How can I find ".dat" within all *.mk files? - awk

I am trying to grep for the .dat string in all my *.mk files using the below command. I am wondering if this is right, because it doesn't give me any output.
find . -name "*.mk" | grep *.dat


No it's not right, there are a couple of issues: 1) you seem to be supplying grep with a glob pattern, 2) the pattern is not quoted and will be expanded by the shell before grep ever sees it, 3) you're grep'ing through filenames, not file contents.
To address 1), use Basic Regular Expression, the equivalent here would be .*\.dat or just .dat. 2) is a matter of using single or double-quotes. 3) find returns filenames, so if you want grep to operate on each of those files either use the -exec flag for find or use xargs. All these taken together:
find . -name '*.mk' | xargs grep '.dat'


Use Find's Exec Flag
You don't really need a pipeline here, and can bypass the need for xargs. Use the following invocation to perform a fixed-string search (which is generally faster than a regex match) on each file found by the standard find command:
find . -name '*.mk' -exec grep -F .dat {} \;
If you're using GNU find, you can use this syntax instead to avoid the process overhead of multiple calls to grep:
find . -name '*.mk' -exec grep -F .dat {} +


Use xargs:
find . -name "*.mk"| xargs grep '\.dat'


Using exec option in find command this way:
find . -name "*.mk" -exec grep ".dat" \{\} \;

Related

SSH command for find and replace

I am wanting to change the username and password in all my config files
What would the command be in SSH to find
$txpcfg['user'] = 'EXAMPLE-1';
And change it across my server to:
$txpcfg['user'] = 'EXAMPLE-2';

sed can be used with the -i flag to do in-line replacement.
Something like:
find /path/to/workingDir -name *.config -type f -print0 | xargs -0 sed -i 's/\$txpcfg\[\'user\'\]\ = \'$oldUser\';/\$txpcfg\[\'user\'\]\ \=\ \'$newUser\';/g'
That regex / search pattern can probably be cleaned up.

Issue with genstrings for Swift file

genstrings works well to extract localizable content from .m file as,
find . -name \*.m | xargs genstrings -o en.lproj
But, not working for .swift file as,
find . -name \*.swift | xargs genstrings -o en.lproj

The genstrings tool works fine with swift as far as I am concerned. Here is my test:
// MyClass.swift
let message = NSLocalizedString("This is the test message.", comment: "Test")
then, in the folder with the class
# generate strings for all swift files (even in nested directories)
$ find . -name \*.swift | xargs genstrings -o .
# See results
$ cat Localizable.strings
/* Test */
"This is the test message." = "This is the test message.";
$

I believe genstrings works as intended, however Apple's xargs approach to generate strings from all your project's files is flawed and does not properly parse paths containing spaces.
That might be the reason why it's not working for you.
Try using the following:
find . -name \*.swift | tr '\n' '\0' | xargs -0 genstrings -o .

We wrote a command line tool that works for Swift files and merges the result of apples genstrings tool.
It allows for key and value in NSLocalizedString
https://github.com/KeepSafe/genstrings_swift

There's an alternative tool called SwiftGenStrings
Hello.swift
NSLocalizedString("hello", value: "world", comment: "Hi!")
SwiftGenStrings:
$ SwiftGenStrings Hello.swift
/* Hi! */
"hello" = "world";
Apple genstrings:
$ genstrings Hello.swift
Bad entry in file Hello.swift (line = 1): Argument is not a literal string.
Disclaimer: I worked on SwiftGenStrings.

There is a similar question here:
How to use genstrings across multiple directories?
find ./ -name "*.m" -print0 | xargs -0 genstrings -o en.lproj

The issue I was having with find/genstrings was twofold:
When it reached folder names with spaces (generated by the output of find), it would exit with an error
When it reached the file where I had my custom routine defined, it was giving me an error when trying to parse my actual function definition
To fix both those problems I'm using the following:
find Some/Path/ \( -name "*.swift" ! -name "MyExcludedFile.swift" \) | sed "s/^/'/;s/$/'/" | xargs genstrings -o . -s MyCustomLocalizedStringRoutine
To summarize, we use the find command to both find and exclude your Swift files, then pipe the results into the sed command which will wrap each file path in quotes, then finally pipe that result into the genstrings command

Xcode now includes a powerful tool for extracting localizations.
Just select your project on the left then Editor menu >> Export localizations.
You'll get a folder with all the text in your files as well as the Localizable.strings and InfoPlist.strings
More details here:
https://developer.apple.com/library/archive/documentation/MacOSX/Conceptual/BPInternational/LocalizingYourApp/LocalizingYourApp.html

how to grep for a pattern in a few set of files under a directory?

i have a large number of files under a directory. out of that i need to search for a pattern ONLY in files which were created/last modified on the month of November. By using Awk and xargs command i was able to acheive this. But I would like to know whether there is a simple grep command to acheive the same. Below is the command which I used
ls -ltr |grep "Nov"|awk '{print $9}'|xargs grep -i (pattern)
Could you please help me on this one ?

Use the find command:
find . -newermt 2013-11-1 ! -newermt 2013-11-30 -type f -print0 | xargs -0 grep -i pattern

How do I handle spaces in a script that uses the results of find in a for loop?

I am trying to write a simple command that searches through a music directory for all files of a certain type and copies them to a new directory. I would be fine if the files didn't have spaces.
I'm using a script from the following question, but it fails for spaces:
bash script problem, find , mv tilde files created by gedit
Any suggestions on how I can handle spaces, once I'm satisfied that all the files are being listed, I'll change echo to cp
for D in `find . -name "*.wma*"`; do echo "${D}"; done

You probably want to do this instead:
find . -name *.wma -exec echo "{}" \;

Scp locate's output by Xargs

I want to make a list of files of locate's output.
I want scp to take the list.
I am not sure about the syntax.
My attempt with pseudo-code
locate labra | xargs scp {} masi#11.11.11:~/Desktop/
How can you move the files to the destination?

xargs normally takes as many arguments it can fit on the command line, but using -I it suddenly only takes one. GNU Parallel http://www.gnu.org/software/parallel/ may be a better solution:
locate labra | parallel -m scp {} masi#11.11.11:~/Desktop/
Since you are looking at scp, may I suggest you also check out rsync?
locate labra | parallel -m rsync -az {} masi#11.11.11:~/Desktop/

Typically, {} is a findism:
find ... -exec cmd {} \;
Where {} is the current file that find is working on.
You can get xargs to behave similar with:
locate labra | xargs -I{} echo {} more arguments
However, you'll quickly notice that it runs the commands multiple times instead of one call to scp.
So in the context of your example:
locate labra | xargs -I{} scp '{}' masi#11.11.11:~/Desktop/
Notice the single quotes around the {} as it'll be useful for paths with spaces in them.