Composition over inheritance 2 - vb.net

Please have a look at the following question: Favor composition over inheritance
The accepted answerer says: " it extends Hashtable, in order to reuse its methods and to avoid reimplementing some of them using delegation". I am not sure what the answerer means by: reimplementing some of them using delegation. What does the answerer mean?
I am familiar with Delegates and the Observer design pattern.

When using composition, if you want to support a method that the underlying class has, you must define your own implementation that simply delegates (or uses) the same method on the underlying class. It can be tempting to use inheritance in this case to avoid writing that simple (delegated) method, but inheritance really should be used only when an IS-A relationship exists.
For example,
public class Foo
{
public virtual void Bar()
{
// do something
}
}
public class InheritedFromFoo : Foo
{
// we get Bar() for free!!!
}
public class ComposedWithFoo
{
private Foo _foo;
public void Bar()
{
_foo.Bar(); // delegated to the Foo instance
}
}

Related

Benefit of non-empty method of non-abstract class and abstract method of abstract method?

I don't understand why we use abstract method (abstract class) while we can use empty method of non-abstract class and then we override it. Does it sound fine? I am seeking to clarify this issue.
I give 2 examples
public abstract class MyClass {public abstract void foo();}
public MyChildClass extends MyClass {public void foo() {//..TODO}}
public class MyClass {public void foo(){//empty}}
public class MyChildClass extends MyClass {public void foo() {//..TODO}}
Which one is better?
I'll start by saying that you should try to use interfaces instead of abstract classes. Abstract classes couple the subclass to the implementation of the superclass. In a language like Java, the subclass can override any method even if the superclass did not intend to do so, and most people don't qualify their methods with "do not override" all the time.
At the lowest level, abstract methods give you two concrete protections at compile time:
They force you to override the method in a subclass
They disallow the creation of the abstract class
Before listing the use cases for abstract methods, I'll just say that "common functionality" is NOT a good reason for an abstract base class. If you need common functionality, just create a class that has the common methods, and let the various classes call these functions as they see fit.
So when would you use an abstract class? Here are some examples:
Template Method
In the template method pattern, you have all of your functionality, but there's just one internal aspect that's polymorphic, so you have subclasses that override that particular aspect.
For example, if you're implementing a cache, but the cache invalidation policy is polymorphic, you may have an abstract invalidate() method that is called internally by other methods, but it's up to subclasses to implement invalidate().
If there is a preferred default cache invalidation policy, then invalidate() could implement that default. But if that default is downright destructive in some cases, then it shouldn't be a default - it should be abstract, and the code that creates the cache should be forced to explicitly choose the invalidation policy.
This can also be achieved by passing an Invalidator class to the constructor (Strategy pattern), but if the invalidation logic needs to call methods of the cache, it's better to make those method protected and call them from a subclass (i.e. Template Method pattern).
Default implementation of other methods
In languages where interfaces cannot have default methods (e.g. Java 7), you can emulate it using abstract classes. All the interface methods will be abstract, but the default methods would be regular public methods.
Common Interface and Functionality
This is just a more generic version of the template method pattern. The difference is that the polymorphic methods are part of the API.
If your common functionality has a lot of overlap with the functionality you want to expose, and you don't want mountains of boilerplate code, you use an abstract class. For example:
interface File {
abstract Buffer read(int size);
abstract void write(Buffer buf);
abstract long getSize();
abstract void setSize();
// ... get/set creation time, get/set modification time, get
// file type etc.
abstract long getOwner();
abstract void setOwner(long owner);
}
abstract class AbstractFile extends File {
DataMap dataMap;
MetadataMap metaMap;
protected getDiskMap() { return dataMap; }
protected getMetaMap() { return metaMap; }
public Buffer read(int size) { /* loop here */ }
public void write(Buffer buf) { /* loop here */ }
public long getSize() { /* logic */ }
public void setSize() { /* logic */ }
// ... implementation of get/set creation time, get/set modification
// time, get file type etc.
}
abstract class HardDriveFile extends AbstractFile {
OwnershipMap ownerMap;
abstract long getOwner() { /* logic */ }
abstract void setOwner(long owner) { /* logic */ }
}
abstract class ThumbDriveFile extends AbstractFile {
// thumb drives have no ownership
abstract long getOwner() { return 0; }
abstract void setOwner(long owner) { /* no-op */ }
}
abstract class SomeOtherfile extends AbstractFile {
...
}
If we cut the middleman and have HardDriveFile and ThumbDriveFile (and possibly other types of files) implement File and spell out all the common methods, each calling a method of some common class, we would get mountains and mountains of boilerplate. So we inherit from an abstract base class, that has the abstract methods we want to specialize (e.g. based on the existence of an ownership map).
The naive thing to do would be to combine File and AbstractFile into a single class, which is where you'd get the abstract methods getOwner() and setOwner(), but it's better to hide abstract classes behind actual interfaces, to prevent the coupling between consumers of an API and the abstract class.

