I have 2 columns in a table of varchar datatype.
date and type are the column names in table.
the data present in the table looks like this
date time
20090610 132713
20090610 132734
i need ms sql server query to concatenate these 2 columns data and display as datetime format.
Note :
1. the datatype of those 2 columns cannot be changed now.
2. i tried
select convert(datetime,date + time)
it says "Conversion failed when converting date and/or time from character string."
Suggest the possible solution.
This will return a datetime. The bottom line is to be replaced by your table
select convert(datetime,date,112)+
coalesce(stuff(stuff(rtrim(time), 5,0,':'), 3,0,':'), '') newdate
from
(VALUES ('20090610','132713'),('20090610', '132734'),('20090610', ' ')) yourtable(date,time)
Result:
newdate
2009-06-10 13:27:13.000
2009-06-10 13:27:34.000
2009-06-10 00:00:00.000
You can get it using
SELECT
convert(varchar, convert(datetime, date), 111)
+ ' ' + substring(time, 1, 2)
+ ':' + substring(time, 3, 2)
+ ':' + substring(time, 5, 2)
CREATE TABLE #Table
(
[date] VARCHAR(100),
[time] VARCHAR(100)
)
INSERT INTO #Table VALUES
('20090610','132713'),
('20090610','132734')
;WITH Bits_CTE
AS
(
SELECT
[Date],
[Time],
[hrs] = CONVERT(INT,SUBSTRING([Time], 1, 2)),
[mns] = CONVERT(INT,SUBSTRING([Time], 3, 2)),
[secs] = CONVERT(INT,SUBSTRING([Time], 5, 2))
FROM #Table
)
SELECT
[Date],
[Time],
DATEADD(HOUR,[hrs],
DATEADD(MINUTE,[mns],
DATEADD(SECOND,[secs],[Date])))
FROM Bits_CTE
CREATE FUNCTION [dbo].[DateTimeAdd]
(
#datepart date,
#timepart time
)
RETURNS datetime2
AS
BEGIN
RETURN DATEADD(dd, DATEDIFF(dd, 0, #datepart), CAST(#timepart AS datetime2));
END
Sorry - Missed the bit in your question about storing the date and time as varchars. You would therefore still need to convert these data itemsbefore using this function.
Related
How to convert date/time from 20150323153528 to 2015-03-23 15:35:28.000. I need this to filter based on the getdate(). Thanks in advance.
Select * from table
Where 20150323153528 > GETDATE() - 7
Statement to convert date to your requirement
DECLARE #Date varchar(20) = '20150323153528'
Select * from table Where
CONVERT(DATETIME, CONVERT(CHAR(8), #Date), 121) + ' ' + stuff(stuff(right('000000' + cast(#Date as varchar),6),5,0,':'),3,0,':') as DATETIME > GETDATE() - 7
In MS SQL you could use
DECLARE #Date varchar(20) = '20150323153528'
Select * from table Where CAST(convert(varchar,#Date) as datetime) > GETDATE() - 7
Please read this page.
SELECT convert(varchar, getdate(), 120) — yyyy-mm-dd hh:mm:ss(24h)
Note: I assume this is a Microsoft SQL Server environment using T-SQL:
The formatting of date / datetime values is not a concern of T-SQL. You should do that in your presentation-layer (i.e. your frontend code).
If you have date/time values represented as integers of the form 20150323153528 then you cannot use them in T-SQL. You need to convert them to strings (preferably in ISO-8601 format) for SQL Server to successfully internally convert them to datetime (or datetimeoffset) values which can then be compared with other datetime values.
I suggest performing the conversion in your application code before you send it to SQL, as a datetime-typed parameter value, like so:
Int32 weirdDateValue = 20150323153528;
String s = weirdDateValue.ToString( CultureInfo.InvariantCulture );
String dtValueAsIso8601 = String.Format("{0}-{1}-{2} {3}:{4}:{5}.{6}",
s.Substring(0, 4), s.Substring(4, 2), s.Substring(6, 2),
s.Substring(8, 2), s.Substring(10, 2), s.Substring(12, 2), s.Substring(14)
);
DateTime dtValue = DateTime.ParseExact( dtValueAsIso8601, "yyyy-MM-dd HH:mm:ss.fff" );
cmd.Parameters.Add("#dtValue", SqlDbType.DateTime).Value = dtValue;
In T-SQL the process is pretty much the same, except using MID - note that MID uses 1-based character indexes instead of 0-based:
DECLARE #input int = 20150323153528
DECLARE #s varchar( 14 ) = CONVERT( #input, nvarchar(14) )
DECLARE #dtStr varchar( 24 ) = MID( #s, 1, 2 ) + '-' + MID( #s, 3, 2 ) + '-' + MID( #s, 5, 2 ) + ' ' + -- etc...
