I have following type of data in my Sql server:-
Field Value Month
Administrative 5 November
Counteracting 7 November
District1 9 November
District2 6 November
Administrative 1 December
Counteracting 2 December
District1 3 December
District2 4 December
Administrative 9 January
Counteracting 8 January
District1 5 January
District2 6 January
Now the problem is I am not able to figure out that how to show this data in the following format:-
Field November December January
Administrative 5 1 9
Counteracting 7 2 8
District1 9 3 5
District2 6 4 6
What you are trying to do is PIVOT the data. There are a few ways to perform this. If you know the values ahead of time, then you can hard-code the values.
You can use an aggregate function with a CASE statement:
select field,
sum(case when month ='November' then value end) November,
sum(case when month ='December' then value end) December,
sum(case when month ='January' then value end) January,
etc
from yourtable
group by field
See SQL Fiddle with Demo
In SQL Server 2005+ you can use the PIVOT function:
select field, November, December, January
from
(
select field,
value, month
from yourtable
) src
pivot
(
sum(value)
for month in (November, December, January, etc)
) piv
See SQL Fiddle with Demo
If you had an unknown number of values to transform into columns then you could use dynamic sql to pivot the data.
That is a typical pivoting problem. Check out the SQL Server PIVOT statement: http://msdn.microsoft.com/en-us/library/ms177410(v=sql.105).aspx
It will solve your problem.
You need to use Pivot, check out example:
http://blogs.msdn.com/b/spike/archive/2009/03/03/pivot-tables-in-sql-server-a-simple-sample.aspx
Related
I'm creating an Absence Report for HR. The Absence Data is stored in the database as a single row per day (the columns are EmployeeId, Absence Date, Duration). So if I'm off work from Tuesday 11 February 2020 to Friday 21 February 2020 inclusive, there will be 9 rows in the table:
11 February 2020 - 1 day
12 February 2020 - 1 day
13 February 2020 - 1 day
14 February 2020 - 1 day
17 February 2020 - 1 day
18 February 2020 - 1 day
19 February 2020 - 1 day
20 February 2020 - 1 day
21 February 2020 - 1 day
(see screenshot below)
HR would like to see a single entry in the report for a contiguous period of absence:
My question is - without using a cursor, how can I calculate the is in SQL (even more complicated because I have to do this using Linq to SQL, but I might be able to swap this out for a stored procedure. Note that the criterion for contiguous data is adjacent working days EXCLUDING weekends and bank holidays. I hope I've made myself clear ... apologies if not.
This is a form of gaps-and-islands. In this case, use lag() to see if two vacations overlap and then a cumulative sum:
select employee, min(absent_from), max(absent_to)
from (select t.*,
sum(case when prev_absent_to = dateadd(day, -1, absent_from) then 0 else 1
end) over (partition by employee order by absent_to) as grp
from (select t.*,
lag(absent_to) over (partition by employee order by absent_from) as prev_absent_to
from t
) t
) t
group by employee, grp;
If you need to deal with holidays and weekends, then you need a calendar table.
After joining two tables in google bigquery, I ended up with a table which have two sets of year and month in four separate columns. First two year and month columns should form one date and the second pair for another date. I need to convert each of those two sets of year and month in to two single dates, and then get the difference between those two dates in terms of months or days.
Example of the table is provided below:
year month year month
0 2013 12 2014 2
1 2014 5 2014 9
2 2015 6 2015 8
If anyone can help code this in bigquery, would be really helpful.
Thanks in advance.
#standardSQL
WITH `project.dataset.table` AS (
SELECT 2013 year1, 12 month1, 2014 year2, 2 month2 UNION ALL
SELECT 2014, 5, 2014, 9 UNION ALL
SELECT 2015, 6, 2015, 8
)
SELECT
DATE(year1, month1, 1) date1,
DATE(year2, month2, 1) date2,
DATE_DIFF(DATE(year2, month2, 1), DATE(year1, month1, 1), DAY) diff_in_days
FROM `project.dataset.table`
with result
Row date1 date2 diff_in_days
1 2013-12-01 2014-02-01 62
2 2014-05-01 2014-09-01 123
3 2015-06-01 2015-08-01 61
To get the difference in months, you don't need to convert to dates. Just use arithmetic:
select (year1 * 12 + month1) - (year2 * 12 + month2)
So you can use the DATE(YEAR,MONTH,DAY) function two times passing the data that you've got on both columns and passing 1 as the day since it doesn't matter, then use DATE_DIFF(date_expression, date_expression, date_part) passing the dates that you got from those functions and the DATE PART that you want to get as a return, it accepts :
DAY,WEEK, ISOWEEK,MONTH,QUARTER,YEAR and ISOYEAR.
I have code that distinctly counts authorizations grouped by month and year.
I added a calculated field to show the percent of change but my issue is I only want to get this percentage between the years by month.
My code calculates the percent for each previous row. which when pulled into SSRS displays the incorrect value after the for column.
Select D.Month
,D.Year
,count( distinct D.authorization_number) [Admission Events]
,CAST(lag(Count(distinct D.authorization_number), 1) over (order by D.month) - Count(distinct D.authorization_number) as FLOAT) / CAST(Count(distinct D.authorization_number)as FLOAT) [Admission Events Pct]
From #Detail D
Group BY D.Month
,D.Year
In these results I would like to only display the pct for year 2018 in SSRS.