How to make interface implementors that are not sub classes of its abstract class behave like abstract class of that interface?

I want to explain my question with an example. Lets say that i have an interface:
interface IActionPerformer
{
bool IsReadyToExecuteAction();
void Action();
IActionImplementor GetImplementor();
}
And an implementor for Action() method. I don't know if it is the right or wrong way to do so, but anyways, keep reading i will explain my purpose. Implementor:
interface IActionImplementor
{
void Action();
}
And an abstract class that implements IActionPerformer:
abstract class ActionPerformerBase: IActionPerformer
{
private IActionImplementor _implementor;
public abstract bool IsReadyToExecuteAction();
public IActionImplementor GetImplementor()
{
return _implementor;
}
public void Action()
{
if (IsReadyToExecuteAction())
{
GetImplementor().Action();
}
}
protected ActionPerformerBase(IActionImplementor implementor)
{
this._implementor = implementor;
}
}
Now sub classes which inherit from this abstract class, execute the actual action only if it is ready to execute.
But let's say that i have an object in my software, that inherits from a different super class. But at the same time, this object must behave like an IActionPerformer. I mean this object must implement IActionPerformer interface, like:
class SomeOtherSubClass : SomeOtherSuperClass, IActionPerformer
At this point, i want to execute Action() method with controlling if it is ready to execute.
I thought invoking method with another object might be a solution. I mean, a controller or handler object gets interface as a parameter and invokes method the way i want. Like:
IActionInvoker.Invoke(IActionPerformer performer)
{
if (performer.IsReadyToExecuteAction())
{
performer.Action();
}
}
Or every IActionPerformer implementor has a IActionPerformer or ActionPerformerBase(it feels better) object which handles the real control like:
class SomeOtherSubClass : SomeOtherSuperClass, IActionPerformer
{
ActionPerformerBase _realHandler;
public bool IsReadyToExecuteAction()
{
return _realHandler.IsReadyToExecuteAction();
}
public void Action()
{
_realHandler.Action();
}
.
.
.
}
//This is the one get the job done actually.
class RealHandlerOfSomething : ActionPerformerBase
I might not be that clear trying to explain my question. I'm new to concepts like abstraction, design patterns and sort of stuff like that. And trying to figure out them. This one looks like a decorator, it is a IActionPerformerand it has a IActionPerformer. But when i study decorator pattern, i saw it is like going from shell to the core, i mean every object executes its method and the wrapped objects method. It is a bit different in my example, i mean question. Is this what we call as "encapsulation"? Or do i have big issues understanding the concepts?
I hope i explained myself clearly. Thanks for everyone reading, trying to help.
Have a nice day/night.
As Design Patterns states in chapter one:
Favor object composition over class inheritance
This was in 1994. Inheritance makes things complicated. The OP is another example.
In the following, I'll keep IActionPerformer and ActionPerformerBase as is. Since inheritance is isomorphic to composition, everything you can do with inheritance, you can also do with composition - and more, such as emulating multiple inheritance.
Here's how you can implement the IActionPerformer interface from another subclass, and still reuse ActionPerformerBase:
public class SomeOtherSubClass : SomeOtherSuperClass, IActionPerformer
{
private readonly ActionPerformerBase #base;
public SomeOtherSubClass(ActionPerformerBase #base)
{
this.#base = #base;
}
public void Action()
{
// Perhaps do something before calling #base...
#base.Action();
// Perhaps do something else after calling #base...
}
// Other methods of IActionPerformer go here, possibly following the same pattern...
}
SomeOtherSubClass composes with any ActionPerformerBase, and since ActionPerformerBase has the desired functionality, that functionality is effectively reused.
Once you've figured out how to use composition for reuse instead of inheritance, do yourself a favour and eliminate inheritance from your code base. Trust me, you don't need it. I've been designing and writing production code for more than a decade without inheritance.