DECLARE #dt datetime = CONVERT( #dtStr, datetime )
SELECT
*
FROM
[table]
WHERE
#dt > GETDATE() - 7
If the integer values are stored in an actual column instead of a parameter you'll need to convert the logic into a scalar UDF which performs the conversion. I strongly suggest you change the table's design to add a strongly-typed datetime column and permanently store the value there, and then drop the datetime-as-int column:
CREATE FUNCTION ConvertIntDateIntoDateTime(#dateAsInt int) RETURNS datetime AS
BEGIN
-- same code as above minus the SELECT statement
RETURN #dt
END
Used in an inner subquery to allow the data to be accessed in WHERE statements, like so:
SELECT
*
FROM
(
SELECT
*,
dbo.ConvertIntDateIntoDateTime( someDateColumn ) AS someDateColumn2
FROM
[table]
) AS FixedTable
WHERE
FixedTable.someDateColumn2 > GETDATE() - 7
Good Day
I am working of a existing SQL Server Database. What the developers did is to keep the Date and time separate. The Date is in DateTime format (what I want) but the time is incorrect. if it is 14:30 it shows as 1430 when its 09:25 shows as 925. I am trying tyo combine the date and time to have a Date Time view for an program I am writing on top of this database.
I have created the date as a normal date like this:
CASE
WHEN LEN(T0.BeginTime) = 3 THEN '0' + LEFT(T0.BeginTime, 1) + ':' + RIGHT(T0.BeginTime, 2)
ELSE LEFT(T0.BeginTime, 2) + ':' + RIGHT(T0.BeginTime, 2)
END AS 'NEW Start Time'`
The date now looks like it's the correct format but when I want to combine the date and time I get VARCHAR to DateTime error.
How can I fix this?
This is the error:
The conversion of a varchar data type to a datetime data type resulted in an out-of-range value (ONLY RAN 804 RECORDS)
Thanks
This should do the trick, Hope it helps.
DECLARE #DateTime TABLE (
DateWithTime DATE,
BeginTime INT);
INSERT INTO #DateTime
VALUES ('2014-08-04', '1525'),
('2014-08-04', '525'),
('2014-08-04', '15'),
('2014-08-04', '5'),
('2014-08-04', '0'),
('2014-08-04', '90')
;WITH cte_BeginTimeFix
AS (
SELECT
CONVERT(VARCHAR(10), DateWithTime, 120) AS DateWithTime,
RIGHT('0000' + CAST(BeginTime AS VARCHAR(4)), 4) AS BeginTime
FROM #DateTime
)
, cte_DateString
AS (
SELECT DateWithTime,
BeginTime,
DateWithTime + ' ' + STUFF(STUFF('00:00:00.000', 4, 2, RIGHT(BeginTime, 2)), 1, 2, LEFT(BeginTime, 2)) AS DateTimeStr
FROM cte_BeginTimeFix
)
SELECT DateWithTime,
BeginTime,
CASE
WHEN ISDATE(DateTimeStr) = 1 THEN CAST(DateTimeStr AS DATETIME)
ELSE NULL
END AS DateTimeStr
FROM cte_DateString
A different approach is to convert the time column in minutes and add it to the date
DATEADD(minute, T0.BeginTime / 100 * 60 + T0.BeginTime % 100
, CONVERT(VARCHAR, T0.BeginDate, 112))
with that the length of the time column doesn't matter
This should work:
CONVERT
(
DATETIME,
CONVERT(VARCHAR,T0.Date,112) +
' ' +
CASE
WHEN ISNULL(T0.BeginTime,'0') = '0'
THEN '00:00'
ELSE
RIGHT
(
'00' + LEFT(T0.BeginTime,LEN(T0.BeginTime) - 3),
2
) +
':' +
RIGHT(T0.BeginTime,2)
END
)
Okay, so I have kind of a weird issue... the dates in the table have been entered in as string values MMDDYYYY and I'm trying to have the displayed as MM/DD/YYYY in a report and only select the most recent date pertaining to an ID, because some ID's may have multiple dates.
