snow,OU=records,DC=1234564786_data for testing, 1234567
CN=Anna Rodriguez,OU=records,DC=1234564786_data for testing, 1234567
Desired display:
Tom Chess
Jack Bauer
John Snow
Anna Rodriguez
I tried playing with TRIM but I don't know how to do it without declaring the position and with names and last names having different lengths I really don't know how to handle that.
Thank you in advance
Update: I wonder about an approach of using Locate to match the position of the comma and then feed that to a sub-string. Not sure if a approach like would work and not sure how to put the syntax together. What do you think? will it be a feasible approach?
You can try this one SUBSTRING(ColumnName, 4, CHARINDEX(',', ColumnName) - 4)
In Postgres, you could use split_part() assuming no name contains a ,
select substr(split_part(the_column, ',', 1), 4)
from ...
Db2 11.x for LUW:
with tab (str) as (values
' CN = Tom Chess , OU = records,DC=1234564786_data for testing, 1234567'
, 'CN=Jack Bauer,OU=records,DC=1234564786_data for testing, 1234567'
, 'CN=John Snow,OU=records,DC=1234564786_data for testing, 1234567'
, 'CN=Anna Rodriguez,OU=records,DC=1234564786_data for testing, 1234567'
)
select REGEXP_REPLACE(str, '^\s*CN\s*=\s*(.*)\s*,\s*OU\s*=.*', '\1')
from tab;
Note, that such a regex pattern allows an arbitrary number of spaces as in the 1-st record of example above.
In Oracle 11g, it might work.
REGEXP_SUBSTR(REGEXP_SUBSTR(COLUMN_NAME, '[^CN=]+',1,1),'[^,OU]+',1,1)
I think there has to be a loop to handle this. Here's SQL Server function that will parse this out. (I know the question didn't specify SQL Server, but it's an example of how it can be done.)
select dbo.ScrubFieldValue(value) from table will return what you're looking for
CREATE FUNCTION ScrubFieldValue
(
#Input varchar(8000)
)
RETURNS varchar(8000)
AS
BEGIN
DECLARE #retval varchar(8000)
DECLARE #charidx int
DECLARE #remaining varchar(8000)
DECLARE #current varchar(8000)
DECLARE #currentLength int
select #retval = ''
select #remaining = #Input
select #charidx = CHARINDEX('CN=', #remaining,2)
while(LEN(#remaining) > 0)
BEGIN
--strip current row from remaining
if (#charidx > 0)
BEGIN
select #current = SUBSTRING(#remaining, 1, #charidx - 1)
END
else
BEGIN
select #current = #remaining
END
select #currentLength = LEN(#current)
-- get current name
select #current = SUBSTRING(#current, 4, CHARINDEX(',OU', #current)-4)
select #retval = #retval + #current + ' '
-- strip off current from remaining
select #remaining =substring(#remaining,#currentLength + 1,
LEN(#remaining) - #currentLength)
select #charidx = CHARINDEX('CN=', #remaining,2)
END
RETURN #retval
END
On my version of DB2 for Z/OS CHARINDEX throws a syntax error. Here are two ways to work around that.
SUBSTRING(ColumnName, 4, INSTR(ColumnName,',',1) - 4)
SUBSTRING(ColumnName, 4, LOCATE_IN_STRING(ColumnName,',') - 4)
I should add that the version is V12R1
If input str is wellformed (i.e. looks like your sample data without any additional tokens such as space), you could use something like:
substr(str,locate('CN=', str)+length('CN='), locate(',', str)-length('CN=')-1)
If your Db2 version support REGEXP, that's a better choice.
Using SQL Server 2008
String like: 'C/123232323' or '/343434343443' or 'C2323232322'
From the string i want to remove C and /
Tried Query
Select replace ('/1233434', 'C/', '')
The above query is working if C/ both is there. if / only there then the replace is not working. if C only there then the replace is not working. How to achieve for both condition
Expected output
123232323
343434343443
2323232322
Need Query output
You can achieve this by nesting replace() like so:
select replace(replace('C/12341234','/',''),'C','')
Probably not the prettiest but it works :)
You could use two nested REPLACE:
WITH SampleData(string) AS(
SELECT 'C/123232323' UNION ALL
SELECT '/343434343443' UNION ALL
SELECT 'C2323232322'
)
SELECT REPLACE(REPLACE(string,'C',''),'/','')
FROM SampleData
Use Patindex + Substring
DECLARE #str VARCHAR(50)='/343434343443' ---or '/343434343443' or 'C2323232322'
SELECT Substring(#str, Patindex('%[0-9]%', #str), Len(#str))
I have a variable where i dynamically store the URL
For Eg. a="https://myaccessdev.searshc.com/aveksa/main?Oid=1&ReqType=GetPage&ObjectClass=com.aveksa.gui.objects.workflow.GuiWorkflowJob&WFObjectID=3478:WPDS"
I want to strip the number in the last before ":WDPS" from this whole string.