declaring a method as optional in abstract class

As far as I've understood in Dart is possible to use abstract classes to declare "interfaces" or "protocols" (if you come from objective-c).
Anyway I'm having trouble in finding a way to declare an optional method in the abstract class/interface.
If I declare a method in the abstract class A, and let the concrete class B implement A, I get a warning in the compiler.
I'd like to be able to declare a method as optional or at least to provide a default implementation without needing to "re-declare" it in a class that implements my interface.
abstract class A{
void abstractMethod();
}
class B implements A{
//not implementing abstract method here gives a warning
}
That's not how interfaces work. If your class states to implement an interface, then this is what it has to do.
You can split the interface
abstract class A {
void abstractMethod();
}
abstract class A1 extends A {
void optionalMethod();
}
class B implements A {
//not implementing abstract method here gives a warning
}
only when it states to implement A1 it has to implement optionalMethod.
Alternatively you can extend the abstract class
abstract class A{
void abstractMethod();
void optionalMethod(){};
}
class B extends A {
//not implementing abstract method here gives a warning
}
then only abstractMethod needs to be overridden because A doesn't provide an implementation.
Abstract methods defined in classes cannot be marked as optional. (At least not in the regular Dart language, I don't know of annotations that might support something like this.)
Any class that implements an interface must provide an implementation of all abstract methods, but, those method implementations may trivially throw an error to indicate that the method is not available.
Throw UnimplementedError if the implementing class is incomplete and the proper implementation is to be added later
Throw UnsupportedError if the implementing class does not intend to implement the method.
Note that UnimplementedError implements UnsupportedError.
Obviously you have to be judicious about what you choose to not implement. If it's in code that is not intended to be shared you can get away only implementing methods that you explicitly know are required. If it's in a library package intended to be shared with others you would need a good reason to not implement a method, and that reason should be well documented.
Example code:
abstract class A {
void abstractMethod();
}
class B implements A {
void abstractMethod() { throw new UnimplementedError(...); }
// or
void abstractMethod() { throw new UnsupportedError(...); }
}
See:
https://api.dartlang.org/stable/1.18.1/dart-core/UnimplementedError-class.html
https://api.dartlang.org/stable/1.18.1/dart-core/UnsupportedError-class.html

Singleton subclass

I have an abstract base class and an implementation class like:
public abstract class Base
{
public Base getInstance( Class<? extends Base> clazz )
{
//expected to return a singleton instance of clazz's class
}
public abstract absMeth();
}
public A extends Base
{
//expected to be a singleton
}
In this example I can make A to be a singleton and even write getInstance in Base to return a singleton object of A for every call, doing this way:
public abstract class Base
{
public Base getInstance( Class<? extends Base> clazz )
{
try
{
return clazz.getDeclaredMethod("getInstance").invoke(null,null);
}
}
public abstract void absMeth();
}
public A extends Base
{
private static A inst;
private A(){}
public static A getInstance( )
{
if( inst!= null)
inst = new A();
return inst;
}
public void absMeth(){
//...
}
}
But my concern is how do I ensure that if somebody writes another class class B extends Base it should also be a singleton and it necessarily implements a static method called getInstance?
In other words I need to enforce this as a specification for all classes extending with the Base class.
You cannot trust classes that extend you to create a single instance of themselves1: even if you could somehow ensure that they all implement getInstance, there is no way to tell that inside that method they check inst before constructing a new instance of themselves.
Stay in control of the process: create a Map<Class,Base>, and instantiate the class passed in through reflection2. Now your code can decide whether to create an instance or not, without relying on the getInstance of a subclass.
1 A popular saying goes, "If you want a job done right, do it yourself."
2 Here is a link describing a solution based on setAccessible(true)
Singleton is a design pattern, not a language feature. It is pretty much impossible to somehow enforce it on the inheritance tree through syntax.
It certainly is possible to require all subclasses to implement a method by declaring it abstract but there is no way to control implementation details. Singleton is all about implementation details.
But why is this a concern at all? Do not make your app dependant on internal details of someone else's code. It is Bad Design™ and having this issue is a sure sign of it. Code against a well-defined interface and avoid relying on internal details.

Abstract class and methods

i have Abstract class
Public class Abstract baseClass
{
public abstract string GetString();
public abstract string GetString1();
}
public class DerivedClass : baseClass
{
public override string GetString()
{
return "test data";
}
public override string GetString1()
{
throw new NotImplementedException();
}
}
In above line of code, i have to implement both abstract method in derived class. But due to some reason i don't want to implement all methods, just one of them like GetString() only. How can it be done?
Thanks
If DerivedClass is going to offer common functionality to other classes, you can mark it as abstract, implement one of the methods here, and then inheritors will only have to implement the remaining method.
If you aren't going to support the other method in a given implementation, you still have to expose the method in your class, but similar to what you have here, you would typically throw a NotSupportedException. For void methods, you could simply return (do nothing).
Finally, if you want to separate out the things that have both methods and those that have only one, you can use interfaces.
public interface IBase
{
string GetString();
}
public interface IBasePlus : IBase
{
string GetStringPlus();
}
You can have one class that implements IBasePlus, but you can supply this to methods that take a parameter of type IBase, in which case you won't see the extra method.
Generally, if you don't implement all the abstract methods then your new class is also an abstract class. To get a concrete class, you need all the methods to be implemented. If you only want/need to implement a subset of the methods, consider using multiple interfaces (one interface with GetString and another with GetString1) rather than an abstract class. Then you can just implement the interfaces with the methods you want to use in the class.
Take the abstract keyword off the other method and provide a default implementation in the base class