Example of my table:
ID | MyDate |
------+----------+
1 | 01302014 |
1 | 04222014 |
2 | 01302014 |
What I want to see when I select and insert into a temp table is this:
ID | MyDate |
------+-----------+
1 | 4/22/2014 |
2 | 1/30/2014 |
I know that storing dates as string values is a poor practice especially when storing them as MMDDYYYY, but does anyone have a solution to this nightmare?
EDIT
I forgot to mention that some fields might be NULL. Not sure if that makes a difference or not, but I think it does if I try to flip the dates using Right, Left, Convert.
This question is for almost a year ago, nut probably someone can find it useful.
You need to CONVERT your string to DATE format and use a ROW_NUMBER function to window your result set.
Create table
DECLARE #tbl TABLE(Id INT, myDate VARCHAR(8))
Sample data
INSERT #tbl
SELECT 1 , '01302014' UNION ALL
SELECT 1 , '04222014' UNION ALL
SELECT 2 , '01302014'
Query
;WITH C AS(
SELECT ROW_NUMBER() OVER (PARTITION BY Id ORDER BY CONVERT(DATETIME, (SUBSTRING(myDate, 5, 4) + '.' + SUBSTRING(myDate, 1, 2) + '.' + SUBSTRING(myDate, 3, 2)), 101) DESC) AS Rn
,Id
,CAST(CONVERT(DATETIME, (SUBSTRING(myDate, 5, 4) + '.' + SUBSTRING(myDate, 1, 2) + '.' + SUBSTRING(myDate, 3, 2)), 101) AS DATE) AS myDate
FROM #tbl
)
SELECT Id, myDate
FROM C
WHERE Rn = 1
SQLFiddle Demo
Using a CONVERT like the following code snippet will work on any SQL Server regardless of language and/or locale configuration.
DECLARE #OldDate varchar(8);
SELECT #OldDate = '04252012';
SELECT CONVERT(datetime, substring(#OldDate,5,4) + '-' + substring(#OldDate,1,2) + '-' + substring(#OldDate,3,2) + 'T00:00:00')
You could try this:
convert(date,SUBSTRING (MyDate,1,2)+'/'+SUBSTRING (MyDate,3,2)+'/'+SUBSTRING (MyDate,5,4),101)
Select CONVERT(datetime,RIGHT('01302014',4) +
LEFT('01302014',2) +
SUBSTRING('01302014',3,2))
'2014-01-30 00:00:00.000'
;with Cte as (Select Id,CONVERT(datetime,RIGHT(MyDate,4)+LEFT(MyDate,2)+SUBSTRING(MyDate,3,2)) as sDate, C=ROW_NUMBER()
over(PARTITION By Id Order by MyDate desc)
From #Temp)
select *
from Cte
where C=1
First do a conversion to a datetime datatype, then convert it to a format you wish to:
select id, convert(varchar, max(convert(datetime,right(mydate, 4)+left(mydate,4))), 101)
from #t
group by id
Although I can't understand why would it not suffice to just convert it do datetime and leave the formatting where it belongs, to the client.
Select id,convert(varchar(11),cast(dateValue as Date),101)
From
(
Select id,MAX(cast(MyDate As Date)) as dateValue
From tableName
Group By id
) t
The simplest solution is mySQL str_to_date() function.
STR_TO_DATE(`MyDate`, '%m%d%Y')
This will convert it to a DATETIME which you then format as required
DATE_FORMAT(STR_TO_DATE(`MyDate`, '%m%d%Y'), '%c/%e/%Y')
Complete Query:
Select ID, Case When IsDate(RIGHT(MyDate,4)+LEFT(MyDate,2)+SUBSTRING(MyDate,3,2)) = 1
THEN Convert(varchar(10), Convert(datetime, RIGHT(MyDate,4)+LEFT(MyDate,2)+SUBSTRING(MyDate,3,2)), 101)
ELSE Null END AS MyDate FROM YourTable a where Case When IsDate(RIGHT(MyDate,4)+LEFT(MyDate,2)+SUBSTRING(MyDate,3,2)) = 1
THEN Convert(varchar(10), Convert(datetime, RIGHT(MyDate,4)+LEFT(MyDate,2)+SUBSTRING(MyDate,3,2)), 101)
ELSE Null END = (Select Max(Case When IsDate(RIGHT(MyDate,4)+LEFT(MyDate,2)+SUBSTRING(MyDate,3,2)) = 1
THEN Convert(varchar(10), Convert(datetime, RIGHT(MyDate,4)+LEFT(MyDate,2)+SUBSTRING(MyDate,3,2)), 101)
ELSE Null END)
FROM YourTable b
Where a.ID = b.ID
)
This is a modified version from Dimitris Kalaitzis' answer.