Is there any way of doing it in SQL
I want to strip the number [...] before ":WDPS" from this whole string.
This is a perfect match for REGEXP_REPLACE:
with test_data as
(select 'https://myaccessdev.searshc.com/aveksa/main?Oid=1&ReqType=GetPage&ObjectClass=com.aveksa.gui.objects.workflow.GuiWorkflowJob&WFObjectID=3478:WPDS' str
from dual)
select REGEXP_REPLACE(str, '.*=([0-9]*):WPDS.*', '\1') from test_data
-- ^^^^^^^^^^^^^^^^^^^^ ^^^^
-- replace everything before and after by the first capturing
-- the target string group (i.e.: the sequence between
-- parenthesis in the regular expression)
Producing:
3478
See http://sqlfiddle.com/#!4/d41d8/37095 for a live demo.
If you just want the number, you can do something like this:
select regexp_substr(regexp_substr(s, '=[0-9]*:WPDS', 1, 1), '[0-9]*', 1, 1)
You can do this with regexp_substr(). I'm having trouble testing it right now. The following comes quite close:
select regexp_substr(s, '=[0-9]*:WPDS', 1, 1)
Try this
DECLARE #string varchar(255) = 'https://myaccessdev.searshc.com/aveksa/main?Oid=1&ReqType=GetPage&ObjectClass=com.aveksa.gui.objects.workflow.GuiWorkflowJob&WFObjectID=3478:WPDS'
DECLARE #end varchar(10) = REVERSE(SUBSTRING(REVERSE(#string),0,CHARINDEX('=', REVERSE(#string))))
SELECT SUBSTRING(#end,0,CHARINDEX(':', #end))
Table FOO has a column FILEPATH of type VARCHAR(512). Its entries are absolute paths:
FILEPATH
------------------------------------------------------------
file://very/long/file/path/with/many/slashes/in/it/foo.xml
file://even/longer/file/path/with/more/slashes/in/it/baz.xml
file://something/completely/different/foo.xml
file://short/path/foobar.xml
There's ~50k records in this table and I want to know all distinct filenames, not the file paths:
foo.xml
baz.xml
foobar.xml
This looks easy, but I couldn't find a DB2 scalar function that allows me to search for the last occurrence of a character in a string. Am I overseeing something?
I could do this with a recursive query, but this appears to be overkill for such a simple task and (oh wonder) is extremely slow:
WITH PATHFRAGMENTS (POS, PATHFRAGMENT) AS (
SELECT
1,
FILEPATH
FROM FOO
UNION ALL
SELECT
POSITION('/', PATHFRAGMENT, OCTETS) AS POS,
SUBSTR(PATHFRAGMENT, POSITION('/', PATHFRAGMENT, OCTETS)+1) AS PATHFRAGMENT
FROM PATHFRAGMENTS
)
SELECT DISTINCT PATHFRAGMENT FROM PATHFRAGMENTS WHERE POS = 0
I think what you're looking for is the LOCATE_IN_STRING() scalar function. This is what Info Center has to say if you use a negative start value:
If the value of the integer is less than zero, the search begins at
LENGTH(source-string) + start + 1 and continues for each position to
the beginning of the string.
Combine that with the LENGTH() and RIGHT() scalar functions, and you can get what you want:
SELECT
RIGHT(
FILEPATH
,LENGTH(FILEPATH) - LOCATE_IN_STRING(FILEPATH,'/',-1)
)
FROM FOO
One way to do this is by taking advantage of the power of DB2s XQuery engine. The following worked for me (and fast):
SELECT DISTINCT XMLCAST(
XMLQuery('tokenize($P, ''/'')[last()]' PASSING FILEPATH AS "P")
AS VARCHAR(512) )
FROM FOO
Here I use tokenize to split the file path into a sequence of tokens and then select the last of these tokens. The rest is only conversion from SQL to XML types and back again.
I know that the problem from the OP was already solved but I decided to post the following anyway to hopefully help others like me that land here.
I came across this thread while searching for a solution to my similar problem which had the exact same requirement but was for a different kind of database that was also lacking the REVERSE function.
In my case this was for a OpenEdge (Progress) database, which has a slightly different syntax. This made the INSTR function available to me that most Oracle typed databases offer.