Month Year Admission Events Admission Events Pct
1 2017 5919 NULL
1 2018 6057 -0.0227835562159485
2 2017 5302 0.142399094681252
2 2018 5234 0.0129919755445166
3 2017 5548 -0.0565969718817592
3 2018 5389 0.0295045462980145
4 2017 5128 0.0508970358814353
4 2018 5503 -0.0681446483736144
5 2017 5768 -0.0459431345353675
5 2018 5708 0.0105115627189909
6 2017 5461 0.0452298113898553
6 2018 2606 1.09554873369148
Is this what you want?
select t.*
from (<your query here>) t
where year = 2018;
You need a subquery or CTE so the where doesn't interfere with the lag().
I have the following table:
Year Line January Febraury March .... December
2011 B1 5 10 20
2012 B1 10 15 25 ...
2011 A1 4 8 10 ...
And I want to insert a subtotal row each two lines (if exists), in particular each time year and Line changing: so
Year Line January Febraury March .... December
2011 B1 5 10 20
2012 B1 10 15 25 ...
--- B1 +100% +50% +25% ..
2011 A1 4 8 10 ...
How can I do this in T-SQL ?
Maybe using cursor ?
Are you certain that you want to insert a new row? Or just be able to calculate that subtotal when you query the data?
Query Version
SELECT
Year,
Line,
SUM(January) AS January,
SUM(February) AS February,
...
SUM(December) AS December
FROM
yourTable
GROUP BY
Year,
Line
WITH
ROLLUP
ORDER BY
Year,
Line
Insert Version
If you just one one level of summary, remove the WITH ROLLUP
INSERT INTO
yourTable
SELECT
Year,
NULL,
SUM(January) AS January,
SUM(February) AS February,
...
SUM(December) AS December
FROM
yourTable
GROUP BY
Year
WITH
ROLLUP
EDIT Follow question edit
I strongly suggest that you mean a query, not a change to the actual data. I also suggest that you either build these lines in your reporting environment, or you put the % values to the right of each record...
SELECT
this_year.Year,
this_year.Line,
this_year.January,
CAST(this_year.January AS DECIMAL(8,2)) / CAST(last_year.January AS DECIMAL(8,2)) AS January_Change,
...
FROM
yourTable AS this_year
LEFT JOIN
yourTable AS last_year
ON last_year.year = this_year.year-1
AND last_year.line = this_year.line
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Running total by grouped records in table
I am trying to put together an SQL statement that returns the SUM of a value by month, but on a year to date basis. In other words, for the month of March, I am looking to get the sum of a value for the months of January, February, and March.
I can easily do a group by to get a total for each month by itself, and potentially calculate the year to date value I need in my application from this data by looping through the results set. However, I was hoping to have some of this work handled with my SQL statement.
Has anyone ever tackled this type of problem with an SQL statement, and if so, what is the trick that I am missing?
My current sql statement for monthly data is similar to the following:
Select month, year, sum(value) from mytable group by month, year
If I include a where clause on the month, and only group by the year, I can get the result for a single month that I am looking for:
select year, sum(value) from mytable where month <= selectedMonth group by year
However, this requires me to have a particular month pre-selected or to utilize 12 different SQL statements to generate one clean result set.
Any guidance that can be provided would be greatly appreciated!
Update: The data is stored on an IBM iSeries.
declare #Q as table
(
mmonth INT,
value int
)
insert into #Q
values
(1,10),
(1,12),
(2,45),
(3,23)
select sum(January) as UpToJanuary,
sum(February)as UpToFebruary,
sum(March) as UpToMarch from (
select
case when mmonth<=1 then sum(value) end as [January] ,
case when mmonth<=2 then sum(value) end as [February],
case when mmonth<=3 then sum(value) end as [March]
from #Q
group by mmonth
) t
Produces:
UpToJanuary UpToFebruary UpToMarch
22 67 90
You get the idea, right?
NOTE: This could be done easier with PIVOT tables but I don't know if you are using SQL Server or not.
As far as I know DB2 does support windowing functions although I don't know if this is also supported on the iSeries version.
If windowing functions are supported (I believe IBM calls them OLAP functions) then the following should return what you want (provided I understood your question correctly)
select month,
year,
value,
sum(value) over (partition by year order by month asc) as sum_to_date
from mytable
order by year, month
create table mon
(
[y] int not null,
[m] int not null,
[value] int not null,
primary key (y,m))
select a.y, a.m, a.value, sum(b.value)
from mon a, mon b
where a.y = b.y and a.m >= b.m
group by a.y, a.m, a.value
2011 1 120 120
2011 2 130 250
2011 3 500 750
2011 4 10 760
2011 5 140 900
2011 6 100 1000
2011 7 110 1110
2011 8 90 1200
2011 9 70 1270
2011 10 150 1420
2011 11 170 1590
2011 12 600 2190
You should try to join the table to itself by month-behind-a-month condition and generate a synthetic month-group code to group by as follows:
select
sum(value),
year,
up_to_month
from (
select a.value,
a.year,
b.month as up_to_month
from table as a join table as b on a.year = b.year and b.month => a.month
)
group by up_to_month, year
gives that:
db2 => select * from my.rep
VALUE YEAR MONTH
----------- ----------- -----------
100 2011 1
200 2011 2
300 2011 3
400 2011 4
db2 -t -f rep.sql
1 YEAR UP_TO_MONTH
----------- ----------- -----------
100 2011 1
300 2011 2
600 2011 3
1000 2011 4