First, you will need to convert your MyDate into String. The data for example (01302014) is not treated as a string and the leading zero will be removed when you convert it. Therefore, use CAST to make MyDate as a String and add a leading 0 to it. Then you find the right 8 characters so to get rid of the leading zero for months from Oct to Dec.
Here is the code that should work for you:
CONVERT(Date, SUBSTRING(RIGHT('0' + CAST(MyDate AS VARCHAR(10)), 8), 1, 2) + '/' + SUBSTRING(RIGHT('0' + CAST(MyDate AS VARCHAR(10)), 8), 3, 2) + '/' + SUBSTRING(RIGHT('0' + CAST(MyDate AS VARCHAR(10)), 8), 5, 4), 101)
Hope this helps.
You first have to add the slashes to be able to convert it to a date, use STUFF
Then convert it to a DATE and select the MAX group by ID
Query:
SELECT ID, FORMAT(MAX(CONVERT(DATE,STUFF(STUFF(MyDate,3,0,'/'),6,0,'/'))),'MM/dd/yyyy') AS MyDate FROM TableName
GROUP BY ID
I have datetime values stored in a field as strings. They are stored as strings because that's how they come across the wire and the raw values are used in other places.
For reporting, I want to convert the custom format string (yyyymmddhhmm) to a datetime field in a view. My reports will use the view and work with real datetime values. This will make queries involving date ranges much easier.
How do I perform this conversion? I created the view but can't find a way to convert the string to a datetime.
Thanks!
Update 1 -
Here's the SQL I have so far. When I try to execute, I get a conversion error "Conversion failed when converting datetime from character string."
How do I handle nulls and datetime strings that are missing the time portion (just yyyymmdd)?
SELECT
dbo.PV1_B.PV1_F44_C1 AS ArrivalDT,
cast(substring(dbo.PV1_B.PV1_F44_C1, 1, 8)+' '+substring(dbo.PV1_B.PV1_F44_C1, 9, 2)+':'+substring(dbo.PV1_B.PV1_F44_C1, 11, 2) as datetime) AS ArrDT,
dbo.MSH_A.MSH_F9_C2 AS MessageType,
dbo.PID_A.PID_F3_C1 AS PRC,
dbo.PID_A.PID_F5_C1 AS LastName,
dbo.PID_A.PID_F5_C2 AS FirstName,
dbo.PID_A.PID_F5_C3 AS MiddleInitial,
dbo.PV1_A.PV1_F2_C1 AS Score,
dbo.MSH_A.MessageID AS MessageId
FROM dbo.MSH_A
INNER JOIN dbo.PID_A ON dbo.MSH_A.MessageID = dbo.PID_A.MessageID
INNER JOIN dbo.PV1_A ON dbo.MSH_A.MessageID = dbo.PV1_A.MessageID
INNER JOIN dbo.PV1_B ON dbo.MSH_A.MessageID = dbo.PV1_B.MessageID
According to here, there's no out-of-the-box CONVERT to get from your yyyymmddhhmm format to datetime.
Your strategy will be parsing the string to one of the formats provided on the documentation, then convert it.
declare #S varchar(12)
set #S = '201107062114'
select cast(substring(#S, 1, 8)+' '+substring(#S, 9, 2)+':'+substring(#S, 11, 2) as datetime)
Result:
2011-07-06 21:14:00.000'
This first changes your date string to 20110706 21:14. Date format yyyymmdd as a string is safe to convert to datetime in SQL Server regardless of SET DATEFORMAT setting.
