I am currently using SQL Server 2008, and i have a list of numbers. There are some that are associated with letters, and I would like to pull only the numbers that are associated with these values. I thought a right statement might work, but I'm kind of a noob, and havent been able to find a way that works.
For example:
columnName
==============
12
13
122b
11a
10z
9
609
I want to view:
Result
==============
122b
11a
10z
try this:
WHERE YourColumn like '%[a-z]'
SQL Server 2008 doesn't support regexes directly (it requires a CLR extension), but it's pattern matching supports ranges:
WHERE column LIKE '%[a-zA-Z]%'
SELECT *
FROM tableName
WHERE ISNUMERIC(columnName) = 0
SQLFIddle Demo
Other Source(s)
ISNUMERIC
Related
I have a few codes as you see in the screenshot below.
I want my database only to take code that has exactly 6 digits. The code which has more than 6 digits is expected to be deleted/ignored.
How do I write my SQL query for the same?
I was thinking to use Patindex but couldn't succeed in it.
I suggest using SQL Server's enhanced LIKE operator here:
SELECT *
FROM yourTable
WHERE Code LIKE '[0-9][0-9][0-9][0-9][0-9][0-9]';
I need for a SQL query to transform an int with a value between 1 to 300000 to a number which has this pattern : always 8 number.
For example:
1 becomes 00000001,
123 becomes 00000123,
123456 becomes 00123456.
I have no idea how to do that... How can I do it?
In Standard SQL, you can use this trick:
select substring(cast( (num + 100000000) as varchar(255)) from 2)
Few databases actually support this syntax. Any given database can do what you want, but the method depends on the database you are using.
For MS SQL Server
You could use FORMAT function, like this:
SELECT FORMAT(123,'00000000')
https://database.guide/how-to-format-numbers-in-sql-server/#:~:text=Starting%20from%20SQL%20Server%202012,the%20output%20should%20be%20formatted.
Read at the link Leading Zeroes
For MySql/Oracle
You could use LPAD, like this:
SELECT LPAD('123',8,'0')
https://database.guide/how-to-add-leading-zeros-to-a-number-in-mysql/
I have a report (built using SSRS) that uses a multi-value parameter.
I want to add a Filter onto my SQL Query WHERE FieldA is LIKE any of the values stored in the parameter.
So FieldA might have the following values:
BOBJAMESLOUISE
MARYBOB
JENNY
JOHNLOUISEJAMES
BOB
JENNYJAMESMIKE
And #ParamA might have the following values:
Bob, Louise
Therefore in this example only records 1, 3, 4 and 5 should be returned
Thanks to any help in advance :)
P.S I'm using SQL Server 2008
You will want to implement a function like the split function. This can take a comma separated value list and separate it into rows like you want.
Below is a link for a couple of different versions, any of them will work for you. It also tells you how to use it.
Split Function
I am guessing its not the spiting sting part that is the issue since just googling for SQL split string you can find a lot of example. In your case what you would want after the split string is something like this. Assuming that the split string function you end up using returns a table of values Here is what your comparison query for with field A would look like.
SELECT * FROM YourTableWithFieldA WHERE (#ParamA IS NULL OR EXISTS ( SELECT * FROM YourSplitFunctionThatReturnsATableOfValues(#ParamA) SplitTable WHERE (FieldA Like '%'+SplitTable.Value+'%')))
I need to order a select query using a varchar column, using numerical and text order. The query will be done in a java program, using jdbc over postgresql.
If I use ORDER BY in the select clause I obtain:
1
11
2
abc
However, I need to obtain:
1
2
11
abc
The problem is that the column can also contain text.
This question is similar (but targeted for SQL Server):
How do I sort a VARCHAR column in SQL server that contains words and numbers?
However, the solution proposed did not work with PostgreSQL.
Thanks in advance, regards,
I had the same problem and the following code solves it:
SELECT ...
FROM table
order by
CASE WHEN column < 'A'
THEN lpad(column, size, '0')
ELSE column
END;
The size var is the length of the varchar column, e.g 255 for varying(255).
You can use regular expression to do this kind of thing:
select THECOL from ...
order by
case
when substring(THECOL from '^\d+$') is null then 9999
else cast(THECOL as integer)
end,
THECOL
First you use regular expression to detect whether the content of the column is a number or not. In this case I use '^\d+$' but you can modify it to suit the situation.
If the regexp doesn't match, return a big number so this row will fall to the bottom of the order.
If the regexp matches, convert the string to number and then sort on that.
After this, sort regularly with the column.
I'm not aware of any database having a "natural sort", like some know to exist in PHP. All I've found is various functions:
Natural order sort in Postgres
Comment in the PostgreSQL ORDER BY documentation
I have stored values in my database that look like 5XXXXXX, where X can be any digit. In other words, I need to match incoming SQL query strings like 5349878.
Does anyone have an idea how to do it?
I have different cases like XXXX7XX for example, so it has to be generic. I don't care about representing the pattern in a different way inside the SQL Server.
I'm working with c# in .NET.
You can write queries like this in SQL Server:
--each [0-9] matches a single digit, this would match 5xx
SELECT * FROM YourTable WHERE SomeField LIKE '5[0-9][0-9]'
stored value in DB is: 5XXXXXX [where x can be any digit]
You don't mention data types - if numeric, you'll likely have to use CAST/CONVERT to change the data type to [n]varchar.
Use:
WHERE CHARINDEX(column, '5') = 1
AND CHARINDEX(column, '.') = 0 --to stop decimals if needed
AND ISNUMERIC(column) = 1
References:
CHARINDEX
ISNUMERIC
i have also different cases like XXXX7XX for example, so it has to be generic.
Use:
WHERE PATINDEX('%7%', column) = 5
AND CHARINDEX(column, '.') = 0 --to stop decimals if needed
AND ISNUMERIC(column) = 1
References:
PATINDEX
Regex Support
SQL Server 2000+ supports regex, but the catch is you have to create the UDF function in CLR before you have the ability. There are numerous articles providing example code if you google them. Once you have that in place, you can use:
5\d{6} for your first example
\d{4}7\d{2} for your second example
For more info on regular expressions, I highly recommend this website.
Try this
select * from mytable
where p1 not like '%[^0-9]%' and substring(p1,1,1)='5'
Of course, you'll need to adjust the substring value, but the rest should work...
In order to match a digit, you can use [0-9].
So you could use 5[0-9][0-9][0-9][0-9][0-9][0-9] and [0-9][0-9][0-9][0-9]7[0-9][0-9][0-9]. I do this a lot for zip codes.
SQL Wildcards are enough for this purpose. Follow this link: http://www.w3schools.com/SQL/sql_wildcards.asp
you need to use a query like this:
select * from mytable where msisdn like '%7%'
or
select * from mytable where msisdn like '56655%'