So I came up with the following code:
SELECT
SUBSTRING(
foo.filepath,
INSTR(foo.filepath, '/',1, LENGTH(foo.filepath) - LENGTH( REPLACE( foo.filepath, '/', '')))+1,
LENGTH(foo.filepath))
FROM foo
However, for my specific situation (being the OpenEdge (Progress) database) this did not result into the desired behaviour because replacing the character with an empty char gave the same length as the original string. This doesn't make much sense to me but I was able to bypass the problem with the code below:
SELECT
SUBSTRING(
foo.filepath,
INSTR(foo.filepath, '/',1, LENGTH( REPLACE( foo.filepath, '/', 'XX')) - LENGTH(foo.filepath))+1,
LENGTH(foo.filepath))
FROM foo
Now I understand that this code won't solve the problem for T-SQL because there is no alternative to the INSTR function that offers the Occurence property.
Just to be thorough I'll add the code needed to create this scalar function so it can be used the same way like I did in the above examples.
-- Drop the function if it already exists
IF OBJECT_ID('INSTR', 'FN') IS NOT NULL
DROP FUNCTION INSTR
GO
-- User-defined function to implement Oracle INSTR in SQL Server
CREATE FUNCTION INSTR (#str VARCHAR(8000), #substr VARCHAR(255), #start INT, #occurrence INT)
RETURNS INT
AS
BEGIN
DECLARE #found INT = #occurrence,
#pos INT = #start;
WHILE 1=1
BEGIN
-- Find the next occurrence
SET #pos = CHARINDEX(#substr, #str, #pos);
-- Nothing found
IF #pos IS NULL OR #pos = 0
RETURN #pos;
-- The required occurrence found
IF #found = 1
BREAK;
-- Prepare to find another one occurrence
SET #found = #found - 1;
SET #pos = #pos + 1;
END
RETURN #pos;
END
GO
To avoid the obvious, when the REVERSE function is available you do not need to create this scalar function and you can just get the required result like this:
SELECT
SUBSTRING(
foo.filepath,
LEN(foo.filepath) - CHARINDEX('\', REVERSE(foo.filepath))+2,
LEN(foo.filepath))
FROM foo
You could just do it in a single statement:
select distinct reverse(substring(reverse(FILEPATH), 1, charindex('/', reverse(FILEPATH))-1))
from filetable
I have a table in a SQL Server database with an NTEXT column. This column may contain data that is enclosed with double quotes. When I query for this column, I want to remove these leading and trailing quotes.
For example:
"this is a test message"
should become
this is a test message
I know of the LTRIM and RTRIM functions but these workl only for spaces. Any suggestions on which functions I can use to achieve this.
I have just tested this code in MS SQL 2008 and validated it.
Remove left-most quote:
UPDATE MyTable
SET FieldName = SUBSTRING(FieldName, 2, LEN(FieldName))
WHERE LEFT(FieldName, 1) = '"'
Remove right-most quote: (Revised to avoid error from implicit type conversion to int)
UPDATE MyTable
SET FieldName = SUBSTRING(FieldName, 1, LEN(FieldName)-1)
WHERE RIGHT(FieldName, 1) = '"'
I thought this is a simpler script if you want to remove all quotes
UPDATE Table_Name
SET col_name = REPLACE(col_name, '"', '')
You can simply use the "Replace" function in SQL Server.
like this ::
select REPLACE('this is a test message','"','')
note: second parameter here is "double quotes" inside two single quotes and third parameter is simply a combination of two single quotes. The idea here is to replace the double quotes with a blank.
Very simple and easy to execute !
My solution is to use the difference in the the column values length compared the same column length but with the double quotes replaced with spaces and trimmed in order to calculate the start and length values as parameters in a SUBSTRING function.
The advantage of doing it this way is that you can remove any leading or trailing character even if it occurs multiple times whilst leaving any characters that are contained within the text.
Here is my answer with some test data:
SELECT
x AS before
,SUBSTRING(x
,LEN(x) - (LEN(LTRIM(REPLACE(x, '"', ' ')) + '|') - 1) + 1 --start_pos
,LEN(LTRIM(REPLACE(x, '"', ' '))) --length
) AS after
FROM
(
SELECT 'test' AS x UNION ALL
SELECT '"' AS x UNION ALL
SELECT '"test' AS x UNION ALL
SELECT 'test"' AS x UNION ALL
SELECT '"test"' AS x UNION ALL
SELECT '""test' AS x UNION ALL
SELECT 'test""' AS x UNION ALL
SELECT '""test""' AS x UNION ALL
SELECT '"te"st"' AS x UNION ALL
SELECT 'te"st' AS x
) a
Which produces the following results:
before after
-----------------
test test
"
"test test
test" test
"test" test
""test test
test"" test
""test"" test
"te"st" te"st
te"st te"st
One thing to note that when getting the length I only need to use LTRIM and not LTRIM and RTRIM combined, this is because the LEN function does not count trailing spaces.
