I need to write a single query
If a record id already exists in table, and the same record id with some different values is
then I have to update its expiry date in the table and also insert the record id with new values to the table.
If not record id not present then make a new entry to the table .
Eg: In a table tmp record_id =101 exists then update main_table expiry_date of all the rows with record id='101' and also insert a new row from tmp to main_table else insert into main_table.
You need a Merge statement and an insert:
merge into your_table t
using(select 5 as id, sysdate as expiry_date from source where coditions) S
on(s.id = t.id)
when matched then update t.expiry_date = s.expiry_date;
insert into your_table t
values (5 , sysdate);
Check this one please:
MERGE INTO mytable b
USING (SELECT * from mytable where id = 10) a
ON b.id = a.id
WHEN MATCHED THEN UPDATE SET b.expirydate = a.expirydate
;
INSERT (id, col1, col2...) VALUES (a.id, col1, col2...)
In the event of matched you will update. At all times you will insert.
Related
I have a table, which has 9 records with id = 1 - 9 (for example, there can be more than 20 ids).
I have one varchar value = 'premium'.
I need to insert these values to another table, after this action I should have 9 records with id from the first table and 'premium' varchar in the second table:
1, 'premium';
2, 'premium';
etc.
How to write the function for SQL?
Are you looking for insert . . . select or create table as?
insert into table2 (id, value)
select id, 'premium'
from table1;
or:
create table table2 as
select id, 'premium' as value
from table1;
Do you want this?
demo:db<>fiddle
INSERT INTO second_table (id, text_value)
SELECT id, 'premium'
FROM first_table;
I need to insert a row into one table and use this row's id to insert two more rows into a different table within one transaction. I've tried this
begin;
insert into table default values returning table.id as C;
insert into table1(table1_id, column1) values (C, 1);
insert into table1(table1_id, column1) values (C, 2);
commit;
But it doesn't work. How can I fix it?
updated
You need a CTE, and you don't need a begin/commit to do it in one transaction:
WITH inserted AS (
INSERT INTO ... RETURNING id
)
INSERT INTO other_table (id)
SELECT id
FROM inserted;
Edit:
To insert two rows into a single table using that id, you could do that two ways:
two separate INSERT statements, one in the CTE and one in the "main" part
a single INSERT which joins on a list of values; a row will be inserted for each of those values.
With these tables as the setup:
CREATE TEMP TABLE t1 (id INTEGER);
CREATE TEMP TABLE t2 (id INTEGER, t TEXT);
Method 1:
WITH inserted1 AS (
INSERT INTO t1
SELECT 9
RETURNING id
), inserted2 AS (
INSERT INTO t2
SELECT id, 'some val'
FROM inserted1
RETURNING id
)
INSERT INTO t2
SELECT id, 'other val'
FROM inserted1
Method 2:
WITH inserted AS (
INSERT INTO t1
SELECT 4
RETURNING id
)
INSERT INTO t2
SELECT id, v
FROM inserted
CROSS JOIN (
VALUES
('val1'),
('val2')
) vals(v)
If you run either, then check t2, you'll see it will contain the expected values.
Please find the below query:
insert into table1(columnName)values('stack2');
insert into table_2 values(SCOPE_IDENTITY(),'val1','val2');
I have a query having cte with number of columns, I want to insert a record if ID from the results of that query does not exist in table that I am inserting, or if the ID exists I want to update data using that ID.
So far I have tried this:
WITH cte_base as(
SELECT DISTINCT ID, statusID
FROM testtable
)
SELECT *
FROM cte_base
IF EXISTS(SELECT * FROM Newtable WHERE EXISTS (SELECT ID FROM cte_base))
UPDATE newtable
SET statusID = 2
WHERE Newtable.ID = cte_base.ID
ELSE
INSERT INTO newtable(ID, statusID)
SELECT ID, statusID
FROM cte_base
WHERE Newtable.ID <> cte_base.ID
I have to run this query against live data, hence I would like to know if my logic is correct.
Basic merge example based on your provided code.
MERGE INTO NewTable AS T
USING
(
SELECT DISTINCT ID,statusID
FROM testtable
) AS S
ON S.ID = T.ID
WHEN MATCHED THEN SET
T.StatusID = 2
WHEN NOT MATCHED INSERT (ID,statusID)
VALUES (S.ID,S.statusID)
;
What are you trying to do?
EXISTS (SELECT ID FROM cte_base)
If cte_base has any records that will be true every time
That is no different than
SELECT DISTINCT ID, statusID
FROM testtable
And will be true every time if there are any records in testtable
Does Big Query support operations like "REPLACE INSERT" or something related to that?
If I run a query like this twice:
INSERT INTO table(column1) VALUES(1)
It'll create a duplicated row, is it possible to insert a row only if a column with the same value does not exist?
Thanks!
Below should make it
#standardSQL
INSERT INTO yourTable(column1)
SELECT value FROM (SELECT 1 AS value)
LEFT JOIN yourTable
ON column1 = value
WHERE column1 IS NULL
Does this work for you?
INSERT INTO table(column1)
WITH s AS (SELECT 1 src)
SELECT src FROM s WHERE NOT EXISTS (
SELECT * FROM table t WHERE t.column1 = s.src
)
I am trying to create a SQL query where I need to insert a new sets of records based but 1 column is needed from required table.
E.g.,
TABLE_1
=======
ID,
A,
B
TABLE2
======
ID,
C,
D
Each ID are identical ID column.
I have a query of this format:
INSERT INTO TABLE_1 (ID, A, B) VALUES (???, "Yes", "What")
WHERE ID IN (SELECT ID FROM TABLE_2 WHERE ID > 10)
This, clearly doesn't work.
My question: how do I add the ID value from Table 2 into Table 1 and make it runnable? This is a query that must run on Oracle 11g.
Try this query:
INSERT INTO MyTable(ID, A, B)
SELECT ID,'YES','What' FROM TABLE_2 WHERE ID > 10