Edit:
declare #T table(S varchar(12))
insert into #T values('201107062114')
insert into #T values('20110706')
insert into #T values(null)
select
case len(S)
when 12 then cast(substring(S, 1, 8)+' '+substring(S, 9, 2)+':'+substring(S, 11, 2) as datetime)
when 8 then cast(S as datetime)
end
from #T
Result:
2011-07-06 21:14:00.000
2011-07-06 00:00:00.000
NULL
You can use CAST or CONVERT.
Example from the site:
G. Using CAST and CONVERT with
datetime data
The following example displays the
current date and time, uses CAST to
change the current date and time to a
character data type, and then uses
CONVERT display the date and time in
the ISO 8901 format.
SELECT
GETDATE() AS UnconvertedDateTime,
CAST(GETDATE() AS nvarchar(30)) AS UsingCast,
CONVERT(nvarchar(30), GETDATE(), 126) AS UsingConvertTo_ISO8601;
GO
Here is the result set.
UnconvertedDateTime UsingCast UsingConvertTo_ISO8601
----------------------- ------------------------------ ------------------------------
2006-04-18 09:58:04.570 Apr 18 2006 9:58AM 2006-04-18T09:58:04.570
(1 row(s) affected)
Generally, you can use this code:
SELECT convert(datetime,'20110706',112)
If you need to force SQL Server to use a custom format string, use the following code:
SET DATEFORMAT ymd
SELECT convert(datetime,'20110706')
A one liner:
declare #datestring varchar(255)
set #datestring = '201102281723'
select convert(datetime, stuff(stuff(#datestring,9,0,' '),12,0,':') , 112 )
Result:
2011-02-28 17:23:00.000
DECLARE #d VARCHAR(12);
SET #d = '201101011235';
SELECT CONVERT(SMALLDATETIME, STUFF(STUFF(#d,9,0,' '),12,0,':'));
Note that by storing date/time data using an inappropriate data type, you cannot prevent bad data from ending up in here. So it might be safer to do this:
WITH x(d) AS
(
SELECT d = '201101011235'
UNION SELECT '201101011267' -- not valid
UNION SELECT NULL -- NULL
UNION SELECT '20110101' -- yyyymmdd only
),
y(d, dt) AS
(
SELECT d,
dt = STUFF(STUFF(LEFT(d+'000000',12),9,0,' '),12,0,':')
FROM x
)
SELECT CONVERT(SMALLDATETIME, dt), ''
FROM y
WHERE ISDATE(dt) = 1 OR d IS NULL
UNION
SELECT NULL, d
FROM y
WHERE ISDATE(dt) = 0 AND d IS NOT NULL;
DECLARE #test varchar(100) = '201104050800'
DECLARE #dt smalldatetime
SELECT #dt = SUBSTRING(#test, 5, 2)
+ '/' + SUBSTRING(#test, 7, 2) + '/'
+ SUBSTRING(#test, 1, 4) + ' ' + SUBSTRING(#test, 9, 2)
+ ':' + SUBSTRING(#test, 11, 2)
SELECT #dt
Output:
2011-04-05 08:00:00
I have a column which has date-values stored in varchar (format ddmmyy) like this
231280
121280
131185
...
How to convert these values into datetime data type?
Set DateFormat DMY
GO
Select Cast(Stuff(Stuff(SomeValue, 3, 0, '-'), 6, 0, '-') As datetime)
From MyData
Use substring to get year, month, and day, if year greater than 11 add 19 to it if not add 20, to get year in format 2009, but this is your query just instead of string add your column name
select CAST(
CASE WHEN CAST(SUBSTRING('231280', 5, 2) AS INT) >11
THEN '19'+SUBSTRING('231280', 5, 2)
else '20'+SUBSTRING('231280', 5, 2)
END
+'-'+SUBSTRING('231280', 3, 2)+'-'+SUBSTRING('231280', 1, 2) as datetime)
You'd have to use some substring footwork to convert your string to a known date format. Here's an example converting the string to format 3, "British/French":
declare #YourTable table (YourColumn varchar(50))
insert #YourTable
select '231280'
union all select '121280'
union all select '131185'
select convert(datetime, substring(YourColumn,1,2) + '/' +
substring(YourColumn,3,2) + '/' + substring(YourColumn,5,2), 3)
from #YourTable
Because this format is non standard, use
DECLARE #field char(6)
SET #field = '231280'
select convert(datetime, right(#field, 2) + substring(#field, 3, 2) + left(#field, 2) , 12)