I know this is an older question post, but my daughter came to me with the question, and referenced this page as having possible answers. Given that she's hunting an answer for this, it's a safe assumption others might still be as well.
All are great approaches, and as with everything there's about as many way to skin a cat as there are cats to skin.
If you're looking for a left trim and a right trim of a character or string, and your trailing character/string is uniform in length, here's my suggestion:
SELECT SUBSTRING(ColName,VAR, LEN(ColName)-VAR)
Or in this question...
SELECT SUBSTRING('"this is a test message"',2, LEN('"this is a test message"')-2)
With this, you simply adjust the SUBSTRING starting point (2), and LEN position (-2) to whatever value you need to remove from your string.
It's non-iterative and doesn't require explicit case testing and above all it's inline all of which make for a cleaner execution plan.
The following script removes quotation marks only from around the column value if table is called [Messages] and the column is called [Description].
-- If the content is in the form of "anything" (LIKE '"%"')
-- Then take the whole text without the first and last characters
-- (from the 2nd character and the LEN([Description]) - 2th character)
UPDATE [Messages]
SET [Description] = SUBSTRING([Description], 2, LEN([Description]) - 2)
WHERE [Description] LIKE '"%"'
You can use following query which worked for me-
For updating-
UPDATE table SET colName= REPLACE(LTRIM(RTRIM(REPLACE(colName, '"', ''))), '', '"') WHERE...
For selecting-
SELECT REPLACE(LTRIM(RTRIM(REPLACE(colName, '"', ''))), '', '"') FROM TableName
you could replace the quotes with an empty string...
SELECT AllRemoved = REPLACE(CAST(MyColumn AS varchar(max)), '"', ''),
LeadingAndTrailingRemoved = CASE
WHEN MyTest like '"%"' THEN SUBSTRING(Mytest, 2, LEN(CAST(MyTest AS nvarchar(max)))-2)
ELSE MyTest
END
FROM MyTable
Some UDFs for re-usability.
Left Trimming by character (any number)
CREATE FUNCTION [dbo].[LTRIMCHAR] (#Input NVARCHAR(max), #TrimChar CHAR(1) = ',')
RETURNS NVARCHAR(max)
AS
BEGIN
RETURN REPLACE(REPLACE(LTRIM(REPLACE(REPLACE(#Input,' ','¦'), #TrimChar, ' ')), ' ', #TrimChar),'¦',' ')
END
Right Trimming by character (any number)
CREATE FUNCTION [dbo].[RTRIMCHAR] (#Input NVARCHAR(max), #TrimChar CHAR(1) = ',')
RETURNS NVARCHAR(max)
AS
BEGIN
RETURN REPLACE(REPLACE(RTRIM(REPLACE(REPLACE(#Input,' ','¦'), #TrimChar, ' ')), ' ', #TrimChar),'¦',' ')
END
Note the dummy character '¦' (Alt+0166) cannot be present in the data (you may wish to test your input string, first, if unsure or use a different character).
To remove both quotes you could do this
SUBSTRING(fieldName, 2, lEN(fieldName) - 2)
you can either assign or project the resulting value
You can use TRIM('"' FROM '"this "is" a test"') which returns: this "is" a test
CREATE FUNCTION dbo.TRIM(#String VARCHAR(MAX), #Char varchar(5))
RETURNS VARCHAR(MAX)
BEGIN
RETURN SUBSTRING(#String,PATINDEX('%[^' + #Char + ' ]%',#String)
,(DATALENGTH(#String)+2 - (PATINDEX('%[^' + #Char + ' ]%'
,REVERSE(#String)) + PATINDEX('%[^' + #Char + ' ]%',#String)
)))
END
GO
Select dbo.TRIM('"this is a test message"','"')
Reference : http://raresql.com/2013/05/20/sql-server-trim-how-to-remove-leading-and-trailing-charactersspaces-from-string/
I use this:
UPDATE DataImport
SET PRIO =
CASE WHEN LEN(PRIO) < 2
THEN
(CASE PRIO WHEN '""' THEN '' ELSE PRIO END)
ELSE REPLACE(PRIO, '"' + SUBSTRING(PRIO, 2, LEN(PRIO) - 2) + '"',
SUBSTRING(PRIO, 2, LEN(PRIO) - 2))
END
Try this:
SELECT left(right(cast(SampleText as nVarchar),LEN(cast(sampleText as nVarchar))-1),LEN(cast(sampleText as nVarchar))-2)
FROM TableName